Sponsor Area
The teachers of Geeta’s school took the students on a study trip to a power generating station, located nearly 200 km away from the city. The teacher explained that electrical energy is transmitted over such a long distance to their city, in the form of alternating current (ac) raised to a high voltage. At the receiving end in the city, the voltage is reduced to operate the devices. As a result, the power loss is reduced. Geeta listened to the teacher and asked questions about how the ac is converted to a higher or lower voltage.
A current I flows along the length of an infinitely long, straight, thin walled pipe. Then
the magnetic field is zero only on the axis of the pipe
the magnetic field is different at different points inside the pipe
the magnetic field at any point inside the pipe is zero
the magnetic field at all points inside the pipe is the same, but not zero
C.
the magnetic field at any point inside the pipe is zero
The phase difference between the alternating current and emf is π/2. Which of the following cannot be the constituent of the circuit?
C alone
R.L
L.C
L alone
B.
R.L
0<phase difference for R-L circuit < π/2
Alternating current can not be measured by D.C. ammeter because
A.C. cannot pass through D.C.
A.C. changes direction
average value of current for complete cycle is zero
D.C. ammeter will get damaged.
C.
average value of current for complete cycle is zero
The full cycle of alternating current consists of two half cycles. For one half, currently is positive and for second half, current is negative. Therefore, for an a.c. cycle, the net value of current average out to zero. While for the half cycle, the value of current is different at different points. Hence, the alternating current cannot be measured by D.C. ammeter.
In an LCR series a.c. circuit, the voltage across each of the components, L, C and R is 50 V. The voltage across the LC combination will be
50 V
50√2 V
100 V
0 V(zero)
D.
0 V(zero)
In an LCR series a.c. circuit, the voltage across inductor L leads the current by 900 and the voltage across capacitor C lags behind the current by 900. Hence, the voltage across LC combination will be zero.
In a LCR circuit capacitance is changed from C to 2C. For the resonant frequency to remain unchanged, the inductance should be changed from L to
4L
2L
L/2
L/4
C.
L/2
In the condition of resonance XL = XC
or
ωL =1/ ωC = .................. (i)
Since, resonant frequency remains unchanged
So, = constant
or LC = constant
∴ L1 C1 = L2 C2 ⇒ L×C = L2× 2C
L2 = L/2
An EM wave from air enters a medium. The electric fields are
in air and in medium, where the wave number k and frequency v refer to their values in air. The medium is non-magnetic. If refer to relative permittivities of air and medium respectively, which of the following options is correct ?
D.
Velocity of EM wave is given by v =
Velocity in air =
velocity in medium = C/2
Here, μ1 = μ2 =1 as medium is non magnetic
An inductor 20 mH, a capacitor 100 µF and a resistor 50 Ω are connected in series across a source of emf, V = 10 sin 314 t. The power loss in the circuit is
0.79 W
0.43
1.13
2.74 W
A.
0.79 W
Power dissipated in an LCR series connected to an a.c source of emf E
An L.C. circuit is in the state of resonance. If C = 0.1F and L = 0.25 Henry. Neglecting ohmic resistance of circuit. What is the frequency of oscillations?
1007 Hz
100 Hz
100 Hz
500 Hz
A.
1007 Hz
From the formula the frequency of oscillation is
When temperature of an ideal gas is increased from 27°C to 227°C, its rms speed is changed from 400 m/s to vs Then, vs is
516 m/s
450 m/s
310 m/s
746 m/s
A.
516 m/s
We know that the rms speed is directly proportional to square root of temperature.
Sponsor Area
In a L-C-R circuit, the capacitance is made one-fourth, then what should be changed in inductance, so that the circuit remains in resonance?
8 IMES
1/4 times
2 times
4 times
D.
4 times
In a RLC circuit , resonance phenomenon occurs when XL =XC or
Inductance should be changed to four times.
In a circuit, L, C and R are connected in series with an alternating voltage source of frequency f. The current leads the voltage by 45°. The value of C is
C.
In series resonance, L-C-R circuit is greater than unity.
In a series L-C-R circuit, resistance R = 10 Ω and the impedance Z = 10 Ω. The phase difference between the current and the voltage is
0o
30o
45o
60o
A.
