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NEET chemistry

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Question
CBSEENCH12011009
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What is the maximum number of orbitals that can be identified with the following quantum numbers?

n=3, l =1, m1 = 0

  • 1

  • 2

  • 3

  • 4

Solution

A.

1

The value of n=3 and l =1 suggest that it is a 3p orbital while the value of m1 = 0 [magnetic quantum number] shows that the given 3p orbital is 3pz in nature.
Hence, the maximum number of orbitals identified by the given quantum number is only 1, i.e. 3pz.

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Question
CBSEENCH12011010
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Calculate the energy in joule corresponding to light of wavelength 45mm: (Planck's constant h=6.63 x10-34)Js; speed of light c= 3 x 108 ms-1)

  • 6.67 x 1015

  • 6.67 x 1011

  • 4.42 x 10-15

  • 4.42 x 10-18

Solution

D.

4.42 x 10-18

The wavelength of light is related to its energy by the equation,
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Question
CBSEENCH12011011
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Equal masses of H2, O2 and methane have been taken in a container of volume V at temperature 270 C in identical conditions. The ratio of the volumes of gases H2 : O2: CH4 would be 

  • 8:16:1

  • 16:8:1

  • 16:1:2

  • 8:1:2

Solution

C.

16:1:2

According to Avogadro's hypothesis,
Volume of a gas (V)  straight alpha number of moles (n)
Therefore, the ratio of the volumes of gases can be determined in terms of their moles. The ratio of volumes of H2:O2: methane (CH4) is given by
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Question
CBSEENCH12011012
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Which of the following salts will give highest pH in water?

  • KCl

  • NaCl

  • Na2CO3

  • CuSO4

Solution

C.

Na2CO3

The highest pH refers to the basic solution containing OH- ions. Therefore, the basic salt releasing OH- ions on hydrolysis will give highest pH in water.
Only the salt of a strong base and weak acid would release OH-ion on hydrolysis. Among the given salts, Na2CO3 corresponds to the basic salt as it is formed by the neutralisation of NaOH [strong base] and H2CO3 [weak acid].
CO subscript 3 superscript 2 minus end superscript space plus straight H subscript 2 straight O space rightwards harpoon over leftwards harpoon HCO subscript 3 superscript minus space plus OH to the power of minus

Question
CBSEENCH12011013
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When 22.4 L of H2 (g) is mixed with 11.2 L of Cl2 (g), each of at STP, the moles of HCl (g) formed is equal to

  • 1 mole of HCl (g)

  • 2 moles of HCl (g)

  • 0.5 mole of (g) 

  • 1.5 mole of HCl(g)

Solution

A.

1 mole of HCl (g)

The given problem is related to the concept of the stoichiometry of chemical equations. Thus, we have to convert the given volumes into their moles and then identify the limiting reagent [possessing minimum number of moles and completely used up in the reaction]
The limiting reagent gives the moles of product formed in the reaction.
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