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Organic Chemistry – Some Basic Principles And Techniques

Question
CBSEENCH11007587

For the following bond cleavages, used curved arrows to show the electron flow and classify each as homolysis or heterolysis. Identify reactive intermediate produced as free radical, carbocation and carbanion.

greater than equals straight O space plus space OH presuperscript minus space space rightwards arrow space space greater than equals straight O space plus space straight H subscript 2 straight O

Solution

It is heterolysis and the reactive intermediate formed is a carbanion.