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A student wants to use two p-n junction diodes to convert alternating current into direct current. Draw the labelled circuit diagram she would use and explain how it works.
The circuit of full wave rectifier is as shown below;
Principle: The underlying working principle of full wave rectifier is that the p-n junction conducts when it is forward biased and does not condut when it is reverse biased.
A p–n junction (D) shown in the figure can act as a rectifier. An alternating current source (V) is connected in the circuit.
C.
Only +ve current passes though the diode. Given figure is half wave rectifier.
The logic circuit shown below has the input waveforms ‘A’ and ‘B’ as shown. Pick out the correct output waveform.
output is
A.
Y is true only when both A and B are true. Y = AB
A working transistor with its three legs marked P, Q and R are tested using a multimeter. No conduction is found between P and Q. By connecting the common (negative) terminal of the multimeter to R and the other (positive) terminal of P or Q, some resistance is seen on the multimeter. Which of the following is true for the transistor?
It is an n-p-n transistor with R as base
It is a p-n-p transistor with R as collector
It is a p-n-p transistor with R as emitter
It is an n-p-n transistor with R as collector
B.
It is a p-n-p transistor with R as collector
In the circuit below, A and B represent two inputs and C represents the output. The circuit represents
NOR gate
AND gate
NAND gate
OR gate
D.
OR gate
A | B | C |
0 | 0 | 0 |
0 | 1 | 1 |
1 | 0 | 1 |
1 | 1 | 1 |
For the given uniform square lamina ABCD, whose centre is O,
IAD = 3IEF
IAC = IEF
C.
IAC = IEF
Carbon, silicon and germanium have four valence electrons each. At room temperature which one of the following statements is most appropriate?
The number of free conduction electrons is significant in C but small in Si and Ge
The number of free conduction electrons is negligibly small in all the three
The number of free electrons for conduction is significant in all the three
The number of free electrons for conduction is significant only in Si and Ge but small in C.
D.
The number of free electrons for conduction is significant only in Si and Ge but small in C.
A thermocouple is made from two metals, Antimony and Bismuth. If one junction of the couple is kept hot and the other is kept cold then, an electric current will
flow from Antimony to Bismuth at the cold junction
flow from Antimony to Bismuth at the hot junction
flow from Bismuth to Antimony at the cold junction
not flow through the thermocouple
A.
flow from Antimony to Bismuth at the cold junction
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The circuit has two oppositely connect ideal diodes in parallel. What is the current following in the circuit?
1.33 A
1.71 A
2.00 A
2.31 A
C.
2.00 A
D1 is reverse biased therefore it will act like an open circuit.
The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than 2480 nm is incident on it. The band gap in (eV) for the semiconductor is
1.1 eV
2.5 eV
0.5 eV
0.7 eV
C.
0.5 eV
Eg = hc/λ
= 0.5eV
therefore correct answer is
0.5 eV
In a common base amplifier, the phase difference between the input signal voltage and output voltage is
π/4
π
0
π/2
C.
0
No phase difference between input and output signal.
The thermistors are usually made of
metals with low temperature coefficient of resistivity
metals with high temperature coefficient of resistivity
metal oxides with high temperature coefficient of resistivity ‘
semiconducting materials having low temperature coefficient of resistivity.
C.
metal oxides with high temperature coefficient of resistivity ‘
These are devices whose resistance varies quite markedly with temperature mean having high-temperature coefficient of resistivity. [Their name are derived from thermal resistors]. Depending on their composition they can have either negative temperature coefficient or positive temperature coefficient or positive temperature coefficient or positive temperature coefficient characteristics. The negative temperature coefficient types consist of a mixture of oxides of iron, nickel and cobalt with small amounts of other substance. The positive temperature coefficient types are based on barium titanate.
When npn transistor is used as amplifier
electrons move from base to collector
holes move from emitter to base
electrons move from collector to base
holes move from base to emitter.
A.
electrons move from base to collector
When npn transistor is used, majority charge carrier electrons n type emitter move from emitter to base and then base to collector.
For a transistor amplifier in common emitter configuration having load impedance of 1 kΩ (hfe = 50 and hoe = 25) the current gain is
-5.2
-15.7
-24.8
-48.78
D.
-48.78
For a transistor amplifier in common emitter configuration, current again
where hfe and hoe are hybrid parameters of a transistor
A piece of copper and another of germanium are cooled from room temperature to 77 K, the resistance of
each of them increases
each of them decreases
copper decreases and germanium increases
copper increases and germanium decreases.
