JEE chemistry

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Question
CBSEENCH11008141

The pKa of a weak acid (HA) is 4.5. The pOH of an aqueous buffered solution of HA in which 50% of the acid is ionized is

  • 4.5

  • 2.5 

  • 9.5

  • 7.0

Solution

C.

9.5

For buffer solution
PH space equals space pKa space plus space log space fraction numerator left square bracket salt right square bracket over denominator left square bracket Acid right square bracket end fraction
equals space 4.5 space plus space log space fraction numerator left square bracket salt right square bracket over denominator left square bracket Acid right square bracket end fraction
as HA is 50% ionized so [Salt] = [Acid]
pH = 4.5 pH + pOH = 14
⇒ pOH = 14 – 4.5 = 9.5

Sponsor Area

Question
CBSEENCH11008142

Assuming that water vapour is an ideal gas, the internal energy change(∆U) when 1 mol of water is vapourised at 1 bar pressure and 100°C, (Given: Molar enthalpy of vapourisation of water at 1 bar and 373 K = 41 kJ mol-1 and R = 8.3 J mol–1K–1 will be) –

  • 4.100 kJ mol–1

  • 3.7904 kJ mol–1

  • 37.904 kJ mol–1

  • 41.00 kJ mol–1

Solution

C.

37.904 kJ mol–1

straight H subscript 2 straight O space left parenthesis straight l right parenthesis space rightwards arrow with vaporisation on top space straight H subscript 2 straight O space left parenthesis straight g right parenthesis
∆ng =1−0 =1
∆H =∆U +∆ngRT
∆U =∆H −∆ngRT
= 41 – 8.3 × 10-3 × 373
= 37.9 kJ mol-1

Question
CBSEENCH11008143

Which of the following sets of quantum numbers represents the highest energy of an atom?

  • n = 3, l = 1, m = 1, s = +½

  • n = 3, l = 2, m = 1, s = +½

  • n = 4, l = 0, m = 0, s = +½

  • n = 3, l = 0, m = 0, s = +½

Solution

B.

n = 3, l = 2, m = 1, s = +½

Question
CBSEENCH11008144

Which of the following hydrogen bonds is the strongest?

  • O – H …… N

  • F – H …… F

  • O – H ….. O

  • O – H …… F

Solution

B.

F – H …… F

The hydrogen bond in HF is strongest, because fluorine is the most electronegative element.

Question
CBSEENCH11008145

In the reaction,
2Al(s) + 6HCl(aq) → 2Al3+ (aq) + 6Cl¯(aq) + 3H2(g)

  • 6L HCl(aq) is consumed for every 3L H2(g) produced

  • 33.6 L H2(g) is produced regardless of temperature and pressure for every mole Al that reacts

  • 67.2 L H2(g) at STP is produced for every mole Al that reacts

  • 11.2 L H2(g) at STP is produced for every mole HCl (aq) consumed

Solution

D.

11.2 L H2(g) at STP is produced for every mole HCl (aq) consumed

2Al(s) + 6HCl(aq) → 2Al3+ (aq) + 6Cl¯(aq) + 3H2(g)
For each mole of HCl reacted, 0.5 mole of H2 gas is formed at STP.
1 mole of an ideal gas occupies 22.4 lit at STP.
Volume of H2 gas formed at STP per mole of HCl reacted is 22.4 × 0.5 litre