JEE mathematics

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Question
CBSEENMA11015581

In a geometric progression consisting of positive terms, each term equals the sum of the next two terms. Then the common ratio of this progression equals

  • 1 half left parenthesis 1 minus square root of 5 right parenthesis
  • 1 half square root of 5
  • square root of 5
  • 1 half left parenthesis square root of 5 minus 1 right parenthesis

Solution

D.

1 half left parenthesis square root of 5 minus 1 right parenthesis WiredFaculty

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Question
CBSEENMA11015582

If space sin to the power of negative 1 end exponent space open parentheses straight x over 5 close parentheses space plus space cosec to the power of negative 1 end exponent space open parentheses 5 over 4 close parentheses space equals space straight pi over 2 then the value of x
  • 1

  • 3

  • 4

  • 5

Solution

B.

3

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Question
CBSEENMA11015583

In the binomial expansion of (a - b)n, n ≥ 5, the sum of 5th and 6th terms is zero, then
a/b equals

  • 5/n −4

  • 6 /n −5

  • n -5 /6

  • n -4 /5

Solution

D.

n -4 /5

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Question
CBSEENMA11015584

The set S: {1, 2, 3, …, 12} is to be partitioned into three sets A, B, C of equal size. Thus, A ∪ B ∪ C = S, A ∩ B = B ∩ C = A ∩ C = φ. The number of ways to partition S is-

  • 12!/3!(4!)3

  • 12!/3!(3!)4

  • 12!/(4!)3

  • 12!/(3!)4

Solution

C.

12!/(4!)3

Number of ways
straight C presuperscript 12 subscript 4 space straight x space straight C presuperscript 8 subscript 4 space straight x space straight C presuperscript 4 subscript 4 space equals space fraction numerator 12 factorial over denominator left parenthesis 4 factorial right parenthesis cubed end fraction

Question
CBSEENMA11015585

A body weighing 13 kg is suspended by two strings 5 m and 12 m long, their other ends being fastened to the extremities of a rod 13 m long. If the rod be so held that the body hangs immediately below the middle point. The tensions in the strings are 

  • 12 kg and 13 kg

  • 5 kg and 5 kg

  • 5 kg and 12 kg

  • 5 kg and 13 kg

Solution

C.

5 kg and 12 kg

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