In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound.
Mass of organic compound = 0.468g
Mass of barium sulphate= 0.668 g
Molecular mass of BaSO4
= 137 + 32 + 64
= 233 g mol-1
Now 233 g BaSO4 contain 32g sulphur