+91-8076753736[email protected]
logo
logo
-->

Organic Chemistry – Some Basic Principles And Techniques

Question
CBSEENCH11007649
Wired Faculty App

Determine the percentage of phosphorus in an organic compound weighing 0.155 of which gave 0.111 g of Mg2P2O7 in a Carius tube.

Solution

Mass of organic compound taken = 0.155 g
Mass of Mg subscript 2 straight P subscript 2 straight O subscript 7 formed = 0.111 g
Now 222 g of Mg subscript 2 straight P subscript 2 straight O subscript 7 contains phosphorus  = 62 g
therefore space space 0.111 space straight g space of space Mg subscript 2 straight P subscript 2 straight O subscript 7 space would space contain space phosphorus space space space space space space space equals space 62 over 222 cross times space 0.111 space Percentage space of space phosphorus space space equals space fraction numerator 62 space cross times space 0.111 space cross times space 100 over denominator 222 space cross times space 0.155 end fraction space space space space space space space space equals space 20.0 space percent sign

Some More Questions From Organic Chemistry – Some Basic Principles and Techniques Chapter

Which characteristic is common to different isomers of a compound?

 

Name three alkanes which do not show chain isomerism.

Name the types of structural isomerism shown by alkanes.

Name the four main types of structural isomerism. 

Write the three possible open chains of five carbon atoms

What types of structural isomerism is shown by the following pairs of organic compounds ?

Write the tautomer of acetaldehyde and write its IUPAC name.

Draw the structure of the tautomer of phenol and write its IUPAC name.

Define ring - chain isomerism. Given one example.?

Write the metamer of diethyl ether ?

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation