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Hydrocarbons

Question
CBSEENCH11007812

Why peroxide effect is shown only by HBr and not by HCl or HI?
Or
Explain why Kharasch effect is shown by HBr only and not by HCl or HI.

Solution

The mechanism of addition of HBr to a unsymmetrical alkene (say propene) in the presence of peroxide is free radical i.e. "H-Br undergoes homolysis to form free radical.
space straight R space minus space straight O minus straight O minus straight R space rightwards arrow with Homolysis on top space stack straight R space minus straight O with bold. on top with Alkoxy space free space radical below space plus space straight O with bold. on top space minus straight R
space straight R space minus straight O with bold. on top space plus space straight H space minus Br space rightwards arrow space space straight R space minus straight O space minus straight H space plus space stack straight B with bold. on top straight r with Free space radical below
HCl is a very stable acid H-Cl bond (430 kJ moH) is stronger than H-Br bond (378 kJ mol-1) and  is not broken symmetrically by the free radicals generated by peroxide. Hence the free radical addition of HCl to alkenes is not possible.
In the case of HI, the H - I bond (297 kJ mo-1) is weaker than H-Br bond and undergoes homolysis readily to form iodine free radical. But iodine free radicals have greater tendency to combine amongst themselves to form iodine molecules rather than add to the ethylenic bond.
space space straight H minus straight I space rightwards arrow from Peroxide to Orangic of space straight H with bold. on top space plus space stack straight I with bold. on top with Iodine space free space radical below
space space straight I space plus space straight I space rightwards arrow space stack straight I subscript 2 with Iodine space molecule below
Hence HI does not respond to the peroxide effect.