NEET physics

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Question
CBSEENPH11020812

One end of a string of length l is connected to a particle of mass ‘m’ and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in circle with speed ‘v’, the net force on the particle (directed towards centre) will be (T represents the tension in the string)

  • T

  • straight T space plus space mv squared over straight I
  • straight T space space minus space mv squared over straight I
  • zero

Solution

A.

T

Centripetal force mv2/l is provided by tension so the net force will be equal to tension i.e., T.

Sponsor Area

Question
CBSEENPH11020813

The x and y coordinates of the particle at any time are x = 5t – 2t2 and y = 10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t = 2 s is

  • 0

  • 5 m/s2

  • -4 m/s2

  • –8 m/s2

Solution

C.

-4 m/s2

x = 5t – 2t2    y = 10t
WiredFaculty
Acceleration of particle at t = 2 s is = –4 m/s2

Question
CBSEENPH11020814

Suppose the charge of a proton and an electron differ slightly. One of them is –e, the other is (e + Δe). If the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance d (much greater than atomic size) apart is zero, then Δe is of the order of [Given mass of hydrogen
mh = 1.67 × 10–27 kg]

  • 10–20 C

  • 10–23 C

  • 10–37 C

  • 10–47 C

Solution

C.

10–37 C

Fe = Fg
WiredFaculty

Question
CBSEENPH11020816

The diagrams below show regions of equipotentials

WiredFaculty

A positive charge is moved from A to B in each diagram.

  • Maximum work is required to move q in figure (c).

  • In all the four cases the work done is the same.

  • Minimum work is required to move q in figure (a).

  • Maximum work is required to move q in figure (b).

Solution

B.

In all the four cases the work done is the same.

Work was done w = qΔV
ΔV is same in all the cases so work is done will be same in all the cases.

Question
CBSEENPH11020819

The physical quantity of the dimensions of length that can be formed out of c, G and e/4πε0 is [c is the velocity of light, G is the universal constant of gravitation and e is charge]

  • 1 over straight c squared space open square brackets straight G fraction numerator straight e squared over denominator 4 πε subscript 0 end fraction close square brackets to the power of 1 half end exponent
  • straight c squared space open square brackets straight G fraction numerator straight e squared over denominator 4 πε subscript 0 end fraction close square brackets to the power of 1 half end exponent
  • straight c squared space open square brackets fraction numerator straight e squared over denominator straight G 4 πε subscript 0 end fraction close square brackets to the power of 1 half end exponent
  • straight c squared space open square brackets fraction numerator straight e squared over denominator straight G 4 πε subscript 0 end fraction close square brackets

Solution

A.

1 over straight c squared space open square brackets straight G fraction numerator straight e squared over denominator 4 πε subscript 0 end fraction close square brackets to the power of 1 half end exponent