CBSE mathematics

Sponsor Area

Question
CBSEENMA12035724

Write the principal value of tan to the power of negative 1 end exponent left parenthesis 1 right parenthesis plus cos to the power of negative 1 end exponent open parentheses negative 1 half close parentheses.

Solution

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Sponsor Area

Question
CBSEENMA12035725

Write the value of open parentheses 2 tan to the power of negative 1 end exponent 1 fifth close parentheses

Solution

We know: 
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Question
CBSEENMA12035726

Find the value of a if open square brackets table row cell straight a minus straight b end cell cell space space space 2 straight a plus straight c end cell row cell 2 straight a minus straight b end cell cell space 3 straight c plus straight d end cell end table close square brackets space equals space open square brackets table row cell negative 1 end cell cell space space space 5 end cell row 0 cell space 13 end cell end table close square brackets

Solution

open square brackets table row cell straight a minus straight b end cell cell space space 2 straight a plus straight c end cell row cell 2 straight a minus straight b end cell cell space 3 straight c plus straight d end cell end table close square brackets space equals space open square brackets table row cell negative 1 end cell cell space space space 5 end cell row 0 cell space space 13 end cell end table close square brackets
Equating the corresponding elements, we get, 
rightwards double arrow straight a minus straight b space equals space minus 1 comma space space 2 straight a plus straight c space equals space 5 comma space space space 2 straight a minus straight b space equals space 0 comma space space space 3 straight c plus straight d space equals space 13

Now consider the equations, 
a - b = -1   and 2a - b = 0
Subtracting first equation from second, we get: a = 1

Question
CBSEENMA12035727

If open vertical bar table row cell straight x plus 1 end cell cell space space straight x minus 1 end cell row cell straight x minus 3 end cell cell space straight x plus 2 end cell end table close vertical bar space equals space open vertical bar table row 4 cell space space minus 1 end cell row 1 cell space space space space 3 end cell end table close vertical bar comma then write the value of x. 

Solution

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Question
CBSEENMA12035728

If open square brackets table row cell space 9 end cell cell space minus 1 end cell cell space space space 4 end cell row cell negative 2 end cell cell space space space 1 end cell cell space space space 3 end cell end table close square brackets space equals space straight A plus open square brackets table row 1 cell space space 2 end cell cell negative 1 end cell row 0 cell space 4 end cell 9 end table close square brackets comma then find the matrix A. 

Solution

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