NEET physics

Sponsor Area

Question
CBSEENPH11020547

The dimensions of left parenthesis straight mu subscript straight o straight epsilon subscript straight o right parenthesis to the power of negative 1 divided by 2 end exponent are

  • [L1/2 T-1/2]

  • [L-1T]

  • [LT-1]

  • [L1/2 T1/2]

Solution

C.

[LT-1]

WiredFaculty

Sponsor Area

Question
CBSEENPH11020548

A stone is dropped from a height h. It hits the ground with a certain momentum p. If the same stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground will change by

  • 68%

  • 41%

  • 200%

  • 100%

Solution

B.

41%

WiredFaculty

Question
CBSEENPH11020549

A car of mass m starts from rest and accelerates so that the instantaneous power delivered to the car has a constant magnitude Po. The instantaneous velocity of this car is proportional to

  • t2Po

  • t1/2

  • t-1/2

  • bevelled fraction numerator straight t over denominator square root of straight m end fraction

Solution

B.

t1/2

Power Po = Fv
WiredFaculty

Question
CBSEENPH11020550

A car of mass m is moving on a level circular track of radius R. If straight mu subscript straight s represents the static friction between the road and tyres of the car, the maximum speed of the car in circular motion is given by

  • square root of straight mu subscript straight s mRg end root
  • square root of Rg divided by straight mu subscript straight s end root
  • square root of mRg divided by straight mu subscript straight s end root
  • square root of straight mu subscript straight s Rg end root

Solution

D.

square root of straight mu subscript straight s Rg end root

In this condition, centripetal force is equal to static frictional force between road and tyres, 
so
WiredFaculty

Question
CBSEENPH11020551

A circular platform is mounted on the frictionless vertical axle. Its radius R =2 m and its moment of inertia about the axle is 200 kg m2. It is initially at rest. A 50 kg man stands on the edge of the platform and begins to walk along the edge at the speed of 1 ms-1 relative to the ground. Time taken by the man to complete one revolution is

  • π sec

  • 3π/2 sec

  • 2π sec

  • π/2 sec

Solution

A.

π sec

For conservation of angular momentum
WiredFaculty