0o
Impedance (Z ) is an expression of the opposition that an electronic component, circuit, or system offers to alternating and/or direct electric current. Impedance is a vector ( two- dimensional ) quantity consisting of two independent scalar ( one dimensional ) phenomena: resistance and reactance.
Impedance,
z =
∴ 10 =
⇒ 100 = 100 +
⇒ ..... (i)
Let is the phase difference between current and voltage
∴
⇒ [ from equation (i) ]
The impedance of a circuit, when a resistance R and an inductor of inductance L are connected in series in an AC circuit of frequency f, is
C.
In L-R circuit,
Z =
Here,
⇒
A choke is preferred to a resistance for limiting current in AC circuit because
choke is cheap
there is no wastage of power
choke is compact in size
choke is a good absorber of heat
B.
there is no wastage of power
In an AC circuit, the coil of high inductance and negligible resistance used to control current, is called the choke coil. The power factor of such a coil is given by
cos =
≈ ...( as R<< ωL )
As R << ωL, cos is very small.
Thus, the power absorbed by the coil is very small. The only loss of energy is due to hysteresis in the iron core, which is much less than the loss of energy in the resistance that can also reduce the current if placed instead of the choke coil.
Induced emf in the coil depends upon
conductivity of coil
amount of flux
rate of change of linked flux
resistance of coil
C.
rate of change of linked flux
According to Faraday's law, "the induced emf in a closed loop equals the time rate of change of magnetic flux through the loop".
i.e
Hence, induced emf in a coil depends on the rate of change of flux.
In an L-C-R circuit inductance is changed from L to L/2.To keep the same resonance frequency, C should be changed to
2 C
4 C
A.
2 C
An LCR circuit is an electrical circuit consisting of Resistor (R), an inductor (L) and a capacitor (C), connected in series or in parallel.
When L is changed, C must be changed to 2C to keep to ω same i.e to balanced equation.
220 V, 50 Hz, AC source is connected to an inductance of 0.2 Hand a resistance of 20 Ω in series. Whatis the current in the circuit?
3.33 A
33.3 A
5 A
10 A
A.
3.33 A
From the formula
I =
I =
I =
I = 3.33 A
If we change the value of R, then
voltage does not change on L
voltage does not change on LC combination
voltage does not change on C
voltage changes on LC combination
D.
voltage changes on LC combination
If we change the value of R, then voltage on LC combination changes.
Real power consumption in a circuit is least when it contains.
high R, low L
high R, high L
low R, high L
high R, low C
C.
low R, high L
Power is the voltage times the current
Power consumption = lrms Vrms cos
Where, cos is power factor.
For cos to be minimum, R should be minimum and Z should be higher. So, higher Z (impedance), L (inductance) should be high.
The rms speed (in m/s) of oxygen molecules of the gas at temperature 300 K, is
483
504
377
346
A.
483
The rms speed is given by
Vrms =
where R = gas constant
T = Temperature of the gas
and M0 = Molecular weight of the gas
Vrms =
Vrms = 483 m/s
An inductor (L = 20 H), a resistor (R = 100 Ω) and a battery (E = 10 V) are connected in series. After a long time, the circuit is short-circuited and then the battery is disconnected. Find the current in the circuit at 1 ms after short circuiting.
4.5 x 105 A
3.2x 10-5 A
9.8 × 10-5 A
6.7 × 10-4 A
D.
6.7 × 10-4 A
The initial current i = i0 =
=
i = 0.10 A
the time constant
=
The current at t = 1 ms is
i = i0 e -t /Τ
⇒ i = ( 0.10 )
⇒ i = ( 0.10 ) e-5
⇒ i = (0.10) × 0.0067
⇒ i = 6.7 × 10-4 A
The magnetic flux through each turn of a coil having 200 turns is given as (t2 1) x 10-3 Wb, where t is in second. The emf induced in the coil at t = 3s is
0.7 V
1.2 V
0.8 V
0.9 V
C.
0.8 V
Given magnetic flux
On differentiating with respect to time t
At time t = 3s
= 4 × 10-3 Wb s-1
Now
= 200 × 4 × 10-3
= 800 × 10-3
⇒
A beam of light travelling along X-axis is described by the electric field Ev = 600 . sin, the maximum magnetic force on a charge q = 2e, moving along Y-axis with the speed of 3 × 108 m/s is
19.2 × 10-17 N
1.92 × 10-17
0.192
None of these
A.
