NEET physics

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Question
CBSEENPH11020765

The position x of a particle with respect to time t along x- axis is given by x = 9t2 -t3 where x is in meter and t in second. What will be the position of this particle when it achieves maximum speed along the +x direction? 

  • 32 m

  • 54 m

  • 81 m 

  • 24 m

Solution

B.

54 m

At the instant when speed is maximum, its acceleration is zero.
Given, the position x of particle with respect to time t along x- axis
x = 9t2-t3 ... (i)
differentiating Eq. (i) with respect to time, we get speed, ie,
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Again differentiating Eq. (ii) with respect to time, we get acceleration, ie,
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Now, when speed of particle is maximum, its acceleration is zero, ie,
a= 0
18-6t = 0 or t = 3s
Putting in eq (i) We, obtain the position of a particle at that time. 
x = 9 (3)2 - (3)3 = 9 (9) -27 
= 81-27 = 54 m

Sponsor Area

Question
CBSEENPH11020766

Assuming the sun to have a spherical outer surface of radius r, radiating like a black body at a temperature  to C, the power received by a unit surface (normal to the incident rays) at a distance R from the centre of the sun is :

  • fraction numerator 4 πr squared σt to the power of 4 over denominator straight R squared end fraction
  • fraction numerator straight r squared straight sigma left parenthesis straight t plus 273 right parenthesis to the power of 4 over denominator 4 πR squared end fraction
  • fraction numerator 16 space straight pi squared straight r squared σt to the power of 4 over denominator straight R squared end fraction
  • fraction numerator straight r squared straight sigma left parenthesis straight t plus 273 right parenthesis to the power of 4 over denominator straight R squared end fraction

Solution

D.

fraction numerator straight r squared straight sigma left parenthesis straight t plus 273 right parenthesis to the power of 4 over denominator straight R squared end fraction

From Stefan's law, the rate at which energy is radiated by sun at its surface si 
P = σ x 4 πr2T4
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[Sun is a perfectly black body as it emits radiations of all wavelengths and so for it e =1]
The intensity of this power at earth's surface (under the assumption R >>ro) is
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Question
CBSEENPH11020767

A particle starting from the origin (0,0) moves in a straight line in the (x,y) plane. Its coordinates at a later time are  ( square root of 3 comma space 3). The path of the particle makes with the x -axis an angle of:

  • 30o

  • 45o C

  • 60o C

  • 00

Solution

C.

60o C

The slope of the path of the particle gives the measure of angle required.
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Draw the situation as shown. OA represents the path of the particle starting from origin O (0,0). Draw a perpendicular from point A to X- axis. Let path pf the particle makes and angle θ with the x -axis, then 
tan θ = slope of line OA

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Question
CBSEENPH11020768

A Wheel has an angular acceleration of 3.0 rad/s2 and an initial angular speed of 2.00 rad/s. In a time of 2s it has rotated thorough an angle (in radian) of:

  • 6

  • 10

  • 12

  • 4

Solution

B.

10

Angular acceleration is time derivative of angular speed and angular speed is time derivative of angular displacement.
By definition,
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Question
CBSEENPH11020769

A uniform rod AB of length l and mass m is free to rotate about point A. The rod is released from rest in the horizontal position. Given that the moment of inertia of the rod about A  is ml2/3, the initial angular acceleration of the rod will be:

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  • 2g/3l

  • mgl/2

  • 3gl/2

  • 3g/2l

Solution

D.

3g/2l

The moment of inertia of the uniform rod about an axis through one end and perpendicular to its length is 
l = ml3/3
where m is a mass of rod and l is the
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Torque acting on centre of gravity of rod is given by