In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12 g of AgBr. Find out the percentage of bromine in the compound.

Solution

Mass of organic compound 0.15g
Mass of AgBr = 0.12g
Molecular mass of AgBr = 108+80 = 188 g mol^-1
Now 188g AgBr contains 80 g bromine
$space space therefore space 0.12 straight g space AgBr space would space contain space 80 over 188 cross times 0.12 space bromine space space space space equals space 0.05 space bromine space space therefore space space space space Percentage space of space bromine space equals space fraction numerator 0.05 over denominator 0.15 end fraction cross times 100 space space space space space space space equals space 33.3 percent sign$

Some More Questions From Organic Chemistry – Some Basic Principles and Techniques Chapter

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Organic Chemistry – Some Basic Principles And Techniques

In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12 g of AgBr. Find out the percentage of bromine in the compound.

Some More Questions From Organic Chemistry – Some Basic Principles and Techniques Chapter

What are heterocyclic compounds?

What type of hybridisation is involved in: (i) Planar (ii) Linear molecules?

What does IUPAC stand for?

What system of nomenclature is accepted universally?

What are isomers?

How many chain isomers are possible for pentane?

Which characteristic is common to different isomers of a compound?

Name three alkanes which do not show chain isomerism.

Name the types of structural isomerism shown by alkanes.

Name the four main types of structural isomerism.

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