NEET chemistry

Question
CBSEENCH11008459

The element Z = 114 has been discovered recently. It will belong to which of the following family group and electronic configuration?

  • Halogen family, [Rn] 5f14 6d10 7s7p5

  • Carbon family, [Rn] 5f14 6d10 7s7p2

  • Oxygen family,[Rn] 5f14 6d10 7s7p4

  • Nitrogen family, [Rn] 5f14 6d10 7s7p3

Solution

B.

Carbon family, [Rn] 5f14 6d10 7s7p2

Z = 114 belong to Group 14, carbon family Electronic configuration , [Rn] 5f14 6d10 7s7p2

Question
CBSEENCH11008460

Match the interhalogen compounds of column I with the geometry in column II and assign the correct code

Column I Column II
a) XX' (i) T-shape

b) XX3'

(ii) Pentagonal
bipyramidal

c) XX'5

(iii) Linear
d) XX'7 (iv) Square-pyramidal
  (v) Tetrahedral
  • (a) (b) (c) (d)
    (iii) (iv) (i) (ii)
  • (a) (b) (c) (d)
    (iii) (i) (iv (ii)
  • (a) (b) (c) (d)
    (iv) (v) (iii) (ii)
  • (a) (b) (c) (d)
    (iv) (iii) (ii) (i)

Solution

B.

(a) (b) (c) (d)
(iii) (i) (iv (ii)

Question
CBSEENCH11008461

20-litre container at 400 K contains CO2(g) at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO). The volume of the containers is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when pressure of CO2 attains its maximum value, will be

Given that: SrCO3 ⇌ SrO(s) + CO2(g) kp = 1.6 atm)

  • 5 litre

  • 10 litre

  • 8 litre

  • 3  litre

Solution

A.

5 litre

Max. the pressure  of CO2= Pressure of CO2 at equilibrium
For reaction, SrCO3 ⇌ SrO(s) + CO2(g)
Kp= PCO2 = 1.6 atm = maximum pressure of CO2
Volume Container at this stage,
V= nRT/P .... (i)

Since container is sealed and reaction was not  earlier at equilibrium
therefore, n = constant
n= Pv/RT  .... (ii)
from equation (i) and (ii) we get
V = (0.4 x 20)/RT = 5 Litre

Question
CBSEENCH11008462

For a given reaction, ΔH = 35.5 kJ mol–1 and ΔS = 83.6 JK–1 mol–1. The reaction is spontaneous at (Assume that ΔH and ΔS do not vary with temperature)

  • T < 425 K

  • T > 425 K

  • All temperatures

  •  T > 298 K

Solution

B.

T > 425 K

∵ ΔG = ΔH – TΔS
For a reaction to be spontaneous, ΔG = –ve
i.e., ΔH < TΔS

therefore, T> ΔH/ΔS
= 35.5 x 103J/83.6JK-1
i.e T>425 K

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Question
CBSEENCH11008457

The correct statement regarding electrophile is

  • Electrophile is a negatively charged species and can form a bond by accepting a pair of electrons from a nucleophile

  • Electrophile is a negatively charged species and can form a bond by accepting a pair of electrons from another electrophile

  • Electrophiles are generally neutral species and can form a bond by accepting a pair of electrons from a nucleophile

  • Electrophile can be either neutral or positively charged species and can form a bond by accepting a pair of electrons from a nucleophile

Solution

D.

Electrophile can be either neutral or positively charged species and can form a bond by accepting a pair of electrons from a nucleophile

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