D.
copper increases and germanium decreases.
Copper is metallic conductor and germanium is semiconductor therefore as temperature decreases resistance of good conductor decreases while for semiconductor it increases.
The manifestation of band structure in solids is due to
Heisenberg’s uncertainty principle
Pauli’s exclusion principle
Bohr’s correspondence principle
Boltzmann’s law
B.
Pauli’s exclusion principle
According to Pauli's exclusion principle, the electronic configuration of a number of subshells existing in a shell and number of electrons entering each subshell is found. Hence, on the basis of Pauli's exclusion principle, the manifestation of band structure in solids can be explained.
When p-n junction diode is forward biased
the depletion region is reduced and barrier height is increased
the depletion region is widened and barrier height is reduced.
both the depletion region and barrier height reducedboth the depletion region and barrier height reduced
both the depletion region and barrier height increased.
C.
both the depletion region and barrier height reducedboth the depletion region and barrier height reduced
When p-end of the p-n junction is connected to positive terminal of battery and n-end to the negative terminal of a battery, then p-n junction is said to be forward bias. In forward bias, the more numbers of electrons go from n-region to p-region and more numbers of holes go from p-region to n-region. Therefore, major current due to both types of carriers takes place through the junction causing a reduction in height of depletion region and barrier potential.
Which one of the following represents forward bias diode?
A.
In forward bias, a p-type semiconductor is at higher potential w.r.t. n-type semiconductor.
The given electrical network is equivalent to
AND gate
NOR gate
OR gate
NOT gate
B.
NOR gate
In the circuit shown in the figure, the input voltage Vi is 20 V, VBE = 0 and VCE = 0. The values of IB, IC and β are given by
IB = 40 μA, IC = 10 mA, β = 250
IB = 25 μA, IC = 5 mA, β = 200
IB = 40 μA, IC = 5 mA, β = 125
IB = 20 μA, IC = 5 mA, β = 250
C.
IB = 40 μA, IC = 5 mA, β = 125
VBE = 0,
Vi = 20 V
VCE = 0
Vb = 0 (earthed)
Ic =
Or
Vi = 0 + IBRB
In a p-n junction diode, change in temperature due to heating
Affects only reverse resistance
Affects only forward resistance
Affects the overall V - I characteristics of p-n junction
Does not affect resistance of p-n junction
C.
Affects the overall V - I characteristics of p-n junction
On heating, a number of electron-hole pairs increases, so overall resistance of diode will change.
Hence, forward biasing and reversed biasing both are changed.
The following circuit represents
OR gate
XOR gate
AND gate
NAND gate
B.
XOR gate
Output of upper AND gate =
Output of lower AND gate =
Thus, the output of OR gate =
This is boolean expression for XOR gate.
Zener diode is used for
producing oscillations in an oscillator
amplification
stabilisation
rectification
C.
stabilisation
A zener diode is a silicon crystal diode having an unusual reverse current characteristic which is particularly suitable for voltage regulating purposes. Due to this characteristic, it is used as a voltage stabilizer in many applications in electronics.
Carbon, silicon and germanium atoms have four valence electrons each. Their valence and conduction bands are separated by energy band gaps represented by respectively. Which one of the following relationships is true in their case?
A.
Crbon, silicon and germanium are semiconductors.
Atomic number:- C - 6 ; Si - 14 and Ge -32 so all these semiconductors have 4 valence electron in their outermost shell.
Choose the only false statement from the following
Substances with energy gap ofthe order of 10 eV are insulators
The conductivity of a semiconductor increases with increases in temperature
In conductors the valence and conduction bands may overlap
The resistivity of a semiconductor increases with increase in temperature
D.
The resistivity of a semiconductor increases with increase in temperature
(a) In insulators energy gap is of the order of 5 to 10 eV and it is practically impossible to impart this much amount of energy to the electrons in valence band. So, as to jump to conduction band. So, choice (a) is correct.
(b) In semiconductors with the rise in temperature more electrons from valence band jump to conduction band and this results is increase in conductivity. So, choice (b) is correct.
(c) In conductors, the conduction band is either partially filled or the conduction band overlaps on the valence band. So, choice (c) is correct.
