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Organic Chemistry – Some Basic Principles And Techniques

Question
CBSEENCH11007647

In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound. 
 

Solution

Mass of organic compound = 0.468g
Mass of barium sulphate= 0.668 g
Molecular mass of BaSO4
                            = 137 + 32 + 64
                            = 233 g mol-1
Now 233 g BaSO4 contain 32g sulphur
  therefore space 0.668 straight g space BaSO subscript 4 space would space contain
space space space space space space space space space space space space space space space space space space 32 over 233 cross times space 0.668 straight g space of space sulphur
space space therefore space space Percentage space of space sulphur space equals space 32 over 233 cross times fraction numerator 0.668 over denominator 0.468 end fraction cross times 100
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 19.60 percent sign space space space space space space space space space space space space space space space space space space space space space space space space