JEE chemistry

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Question
CBSEENCH11008078

The incorrect expression among the following is

  • fraction numerator increment space straight G subscript system over denominator increment straight G subscript total end fraction space equals space minus straight T
  • In isothermal process

    straight W subscript reversible space equals negative nRT space ln straight V subscript straight f over straight V subscript straight i

  • In space straight K space equals space fraction numerator increment straight H to the power of straight o minus straight T increment straight S over denominator RT end fraction
  • straight K space equals space straight e to the power of increment straight G to the power of straight o divided by RT end exponent

Solution

C.

In space straight K space equals space fraction numerator increment straight H to the power of straight o minus straight T increment straight S over denominator RT end fraction

Option C has incorrect expression. The correct expression is,
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Sponsor Area

Question
CBSEENCH11008079

The species which can best serve as an initiator for the cationic polymerization is

  • LiAlH4

  • HNO3

  • AlCl3

  • BaLi

Solution

C.

AlCl3

Electron-deficient species (Lewis acid) like AlCl3, BF3, etc, are is used as an initiator for cationic polymerisation.

Question
CBSEENCH11008081

The standard reduction potentials for Zn2+/ Zn, Ni2+/ Ni, and F2+/ Fe are –0.76, –0.23 and –0.44 V respectively. The reaction X + Y2+ → X 2+ + Y will be spontaneous when

  • X = Ni, Y = Fe

  • X = Ni, Y = Zn

  • X =Fe, Y= Zn

  • X = Zn, Y = Ni

Solution

D.

X = Zn, Y = Ni

X = Zn, Y = Ni
Zn + Ni2+  →Zn2+ + Ni
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Question
CBSEENCH11008082

The equilibrium constant (Kc) for the reaction, N2(g) + O2 (g) → 2NO (g) at temperature T is 4 x 10-4. The value of Kc for the reaction NO space left parenthesis straight g right parenthesis space rightwards arrow 1 half space straight N subscript 2 space left parenthesis straight g right parenthesis space plus 1 half straight O subscript 2 space left parenthesis straight g right parenthesis at the same temperature is

  • 0.02

  • 2.5 x 102

  • 4 x 10-4

  • 50.0

Solution

D.

50.0

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Question
CBSEENCH11008083

The compressibility factor for a real gas at high pressure is

  • 1 plus RT over pb
  • 1
  • 1 plus pb over RT
  • 1 minus pb over RT

Solution

C.

1 plus pb over RT

Vander Waal's equation for one mole of real gas is
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