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Hydrocarbons

Question

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Explain the mechanism of the following reaction:

$straight C subscript 2 straight H subscript 5 OH space rightwards arrow from 440 space straight K to Conc. space straight H subscript 2 SO subscript 4 of space CH subscript 2 space equals space CH subscript 2 space plus space straight H subscript 2 straight O$

Solution

Mechanism of the above reaction involves three steps:
(i) Formation of protonated alcohol. H₂SO₄ionises to give H⁺ ion which attacks the molecule of alcohol to form protonated alcohol.

(ii) Formation of the carbocation. Protonated alcohol eliminates a molecule of water to give a carbocation.

(iii) Formation of ethylene. Carbocation finally loses a proton to hydrogen sulphate ion to form ethylene.

Some More Questions From Hydrocarbons Chapter

Which metal is used in Wurtz’s reaction?

Name the metal which is a constituent of Grignard's reagent.

Name the products formed when an ethereal solution containing ethyl iodide and methyl iodide is heated with sodium metal.

Alkanes are less reactive. Why?

Out of n-pentane, isopentane and neopentane which has lower boiling point?

During the pyrolysis of alkanes C-C bonds break in preference to C-H bond. Why?

Define cracking.

What is the function of iodic acid in the iodination of alkanes? Can we use any other substance in its place?

What is alternation effect?

Arrange the following compounds in order of their increasing boiling points:
n-Pentane, n-Hexane, Ethane, 2-2-Dimethylpentane, 2-Methylpentane.

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