NEET chemistry

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Question
CBSEENCH11008235

Which of the following species contains an equal number of σ and Π bond? 

  • HCO3-

  • XeO4

  • (CN)2

  • CH2(CN)2

Solution

B.

XeO4

Structure

σ and Π 

 

 σ bond -4
 Π bond-1 

 

 σ bond -4
 Π bond-4

 straight N identical to straight C minus straight C identical to straight N

 σ bond -3
 Π bond-4

 

 σ bond -6
 Π bond-4 

Sponsor Area

Question
CBSEENCH11008236

The species Ar, K+ and Ca2+ contain the same number of electrons. In which order do their radii increase?

  • Ar < K+< Ca2+

  • Ca2+ < Ar < K+

  • Ca2+ < K+ < Ar

  • K+< Ar < Ca2+

Solution

B.

Ca2+ < Ar < K+

Ca2+ < K+ < Ar
 Ar, K+ and Ca2+ are isoelectronic i.e with the same number of electrons, 18. For isoelectronic species, ionic radii decrease with increases in effective (relative) positive charge. Also Ar, K and Ca belong to the same period.

Question
CBSEENCH11008237

Solubility of the alkaline earth's metal sulphates in water decreases in the sequence

  • Mg>Ca>Sr>Ba

  • Ca>Sr>Ba>Mg>

  • Sr>Ca>Mg>Ba

  • Ba>Mg>Sr>Ca

Solution

A.

Mg>Ca>Sr>Ba

The solubility of the sulphates. The sulphates becomes less soluble as  you fo down the group i.e
Mg> Ca>Sr> Ba
The magnitude of the lattice energy remains almost constant as the size of the sulphate ion is so big that small increase in the size of the cation from Be to Ba does not make any difference. However, the hydration energy decreases from Be2+ to Ba2+ appreciably as the size of the cation increases down the group. The significantly high solubility of MgSO4 is due to high enthalpy of solvation on the smaller Mg2+ ions.

Question
CBSEENCH12011004

Which of the following pairs of ions are isoelectronic and isostructural? 

  • CO subscript 3 superscript 2 minus end superscript comma space SO subscript 3 superscript 2 minus end superscript
  • ClO subscript 3 superscript minus comma space CO subscript 3 superscript 2 minus end superscript
  • SO subscript 3 superscript 2 minus end superscript comma NO subscript 3 superscript minus
  • ClO subscript 3 superscript minus comma space SO subscript 3 superscript 2 minus end superscript

Solution

D.

ClO subscript 3 superscript minus comma space SO subscript 3 superscript 2 minus end superscript

Isostructural chemical compounds have similar chemical structures.
Isoelectronic terms refer to two atom, ions or molecules that have the same number of valence electrons.

ClO3- = SO32-
 Number of electrons
CO32- = 6+2+24 =32
SO32- = 16+2+24 = 32
ClO32- = 17+24+1 = 42
NO32- = 7+2+24 = 33
Hence ClO32- and SO32-  are isoelectronic and are pyramidal in shape.

Question
CBSEENCH11008238

Magnetic moment 2.84 BM is given by (At. no. Ni= 28, Ti= 22, Cr=24, Co = 27)

  • Ni2+

  • Ti3+

  • Cr3+

  • Co2+

Solution

A.

Ni2+

Magnetic space moment space left parenthesis straight mu right parenthesis space equals space square root of straight n space left parenthesis straight n plus 2 right parenthesis space end root space BM space where comma space
straight n equals space number space of space unpaired space electrons
straight mu space equals space 2.84 space left parenthesis given right parenthesis
284 space equals space space square root of straight n left parenthesis straight n plus 2 right parenthesis space end root space straight B. straight M
left parenthesis 2.84 right parenthesis squared space equals space straight n space left parenthesis straight n plus 2 right parenthesis
8 equals straight n squared plus 2 straight n
straight n squared space plus 2 straight n space minus 8 space equals space 0
solving space the space equation
straight n squared space plus 4 straight n minus 2 straight n minus 8 space equals 0
straight n left parenthesis straight n plus 4 right parenthesis minus 2 left parenthesis straight n plus 4 right parenthesis space equals space 0
straight n equals 2
The electronic configuration of the given ions,
Ni2+ = [Ar]3d8 4s0 (two unpaired electron)
Ti3+ = [Ar] 3d1 4s0 ( one unpaired electrons)
Cr3+ = [Ar] 3d3 ( three unpaired electrons)
Co2+ = [Ar],3d7, 4s0 (three unpaired electrons)
So, only Ni2+ has 2 unpaired of electrons.