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Organic Chemistry – Some Basic Principles And Techniques

Question
CBSEENCH11007445

Discuss the shape of ethylene (first member of alkenes).

Solution
In ethene molecule, each carbon atom undergoes sp2 hybridisation. One sp2 hybrid orbital of one carbon atom overlaps axially with one sp2 hybrid orbital of the other carbon atom to form sigma (σ;) C – C bond. The other two sp2 hybrid orbitals of each carbon atom overlap axially with Is orbital of the hydrogen atom to form sigma (σ;) C – H bonds. The unhybridised p-orbitals of the two carbon atoms overlap sidewise with each other to form a weak pi left parenthesis straight pi right parenthesis bond, The straight pi bond consists of two straight pi electron clouds which lie above and below the plane of carbon and hydrogen atoms. 

Thus, ethylene molecule consists of four sigma C – H bonds, one sigma C – C bond and one straight pi; the bond between carbon-carbon atom. The bond length of carbon-carbon double bond of ethylene is 134 pm (1.34 Å).