NEET chemistry

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Question
CBSEENCH11008288

Give that the equilibrium constant for the reaction,

2SO2 (g) + O2 (g)  ⇌ 2SO3 (g)

has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the following reaction t the same temperature?

SO3 (g)  ⇌ SO2 (g) +1/2 O2 (g)

  • 1.8 x 10-3

  • 3.6 x 10-3

  • 6.0 x 10-2

  • 1.3 x 10-5

Solution

C.

6.0 x 10-2

2SO2 (g) +O2 (g)  ⇌ 2SO3 (g)
Equilibrium constant for this reaction,
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Question
CBSEENCH12011024

Given the reaction between two gases represented by A2 and B2 to give the compound AB (g).
A2(g) +B2 (g)  ⇌ 2AB (g)
At equilibrium the concentration
of A2 = 3.0 x 10-3 M
of B2 = 4.2 x 10-3 M
of AB = 2.8 x 10-3 M

If the reaction takes place in a sealed vessel at 527oC, then the value of Kc will be

  • 2.0

  • 1.9

  • 0.62

  • 4.5

Solution

C.

0.62

A2 (g) +B2 (g)  ⇌ 2AB (g)
The equilibrium constant is given by
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Question
CBSEENCH12011025

During the change of O2 to O2- ion, the electron adds on which one of the following orbitals?

  • π* orbital

  • π orbital

  • σ* orbital

  • σ orbital

Solution

A.

π* orbital

During the change of O2 to O2-the electron adds on π* orbital. Molecular orbital configuration of O2 (total e- =16)
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Question
CBSEENCH11008289

A  certain gas takes three times as long to effuse out as helium. Its molecular mass will be 

  • 27 u

  • 36 u 

  • 64 u

  • 9 u

Solution

B.

36 u 

From Graham's diffusion law,
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Question
CBSEENCH11008290

The orbital angular momentum of p-electron is given as

  • fraction numerator straight h over denominator square root of 2 straight pi end root end fraction
  • square root of 3 fraction numerator h over denominator 2 pi end fraction
  • square root of 3 over 2 end root space h over pi
  • square root of 6. end root fraction numerator h over denominator 2 pi end fraction

Solution

A.

fraction numerator straight h over denominator square root of 2 straight pi end root end fraction

Orbital angular momentum = 
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