JEE physics

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Question
CBSEENPH11020356

A thin uniform rod of length

  • 1 third fraction numerator calligraphic l squared straight omega squared over denominator straight g end fraction
  • 1 over 6 fraction numerator calligraphic l straight omega over denominator straight g end fraction
  • 1 half fraction numerator calligraphic l squared straight omega squared over denominator straight g end fraction
  • 1 over 6 fraction numerator calligraphic l squared straight omega squared over denominator straight g end fraction

Solution

D.

1 over 6 fraction numerator calligraphic l squared straight omega squared over denominator straight g end fraction 1 half open parentheses fraction numerator straight m space calligraphic l squared over denominator 3 end fraction close parentheses straight omega squared space equals space mgh
rightwards double arrow space straight h space equals space fraction numerator straight omega squared calligraphic l squared over denominator 6 straight g end fraction

Sponsor Area

Question
CBSEENPH11020357

Let P(r) = Qr/πR4 be the charge density distribution for a solid sphere of radius R and total charge Q. for a point ‘p’ inside the sphere at distance r1 from the centre of the sphere, the magnitude of electric field is

  • fraction numerator straight Q over denominator 4 πε subscript straight o straight r subscript 1 superscript 2 end fraction
  • 0

  • fraction numerator Qr subscript 1 superscript 2 over denominator 4 πε subscript straight o straight R to the power of 4 end fraction
  • fraction numerator Qr subscript 1 superscript 2 over denominator 3 πε subscript straight o straight R to the power of 4 end fraction

Solution

C.

fraction numerator Qr subscript 1 superscript 2 over denominator 4 πε subscript straight o straight R to the power of 4 end fraction fraction numerator straight Q over denominator 4 πε subscript 0 straight r subscript 1 superscript 2 end fraction space integral subscript straight r space equals 0 end subscript superscript straight r subscript 1 end superscript space fraction numerator 4 space πr cubed dr over denominator πR to the power of 4 end fraction
space equals space fraction numerator straight Q over denominator 4 πε subscript 0 end fraction fraction numerator straight r subscript 1 superscript 2 over denominator straight R subscript 4 end fraction

Question
CBSEENPH11020360

A particle has an initial velocity of 3 space stack straight i space with hat on top plus space 4 space stack straight j space with hat on top and an acceleration of It speed 0.4 space stack straight i space with hat on top plus space 0.3 space stack straight j space with hat on topafter 10 s

  • 10 units

  • 7 space square root of 2
  • 7 units

  • 8.5 units

Solution

B.

7 space square root of 2 straight V with rightwards arrow on top space equals straight u with rightwards arrow on top space plus straight a with rightwards arrow on top straight t
straight V with rightwards arrow on top space space equals space left parenthesis 3 straight i with hat on top space plus 4 space straight j with hat on top right parenthesis space plus space 10 left parenthesis 0.4 space straight i with hat on top space plus 0.3 space straight j with hat on top right parenthesis
straight V with rightwards arrow on top space equals 7 space straight i with hat on top space plus 7 straight j with hat on top space
rightwards double arrow space vertical line straight V with rightwards arrow on top vertical line space equals space 7 square root of 2

Question
CBSEENPH11020361

A motorcycle starts from rest and accelerates along a straight path at 2 m/s2. At the straight point of the motorcycle, there is a stationary electric siren. How far has the motorcycle gone when the driver hears the frequency of the siren at 94% of its value when the motorcycle was at rest?

  • 49 m

  • 98 m

  • 147 m

  • 196 m

Solution

B.

98 m

straight V space equals space square root of 2 aS end root space equals space square root of 4 straight S end root
also comma space 94 space equals space 100 space open parentheses fraction numerator 330 minus straight V over denominator 330 end fraction close parentheses
rightwards double arrow fraction numerator 33 space straight x space 6 over denominator 10 end fraction space equals space square root of 4 straight S end root
rightwards double arrow straight S space equals 98 space straight m

Question
CBSEENPH11020362

Consider a rubber ball freely falling from a height h = 4.9 m onto a horizontal elastic plate.Assume that the duration of collision is negligible and the collision with the plate is totally elastic.Then the velocity as a function of time and the height as a function of time will be

Solution

C.

When ball strikes the surface its velocity will be reversed therefore correct answer is 3.