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Organic Chemistry – Some Basic Principles And Techniques

Question
CBSEENCH11007642

0.3780 of an organic chloro compound gave 0.5740 g of silver chloride in Carius estimation. Calculate the percentage of chlorine present in the compound. 

Solution

Pecentage space of space Cl equals

fraction numerator Atomic space mass space of space Cl space straight x space mass space of space AgCl space form space space straight x space 100 over denominator Molecular space mass space of space AgCl space space straight x space straight m end fraction
Molecular mass of AgCl = 108 + 35.5 = 143.5 g mol-1.
Now 143.5 g AgCl contains 35.5 g chlorine
  0.5740 g AgCl would contain
                 equals fraction numerator 35.5 over denominator 143.5 end fraction cross times 0.5740 space straight g space chlorine
Mass of organic compound is =0.3780
therefore space space Percentage space of space chlorine
space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator 35.5 over denominator 143.5 end fraction cross times fraction numerator 0.5740 over denominator 0.3780 end fraction cross times 100
space space space space space space space space space space space space space space space space space space space space space equals space 37.57 percent sign