(d) In semiconductor, resistivity decreases with increase in temperature. So, choice (d) is wrong.
The total energy of an electron in the first excited state of hydrogen is about -3.4 eV. Its kinetic energy in this state is
-3.4 eV
-6.8 eV
6.8 eV
3.4 eV
D.
3.4 eV
The kinetic energy is equal to the negative of total energy.
Kinetic energy of electron
⇒ E = - K
⇒ K = - E
= - ( - 3.4 )
⇒ K = 3.4 eV
Which logic gate is represented by the following combination of logic gates?
OR
NOR
AND
NAND
C.
AND
Output of gate-1, Y1 =A
Output of gate-2, Y2 = B
Output of gate-3,
=
=
Y = AB
which is the output of AND gate.
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The principle of LASER action involves
amplification of particular frequency emitted by the system
population inversion
stimulated emission
All of the above
D.
All of the above
Laser action involves all the given phenomena
(i) Amplification of particular frequency
(ii) Population inversion
(iii) Stimulated emission
Which of the following is unipolar transistor?
p-n-p transistor
n-p-n transistor
Field effect transistor
Point contact transistor
C.
Field effect transistor
In Field effect Transistor ( FET ) there is only one type of charge for conduction from drain to source i.e either electrons ( n-channel FET ) or holes (P-channel FET).
In NPN and PNP transistor both electron and holes take part in conduction. Hence they are bipolar Junction Transistor.
Point contact Transistor is also Bipolar Junction Transistor.
The truth table given below is for (A and B are the inputs, Y is the output)
A | B | Y |
0 | 0 | 1 |
0 | 1 | 1 |
1 | 0 | 1 |
1 | 1 | 0 |
NOR
AND
XOR
NAND
D.
NAND
The NAND gate is an AND gate followed by a NOT gate. If inputs A and B are both '1' the output Y is not '1'. The gate gets its name from this NOT AND behaviour.
This is a logical symbol.
The output Y is a combination of AND + NOT gate. Hence, the truth table is for NAND gate.
Which logic gate is represented by the following combination of logic gates?
OR
NOR
AND
NAND
C.
AND
Output of gate 1, Y1 =
Output of gate 2, Y2 =
Outout of gate 3
Y =
Y =
Y =
Y = AB
Which the output of AND gate.
An AND gate has two or more inputs and one output. The output Y of AND gate is 1 only when input A and input B are both 1.
The reason of current flow in p-n junction in forward bias is
drifting of charge carriers
drifting of minority charge carriers
diffussion of charge carriers
All of the above
C.
diffussion of charge carriers
In forward biased condition, the width of the depletion region is very narrow. Hence, the free electrons and holes easily overcome the weak opposite electric field from the depletion region and cross the depletion region. Therefore, the electric current flows in the forward biased condition.
Due to diffusion of charge carriers current flows throw in p-n junction.
A change of 8.0 mA in the emitter current brings a change of 7. 9 mA in the collector current. The value of a will be
0.96
0.93
0.90
0.99
D.
0.99
We have
IE = IB + IC
ΔIE = ΔIB + ΔIC
According to question,
ΔIE = 8.0 mA
ΔIC = 7.9 mA
∴ ΔIB = 8.0 mA - 7.9 mA
ΔIB = 0.1 mA
Now
Where IC is the current flowing into the collector terminal
IB is the current flowing into the base terminal
IE is the current flowing into the emitter terminal
=
= 0.99
The truth table for the following logic circuit is
A.
The truth table for the given logic circuit is
A | B | |||||
0 | 0 | 1 | 1 | 0 | 0 | 0 |
0 | 1 | 1 | 0 | 1 | 0 | 1 |
1 | 0 | 0 | 1 | 0 | 1 | 1 |
1 | 1 | 0 | 0 | 0 | 0 | 0 |
The transfer ratio B of a transistor is 50. The input resistance of the transistor when used in the common emitter configuration is 2 kΩ. The peak value of the collector AC current for an AC input voltage of 0.02 V peak is
200 μA
0.01 mA
0.25 mA
500 μA
D.
500 μA
Given:-
β = 50,
R = 2 kΩ = 2 x 103 Ω
ΔVb = 0.02 V
ic = ?
Input current,
ib =
=
ib = 10-5 A
Also, current gain is the ratio of collector current to the base current.