19.2 × 10-17 N
Given, electric field
Ey = . sin ......(i)
We know that
E = E0 sinω .........(ii)
On comparing Eqs. (i) and (ii), we get
E0 = 600 V/m
and C = 3 × 108 m/s
Maximum magnetic field
B0 =
=
B0 = 2 × 10-6 T
∴ Fm = q V B0
= 2 ev B0
= 2 × 1.6 × 10-19 × 3 × 108 × 2 × 10-6
Fm = 19.2 × 10-17
An L-C-R series circuit with a resistance of 100 Ω is connected to 200 V (AC source) and angular frequency 300 rad/s. When only the capacitor is removed, then the current lags behind the voltage by 60°. When only the inductor is removed the current leads the voltage by 60°. The average power dissipated in original L-C-R circuit is
50 W
100 W
200 W
400 W
D.
400 W
Given:-
R = 100 Ω,
V = 200 V,
θ = 60°,
ω = 300 rad/s
∴ Phase angle
tanθ = =
⇒ tan 60o = =
∴ XL = XC =
Z =
Z = R
So average power
P =
=
P = 400 W
In an LCR circuit as shown in figure, both switches are open initially. Now switch S1 is closed, S2 kept open. (q is charge on the capacitor and τ = RC is capacitive time constant). Which of the following statement is correct?
At t = , q = CV ( 1 e-1 )
Work done by the battery is half of the energy dissipated in the resistor
At t = τ, q = CV/2
At t = τ, q = CV ( 1 e-2 )
D.
At t = τ, q = CV ( 1 e-2 )
As switch S1 is closed and switch S2 is kept open. Now, capacitor is charging through a resistor R. Charge on a capacitor at any time t is
q = q0 ( 1 e-t/τ )
And q0 = CV
At t = ,
q = CV ( 1 e-t/2τ )
= CV ( 1 e-1/2 )
At t = τ
q = CV ( 1 e-τ/τ )
= CV ( 1 e-1 )
At t = 2τ
q = CV ( 1 e-2t /τ )
= CV ( 1 e-2 )
A circular coil of radius 10 cm, 500 turns and resistance 2 Ω is placed with its plane perpendicular to the horizontal component of the earth's magnetic field. It is rotated about its vertical diameter through 180° in 0.25 s. The
current induced in the coil is
(Horizontal component of the earth's magnetic field at that place is 3.0 x 10-5 T)
1.9 × 10-3 A
2.9 × 10-3 A
3.9 × 10-3 A
4.9 × 10-3 A
A.
1.9 × 10-3 A
Initial magnetic flux through the coil
= BH Acosθ
= 3.0 × 10-5 × ( × 10-2 ) × cos0o
= 3 × 10-7 Wb
Final magnetic flux after the rotation
= 3.0 × 10-5 × ( × 10-2 )×cos180o
= 3 × 10-7 Wb
lnduced emf,
=
=
= 3.8 × 10-3 V
Current is given by
I =
=
I = 1.9 × 10-3 A
A series resonant LCR circuit has a quality factor ( Q-factor) 0.4. If R = 2 kΩ, C = 0.1 μF, then the value of inductance is
0.1 H
0.064 H
2 H
5 H
B.
0.064 H
The amplitude of the current is maximum at resonant frequency ωo . The quantity factor is given by
Q = =
where ωo = resonant frequency
Given:- R = 2kΩ = 2 × 103 Ω
C = 0.1 μF = 0.1 × 10-6 F
The quantity factor Q defined by
Q =
= (QR)2
∴ L = ( 0.4 × 2 × 103 )2 × 0.1 × 10-6
L = 0.064 H
Assertion: At resonance, LCR series circuit have a minimum current.
Reason: At resonance, in LCR series circuit, the current and e.m.f are not in phase with each other.
If both assertion and reason are true and reason is the correct explanation of assertion.
If both assertion and reason are true but reason is not the correct explanation of assertion.
If assertion is true but reason is false.
If both assertion and reason are false.
D.
If both assertion and reason are false.
At resonance
XL = XC or ωL = .
Because of this impedance of LCR series circuit be equal to resistance of circuit
Therefore from I = , at resonance, current in LCR circuit is maximum. Correspondingly phase angle is also equal to zero. Therefore emf and current are in phase in LCR series circuit.
Sponsor Area
Sponsor Area