NEET physics

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Question
CBSEENPH11020567

When a string is divided into three segments of length l1, l2, and l3 the fundamental frequencies of these three segments are v1, v2, and v3 respectively. The original fundamental frequency (v) of the string is

  • square root of straight v space equals space square root of v subscript 1 end root plus square root of v subscript 2 end root plus square root of v subscript 3 end root
  • v = v1 +v2 +v3

  • 1 over straight v space equals space 1 over v subscript 1 space plus 1 over v subscript 2 plus 1 over v subscript 3
  • fraction numerator 1 over denominator square root of straight v end fraction space equals space fraction numerator 1 over denominator square root of v subscript 1 end root end fraction plus fraction numerator 1 over denominator square root of v subscript 2 end root end fraction plus 1 over square root of v subscript 3

Solution

C.

1 over straight v space equals space 1 over v subscript 1 space plus 1 over v subscript 2 plus 1 over v subscript 3

The fundamental frequency of string
WiredFaculty

Sponsor Area

Question
CBSEENPH11020570

A 200 W sodium street lamp emits yellow light of wavelength 0.6 um. Assuming it to be 25% efficient in converting electrical energy to light, the number of photons of yellow light it emits per second is

  • 1.5 x 1020

  • 6 x 1018

  • 62 x 1020

  • 3 x1019

Solution

A.

1.5 x 1020

 Efficient power P= 
WiredFaculty

Question
CBSEENPH11020571

When a mass is rotating in a plane about a fixed point, its angular momentum is directed along

  • a line perpendicular to the plane of rotation

  • the line making an angle of 45o to the plane of rotation

  • the radius

  • the tangent to the orbit

Solution

A.

a line perpendicular to the plane of rotation

We knows  L = m (r x v)
So, here, angular momentum is directed along a line perpendicular to the plane of rotation.

Question
CBSEENPH12039772

The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is

  • straight theta space equals space tan to the power of negative 1 end exponent open parentheses 1 fourth close parentheses
  • straight theta space equals tan to the power of negative 1 end exponent space left parenthesis 4 right parenthesis
  • straight theta space equals space tan to the power of negative 1 end exponent space left parenthesis 2 right parenthesis
  • straight theta space equals space 45 to the power of straight o

Solution

B.

straight theta space equals tan to the power of negative 1 end exponent space left parenthesis 4 right parenthesis

Given, R = H
WiredFaculty

Question
CBSEENPH11020576

Two persons of masses 55 kg and 65 kg respectively. are at the opposite ends of the boat. The length of the boat is 3.0 m and weigh 100 kg. The 55 kg man walks to the 65 kg man and sits with him. If the boat is in still water the centre of mass of the system shifts by

  • 3.0 m

  • 2.3 m

  • zero

  • 0.75 m

Solution

C.

zero

Here on the entire system net external force on the system is zero hence centre of mass remains unchanged.