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The P-Block Elements

Question
CBSEENCH11007266

How does aluminium react with:
(i) boiling water.
(ii) concentrated H2SO4
(iii) dilute nitric acid
(iv) concentrated HCl
(v) NaOH?

Solution

(i) Action with boiling water. It decomposes boiling water to liberate hydrogen.
                2 Al space plus space 6 straight H subscript 2 straight O space space space rightwards arrow space space space 2 Al left parenthesis OH right parenthesis subscript 3 space plus space 3 straight H subscript 2
(ii) Action with concentrated H2SO4. It reacts with hot concentrated sulphuric acid to liberate sulphur dioxide.
               2 Al space plus space 6 straight H subscript 2 SO subscript 4 space space space rightwards arrow space space Al subscript 2 left parenthesis SO subscript 4 right parenthesis subscript 3 space plus space 3 SO subscript 2 space plus space 6 straight H subscript 2 straight O
(iii) Action with dilute nitric acid. Aluminium reacts with dilute nitric acid to form aluminium nitrate and ammonium nitrate.
        8 Al space plus space 30 HNO subscript 3 space space rightwards arrow space space space 8 Al left parenthesis NO subscript 3 right parenthesis subscript 3 space plus space 3 NH subscript 4 NO subscript 3 space plus space 9 straight H subscript 2 straight O
(iv) Action with concentrated HCl. Aluminium dissolves in moderately concentrated hydrochloric acid to form (hydrated) chloride. 
      2 Al space plus space 6 HCl space rightwards arrow space space space 2 AlCl subscript 3 space plus space 3 straight H subscript 2 space upwards arrow
(v) Action with NaOH. It dissolves in hot sodium hydroxide solution to form sodium meta-aluminate. 
   2 Al space plus space 2 NaOH space plus space 2 straight H subscript 2 straight O space rightwards arrow space space space stack 2 NaAlO subscript 2 with Sodium space meta space aluminate below space plus space 3 straight H subscript 2