A wire of length 80 cm has a frequency of 256 Hz. Calculate the length of a similar wire under similar tension, which will have frequency 1024 Hz.
As the frequency (F) of wire is inversely proportional to its length (l)
So, for the same tension, we have, F1l1 = F2l2
Given, F1 = 256 Hz, F2 = 1024 Hz and
Hence, the length of wire, which has frequency 1024 Hz is 20 cm.




