CBSE chemistry

Sponsor Area

Question
CBSEENCH12010324

What are n-types semiconductors?

Solution

The semiconductor whose increased conductivity is a result of negatively-charged electrons is called an n-type semiconductor. These are generated when the crystal of a group 14 element such as Si or Ge is doped with a group 15 element such as P or As.

Sponsor Area

Question
CBSEENCH12010325

Define ‘peptization’.

Solution

Peptization can be defined as a process of converting a precipitate into colloidal sol by shaking it with dispersion medium in the presence of small amount of electrolyte.The electrolyte used in this process is known as a peptizing agent.

Question
CBSEENCH12010326

How is copper extracted from a low-grade ore of it?

Solution

Copper can be obtained from low grade from low through the process of leaching using acid or bacteria (leaching processes in which ore is treated with a suitable reagent which dissolves ore but not the impurities). 

Question
CBSEENCH12010327

What is the basicity of H3PO2 acid and why?

Solution

Basicity of H3PO2 depends on upon the number of ionizable -OH groups present in the molecule. That is the number of hydrogen attached to the electronegative atom oxygen.

H3PO2 has one ionizable –OH group, thus its basicity is 1.

 The structure of H3PO2 is as follows:

Question
CBSEENCH12010332

A reaction is of second order with respect to a reactant. How is its rate affected if the concentration of the reactant is (i) doubled (ii) reduced to half?

Solution

Let the concentration of the reactant be [A] = a

Rate of reaction, R = k [A]2 = ka2

(i) If the concentration of the reactant is doubled, i.e. [A] = 2a, then the rate of the reaction would be

R = k (2a)2

= 4ka

= 4R

Therefore, the rate of the reaction would increase by 4 times.

(ii) If the concentration of the reactant is reduced to half, i.e., left square bracket A right square bracket equals 1 half a then the rate of the reaction would be
Rate space of space reaction comma space straight R space equals space straight k open parentheses 1 half straight a squared close parentheses

equals 1 fourth ka squared

equals 1 fourth straight R

 

Therefore, the rate of the reaction would be reduced to  1 to the power of th over 4