NEET physics

Sponsor Area

Question
CBSEENPH11020601

In an experiment, four quantities a,b, c and d are measured with percentage error 1%, 2%, 3% and 4% respectively. Quantity P is calculated as follows:

P = fraction numerator straight a cubed straight b squared over denominator cd end fraction space percent sign, error in P is

  • 14 %

  • 10 %

  • 7 %

  • 4 %

Solution

A.

14 %

Here, P = fraction numerator straight a cubed straight b squared over denominator cd end fraction
Therefore,
fraction numerator increment straight P over denominator straight P end fraction space x space 100
open parentheses fraction numerator 3 increment straight a over denominator straight a end fraction plus fraction numerator 2 increment b over denominator b end fraction plus fraction numerator increment c over denominator c end fraction plus fraction numerator increment d over denominator d end fraction close parentheses x 100
3 fraction numerator increment straight a over denominator straight a end fraction straight x 100 space plus space 2 space fraction numerator increment straight b over denominator straight b end fraction straight x 100 space plus space fraction numerator increment straight c over denominator straight c end fraction straight x 100 space plus space fraction numerator increment straight d over denominator straight d end fraction straight x 100
= 3 x1 + 2 x 2 + 3 +4 
= 3 + 4 + 3 + 4
= 14 %

Sponsor Area

Question
CBSEENPH11020602

The velocity of a projectile at the initial point A is (2 i + 3 j) m/s. Its velocity (in m/s) at point B is,

  • -2 i - 3 j

  • -2 i + 3 j

  • i - 3 j

  • i + 3 j

Solution

C.

i - 3 j

From the fig,, the X component remain unchanged, while the Y-component is reverse. Then, the velocity at point B is (2 i - j) m/s.

Question
CBSEENPH11020603

A stone falls freely under gravity. It covers distances h1 , h2 and h3 in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relations between h1, h2 and h3 is,

  • h1 = 2 h2 = 3 h3

  • h1straight h subscript 2 over 3 space equals space h subscript 3 over 5

  • h2 = 3 h1 and h3 = 3 h2

  • h1 = h2 = h3

Solution

B.

h1straight h subscript 2 over 3 space equals space h subscript 3 over 5

Relations between h1, h2 and h3 is,

straight h subscript 1 space equals space straight h over 3 space equals space straight h subscript 3 over 5

rightwards double arrow space straight h subscript 1 space colon space straight h subscript 2 space colon straight h subscript 3 space equals space 1 colon space 3 colon space 5

Question
CBSEENPH11020604

Three blocks will masses m, 2m and 3m are connected by strings, as shown in the figure. After an upward force F is applied on block m, the masses move upward at constant speed v. What is the net force on the block of mass 2m? (g is the acceleration due to gravity)

  • zero

  • 2 mg

  • 3 mg

  • 6 mg

Solution

A.

zero

Since all the blocks are moving with constant velocity, then the net force on all blocks will be zero.

Question
CBSEENPH11020605

The upper half of an inclined plane of the inclination straight theta is perfectly smooth while lower half is rough. A block starting from rest at the top of the plane will again come to rest at the bottom, if the coefficient of friction between the block and lower half of the plane is given by,

  • straight mu space equals space fraction numerator 1 over denominator tan space straight theta end fraction
  • straight mu space equals space fraction numerator 2 over denominator tan space straight theta end fraction
  • straight mu space equals space 2 space tan space straight theta
  • straight mu space equals space tan space straight theta

Solution

C.

straight mu space equals space 2 space tan space straight theta
The block will be stationary when,

mg sin straight theta . L = straight alpha mg cos straight theta space. space straight L over 2
straight mu space equals space fraction numerator mg space sin space straight theta space straight L over denominator mg space cos space straight theta space begin display style bevelled straight L over 2 end style space end fraction

space space equals space 2 space fraction numerator sin space straight theta over denominator cos space straight theta end fraction

space space equals space 2 space tan space straight theta

straight mu equals space 2 space tan space straight theta