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Relative Molecular Mass And Mole

Question
ICSEENICH12029065
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What is the mass of a non-volatile solute (molar mass 60) that need to be dissolved in 100 g of water in order to decrease the vapour pressure of water by 25%? What will be the molality of the solution?

Solution

We have given,
P° = 100,
P = 25,
M = 60,
W = 100,
MH20 = 18

fraction numerator straight P to the power of 0 minus straight P over denominator straight P to the power of 0 end fraction space equals straight w over straight m space straight x straight M over straight W equals space fraction numerator 100 minus 25 over denominator 100 end fraction space equals space straight w over 60 straight x 18 over 100 equals space fraction numerator 75 space straight x space 60 space straight x space 100 over denominator 100 space straight x space 18 end fraction space equals space straight W subscript left parenthesis solute right parenthesis end subscript straight w equals space 250 space gram Molality space space equals space fraction numerator Mole space of space solute over denominator weight space of space solvent space left parenthesis in space Kg right parenthesis end fraction space equals space fraction numerator 250 space gm space space straight x space 1000 over denominator 60 space straight x space 1000 end fraction space equals space 2500 over 60 Molality space equals space 41.66 space straight m

Some More Questions From Relative Molecular Mass And Mole Chapter

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