β =
∴ ic = β ib
= 50× 10-5 A
ic = 500 × 10-6 A
ic = 500 μA
In the circuit shown in figure, when the input voltage of the base resistance is 10 V, Vb, is zero and Vce is also zero. Value of β is
133
154
196
105
A.
133
Given:-
Vi = 10 V
Rb = 400 kΩ
= 400 × 103 Ω
Rc = 3 kΩ = 3 × 103 Ω
Vbe = 0
Vce = 0
Vcc = 10 V
As Vi Vbe = Rb Ib
10 0 = ( 400 × 103 ) Ib
⇒ Ib =
= 25 × 10-6 A
⇒ Ib = 25 μA
and Vcc Vce = Ic Rc
⇒ Ic =
⇒ = 3.33 × 10-3
⇒ Ic = 3.33 mA
β :- The ratio of collector current Ic to base current Ib
β =
=
β = 133
Assertion: An n-type semiconductor has a large number of electrons but still it is electrically neutral.
Reason: An n-type semiconductor is obtained by doping an intrinsic semiconductor with a pentavalent impurity.
If both assertion and reason are true and reason is the correct explanation of assertion.
If both assertion and reason are true but reason is not the correct explanation of assertion.
If assertion is true but reason is false.
If both assertion and reason are false.
B.
If both assertion and reason are true but reason is not the correct explanation of assertion.
A n-type semiconductor is formed by doping pure germanium or silicon crystal with suitable impurity atoms of valency five. As the impurity atoms take the position of Ge atom in germanium crystal, its four electrons form covalent bonds by sharing electrons with the neighbouring four atoms of germanium whereas the fifth electron is left free. Since the atom, on the whole, is electrically neutral, the n-type semiconductor is also neutral.
A transistor connected at common emitter mode contains load resistance of 5 kΩ and an input resistance of 1 kΩ. If the input peak voltage is 5 mV and the current gain is 50, find the voltage gain.
250
500
125
50
A.
250
Load resistance = 5 kΩ
Input resistance = 1 kΩ
β = 50
Voltage gain Av = β ×
= 50 ×
Av = 250
The output for the given, circuit is
(A B) B
( A + B )B
( A B ) + B
A.
Y' = A + B
and Y = Y'.
Y = ( A + B ).
If the plate resistance oftriode valve is 13 x 106 Ω and amplification factor is 21. The mutual conductance will be
1.6 × 10-6 mho
1.6 × 106 mho
2.6 × 10-5 mho
2.6 × 105 mho
D.
2.6 × 105 mho
For triode value
Amplification factor
μ = rp × gm
Here rp = 13 × 106 Ω
μ = 21
gm = ?
∴ gm =
=
gm = 1.6 × 10-6 mho
Assertion: A p-n junction with reverse bias can be used as a photo-diode to measure light intensity.
Reason: In a reverse bias condition the current is small but it is more sensitive to change in intensity of incident light.
If both assertion and reason are true and reason is the correct explanation of assertion.
If both assertion and reason are true but reason is not the correct explanation of assertion.
If assertion is true but reason is false.
If both assertion and reason are false.
A.
If both assertion and reason are true and reason is the correct explanation of assertion.
The assertion and reason both are true.
A photodiode is a p-n junction. When a photon of sufficient energy strikes the diode, it creates an electron-hole pair.
By using reverse-bias condition, this reduces the response time because the additional reverse bias increases the width of the depletion layer, which decreases the junction's capacitance. The reverse bias also increases the dark current without much change in the photocurrent.
Assertion: The output voltage and the input voltage of the NOT gate have 180° phase difference.
Reason: The logic NOT can be built using diode.
If both assertion and reason are true and reason is the correct explanation of assertion.
If both assertion and reason are true but reason is not the correct explanation of assertion.
If assertion is true but reason is false.
If both assertion and reason are false.
C.
If assertion is true but reason is false.
Output of NOT gate is out of phase with its input.
The logic NOT cannot be designed using a diode.
Assertion: In a common emitter transistor amplifier, the input current is much less than the output current than output impedance.
Reason: The common emitter transistor amplifier has higher input impedance than output impedance.
If both assertion and reason are true and reason is the correct explanation of assertion.
If both assertion and reason are true but reason is not the correct explanation of assertion.
If assertion is true but reason is false.
If both assertion and reason are false.
C.
If assertion is true but reason is false.
The output impedance is higher than the input impedance in a common emitter transistor amplifier.
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