+91-8076753736 support@wiredfaculty.com
Wired Faculty Logo
Wired Faculty Logo Wired Faculty

SSCCGL quantitative aptitude

Question
SSCCGLENQA12042668
Wired Faculty App

The average monthly expenditure of a family for the first four months is ₹ 2570, for the next three months ₹ 2490 and for the last five months ₹ 3030. If the family saves ₹ 5320 during the whole year, the average monthly income of the family during the year is

  • ₹ 3000
  • ₹ 3185
  • ₹ 3200
  • ₹ 3580

Solution

B. 

₹ 3185

Total annual expenditure of the family = Rs. (4 x 2570 + 3 x 2490 + 5 x 3030)
= Rs. (10280 + 7470 + 15150) = Rs. 32900
Total income  = Rs. (32900 + 5320)
                    = Rs. 38220
∴  Required average monthly income = 3880 over 12 space equals space Rs. space 3185

Question
SSCCGLENQA12042669
Wired Faculty App

The average of six numbers is 20. If one number is removed, the average becomes 15. What is the number removed?

  • 5

  • 35

  • 112

  • 45

Solution

D.

45

Required number = Sum of six numbers - Sum of five numbers.
                          = 6 x 20 - 15 x 5
                          = 120 - 75 = 45

Question
SSCCGLENQA12042670
Wired Faculty App

There is a profit of 20% on the cost price of an article. The % of profit, when calculated on selling price is

  • 16 2 over 3 percent sign

  • 20 percent sign
  • 33 1 third percent sign

  • None of these

Solution

A.

16 2 over 3 percent sign

Shortcut Method:
Profit on cost price = 20 percent sign space equals space 1 fifth
When we go cost price to selling price add 1 to denomiator  i.e.
 rightwards double arrow space fraction numerator 1 over denominator left parenthesis 5 plus 1 right parenthesis end fraction space equals space 1 over 6 space cross times space 100 space equals space 50 over 3 space equals space 16 2 over 3 percent sign

Question
SSCCGLENQA12042671
Wired Faculty App

An item costing ₹ 200 is being sold at 10% less. If the price is further reduced by 5%, the selling price will be

  • ₹ 170

  • ₹ 171

  • ₹ 175

  • ₹ 179

Solution

B.

₹ 171

First article is sold at 10% loss
Selling price equals space fraction numerator 200 space cross times space 90 over denominator 100 end fraction space equals Rs. space 180
Second, further price is reduced by 5%
Selling price = fraction numerator 180 space cross times space 95 over denominator 100 end fraction equals space space Rs. space 171

Sponsor Area

Question
SSCCGLENQA12042672
Wired Faculty App

A train 300 m long is running with a speed of 54 km/hr. In what time will it cross a telephone pole?

  • 20 seconds

  • 15 seconds

  • 17 seconds

  • 18 seconds

Solution

A.

20 seconds

Distance = 300 m (given)
Speed  = 54 km/hr
equals space open parentheses fraction numerator 54 space cross times space 5 over denominator 18 end fraction close parentheses space straight m divided by sec space equals space 15 space straight m divided by sec
Required time
    WiredFaculty

Sponsor Area

Sponsor Area

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation