Chemistry Part Ii Chapter 9 Hydrogen
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    NCERT Solution For Class 11 Chemistry Chemistry Part Ii

    Hydrogen Here is the CBSE Chemistry Chapter 9 for Class 11 students. Summary and detailed explanation of the lesson, including the definitions of difficult words. All of the exercises and questions and answers from the lesson's back end have been completed. NCERT Solutions for Class 11 Chemistry Hydrogen Chapter 9 NCERT Solutions for Class 11 Chemistry Hydrogen Chapter 9 The following is a summary in Hindi and English for the academic year 2021-2022. You can save these solutions to your computer or use the Class 11 Chemistry.

    Question 1
    CBSEENCH11006814
    Question 2
    CBSEENCH11006815

    Why does hydrogen occur in a diatomic form rather than in a monoatomic form under normal conditions?

    Solution

    A molecule of hydrogen is formed by the combination of two atoms of hydrogen with one electron each present in the 1s orbital. hydrogen (1s1) has one electron less than the stable inert gas configuration (He;1s2) and therefore it shares its single electron with an electron of another hydrogen atom to form a stable diatomic molecule. Thus two electrons are present in the hydrogen molecule and both will be accommodated in the molecular orbital of lowest energy. The bond order of H2 is +1. The positive value of bond order indicates that the H2 (diatomic) molecules are stable.

    Question 3
    CBSEENCH11006816

    Give one example in which hydrogen acts as an oxidising agent.

    Solution
    2Na + H2 → 2NaH
    Here, hydrogen acts as the oxidising agent.
    Question 4
    CBSEENCH11006817

    Give laboratory Preparation of Dihydrogen ?

    Solution

    It can also be prepared by the reaction of zinc with aqueous alkali.
    Zn + 2NaOH → Na2ZnO2 + H2

    Question 5
    CBSEENCH11006818

    Name the substances in which hydrogen exhibits 0 and -1 oxidation states.

    Solution
    In H2, oxidation state of hydrogen is zero and in NaH (sodium hydride) oxidation state of hydrogen is -1.
    Question 6
    CBSEENCH11006819

    Name different isotopes of the element whose atomic number is 1.

    Solution
    The element with atomic number 1 is hydrogen. Three isotopes of hydrogen are known, namely:
    left parenthesis straight i right parenthesis space Protium space left parenthesis straight H presubscript 1 presuperscript 1 right parenthesis space space space space left parenthesis ii right parenthesis space Deuterium space left parenthesis straight H presubscript 1 presuperscript 2 space space or space space straight D right parenthesis
and space left parenthesis iii right parenthesis space Tritium space left parenthesis straight H presubscript 1 presuperscript 1 space or space straight T right parenthesis
    Question 7
    CBSEENCH11006820
    Question 8
    CBSEENCH11006821
    Question 9
    CBSEENCH11006822

    Which isotope of hydrogen is used as a tracer in organic reactions ?

    Solution
    Both deuterium and tritium can be used as the tracer in organic compound. But tritium is not only radioactive but also least abundant isotope of hydrogen. Hence, deuterium is most commonly used as a tracer to study the mechanism of organic reactions.
    Question 10
    CBSEENCH11006823

    Hydrogen is the lightest gas. Still its use in filling balloons has been discarded. Why?

    Solution
    This is because of its combustible nature.
    Question 11
    CBSEENCH11006824

    Hydrogen forms both H+ ion and Hion. Explain.

    Solution
    Hydrogen can easily lose the only electron present in the valence shell (1s1) and can exist as H+ ion. It can also take up one electron from outside to attain a stable configuration and therefore it exists as H-.
    Question 12
    CBSEENCH11006825

    What happens when water is added to hydrolith?

    Solution
    Hydrogen gas is produced.
    space space space space space space space space stack CaH subscript 2 with stack Calcium space hydride with left parenthesis Hydrolith right parenthesis below below space plus space 2 straight H subscript 2 straight O space space rightwards arrow space space space Ca left parenthesis OH right parenthesis subscript 2 space plus space straight H subscript 2 space space space
    Question 13
    CBSEENCH11006826

    Can dihydrogen act as an oxidising agent? If so, give an example.

    Solution
    Yes, dihydrogen acts as an oxidising agent.
    stack 2 Na left parenthesis straight s right parenthesis with Reducing space agent below space plus space space space stack straight H subscript 2 left parenthesis straight g with Oxidising space agent below right parenthesis space space space rightwards arrow space space stack 2 NaH with Sodium space hydride below
    Question 14
    CBSEENCH11006827

    What is the molecular mass of a compound formed when tritium is burnt in air?

    Solution
    When tritium is burnt in air, tritium oxide (T2O) is formed.
    Molecular mass of tritium = 3.0 amu
    Molecular mass of oxygen =16 amu
    Therefore, the mass of (T2O)
    Molecular mass of T2O = 3 x 2 + 16 = 22 amu.
    Question 15
    CBSEENCH11006828

    Why ionic hydrides are kept away from moisture?

    Solution
    Ionic hydrides are kept away from moisture because ionic hydrides are very reactive towards the water. Traces of water decompose it with-the liberation of dihydrogen.
    NaH space plus space straight H subscript 2 straight O space space rightwards arrow space space NaOH space plus space straight H subscript 2 space upwards arrow
    Question 16
    CBSEENCH11006829

    Ionic hydrides are generally used to remove traces of water from organic compounds. Explain.

    Solution

    Ionic hydrides liberate H- ions which act as a Bronsted base. They combine with water to produce H2 gas.
    Na to the power of plus straight H to the power of minus space plus space straight H subscript 2 straight O space space rightwards arrow space space space NaOH space plus space straight H subscript 2
    The ionic hydrides can be used to remove last traces of water from organic compounds.

    Question 17
    CBSEENCH11006830

    Out of H2 and D2 which has higher boiling point and why?

    Solution
    D2 has a higher boiling point because of higher molar mass.

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    Question 18
    CBSEENCH11006831

    Give one use of liquid hydrogen. 

    Solution
    Liquid hydrogen is used as fuel in space rockets.
    Question 19
    CBSEENCH11006832

    Why dihydrogen (H2) is not preferred for filling of balloons and airships?

    Solution

    Dihydrogen is not preferred for filling of balloons and airships because dihydrogen is flammable in nature.

    Question 20
    CBSEENCH11006833

    What is nascent hydrogen?

    Solution
    The hydrogen produced in contact with the substance to be reduced is called nascent hydrogen. It is the hydrogen at the moment of its generation, that is why it is also called newly born hydrogen.
    Question 21
    CBSEENCH11006834

    What is atomic hydrogen?

    Solution

    When molecular hydrogen is passed through tungsten electric are (2000 - 3000°C), at low pressure, it dissociates to form atoms of hydrogen known as atomic hydrogen.
                        space space stack straight H subscript 2 with molecular space hydrogen below space space space rightwards arrow from arc to space space space space space space space space space space space space space Electric of space space stack space 2 straight H with space space space space Atomic space hydrogen below

    Question 22
    CBSEENCH11006835

    Give one use of atomic hydrogen?

    Solution

    Atomic hydrogen is used for welding purposes in the form of atomic hydrogen torch. 

    Question 23
    CBSEENCH11006836

    Name two complex hydrides of alkali metals which are widely used as reducing agents in the laboratory?

    Solution

    Lithium aluminium hydride (LiAlH4) and sodium borohydride (NaBH4) used as reducing agents in the laboratory.

    Question 24
    CBSEENCH11006837

    Why is molecular hydrogen very little reactive chemically?

    Solution
    Hydrogen molecule has high bond dissociation energy. Hence, it is very less reactive.
    Question 25
    CBSEENCH11006838

    What is the phenomenon of adsorption of hydrogen on the surface of a metal called?

    Solution
    The adsorption of hydrogen on the surface of a metal known as Occlusion.
    Question 26
    CBSEENCH11006839

    What are the constituents of water gas?

    Solution

    Carbon monoxide and hydrogen (CO, H2)

    Question 27
    CBSEENCH11006840

    What is the state of hybridization of oxygen atom in H2O?

    Solution
    The state of hybridization of oxygen in H2O is sp3.
    Question 28
    CBSEENCH11006841

    What is the shape of H2O molecule ?

    Solution

    It is of bent shape. 

    Question 29
    CBSEENCH11006842

    What happens when heavy water is added to calcium carbide?

    Solution
    Deuterioacetylene is formed.
    CaC subscript 2 space plus space space 2 straight D subscript 2 straight O space space rightwards arrow space space space Ca left parenthesis OD right parenthesis subscript 2 space plus stack space DC space identical to space space space CD with Deuterioacetylene below
    Question 30
    CBSEENCH11006843

    How will you prepare a sample of ND3?

    Solution
    ND3 can be prepared by the action of heavy water on magnesium nitride.
    Mg subscript 3 straight N subscript 2 space plus space 6 straight D subscript 2 straight O space space rightwards arrow space space space 3 Mg left parenthesis OD right parenthesis subscript 2 space plus space 2 ND subscript 3
    Question 31
    CBSEENCH11006844

    Can hard water be used for drinking purposes?

    Solution

    Drinking of hard water is harmful. If the concentration ca2+ and Mg2+ of ions is present in an excess amount. 

    Question 32
    CBSEENCH11006845

    Hard water is not suitable for washing purposes, Why?

    Solution

    Hard water is not suitable for washing purposes since a lot of soap is wasted in precipitating out Ca2+ and Mg2+ ions present in hard water. 

    Question 33
    CBSEENCH11006846

    What is zeolite ?

    Solution
    Zeolite is hydrated sodium aluminium silicate i.e. Na2Al2Si2O8 .xH2O.
    Question 34
    CBSEENCH11006847

    Can sodium bicarbonate make water hard?

    Solution

    The hardness of water depends on the concentration of Ca2+ and Mg2+ion. Also, sodium ions do not precipitate soap. Hence, sodium bicarbonate does not make hard water.

    Question 35
    CBSEENCH11006848

    What is calgon?

    Solution

    Sodium hexa-metaphosphate:
    Na2[Na4(PO3)6] is called calgon.

    Question 36
    CBSEENCH11006849

    How temporary hardness of water is removed?

    Solution
    A temporary hardness of water is removed by the following way:
     (i) By boiling and (ii) by adding lime.
    Question 37
    CBSEENCH11006850

    Which would you predict to have higher electrical conductivity - pure water or pure D2O?

    Solution
    Pure water has higher electrical conductivity due to its greater degree of dissociation.
    Question 38
    CBSEENCH11006851

    Explain why water has high melting and boiling points as compared to H2S.

    Solution
    It is due to the association of water molecules by intermolecular hydrogen bonding. When hydrogen is attached to an electronegative atom like oxygen, the oxygen pulls the electrons closer to itself giving it a partial negative charge and leaving hydrogens with a partial positive charge. The partial charges are attracted to each other, so the hydrogens of one water molecule are attracted to the oxygen of another. This extra bond allows the water to absorb more energy. H2S does not show this property.



    Question 39
    CBSEENCH11006852

    Can distilled water be called deionised water ?

    Solution

    Yes, Distilled water does not contain any cations and anions and hence it can be called deionized water.

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    Question 40
    CBSEENCH11006853

    Can marine species live in distilled water?

    Solution
    Marine species also need oxygen to survive. Since distilled water does not contain dissolved oxygen, therefore, marine species does not live in distilled water.
    Question 41
    CBSEENCH11006854

    What is demineralised water? How is it obtained?

    Solution
    Water which does not contain cations and anions is called demineralised water. It is obtained by passing ordinary water through an exchange resin.
    Question 42
    CBSEENCH11006855

    How is heavy water produced from ordinary water?

    Solution

    It is obtained by repeated electrolysis of ordinary and water containing 3% NaOH.

    Question 43
    CBSEENCH11006856

    Explain why electrolysis of ordinary water occurs faster than heavy water.

    Solution

    Due to lower bond dissociation energy of protium bonds in H – O – H than deuterium bonds in D – O – D, electrolysis of H2O occurs much faster than that of D2O.

    Question 44
    CBSEENCH11006857

    Give two advantages of using hydrogen as a fuel over gasoline. 

    Solution

    Advantage of using hydrogen as fuel over gasoline:
    i) The high heat of combustion
    ii) No pollutants like SO2, NO2, CO2 etc.

    Question 45
    CBSEENCH11006858

    What is the starting material for the manufacture of H2O2 by electrolysis by a most modern method?

    Solution
    An equimolar mixture of (NH4)9SO4 and H2SO4.
    Question 46
    CBSEENCH11006859

    How do we prepare H2O2 by reaction between BaO2.8H2O and dilute sulphuric acid ?

    Solution

    By the action of sulphuric acid  on hydrated barium peroxide BaO2.8H2O

    BaO2.8H2O + H2SO4 → BaSO4 ↓+ H2O2 + 8H2O
    It must be noted that anhydrous barium peroxide does not react readily with sulphuric acid (because a coating of insoluble barium sulphate is formed on its surface which stops the further action of the acid). Therefore, hydrated barium peroxide, BaO2.8H2O must be used.

    Question 47
    CBSEENCH11006860

    What is the defect of permutit method?

    Solution
    It removes only Ca2+ and Mg2+ present in hard water and other ions such as Na+, K+ are not removed.
    Question 48
    CBSEENCH11006861

    What is the structure of H2O2?

    Solution
    Non-planar - open book structure.
    Question 49
    CBSEENCH11006862

    What is perhydral?

    Solution
    Perhydrol is a solution of hydrogen peroxide (H2O2) at a concentration of  30% of weight by volume(w/v) .
    Question 50
    CBSEENCH11006863

    How saline hydride react with water ?

    Solution

    Saline hydrides react violently with water producing dihydrogen gas.

    NaH(s)+ H2O (aq) → NaOH (aq) + H2 (g)

    Question 51
    CBSEENCH11006864

    How is H2O2 prepared by auto-oxidation method?

    Solution

    (i) 2-Ethyl anthraquinone is reduced to 2-ethyl anthraquinol by H2 in the presence of palladium.
    (ii) This 2-ethyl anthraquinol is oxidised by air to 2-ethyl anthraquinone again. Then H2O7 (20% solution) forms.

    Question 52
    CBSEENCH11006865

    Out of H2SO4 and H3PO4, which is preferred to prepare H2O2?

    Solution
    H3PO4 is preferred to prepare H2O2.
    Question 53
    CBSEENCH11006866

    Why is 2-anthraquinol preferred in the commercial preparation of H2O2?

    Solution
    2-anthraquinol preferred in the commercial preparation of H2O2, since it gets regenerated during the reaction.
    Question 54
    CBSEENCH11006867

    Is H2O2 a strong acid in aqueous solution?

    Solution
    No, it is a weak acid.
    Question 55
    CBSEENCH11006868

    Give a test to identify H2O2.

    Solution
    It decolourises acidified solution of potassium permanganate.
    Question 56
    CBSEENCH11006869

    How decomposition of H2O2 is accelerated ?

    Solution

    The decomposition can be accelerated in the presence of:
    (i) MnO2, carbon or metals like Pt.
    (ii) light.

    Question 57
    CBSEENCH11006870

    How decomposition of H2O2 is prevented?

    Solution
    It is prevented by the addition of little H3PO4, glycerine, acetanilide, alcohol etc. which act as negative catalysts or inhibitors.
    Question 58
    CBSEENCH11006871

    Explain why hydrogen peroxide is used to restore old lead paintings in museums ?

    Solution

    Hydrogen peroxide oxidises black coloured PbS to PbSO4 and hence is used to restore the colour of old paintings. 

    Question 59
    CBSEENCH11006872

    Justify the position of hydrogen in the periodic table on the basis of its electronic configuration.

    Solution
    Hydrogen (Z=1) has electronic configuration 1s1. On one hand, its electronic configuration is similar to the outer electronic configuration (ns1) of alkali metals.
    Hydrogen space left parenthesis straight H presubscript 1 presuperscript 1 right parenthesis space equals space 1 straight s to the power of 1
Lithium space left parenthesis Li presubscript 3 right parenthesis space equals space 1 straight s squared space 2 straight s to the power of 1
Sodium space left parenthesis Na presubscript 11 right parenthesis space equals space 1 straight s squared space 2 straight s squared space 2 straight p to the power of 6 space 3 straight s to the power of 1
Potassium space left parenthesis straight K presubscript 19 right parenthesis space equals space 1 straight s squared space 2 straight s squared space 2 straight p to the power of 6 space 3 straight s squared space 3 straight p to the power of 6 space 4 straight s to the power of 1
    On the other hand, like halogens (having electronic configuration ns2np5 belonging to group 17 of the periodic table), it is short by one electron to the corresponding noble gas configuration (ns2np6).
                           space space straight H presubscript 1 left parenthesis 1 space straight s to the power of 1 right parenthesis
straight F presubscript 9 left parenthesis 1 straight s squared space 2 straight s squared space 2 straight p to the power of 5 right parenthesis
Cl presubscript 17 left parenthesis 1 straight s squared space 2 straight s squared space 2 straight p to the power of 6 space 3 straight s squared space 3 straight p to the power of 5
    Although hydrogen to a certain extent resembles both with alkali metals (Group I) and halogens (Group 17), yet it differs from them as well. Therefore, it is best placed separately in the periodic table.
    Question 60
    CBSEENCH11006873

    Give examples showing electropositive character of hydrogen.

    Solution
    (i) It combines with electronegative elements to form covalent compounds e.g., H2O, H2S, HF, NH3 etc.
    (ii) When an aqueous solution of HCl or acidulated water is electrolyzed, hydrogen is liberated at the cathode showing that it is present as H+ ions in solution.
                       HCl space space rightwards harpoon over leftwards harpoon space space space straight H to the power of plus space plus space Cl to the power of minus
At space cathode colon
space space space space straight H to the power of plus space plus space straight e to the power of minus space space space rightwards arrow space space space straight H space space space space open square brackets Primary space change close square brackets
space space space space straight H space space plus space straight H space space space rightwards arrow space space space space straight H subscript 2 space space space space left square bracket Secondary space change right square bracket
space space space space space space space space space space space space space space space space space space space space space space space space space space space left parenthesis Cathode right parenthesis
    Question 61
    CBSEENCH11006874

    Give an examples showing electronegative character of hydrogen. 

    Solution
    (i) Hydrogen has a tendency to accept one electron to form the hydride ion.
    H + e→ H-

    (ii) When fused alkali metal hydride (NaH) is electrolyzed, hydrogen is liberated at the anode showing that is present as H.
        space space space space space space space space space space space space space space space NaH space space rightwards harpoon over leftwards harpoon space space Na to the power of plus space plus space straight H to the power of minus
At space anode space space space space straight H to the power of minus space space rightwards arrow space space straight H space plus space straight e to the power of minus space left square bracket Primary space change right square bracket
space space space space space space space space space space space straight H space plus space straight H space space rightwards arrow space space straight H subscript 2 space left square bracket Secondary space change right square bracket
    Question 62
    CBSEENCH11006875

    What are isotopes? Discuss briefly the various isotopes of hydrogen.

    Solution

    Isotopes: Isotopes are the atoms of the same element having the same number of electrons and protons but a different number of neutrons. They have the same atomic number but different mas-numbers.
    Isotopes of the same element have the same chemical properties because of the presence of an equal number of electrons in their extra nuclear parts. Chemical properties of an element are dependent only on the number of electrons and their distribution in various shells around the nucleus. Isotopes of the same element differ in their physical properties because these isotopes differ in the number of neutrons which cause a difference in the mass numbers.
    Isotopes of hydrogen:
    Three isotopes of hydrogen are known. They are:
    (i) Protium or ordinary hydrogen or light hydrogen open parentheses straight H presubscript 1 presuperscript 1 close parentheses colon It is the most abundant isotope of hydrogen. Its atomic number is 1 and mass number is 1. Its nucleus consists of one proton and has one electron in the 1s orbital. It is a non-radioactive isotope of hydrogen.
    (ii) Deuterium or heavy hydrogen open parentheses straight H presubscript 1 presuperscript 2 space or space straight D close parentheses colon
    It is present in heavy water (D2O) and can be recovered from it by fractional electrolysis. Its atomic number is 1 and mass number is 2. Its nucleus consists of one proton and one neutron and has one electron in the 1s orbital. It is a non-radioactive isotope of hydrogen.
    (iii) Tritium left parenthesis straight H presubscript 1 presuperscript 3 space or space straight T right parenthesis colon It is the rarest isotope of hydrogen left parenthesis 10 to the power of negative 15 end exponent percent sign right parenthesis. Its atomic number is 1 and mass number is 3. Its nucleus consists of one proton and two neutrons and has one electron in the 1s orbital. Tritium is the only radioactive isotope of hydrogen.



    Question 63
    CBSEENCH11006876
    Question 64
    CBSEENCH11006877

    How do the isotopes of hydrogen differ from each other in their properties? In what physical properties do hydrogen and deuterium differ?

    Solution

    The electronic configuration of all the isotopes of hydrogen is same, therefore, chemical properties of all the isotopes are identical. However, they differ from each other in their rates of reaction and equilibrium constants for reversible reactions e.g. protium reacts with chlorine 13.4 times as fast as deuterium does.
    Due to the difference in the masses of the isotopes of hydrogen, they have different physical properties. Property differences arising from differences in mass are called isotopic effects.
    Properties: The difference in the masses of protium and deuterium produce appreciable changes in many of their physical properties like melting point and boiling point, latent heat of fusion, evaporation, sublimation etc. As deuterium is heavier than hydrogen, so the rates of a reaction involving deuterium are slower than reactions involving hydrogen. For the same reason, D2 has a higher boiling point than that of H2.

    Question 65
    CBSEENCH11006878

    Write a short note on allotropy of hydrogen.
    Or
    How many allotropes of dihydrogen are known? What is their importance?

    Solution
    The hydrogen molecule occurs in two forms known as ortho and para hydrogen. The nuclei of two atoms are spinning.
    (i) When the spins of the nuclei are in the same direction (parallel spin), the molecule is known as ortho-hydrogen.

    (ii) If the spins are opposite (anti-parallel spins), the molecule is para hydrogen.
    Para-hydrogen has a lower internal energy and is more stable than ortho-hydrogen. Hydrogen at room temperature is an equilibrium mixture of 75% ortho-hydrogen and 25% para hydrogen. At 25K. a sample of ordinary contains 99% para and 1% of ortho form.
    Question 66
    CBSEENCH11006879

    How would you prepare dihydrogen from water using a reducing agent?

    Solution
    1. By the action of water on metals:
    (i) Active metals like N,a, K, Ca etc. decompose water at room temperature to liberate hydrogen gas.
    2 Na left parenthesis straight s right parenthesis space plus space space 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis space space space rightwards arrow space space space 2 NaOH left parenthesis aq right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis
Reducing space agent
2 straight K left parenthesis straight s right parenthesis space plus space 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis space space rightwards arrow space space space space 2 KOH left parenthesis aq right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis
Reducing space agent
Ca left parenthesis straight s right parenthesis space plus space 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis space space rightwards arrow space space Ca left parenthesis OH right parenthesis subscript 2 left parenthesis aq right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis
Reducing space agent
    (ii) Less active metals like Mg, Al or Zn decompose boiling water producing dihydrogen gas.
    Mg left parenthesis straight s right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight l right parenthesis space space space rightwards arrow space space space MgO left parenthesis straight s right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis
Reducing space agent
2 Al left parenthesis straight s right parenthesis space plus space 3 straight H subscript 2 straight O left parenthesis straight l right parenthesis space rightwards arrow space space space Al subscript 2 straight O subscript 3 left parenthesis straight s right parenthesis space plus space 3 straight H subscript 2 left parenthesis straight g right parenthesis
Reducing space agent
Zn left parenthesis straight s right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight l right parenthesis space rightwards arrow space space space ZnO left parenthesis straight s right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis
Reducing space agent
    (iii) Still less active metals like iron, tin or nickel decompose steam at high temperature.
    stack 3 Fe left parenthesis straight s right parenthesis space plus space 4 straight H subscript 2 straight O with Reducing space agent below left parenthesis straight g right parenthesis space space rightwards arrow with 1023 minus 1073 space straight K on top space stack Fe subscript 3 straight O subscript 4 space plus space 4 straight H subscript 2 left parenthesis straight g right parenthesis with Ferroso minus ferric space oxide below
    2. By passing steam over red-hot coke:
    When steam is passed over red-hot coke (carbon) at 1270 K, a mixture of carbon monoxide and dihydrogen called water gas is produced.
    stack straight C left parenthesis straight s right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight g right parenthesis with Reducing space agent below space space rightwards arrow with 1270 space straight K on top space space stack CO left parenthesis straight g right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis with Water space gas below
    Dihydrogen is then recovered from water gas either by liquefaction or by Bosch process.
    Question 67
    CBSEENCH11006880

    How would you prepare dihydrogen from a substance other than water?

    Solution
    1. From acids. Active metals such as Zn, Fe, Mg etc. react with dilute mineral acids (HCl, H2SOetc.) to produce dihydrogen gas.
    Zn left parenthesis straight s right parenthesis space plus straight H subscript 2 SO subscript 4 left parenthesis aq right parenthesis space space rightwards arrow space space space ZnSO subscript 4 left parenthesis aq right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis
Mg left parenthesis straight s right parenthesis space plus space 2 HCl left parenthesis aq right parenthesis space space space rightwards arrow space space MgCl subscript 2 left parenthesis aq right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis
Fe left parenthesis straight s right parenthesis space plus space 2 HCl left parenthesis aq right parenthesis space space rightwards arrow space space FeCl subscript 2 left parenthesis aq right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis
    Since metals have displaced hydrogen from the acids, hence their reactions are called displacement reactions.
    2. From alkalies: Metals like Zn, Al, Sn, Pb, Sb etc. react with boiling sodium hydroxide solution to liberate hydrogen gas.
    Zn left parenthesis straight s right parenthesis space plus space 2 NaOH left parenthesis aq right parenthesis space space rightwards arrow space space space stack Na subscript 2 ZnO subscript 2 left parenthesis aq right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis with Sodium space zincate below
2 Al left parenthesis straight s right parenthesis plus 2 NaOH left parenthesis aq right parenthesis plus 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis space space rightwards arrow space space stack 2 NaAlO subscript 2 left parenthesis aq right parenthesis with Sodium space meta space aluminate below plus 3 straight H subscript 2 left parenthesis straight g right parenthesis
Sn left parenthesis straight s right parenthesis space plus space 2 NaOH left parenthesis aq right parenthesis space space rightwards arrow space space space stack Na subscript 2 SnO subscript 2 left parenthesis aq right parenthesis with Sodium space stannite below space plus space straight H subscript 2 left parenthesis straight g right parenthesis
    Question 68
    CBSEENCH11006881

    How would you prepare pure dihydrogen in the laboratory?

    Solution
    (i) A sample of pure dihydrogen can be prepared by the action of pure dilute sulphuric acid on magnesium.
    Mg left parenthesis straight s right parenthesis space plus space straight H subscript 2 SO subscript 4 left parenthesis aq right parenthesis space space rightwards arrow space space space MgSO subscript 4 left parenthesis aq right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis
left parenthesis ii right parenthesis space By space the space action space of space water space on space NaH.
space space space space space space space space space space space space space space space space NaH space plus space straight H subscript 2 straight O space space rightwards arrow space space space NaOH space plus space straight H subscript 2 space upwards arrow
    (iii) By the electrolysis of barium hydroxide solution in a U-tube using platinum electrodes or nickel electrodes. 
    Question 69
    CBSEENCH11006882

    How will you prepare hydrogen in laboratory?

    Solution
    Dihydrogen gas is prepared in the laboratory by the action of dilute sulphuric acid on granulated zinc in a Woulfe’s bottle.
    Zn left parenthesis straight s right parenthesis space plus space straight H subscript 2 SO subscript 4 left parenthesis aq right parenthesis space space rightwards arrow space space space ZnSO subscript 4 left parenthesis aq right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis

    Dilute sulphuric acid is poured dropwise through thistle funnel on granulated zinc pieces, hydrogen gas is produced which is collected by the downward displacement of water.
    Sometimes, the bubbles of hydrogen formed to adhere to the surface of zinc metal and this prevents the further attack of acid on the metal.
    To check this, a small amount of copper sulphate is added along with granulated zinc.
    Question 70
    CBSEENCH11006883

    Why are pure zinc and concentrated sulphuric acid not used in the preparation of hydrogen?

    Solution

    (i) Completely pure zinc metal is not used for the preparation of hydrogen because it is slowly attacked by the acid. The presence of impurities increases the rate of the reaction by forming electrochemical couples.
    (ii) Concentrated H2SO4 cannot be used for the preparation of hydrogen gas as it results in the formation of SO2 gas instead of H2 from zinc.
    Zn left parenthesis straight s right parenthesis space plus space straight H subscript 2 SO subscript 4 left parenthesis conc right parenthesis. space rightwards arrow space space space ZnSO subscript 4 left parenthesis aq right parenthesis space plus space SO subscript 2 left parenthesis straight g right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight l right parenthesis

    Question 71
    CBSEENCH11006884

    What is water gas? How will you prepare hydrogen from water gas?
    Or
    How is dihydrogen prepared on a commercial scale? 

    Solution
    Water gas is a mixture of CO and H2 in the ratio of 1 : 1 by volume. It is prepared by passing steam over red-hot coke (carbon at 1270 K).
    stack straight C left parenthesis straight s right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight g right parenthesis with Red space hot space coke space steam below space space rightwards arrow with 1270 space straight K on top space stack CO left parenthesis straight g right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis with Water space gas below
    (i) From water gas, hydrogen is prepared, by Bosch process. Here water gas is mixed with steam and passed over a heated catalyst (Fe2O3 + Cr2O3) at 770 K when carbon monoxide is oxidised to carbon dioxide. 
    stack straight H subscript 2 left parenthesis straight g right parenthesis space plus space CO left parenthesis straight g right parenthesis with water space gas below space plus space stack straight H subscript 2 straight O with steam below space space space rightwards arrow from Fe subscript 2 straight O subscript 3. space Cr subscript 2 straight O subscript 3 to 773 space straight K of space CO subscript 2 left parenthesis straight g right parenthesis space plus space 2 straight H subscript 2 left parenthesis straight g right parenthesis
    The resulting gaseous mixture (CO2 and H2) is passed into cold water under a pressure of the 20-25 atmosphere. Under this pressure, CO2 goes into the solution while dihydrogen gas is left behind and collected.
    (ii) By liquefaction: Water gas is cooled under pressure when CO gets liquefied while dihydrogen gas passes out.
    Question 72
    CBSEENCH11006885

    What do you understand by the term syngas?

    Solution
    Syngas (or synthesis gas) is a mixture of CO and H2. It is obtained by the action of steam on hydrocarbon or coke at high temperature in the presence of nickel as catalyst.
    straight C subscript straight n straight H subscript 2 straight n plus 2 end subscript space plus space nH subscript 2 straight O left parenthesis straight g right parenthesis space space space rightwards arrow from Ni to 1270 space straight K of space nCO space plus space left parenthesis 2 straight n plus 1 right parenthesis straight H subscript 2
CH subscript 4 left parenthesis straight g right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis space space rightwards arrow from Ni to 1270 space straight K of space CO left parenthesis straight g right parenthesis space plus space 3 straight H subscript 2 left parenthesis straight g right parenthesis

    Nowadays ‘syngas’ is obtained from sewage, sawdust, scrap wood, newspaper etc. The process of getting syngas from coal is called “'coal gasification. ”.
    straight C left parenthesis straight s right parenthesis space plus space straight H subscript 2 straight O space space rightwards arrow from Ni to 1270 straight K of space CO left parenthesis straight g right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis
    Question 73
    CBSEENCH11006886

    How can the production of dihydrogen, obtained from 'coal gasification' be increased?

    Solution
    Coal gasification is the process of producing syngas or synthesis gas (water gas) from coal.
    stack straight C left parenthesis straight s right parenthesis with Coal below space plus space space straight H subscript 2 straight O left parenthesis straight g right parenthesis space space space rightwards arrow from Ni to 1270 space straight K of space space space space stack stack CO left parenthesis straight g right parenthesis space plus space straight H subscript 2 left parenthesis straight g with underbrace below with Syngas below right parenthesis
    The production of dihydrogen can be increased by passing carbon monoxide gas(of syngas) through steam in the presence of iron chromate (catalyst) at 673 K.
    CO left parenthesis straight g right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight g right parenthesis space space rightwards arrow from 673 space straight K to FeCrO subscript 4 of space CO subscript 2 left parenthesis straight g right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis space
    The COso produced is removed by scrubbing with a solution of sodium arsenite.
    Question 74
    CBSEENCH11006887

    What do you understand by the term:
    water-gas shift reaction. 

    Solution
    The quantity of hydrogen in the syngas can be increased by reacting CO of syngas mixture with steam in the presence of iron chromate as a catalyst.
    stack CO left parenthesis straight g right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight g right parenthesis space with left parenthesis From space syngas right parenthesis below space rightwards arrow from FeCrO subscript 4 to 673 space straight K of space CO subscript 2 left parenthesis straight g right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis
    This reaction is called  the water-gas shift reaction. By this process, more hydrogen gas is prepared. This method is used for the production of 77% of industrial hydrogen.
    Question 75
    CBSEENCH11006888

    How will you prepare hydrogen commercially from hydrocarbons?
    Or
    What is understood by ‘water gas shift reaction’? Discuss its use for the preparation of hydrogen. 

    Solution

    These days, dihydrogen is produced commercially from hydrocarbons by reaction with steam in the presence of a catalyst and at high temperature. 
        straight C subscript straight n straight H subscript 2 straight n plus 2 end subscript space plus space nH subscript 2 straight O space rightwards arrow from Catalyst to 1270 space straight K of space nCO space plus space left parenthesis 2 straight n plus 1 right parenthesis space straight H subscript 2 straight O
space space space Example space CH subscript 4 space plus space straight H subscript 2 straight O space space rightwards arrow with 1270 space straight K on top space CO space plus space 3 straight H subscript 2
space space straight C subscript 3 straight H subscript 8 space plus space 3 straight H subscript 2 straight O space space rightwards arrow from Catalyst to 1270 space straight K of space 3 CO left parenthesis straight g right parenthesis space plus space 7 straight H subscript 2 left parenthesis straight g right parenthesis
    CO is converted to CO2 by passing the gases and steam over an iron oxide or cobalt oxide catalyst at 673K resulting in the production of more H2.
    CO space plus space straight H subscript 2 straight O space rightwards arrow from Catalyst to 673 space straight K of space CO subscript 2 space plus space straight H subscript 2

    This is called water-gas shift reaction. A mixture of CO2 and H2 is passed through water under pressure. Carbon dioxide dissolves in water leaving behind hydrogen gas.

    Question 76
    CBSEENCH11006889

    Describe the bulk preparation of hydrogen by an electrolytic method. What is the role of electrolyte in this process?
    Or
    How is dihydrogen manufactured by the electrolysis of water?

    Solution

    It is manufactured by the electrolysis of water containing a small amount of acid or alkali(electrolyte) using nickel plated iron as anode and iron as a cathode. The two electrodes are separated from each other by an asbestos diaphragm which prevents mixing of H2 and O2. On passing an electric current, water is decomposed into hydrogen and oxygen. Dihydrogen is collected at the cathode while oxygen is collected at the anode.
            space space space space space space space space space space space space space space space space space straight H subscript 2 straight O space space rightwards harpoon over leftwards harpoon space space space space straight H to the power of plus space plus space OH to the power of minus
At space cathode. space space 2 straight H to the power of plus space plus space 2 straight e to the power of minus space space space rightwards arrow space space space 2 straight H
space space space space space space space space space space space space space space space space space space space space space space space 2 straight H space space rightwards arrow space space space straight H subscript 2
At space anode colon space space space space space space 4 OH to the power of minus space space rightwards arrow space space 4 OH space plus space 4 straight e to the power of minus
space space space space space space space space space space space space space space space space space space space 4 OH space space space space rightwards arrow space space space 2 straight H subscript 2 space plus space straight O subscript 2
space
    The role of electrolyte (acid) is to make water conducting. 

    Question 77
    CBSEENCH11006890

    How is dihydrogen manufactured by Lane's process?

    Solution

    Lane's process consists of two stages:
    (i) Oxidation stage: Super -heated steam is passed over iron filings, at 1023-1073 K when dihydrogen is formed.
                   3 Fe space plus space stack 4 straight H subscript 2 straight O with Steam below space space space rightwards arrow space space space space stack Fe subscript 3 straight O subscript 4 space plus space 4 straight H subscript 2 with Magnetic space oxide below
    (ii) Reduction stage: Iron is regenerated by reducing magnetic oxide with water gas (CO + H2). This reaction is called vivification.
    Fe subscript 3 straight O subscript 4 space plus space 4 CO space space rightwards arrow space space space 3 Fe space plus space 4 CO subscript 2
Fe subscript 3 straight O subscript 4 space plus space space 4 straight H subscript 2 space space rightwards arrow space space space 3 Fe space plus space 4 straight H subscript 2 straight O
    Thus, by passing steam and water gas alternatively over iron, dihydrogen gas can be manufactured from a small quantity of iron. 

    Question 78
    CBSEENCH11006891

    How would you prepare heavy hydrogen in laboratory?

    Solution
    Heavy hydrogen (D2) can be prepared in the laboratory by the electrolysis of heavy water (D2O).
    2 straight D subscript 2 straight O left parenthesis l right parenthesis space rightwards arrow with Electrolysis on top space stack 2 straight D subscript 2 left parenthesis straight g right parenthesis with left parenthesis At space cathode right parenthesis below space plus stack space straight O subscript 2 left parenthesis straight g right parenthesis with left parenthesis At space anode right parenthesis below
    Question 79
    CBSEENCH11006892

    Discuss the consequences of high enthalpy of H – H bond in terms of chemical reactivity of dihydrogen.

    Solution

    The H-H bond dissociation enthalpy is the highest for a single bond between two atoms of any element.This influences the chemical behaviour of dihydrogen. It is inert at room temperature with many metals and non-metals. However, at high temperature or in the presence of the catalyst, it combines with metals and non-metals to form hydrides.

    Since its orbital is incomplete with 1s electronic configuration, it combines with all the almost all elements.It takes part in reaction by
    i) Loss of the only electron to give H+
    ii)The gain of an electron to form H-.
    iii)Sharing electron to form a single covalent bond.

     

    Sponsor Area

    Question 80
    CBSEENCH11006893

    How does dihydrogen react with:
    (a) non-metals      (b) metals and         (c) metal oxides?

    Solution
    (a)Reaction of dihydrogen with non-metals:
    (i) With halogens: Dihydrogen forms hydrogen halides with halogens. With fluorine, the reaction is very violent and the reactivity decreases in the order Cl2, Br2 and I2.
    straight H subscript 2 space plus space straight F subscript 2 space space rightwards arrow from Dark to 20 minus 30 space straight K of space 2 HF
straight H subscript 2 space plus space Cl subscript 2 space rightwards arrow from Sun space light to Diffused of space 2 HCl
straight H subscript 2 space plus space space Br subscript 2 space rightwards arrow with 620 space straight K on top space 2 HBr
straight H subscript 2 space plus space straight I subscript 2 space rightwards harpoon over leftwards harpoon from 673 space straight K to Pt of space 2 HI
    (ii) When nitrogen: When a mixture of dihydrogen and dinitrogen under pressure is passed over finely divided iron containing traces of molybdenum at 673K, it produces ammonia.
                   straight N subscript 2 left parenthesis straight g right parenthesis space plus space 3 straight H subscript 2 left parenthesis straight g right parenthesis space space rightwards harpoon over leftwards harpoon from Fe divided by Mo to 673 space straight K of space 2 NH subscript 3 left parenthesis straight g right parenthesis
    (iii) With oxygen: Dihydrogen combines with oxygen either at 970 K or by passing electric spark into the gaseous mixture to form water vapours.
    2 straight H subscript 2 plus straight O subscript 2 space rightwards arrow with 970 space straight K on top space 2 straight H subscript 2 straight O
     
    (iv) With sulphur: When dihydrogen is bubbled through molten sulphur at 700 K, hydrogen sulphide is produced. 
    straight H subscript 2 left parenthesis straight g right parenthesis space plus space straight S left parenthesis l right parenthesis space rightwards arrow with 700 space straight K on top space straight H subscript 2 straight S left parenthesis straight g right parenthesis
    (v) With carbon: Dihydrogen combines with carbon to form methane or acetylene depending upon the condition of the reaction.
         straight C left parenthesis straight s right parenthesis space plus space 2 straight H subscript 2 left parenthesis straight g right parenthesis space space rightwards arrow with 1373 space straight K on top space stack CH subscript 4 left parenthesis straight g right parenthesis with Methane below
2 straight C left parenthesis straight s right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis space space rightwards arrow from Electric space arc to 3300 space straight K of space space space stack straight C subscript 2 straight H subscript 2 left parenthesis straight g right parenthesis with Acetylene below
    (b) The combination with metals (Dihydrogen acts as an oxidising agent): Dihydrogen combines with metals like sodium, potassium and calcium upon heating to from corresponding hydrides.
    2 Na left parenthesis straight s right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis space space rightwards arrow with Heat on top space 2 NaH
space Ca left parenthesis straight s right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis space space rightwards arrow with Heat on top space CaH subscript 2
    These hydrides are of ionic nature (salt-like). In the above reactions,  hydrogen acts as an oxidising agent.
    (c) Combination with metallic oxides(Dihydrogen acts as a reducing agent):
    Dihydrogen reduces heated metal oxides to metals. 
    CuO left parenthesis straight s right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis space space rightwards arrow with Heat on top space Cu left parenthesis straight g right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight g right parenthesis
ZnO left parenthesis straight s right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis space rightwards arrow with Heat on top space Zn left parenthesis straight s right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight g right parenthesis
PbO left parenthesis straight s right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis space space rightwards arrow with Heat on top space Pb left parenthesis straight s right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight g right parenthesis
Fe subscript 3 straight O subscript 4 left parenthesis straight s right parenthesis space plus 4 straight H subscript 2 left parenthesis straight g right parenthesis space space rightwards arrow with Heat on top space 3 Fe left parenthesis straight s right parenthesis space plus space space 4 straight H subscript 2 straight O left parenthesis straight g right parenthesis
    Question 81
    CBSEENCH11006894
    Question 82
    CBSEENCH11006895
    Question 83
    CBSEENCH11006896

    Comment on the reactions of dihydrogen with: (i) chlorine (ii) sodium and (iii) copper (II) oxide. 

    Solution

    (i) With chlorine. H2 reduces chlorine into chloride (Cl-) ion and itself get oxidised to H+ ion by chlorine to form HCl. An electron pair is shared between H and Cl leading to the formation of a covalent molecule.
    H2 +Cl2 --> 2HCl
    (ii) With sodium. H2 is reduced by sodium to form NaH. An electron is transferred from Na to H leading to the formation of Na+H- (ionic compound).
    (iii) With copper (II) oxide. H2 reduces copper (II) oxide to copper and itself gets oxidised to H2O, which is a covalent molecule.
    CuO +H2 ---> Cu +H2O

    Question 84
    CBSEENCH11006897

    What do you understand by hydrogenation of oils or hardening of oils ?

    Solution

    Hydrogenation means the addition of hydrogen across double and triple bonds to form saturated compounds.
    Hydrogenation is used for the conversion of polyunsaturated oils into edible fats. When dihydrogen under pressure is bubbled through vegetable oils (contain many C = C bonds) in the presence of finely divided nickel at about 400K, they are converted into solid fats. The product formed is called vanaspati ghee (hydrogenated vegetable oil).
    Vegetable space oil space space plus space straight H subscript 2 space rightwards arrow from Ni to 400 space straight K of space stack Vanaspati space ghee with left parenthesis solid space fat right parenthesis below
    The above reaction is known as hardening of oils. 

    Question 85
    CBSEENCH11006898

    What do you understand by the term fuel cell?

    Solution

    A fuel cell is a device which converts the energy produced during the combustion of a fuel directly into electrical energy. Dihydrogen gas is used in H2 – O2 fuel cells for generating electrical energy. It should be noted that it has many advantages, for example, it does not produce any pollution and releases more amount of energy per unit mass of fuel as compared to gasoline and other fuels. 

    Question 86
    CBSEENCH11006899
    Question 87
    CBSEENCH11006900
    Question 88
    CBSEENCH11006901
    Question 89
    CBSEENCH11006902

    Why does elemental hydrogen react with other substances only slowly at room temperature?

    Solution

    Dihydrogen has higher bond dissociation energy (436 kJ mol-1). Therefore, it does not react easily with other elements or substances at room temperature. 

    Question 90
    CBSEENCH11006903

    What are hydrides? Give their types.

    Solution

    The binary compounds of hydrogen with metals and non-metals are called hydrides. The hydrides are of three types:
    (i) Ionic or salt like hydrides: These hydrides are formed by the highly electropositive elements of Group 1 and Group 2 except Be and Mg. They are formed by the transfer of electrons from the metals to the hydrogen atom. As such they are ionic compounds (Li+H-) and thus behave like salts. For example, LiH, NaH, CaH2.
    (ii) Molecular or covalent hydrides: These are formed by elements having higher electronegativity than hydrogen i.e. by the p-block elements. These are formed by sharing of electrons between the element and hydrogen atom. As such they are covalent or molecular compounds. For example, B2H6, NH3, H2O, H2S etc.
    (iii) Metallic or interstitial hydrides: The d-block and f-block elements combine with hydrogen to form non-stoichiometric interstitial hydrides. Hydrogen is in the atomic state which occupies interstitial holes in close-packed metal structures. The composition of an interstitial hydride changes with temperature and pressure. These hydrides give out hydrogen easily and hence act as strong reducing agents.

    Question 91
    CBSEENCH11006904

    Distinguish clearly between salt like hydrides and covalent hydrides.

    Solution
    Salt like hydrides Covalent hydrides
    1. Salt-like hydrides are also called ionic hydrides.  1. Covalent hydrides are also called molecular hydrides.
    2. These are formed by s-block elements except Be and Mg. 2. These are formed by p-block elements.
    3. These are formed by transfer of electrons from the metals to the hydrogen atoms. As such they contain H+ ions. 3. These are formed by sharing of an electron between the element and hydrogen atoms. As such they do not contain H ions.
    4. They possess high melting and boiling points and conduct electricity in the fused state. On electrolysing such fused hydrides, hydrogen is liberated at the anode. 4. They are soft, have low melting and boiling points. They have low electrical conductivity.
    5. They are powerful reducing agents.  5. They are weak reducing agents.
    Question 92
    CBSEENCH11006905

    What do you understand by:
    (i) electron deficient
    (ii) electron-precise and
    (iii) electron rich compounds of hydrogen?
    Provide justification with suitable examples.

    Solution

    Electron deficient compounds. Hydrides of group 13 (i.e. BH3, AlH3etc.) have lesser electrons to form normal covalent bonds and hence are called electron deficient hydrides. To make up this deficiency, these hydrides generally exist in polymeric forms such as B2H6, B4H10, (AlH3)n etc. They act as Lewis acids i.e. electron acceptors.
    (ii) Electron-precise compounds. Electron precise compounds have the required number of electrons to write their conventional Lewis structures. All elements of group 14 form such compounds (i.e. CH4, SiH4, GeH4, SnH4, PbH4), which are tetrahedral in geometry. They do not act as Lewis acids or Lewis bases.
    (iii) Electron rich compounds. Electron rich hydrides have excess electrons which are present as lone pairs. Elements of group 15, 16, 17 form such compounds (NH3, PH3, H2O, H2S, HF, HCl etc.). They all behave as Lewis bases i.e. electron donors.

    Question 93
    CBSEENCH11006906

    What characteristics do you expect from an electron-deficient hydride with respect to its structure and chemical reactivity ? 

    Solution
    Since electron deficient hydrides have lesser electrons to form normal covalent bonds, therefore we expect the following characteristics from these hydrides:
    (i) They generally exist in polymeric forms such as B2H6, B4H10.(AlH3)n etc.
    (ii) They react with many metals, non-metals and their compounds. Hence these hydrides are very reactive. 
              straight B subscript 2 straight H subscript 6 left parenthesis straight g right parenthesis space plus space 3 straight O subscript 2 space rightwards arrow space straight B subscript 2 straight O subscript 3 left parenthesis straight s right parenthesis space plus space 3 straight H subscript 2 straight O left parenthesis straight g right parenthesis
2 NaH left parenthesis straight s right parenthesis space plus space straight B subscript 2 straight H subscript 6 left parenthesis straight g right parenthesis space space rightwards arrow with Diethyl space ether on top space stack 2 Na to the power of plus space open square brackets BH subscript 4 close square brackets to the power of minus space left parenthesis straight s right parenthesis with Sodium space borohydride below
    (iii) They act as Lewis acids and thus form complexes with Lewis bases.
    stack straight B subscript 2 straight H subscript 6 with Diborane below space plus space CO space space rightwards arrow space space straight H subscript 3 straight B space space leftwards arrow space space CO with Complex below
stack straight B subscript 2 straight H subscript 6 with Diborane below space plus space stack 2 NMe subscript 3 with Trimethylamine below space rightwards arrow space space space 2 straight H subscript 3 straight B space space leftwards arrow space space space NMe subscript 3
    Question 94
    CBSEENCH11006907

    Do you expect the carbon hydride of the type(CnH2n+2) to act as Lewis acid or base? 

    Solution
    Carbon hydrides (CnH2n+2) being electron-precise hydrides (i.e. having exact numbers of electrons required to form covalent bonds) do not have a tendency to either gain or lose electrons. Hence they do not act as Lewis acids or Lewis bases.
    Question 95
    CBSEENCH11006908

    What do you understand by the term ‘non-stoichiometic hydrides’? Do you expect this type of hydrides to be formed by alkali metals?

    Solution

    ‘Non-stoichiometric’ are those hydrides in which the ratio of the metal to hydrogen is fractional. This fractional ratio is not fixed but varies with temperature and pressure. Many of the d-block elements and f-block elements (lanthanoids and actinoids) react with hydrogen at elevated temperature to give metallic or non-stoichiometric hydrides. For example LaH2.87, TiH1.8.,Zr H1.9, VH1.6 etc. Since in these hydrides, hydrogen is present in the interstices (holes or voids) existing in between the atoms, therefore these hydrides are also called interstitial hydrides.

    Alkali metals do not form non-stoichiometric hydrides and form only stoichiometric hydrides. Alkali metals hydrides are ionic in which H- ions are present in holes existing in between the atoms in the lattice. Since hydride ion (H+) is formed by complete transfer of lone electron of alkali metal to hydrogen, the, therefore, ratio of metal to hydrogen is always fixed. As a result, these alkali metals do not form non-stoichiometric hydrides. 

    Question 96
    CBSEENCH11006909

    Saline hydrides are known to react with water violently producing fire. Can CO2, a well-known fire extinguisher, be used in this case? Explain.

    Solution
    CO2 can not be used as a fire extinguisher. This is because saline hydrides (such as NaH, CaHetc.) react with water violently producing corresponding metal hydrides and dihydrogen.
    NaH left parenthesis straight s right parenthesis space plus space straight H subscript 2 straight O left parenthesis l right parenthesis space space rightwards arrow space space space NaOH left parenthesis aq right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis
CaH subscript 2 left parenthesis straight s right parenthesis space plus space 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis space rightwards arrow space space space Ca left parenthesis OH right parenthesis subscript 2 left parenthesis aq right parenthesis space plus space 2 straight H subscript 2 left parenthesis straight g right parenthesis
    The above reactions are highly exothermic that evolved H2 immediately catches fire. This fire can not be extinguished by CO2 because it gets reduced by the hot metal hydride.
    NaH space plus space CO subscript 2 space space rightwards arrow space HCOONa
    On the other hand sand (being a stable solid) can be used for extinguishing fire.
    Question 97
    CBSEENCH11006910

    What do you expect the nature of hydrides if formed by elements of atomic numbers 15, 19, 23, 44 with dry dihydrogen? Compare their behaviour towards water. 

    Solution

    (i) The element having Z = 15 is a non-metal (i.e. P), therefore it forms covalent hydride (i.e. PH3).
    (ii) The element having Z = 19 is an alkali metal (i.e. K), therefore it forms ionic or saline hydride (i.e. K+ H-).
    (iii) The  element having Z = 23 is a transition metal (i.e. V) of group 5, therefore it forms an interstitial or metallic hydride (i.e. V H1.6).
    (iv) The element having Z =44 is a transition metal (i.e. Ru) of group 8, therefore it does not form any hydride.
    Behaviour towards the water. Only ionic hydrides react with water evolving H2 gas.
    2 KH left parenthesis straight s right parenthesis space plus space 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis space space rightwards arrow space space space 2 KOH left parenthesis aq right parenthesis space plus space 2 straight H subscript 2 left parenthesis straight g right parenthesis

     
    Question 98
    CBSEENCH11006911

    How saline hydrides can remove traces of water from organic compounds?

    Solution

    Organic compounds containing traces of water can be dried by placing these organic compounds in a desiccator containing saline hydrides (i.e. NaH, CaH2 etc.) at the bottom for overnight. Saline hydrides absorb water and thus traces of water can be easily removed from the organic compounds.

    Question 99
    CBSEENCH11006912

    Can Phosphorus with outer electronic configuration 3s23p3 form PH5?
    Or

    P forms PH3 but not PH5. Comment.

    Solution
    Although phosphorus exhibits +3 and +5 oxidation states, yet it can not form PH5. Because of high ∆H–H and slightly negative ∆ e.g. H (electron gain enthalpy), dihydrogen acts only as a weak oxidising agent. Thus it can oxidise P to +3 oxidation state but not to its highest oxidation state of +5. Hence P forms PH3 and not PH5
    Question 100
    CBSEENCH11006913

    Arrange the following:
    CaH2, BeH2 and TiH2 in order of increasing electric conductance.

    Solution

    Electrical conductance. The order of increasing electrical conductance is
    BeH< CaH< TiH2.
    Reason: BeH2 being a covalent hydride, therefore it does not conduct electricity. On the other hand, CaH2 conducts electricity in the fused state and TiH2 conducts electricity at room temperature. Hence order of increasing electrical conductance is
    BeH2<CaH2<TiH2

    Question 101
    CBSEENCH11006914

    Arrange the following:
    LiH, NaH and CsH in order of increasing ionic character.

    Solution
    Ionic character. The order of increasing ionic character is LiH < NaH < CsH.
    Reason: Since electronegativity decreases as we move down the group from Li to Cs (Li > Na > Cs), therefore the ionic character of their hydrides also increases in the same order.
    LiH < NaH < CsH
    Question 102
    CBSEENCH11006915

    Arrange the following:
    H–H, D–D and F–F in order of increasing bond dissociation enthalpy.

    Solution
    Bond dissociation enthalpy. The order of increasing bond dissociation enthalpy is:
    F-F<H-H<D-D
    Reason: Since D has a smaller size than H, therefore D-D bond has the highest bond dissociation enthalpy followed by H – H. On the other hand, F – F bond has minimum dissociation enthalpy because of repulsion between lone pairs of F and bond pair.


    Hence the bond dissociation enthalpy increases in the order F-F<H-H<D-D
    Question 103
    CBSEENCH11006916

    Arrange the following:

    NaH, MgH2 and H2O in order of increasing reducing property.

    Solution

    Reducing property. The order of increasing reducing character is:
    H2O < MgH2 < NaH
    Reason: NaH being an ionic hydride, therefore it is a powerful reducing agent. On the other hand, both MgH2 and H2O are covalent hydrides, but the bond dissociation energy of H2O is more than that of MgH2. Hence the reducing character increases in the order:
    H2O < MgH2 < NaH

    Question 104
    CBSEENCH11006917

    Describe the industrial uses of hydrogen which depend on:
    (i) the heat liberated when it burns,
    (ii) its ability to react with vegetable oil in the presence of catalyst,
    (iii) its ability to unite with nitrogen.

    Solution

    (i) When hydrogen is burnt in oxygen, heat is liberated. This heat is used in cutting as well as welding of metals. The apparatus in which heat is produced is called a oxy-hydrogen torch.
    (ii) When dihydrogen is passed through vegetable oil at 8-10 atmospheric pressure and a temperature of 470 K.,vanaspati ghee (solid fat) is produced. The process is called hydrogenation or hardening of oils.
    Vegetable space oil space space plus space straight H subscript 2 space space space rightwards arrow from 400 space straight K to Under space pressure of space Vanaspati space ghee left parenthesis solid space fat right parenthesis
    (iii) Dihydrogen combines with dinitrogen at 770 K and a pressure of 400-600 atmospheres in the presence of finely divided iron containing molybdenum, ammonia is produced. This is called Haber’s process for the manufacture of ammonia.
    straight N subscript 2 left parenthesis straight g right parenthesis space plus space 3 straight H left parenthesis straight g right parenthesis space space rightwards arrow from Fe divided by Mo to 770 space straight K of space 2 NH subscript 3 left parenthesis straight g right parenthesis

    Question 105
    CBSEENCH11006918

    How does the atomic hydrogen or oxy-hydrogen torch function for cutting and welding purposes? Explain.

    Solution

    Atomic hydrogen is formed by passing dihydrogen gas through electric are struck between two hydrogen two tungsten electrodes, when dihydrogen molecules dissociate into H-atoms. 
    straight H subscript 2 left parenthesis straight g right parenthesis space space rightwards arrow with 3270 space straight K on top space 2 straight H left parenthesis straight g right parenthesis semicolon space space increment straight H space equals space 435.9 space kJ
    The life period of atomic hydrogen is 0.3 sec. Consequently, it returns to molecular form (H2) liberating a tremendous amount of energy which is used for cutting and welding purposes in the form of atomic hydrogen. 

    Question 106
    CBSEENCH11006919

    Mention some important uses of dihydrogen ?

    Solution

    It is used:
    (i) in filling toy balloons and airships.
    (ii) in the hydrogenation of oils to get vanaspati ghee.
    (iii) in the manufacture of ammonia, methyl alcohol, water gas and fertilisers.
    (iv) in oxy-hydrogen torch for welding purposes
    (v) as a reducing agent in laboratory and industry.

    Question 107
    CBSEENCH11006920

    What is understood by ‘Hydrogen economy.’

    Solution

    Hydrogen is required for the synthesis of a number of industrial products and thus, affects the economy of a country. For example:
    (i) Synthesis of ammonia: A mixture ofN2 and H2 in the ratio of 1:3 compressed to 200 atmospheres and heated to 673 K in the presence of a catalyst is used for the manufacture of ammonia in Haber's process.
    straight N subscript 2 plus space 3 straight H subscript 2 space rightwards harpoon over leftwards harpoon from Fe divided by Mo to 673 straight K divided by 200 space atm of 2 NH subscript 3
    (ii) Hydrogenation of oils: Hydrogen is used in the hydrogenation of edible oils (unsaturated in nature) to form solid fats for the production of vegetable ghee.
    Vegetable space oil space space plus space straight H subscript 2 space space rightwards arrow with Under space pressure on top space stack Vanaspati space ghee with left parenthesis solid space fat right parenthesis below
    (iii) Manufacture of methyl alcohol: Water gas enriched with H2 is compressed to 200 atmospheres and is then passed over catalyst mixture of ZnO and Cr2O3 at 573K to form methyl alcohol.
       stack CO plus straight H subscript 2 with left parenthesis Water space gas right parenthesis below plus straight H subscript 2 space rightwards arrow from ZnO divided by Cr subscript 2 straight O subscript 3 to 573 space straight K space Cr subscript 2 straight O subscript 3 of space stack CH subscript 3 OH with Methyl space alcohol below
    (iv) Oxy-hydrogen flame. When hydrogen is burnt in oxygen heat is liberated. This heat is used in cutting as well as welding of metals. The apparatus in which heat is produced is called an oxy-hydrogen torch. Atomic hydrogen torch used for the same purpose employs atomic hydrogen.
    (v) Synthetic petrol: Hydrogen is used as a constituent of synthetic petrol. It is formed by, passing hydrogen into a paste of powdered coal in crude oil by using a suitable catalyst.

    Question 108
    CBSEENCH11006921

    How do you expect the metallic hydrides to be useful for hydrogen storage? Explain.

    Solution
    In metallic hydrides, hydrogen is absorbed as H- atoms. Due to the inclusion of H atoms, the metal lattice distorts and expands and thus becomes less stable. On heating, metallic hydride decomposes to give hydrogen and very finely divided metal. The liberated hydrogen gas can be used as a fuel. Thus transition metals (eg Pd, Pt) or their alloys can be used as storage media and transport hydrogen to be used as a fuel. This is called hydrogen economy. 
    Question 109
    CBSEENCH11006922

    Give reason for the fact that liquid hydrogen is used as a fuel.

    Solution

    Using H2 as a fuel has two major advantages:
    (i) Heat of combustion of H2 is by far the largest, i.e. 115 megajoules per kilogram (MJ/kg):
    (ii) Exhaust is free from pollutants.
    The most effective means of storing hydrogen is in the liquid form. The liquid H2 is widely used as a rocket fuel since it gives higher thrusts than most of the other fuels. The range of supersonic aircraft could be increased if the aircraft used liquid H2 as a fuel. Further hypersonic aircraft would also become possible if liquid H2 is used as a fuel.

    Question 110
    CBSEENCH11006923

    Discuss the structure of H2O molecule. 

    Solution
    In H2O, the oxygen is sp3 hybridised and hence has four sp3 hybrid orbitals. Two of these sp3 hybrid orbitals are half filled and hence overlap with 1s-orbitals of hydrogen to form two O-H bonds. The other two sp3 hybrid orbitals contain a lone pair of electrons each. Due to the presence of four pairs of electrons (two bond pairs and two lone pairs) around the central oxygen atom, the geometry of the molecule is expected to be tetrahedral and ZHOH bond angle should be 109°– 28'. But actually ∠HOH bond angle is 104 . 5°. This is because lone pair-lone-pair repulsions are greater than lone-pair-bond-pair repulsion which in turn are greater than bond pair-bond pair repulsions. As a result ∠HOH bond angle in water is slightly lower than the regular tetrahedron angle (109°–28'). It is 104.5° as shown.

    The H2O molecule is of polar nature because of its bent geometry i.e. V-shaped geometry. It has a dipole moment of 1.84D.
    Question 111
    CBSEENCH11006924

    Draw the structure of common form of ice.
    Or
    Discuss hydrogen bonding in water and ice. 
    Or
    Why does ice float on water?

    Solution
    In the liquid state, H2O molecules are held together by intermolecular hydrogen bonds. Each oxygen atom can form two H-bonds using each of its two lone pairs of electrons. In other words, each water molecule is generally H-bonded to four other water molecules.


    Thus, in the liquid state, H2O exists as an associated liquid.
    We know that in ice, each oxygen atom is surrounded by four hydrogen atoms in such a way that two hydrogen atoms are linked to an oxygen atom by covalent bonds whereas other two hydrogen atoms are linked by hydrogen bonds. In ice (solid state), a water molecule is associated with four other water molecules through hydrogen bonding in a tetrahedral manner. This gives rise to open cage-like structure which prevents the close packing of molecules (lower density). When ice absorbs heat and melts to form water, hydrogen bonds break and close packing of water molecules take place. Due to this close packing, the density of water is higher than that of ice and ice floats over water.

    Question 112
    CBSEENCH11006925

    Among NH3, H2O and HF, which would you expect to have the highest magnitude of hydrogen bonding and why ?

    Solution
    All these molecules exhibit hydrogen bonding due to the presence of highly electronegative atom N, O and F.

    Electronegativity of N, O F increases as N < O < F.
    Therefore strength of hydrogen bond also increases as
    N - H ... N < O - H ... O < F - H ... F
    In other words, the magnitude of the +ve charge on hydrogen and -ve charge on F is highest and hence electrostatic attraction or hydrogen bonding is strongest in H – F.

    Question 113
    CBSEENCH11006926

    Would you expect the hydrides of N, O and F to have lower boiling points than the hydrides of their subsequent group members? Give reasons. 

    Solution
    The boiling points of NH3, H2O and HF are expected to be lower than those of the subsequent group member hydrides on the basis of molecular masses. But boiling points of NH3, H2O and HF will be higher than the hydrides of their subsequent group members. This is because of higher electronegativity of N, O and F. As a result, these exhibit hydrogen bonding in their hydrides.
    Question 114
    CBSEENCH11006927
    Question 115
    CBSEENCH11006928
    Question 118
    CBSEENCH11006931

    Consider the reaction of water with F2 and suggest, in terms of oxidation and reduction which species are oxidised/ reduced. 

    Solution
    The reactions of water with F2 are as indicated below:
    stack 2 straight F subscript 2 left parenthesis straight g right parenthesis with left parenthesis Oxidant right parenthesis below space plus space stack 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis with left parenthesis Reductant right parenthesis below space space rightwards arrow space space space straight O subscript 2 left parenthesis straight g right parenthesis space plus space 4 straight H to the power of plus left parenthesis aq right parenthesis space plus space 4 straight F to the power of minus left parenthesis aq right parenthesis
or
stack 3 straight F subscript 2 left parenthesis straight g right parenthesis with left parenthesis Oxidant right parenthesis below space plus space stack 3 straight H subscript 2 straight O left parenthesis straight l right parenthesis with left parenthesis Reductant right parenthesis below space rightwards arrow space space straight O subscript 3 left parenthesis straight g right parenthesis space plus space 6 straight H to the power of plus left parenthesis aq right parenthesis space plus space 6 straight F to the power of minus left parenthesis aq right parenthesis
    In these reactions, water acts as a reductant and hence itself gets oxidised to either O2 or O3 while F2 acts as an oxidant and is itself reduced to F- ion. 
    Question 119
    CBSEENCH11006932

    What happens when:
    (i) Steam is passed over red hot coke at 1273 K
    (ii) Water is added to Cl2O7
    (iii) Water is added to bismuth chloride
    (iv) Water is added to silicon tetrachloride?

    Solution

    (i) Water gas is formed
    straight C left parenthesis straight s right parenthesis space plus space space straight H subscript 2 straight O left parenthesis straight g right parenthesis space space space rightwards arrow with space 1273 space straight K on top space stack CO left parenthesis straight g right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis with water space gas below
    (ii) Perchloric acid is formed
                       Cl subscript 2 straight O subscript 7 space plus space straight H subscript 2 straight O space space rightwards arrow space space HClO subscript 4
    (iii) Bismuth oxychloride is formed
               BiCl subscript 3 space plus space straight H subscript 2 straight O space space rightwards arrow space space space space BiOCl with Bismuth space oxychloride below space plus space 2 HCl
    (iv) Silicon dioxide is formed. 
                      SiCl subscript 4 space plus space 2 straight H subscript 2 straight O space space rightwards arrow space space space SiO subscript 2 space plus space 4 HCl

    Sponsor Area

    Question 120
    CBSEENCH11006933
    Question 121
    CBSEENCH11006934

    Write chemical reactions to show amphoteric nature of water.

    Solution
    The following reactions of water show its amphoteric nature i.e. water behaves both as an acid as well as the base.
    (i) Water acting as an acid. 
    stack straight H subscript 2 straight O left parenthesis straight l right parenthesis with Acid below space plus space stack NH subscript 3 with Base below space space space rightwards arrow space space space NH subscript 4 superscript plus left parenthesis aq right parenthesis space plus space OH to the power of minus left parenthesis aq right parenthesis
    stack straight H subscript 2 straight O left parenthesis straight l right parenthesis with Acid below space plus space stack CO subscript 3 superscript 2 minus end superscript left parenthesis aq right parenthesis with Base below space space rightwards arrow space space space HCO subscript 3 superscript minus left parenthesis aq right parenthesis space plus space OH to the power of minus left parenthesis aq right parenthesis
    (ii) Water acting as a base.
        stack straight H subscript 2 straight O left parenthesis straight l right parenthesis with Base below space plus space stack HCl left parenthesis aq right parenthesis with Acid below space space rightwards arrow space space space straight H subscript 3 straight O to the power of plus left parenthesis aq right parenthesis space plus space Cl to the power of minus left parenthesis aq right parenthesis
stack straight H subscript 2 straight O left parenthesis straight l right parenthesis with Base below space plus space stack CH subscript 3 COOH left parenthesis aq right parenthesis with Acid below space space rightwards arrow space space space straight H subscript 3 straight O to the power of plus left parenthesis aq right parenthesis space plus space CH subscript 3 COO to the power of minus left parenthesis aq right parenthesis

    Question 122
    CBSEENCH11006935

    Give two chemical reactions in which water acts as a reducing agent.

    Solution

    With strongly active non-metals such as fluorine or chlorine, water acts as weak reductant and thus releases dioxygen. 
              stack 2 straight F subscript 2 left parenthesis straight g right parenthesis with oxidant below space plus space stack 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis with reductant below space space space rightwards arrow space space space space 4 HF left parenthesis aq right parenthesis space plus space straight O subscript 2 left parenthesis straight g right parenthesis
stack 2 Cl subscript 2 left parenthesis straight g right parenthesis with oxidant below space plus space stack 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis with reductant below space space rightwards arrow space space space space 4 HCl left parenthesis aq right parenthesis space plus space straight O subscript 2 left parenthesis straight g right parenthesis

    Question 123
    CBSEENCH11006936

    Give two points to distinguish between fresh tap water and distilled water.

    Solution

    (i) Fresh tap water has a specific taste due to the presence of dissolved salts in it while distilled water has a flat taste.

    ii) Tap water contains chloride ions due to the presence of dissolved chlorine. Hence tap water gives the white precipitate with silver nitrate solution. Distilled water does not give a white precipitate with silver nitrate solution indicating the absence of chloride ions.

    Question 124
    CBSEENCH11006937

    Water has some air dissolved in it. What is its significance?

    Solution

    Air dissolved in water has the following advantages:
    (i) Oxygen present in water is very useful for giving life to fish and other sea animals in the water.
    (ii) Carbondioxide dissolved in water is very useful for carrying out photosynthesis in plants.
    (iii) Carbon dioxide dissolved in water reacts with calcium carbonate present in marble rocks to produce calcium bicarbonate which is soluble.
    CaCO subscript 3 space plus space straight H subscript 2 straight O space space plus space CO subscript 2 space space space rightwards arrow space space space space Ca left parenthesis HCO subscript 3 right parenthesis subscript 2
    Marine organisms fulfil their requirement of calcium carbonate from calcium bicarbonate.

    Question 125
    CBSEENCH11006938

    What properties of water make it useful as a solvent? What type of compounds can it: (i) dissolve and (ii) hydrolyse?

    Solution

    Water is a universal or ideal solvent because it has high dielectric constant (79.39C2/Nm2) and high dipole moment (μ = 1 . 84 D). Due to these properties, water dissolves most of the inorganic compounds and many covalent compounds. The solubility of ionic compounds in water is due to ion-dipole interaction or solvation of ions. Covalent compounds (such as alcohols, amines, urea, glucose sugar etc.) dissolve in water because such compounds form intermolecular hydrogen bonds with water.
    Water can also hydrolyse many oxides, hydrides, carbides, nitrides, phosphides and other salts. In such reactions, H+ and OH- ions of water interact with anions and cations respectively to form acid or base or both.
    CaO left parenthesis straight s right parenthesis space space plus space straight H subscript 2 straight O left parenthesis straight l right parenthesis space space rightwards arrow space space space Ca left parenthesis OH right parenthesis subscript 2 left parenthesis aq right parenthesis
SO subscript 2 left parenthesis straight g right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight l right parenthesis space space space rightwards arrow space space space straight H subscript 2 SO subscript 4 left parenthesis aq right parenthesis
CaC subscript 2 left parenthesis straight s right parenthesis space plus space 2 straight H subscript 2 left parenthesis straight l right parenthesis space rightwards arrow space space space Ca left parenthesis OH right parenthesis subscript 2 left parenthesis aq right parenthesis space plus space HC space identical to space space space CH left parenthesis straight g right parenthesis
CaH subscript 2 left parenthesis straight s right parenthesis space plus space 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis space space rightwards arrow space space Ca left parenthesis OH right parenthesis subscript 2 left parenthesis aq right parenthesis space plus space 2 straight H subscript 2 left parenthesis aq right parenthesis

    Question 126
    CBSEENCH11006939

    Why is water an excellent solvent for ionic and polar compounds?

    Solution
    ‘Like dissolves like’ is the general rule of solubility. It means polar substances dissolve in polar solvents and non-polar substances dissolve in non-polar solvents. Water is a highly polar solvent and interacts with polar or ionic substances effectively with the liberation of a considerable amount of energy i.e. it is responsible for breaking the crystal lattice and hence explains the solubility. also, A high value of dielectric constant (78.39 C2/Nm2) and dipole moment make water a universal solvent. Water has the ability to dissolve ionic compounds in it. Because of the ion-dipole interaction.
    Question 127
    CBSEENCH11006940

    What do you understand by the term ‘auto-protolysis’ of water? What is its significance?

    Solution
    Auto-protolysis of water. Auto-protolysis of water means its self-ionisation. Self-ionisation of water can be represented as:
    stack straight H subscript 2 straight O left parenthesis straight l right parenthesis with Acid subscript 1 below space plus space stack straight H subscript 2 straight O left parenthesis straight l right parenthesis with Base subscript 2 below space space space leftwards harpoon over rightwards harpoon space space stack straight H subscript 3 straight O to the power of plus with Acid subscript 2 below space plus space stack OH to the power of minus left parenthesis aq right parenthesis with Base subscript 1 below
    The significance of auto-protolysis. water shows its amphoteric nature due to autoprotolysis i.e. water reacts with both acids and bases.
     Water acting as an acid:
       stack straight H subscript 2 straight O left parenthesis straight l right parenthesis with Acid subscript 1 below space plus space stack NH subscript 3 left parenthesis aq right parenthesis with Base subscript 2 below space space space rightwards arrow space space space space stack straight N to the power of plus straight H subscript 4 left parenthesis aq right parenthesis with Acid subscript 2 below space plus space stack OH to the power of minus left parenthesis aq right parenthesis with Base subscript 1 below
    Water acting as a base:
    straight H subscript 2 straight O left parenthesis straight l right parenthesis space plus space CH subscript 3 COOH left parenthesis aq right parenthesis space space rightwards arrow space space space straight H subscript 3 straight O to the power of plus left parenthesis straight l right parenthesis space plus space CH subscript 3 COO to the power of minus
left parenthesis aq right parenthesis
Base subscript 1 space space space space space Acid subscript 2 space space space space space space space space space space space space space space space space space space space space space space space Acid subscript 1 space space space space space space space space space space space space Base subscript 2 space space space space space space space space space space space space space space space space
    Question 128
    CBSEENCH11006941

    Describe the usefulness of water in the biosphere and biological system.

    Solution

    (i) The high heat of vaporisation and heat capacity of water are responsible for moderation of the climate and body temperature of living beings.
    (ii) High specific heat capacity of water enables it to absorb heat of various biochemical and physiological reactions, going on inside the body, with the minimum rise of temperature.
    (iii) Water has a high dipole moment (μ = 1.84D). So, water is an ideal medium for the dissolution of a wide variety of compounds.
    (iv) Water is an ideal solvent for transportation of minerals and other nutrients for plant and animal metabolism.
    (v) Water is an essential component for the photosynthesis in plants which releases O2 in the atmosphere.

    Question 129
    CBSEENCH11006942

    What are the ways in which water molecules are bound to an anhydrous salt to form a hydrate?

    Solution

    Water combines with many salts during crystallisation to form hydrates. For example, CuSO4.5H2O; FeSO4.7H2O ; Na2SO4, 10H2CO etc.

    This water in combination with ionic salts is called water of crystallisation and such crystals are called hydrated salts or simply hydrates. Water may be bonded to an anhydrous salt in three ways:
    (i) Water molecules are coordinated to the central metal ion in complex ions such as [Li(H2O)6]+Cl-.
    (ii) Water may be bonded by hydrogen bonds in certain oxygen-containing anions. For example, in CuSO4.5H2O four water molecules are coordinated to a central Cu2+ ion while the fifth water molecule is linked to sulphate group through hydrogen bonding.
    (iii) Water molecules may occupy voids in the crystal lattice. For example, BaCl2.2H2O.

    Question 130
    CBSEENCH11006943

    How many hydrogen - bonded water molecule(s) are associated in CuSO4.5H2O? 

    Solution

    Only one molecule of water, which is outside the bracket (coordinate sphere), is hydrogen bonded. The other four molecules of water are coordinated.
    open square brackets Cu left parenthesis straight H subscript 2 straight O right parenthesis subscript 4 close square brackets to the power of 2 plus end exponent space SO subscript 4 superscript 2 minus end superscript. space straight H subscript 2 straight O.

    Question 131
    CBSEENCH11006944

    Do you expect different products in solution when aluminium (III) chloride and potassium chloride are treated separately with:
    (i) normal water  (ii) acidifed water and  (iii) alkaline water?

    Solution
    Potassium chloride (KCl) Aluminium (III) chloride (AlCl3)
    1. Normal water. KCl being a salt of strong base and strong acid does not undergo hydrolysis in normal water but simply dissociates to give K+ (aq) and Cl- (aq) ions. 
    KCl left parenthesis straight s right parenthesis space rightwards arrow with Water on top space straight K to the power of plus left parenthesis aq right parenthesis space plus space Cl to the power of minus left parenthesis aq right parenthesis
    1. Normal water. AlCl3 being a salt of weak base and strong acid, it undergoes hydrolysis in normal water.
    AlCl subscript 3 space plus space 3 straight H subscript 2 straight O left parenthesis straight l right parenthesis space rightwards arrow space space Al left parenthesis OH right parenthesis subscript 3 space plus space 3 straight H to the power of plus left parenthesis aq right parenthesis space plus space 3 Cl to the power of minus left parenthesis aq right parenthesis
    2. Acidified water and alkaline water. Since aqueous solution of KCl is neutral, therefore in acidified water and alkaline water, the ions will remain as such i.e. do not react further. 2. In acidic water. H+ ions react with Al(OH)3 to form Al3+ (aq) ions and H2O. Hence in acidic water, AlCl3 exists as Al3+(aq) and Cl-(aq) ions. 
    AlCl subscript 3 left parenthesis straight s right parenthesis space space rightwards arrow from Water to Acidified of space Al to the power of 3 plus end exponent left parenthesis aq right parenthesis space plus space 3 Cl to the power of minus left parenthesis aq right parenthesis
      3. In alkaline water. Al left parenthesis OH right parenthesis subscript 3 reacts to form soluble tetrahydroxaluminate complex or meta-aluminate ion. 
    Al left parenthesis OH right parenthesis subscript 3 left parenthesis straight s right parenthesis space plus space OH to the power of minus left parenthesis aq right parenthesis space space rightwards arrow space space open square brackets Al left parenthesis OH right parenthesis subscript 4 close square brackets to the power of minus left parenthesis aq right parenthesis
space space space space or
Al left parenthesis OH right parenthesis subscript 3 left parenthesis straight s right parenthesis space plus space OH to the power of minus left parenthesis aq right parenthesis space space space space rightwards arrow space space AlO subscript 2 superscript minus left parenthesis aq right parenthesis space plus space 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis
    Question 132
    CBSEENCH11006945

    What is hard and soft water?

    Solution

    Hard water: A sample of water which does not produce lather with soap readily is called hard water. The hardness of water is due to the presence of bicarbonates, chlorides and sulphates of calcium and magnesium dissolved in water, e.g. sea water, river water, lake water and well water.
    Soft water. A sample of water which produces lather with soap readily is called soft water. This type of water either does not contain or contains negligible amounts of dissolved salts in it. For example, rain water distilled water and demineralised water.

    Question 133
    CBSEENCH11006946

    What causes the temporary and permanent hardness of water?
    Or
    Distinguish clearly between temporary hardness and permanent hardness.
    Or
    What is hardness of water due to? What are its types?
     

    Solution

    The hardness of water is due to the presence of bicarbonates, chlorides and sulphates of calcium and magnesium dissolved in water. It is of two types:
    (i) Temporary hardness: It is due to the presence of bicarbonates of calcium, magnesium and iron dissolved in water, it is described as temporary hardness because it is easily removed by simply boiling the water. This type of hardness is also known as carbonate hardness.
    (ii) Permanent hardness: It is due to the presence of chlorides and sulphates of calcium, magnesium and iron in the water. This type of hardness is called permanent hardness since it cannot be removed simply by boiling the water. It is also called non-carbonate hardness.
    CaO with Quick space lime below space plus space straight H subscript 2 straight O space space rightwards arrow space space space space stack Ca left parenthesis OH right parenthesis subscript 2 with Slaked space lime below
    Ca left parenthesis HCO subscript 3 right parenthesis subscript 2 space plus space Ca left parenthesis OH right parenthesis subscript 2 space space rightwards arrow space space 2 CaCO subscript 3 space downwards arrow space plus space 2 straight H subscript 2 straight O
Mg left parenthesis HCO subscript 3 right parenthesis subscript 2 space plus space Ca left parenthesis OH right parenthesis subscript 2 space space rightwards arrow space space CaCO subscript 3 space downwards arrow space plus space MgCO subscript 3 downwards arrow space plus space 2 straight H subscript 2 straight O
    Excess of lime must be avoided because a solution of slaked lime shows hardness again due to absorption of CO2 from the air. 

    Question 134
    CBSEENCH11006947

    Why does hard water not form lather with soap?

    Solution

    Soap is sodium or potassium salt of certain long chain fatty acids such as stearic acid, palmitic acid, oleic acid etc. When hard water is treated with soap solution, Ca2+and Mg2+ ions present in hard water react with the anions of fatty acids present in the soap to form a scum (curdy white precipitate).
    stack Ca to the power of 2 plus end exponent left parenthesis aq right parenthesis with left parenthesis Hard space water right parenthesis below space plus space stack 2 straight C subscript 17 straight H subscript 35 COO to the power of minus left parenthesis aq right parenthesis with Stearate space ion left parenthesis Soap right parenthesis below space space rightwards arrow space space space stack left parenthesis straight C subscript 17 straight H subscript 35 COO right parenthesis subscript 2 space Ca with Calcium space stearate space ppt. space left parenthesis scum right parenthesis below downwards arrow
Mg to the power of 2 plus end exponent left parenthesis aq right parenthesis space plus space 2 straight C subscript 17 straight H subscript 35 COO to the power of minus left parenthesis aq right parenthesis space rightwards arrow space space space stack left parenthesis straight C subscript 17 straight H subscript 35 COO right parenthesis subscript 2 space Mg with Magnesium space stearate space ppt. space left parenthesis scum right parenthesis below downwards arrow space
space space space space space space space space space space space space space space space space space
    Soap will not produce a lather with hard water until all the calcium and magnesium ions have been precipitated as stearates. Hard water thus wastes soap.

    Question 135
    CBSEENCH11006948

    What are different methods used for softening of hard water?

    Solution

    The hardness of water is of two types:
    i) Temporary hardness
    ii) permanent hardness

    Temporary hardness:
    Temporary hardness is due to the presence of magnesium and calcium hydrogen-carbonates. It can be removed by;
    Boiling: During boiling, the soluble Mg(HCO3)2 is converted into insoluble Mg(OH)and Ca(HCO3)2 is changed to insoluble CaCO3. It is because of high solubility product of Mg(OH)2 as compared to that of MgCO3, that Mg(OH)2 is precipitated. These precipitates can be removed by filtration. Filtrate thus obtained will be soft water.
    bold Mg bold left parenthesis bold HCO subscript bold 3 bold right parenthesis subscript bold 2 bold space bold rightwards arrow with bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold increment bold space bold space bold space bold space bold space bold space bold space on top bold Mg bold left parenthesis bold OH bold right parenthesis subscript bold 2 bold space bold plus bold 2 bold CO subscript bold 2

    It is due to the presence of soluble salts of magnesium and calcium in the form of chlorides and sulphates in water. Permanent hardness is not removed by boiling. It can be removed by the following method:
    Treatment with washing soda; Washing soda reacts with soluble calcium and magnesium chlorides and sulphate in hard water to form insoluble carbonates.
    MCl2 +Na2CO3 --> MCO3 +2NaCl
    (M =Mg, Ca )

     

    Question 136
    CBSEENCH11006949

    What is ‘demineralised water’ and how can it be obtained?

    Solution
    Water which does not contain cations and anions is called demineralised water. It is obtained by passing hard water first through cation exchange resin and then through anion exchange resin.

    During the cation exchange process, H+ exchange for Na+, Mg2+, Ca2+ and other cations present in water.
    bold 2 bold RH subscript bold left parenthesis bold s bold right parenthesis end subscript bold space bold plus bold M subscript bold left parenthesis bold aq bold right parenthesis end subscript superscript bold 2 bold plus end superscript bold rightwards arrow over leftwards arrow bold space bold MR subscript bold left parenthesis bold s bold right parenthesis end subscript bold space bold plus bold 2 bold H subscript bold left parenthesis bold aq bold right parenthesis end subscript superscript bold plus bold. bold. bold. bold 1

    In anion exchange process OH- exchange for anions such as Cl-, HCO3- etc.present in water.
    bold RNH subscript bold 2 bold space bold left parenthesis bold s bold right parenthesis end subscript bold space bold plus bold H subscript bold 2 bold O subscript bold left parenthesis bold l bold right parenthesis end subscript bold space bold rightwards arrow over leftwards arrow bold RNH subscript bold 3 superscript bold plus bold. bold OH to the power of bold minus
bold RNH subscript bold 3 superscript bold plus bold. bold OH to the power of bold minus bold left parenthesis bold s bold right parenthesis bold plus bold X subscript bold left parenthesis bold aq bold right parenthesis end subscript superscript bold minus bold space bold rightwards arrow over leftwards arrow bold space bold RNH subscript bold 3 superscript bold plus bold. bold X to the power of bold minus bold space bold plus bold space bold OH to the power of bold minus bold left parenthesis bold aq bold right parenthesis bold space bold space bold space bold. bold. bold. bold. bold 2

    ions liberated in reaction 1 and 2 neturlaize each other, thus forming water.
    bold H to the power of bold plus bold space bold plus bold OH to the power of bold minus bold space bold rightwards harpoon over leftwards harpoon bold space bold H subscript bold 2 bold O



    Question 137
    CBSEENCH11006950

    Discuss the principle and method of softening of hard water by synthetic ion-exchange resins.
    Or
    What do you mean by synthetic ion-exchange resins?

    Solution

    Synthetic ion-exchange resins are of two types:
    (i) Cation exchange resins. These are either carboxylic acids or sulphonic acids having the general formula, RCOOH or R-SO3H where R represents the giant hydrocarbon framework. These resins exchange their H+ ions with Ca2+ and Mg2+ ions present in hard water.
    stack 2 straight H to the power of plus space minus space Resin with Cation space exchange below space plus space stack stack Ca to the power of 2 plus end exponent with left parenthesis in space hard space water right parenthesis below with resin below space space rightwards arrow space space space space stack Ca left parenthesis resin right parenthesis subscript 2 space with Exhausted space resin below plus space 2 straight H to the power of plus
stack 2 straight H to the power of plus space minus space Resin with Cation space exchange space below space plus space space stack Mg to the power of 2 plus end exponent with left parenthesis in space hard space water right parenthesis below space space space rightwards arrow space space space space space stack Mg left parenthesis resin right parenthesis subscript 2 with Exhausted space resin below space plus space 2 straight H to the power of plus
    (ii) Anion exchange resin. These are substituted ammonium hydrides the general formula. 
    straight R space minus space straight N with plus on top straight H subscript 3 OH to the power of minus where space straight R space denotes space the space giant space hydrocarbon space frame space
work. space T hese space resins space exchange space their space OH to the power of minus space ions space with space
Cl to the power of minus space and space SO subscript 4 superscript 2 minus end superscript space ion space present space in space hard space water.
space
stack HO to the power of minus space minus space resin with Anion space exchange space below space space plus stack space Cl to the power of minus with left parenthesis in space hard space water right parenthesis below space rightwards arrow space stack Cl to the power of minus space minus space resin with Exhausted space resin below space plus space stack OH to the power of minus with resin below
    2 HO to the power of minus space minus space resin space plus space SO subscript 4 superscript 2 minus end superscript space space space rightwards arrow space space space SO subscript 4 superscript 2 minus end superscript left parenthesis resin right parenthesis subscript 2 space plus space 2 OH to the power of minus
Anion space exchange space space left parenthesis in space hard space water right parenthesis space resin space space Exhausted space resin space
    Now H+ ion produced from cation exchange resins and OH- ions produced from anion exchange resins combine to form water.

    Question 138
    CBSEENCH11006951

    How will you prepare a sample of temporary hard water from lime water? Write equation for the reactions involved.

    Solution

    Temporary hard water can be obtained by passing carbon dioxide in excess through lime water when calcium carbonate is first formed. It changes to soluble calcium bicarbonate by passing more carbon dioxide which imparts temporary hardness to water. 
      CO subscript 2 space plus space stack Ca left parenthesis OH right parenthesis subscript 2 with Lime space water below space space rightwards arrow space space space space space space stack CaCO subscript 3 with Calcium space carbonate below space plus space straight H subscript 2 straight O
CaCO subscript 3 space plus space CO subscript 2 space plus space straight H subscript 2 straight O space space rightwards arrow space space space stack Ca left parenthesis HCO subscript 3 right parenthesis subscript 2 with Calcium space bicarbonate below

    Question 139
    CBSEENCH11006952

    When hard water is boiled in electric kettle, a white scale gets formed inside the kettle. How is this scale formed? What is its harm?

    Solution
    When hard water is boiled in an electric kettle, a white scale is formed inside the kettle. It is due to the formation of calcium and magnesium carbonates.
    The name of the clear solution is lime water.
    Ca left parenthesis HCO subscript 3 right parenthesis subscript 2 space space rightwards arrow with Heat on top space stack CaCO subscript 3 with left parenthesis Insoluble right parenthesis below space plus space CO subscript 2 space plus space straight H subscript 2 straight O
Mg left parenthesis HCO subscript 3 right parenthesis subscript 2 space rightwards arrow with Heat on top space stack MgCO subscript 3 with Insoluble below space plus space CO subscript 2 space plus space straight H subscript 2 straight O
    As the scale formed is a poor conductor of heat, a lot of heat gets wasted.
    When CO2 is passed through the clear solution, it becomes milky due to the formation of insoluble calcium carbonate but the milkiness soon disappears since soluble calcium carbonate gets formed.
    Question 140
    CBSEENCH11006953

    Sea water cannot be used in boilers. Explain. 

    Solution
    Sea water is a type of hard water and contains soluble salts. It cannot be used in boilers because of the following three main difficulties:
    (i) Formation of scales: The dissolved salts present in sea water deposit a hard crust (boiler scale) on the walls of the boiler. The crust is hard and heat insulating. It makes wastage of fuel. Sometimes the crust breaks at certain place which leads to an accident.
    (ii) Corrosion : The chlorides of calcium and magnesium present in sea water upon boiling undergo hydrolysis to produce HCl.
    MgCl subscript 2 space plus space straight H subscript 2 straight O space space rightwards arrow space space space Mg left parenthesis OH right parenthesis Cl space plus space HCl
    HCl thus formed attacks the metal surface of the boiler and thereby shortens its life. 
    (iii) Foaming: It is the formation of bubbles on the surface of the water in the boiler. This occurs due to the presence of suspended particles in water. It causes wastage of fuels. 
    Question 141
    CBSEENCH11006954
    Question 142
    CBSEENCH11006955

    How is heavy water prepared from neutral water?

    Solution

    Heavy water is the oxide of deuterium (D2O) and is formed from ordinary water by exhaustive electrolysis of water containing 3% NaOH. As a result of repeated electrolysis of ordinary water, protium is liberated at the cathode in preference to deuterium. Consequently, the concentration of heavy water in ordinary water increases. Actually, electrolysis is carried out in different stages. The gases obtained from each stage are separately burnt and water thus formed is returned to the previous stage. At the end of the seventh stage, 99% D2O is obtained. This is subjected to careful fractional distillation. 100% heavy water is obtained.

    Question 143
    CBSEENCH11006956

    What is the importance of heavy water with regard to nuclear power generation?
    Or
    Discuss the importance of heavy water in nuclear reactor.

    Solution
    Heavy water has been used in nuclear reactors. In nuclear reactors, chain reactions occur very fast. In order to slow down the rate of these reactions, heavy water is used as a moderator. Actually, the speed of neutrons is slowed down by passing through heavy water before bringing about fission of uranium.
    Question 144
    CBSEENCH11006957

    Knowing the properties of H2O and D2O, do you think that D2O can be used for drinking purposes? 

    Solution

    Heavy water decomposes more slowly than ordinary water. Thus, it slows down the rates of reactions occurring in human beings, plants and animals, therefore it is injurious to living organisms. Hence heavy water does not support life so well as ordinary water does.

    Question 145
    CBSEENCH11006958

    What is the difference between 'hydrolysis' and 'hydration'?

    Solution
    Hydrolysis. Interaction of H+ and OHions of H2O with the anion and cation of a salt respectively to give the original acid and the original base is called hydrolysis. For example,
    stack Na subscript 2 CO subscript 3 with Salt below space plus space 2 straight H subscript 2 straight O space space rightwards arrow space space space stack 2 NaOH with Base below space space plus stack straight H subscript 2 CO subscript 3 with Acid below
    Mechanism:
          stack Na subscript 2 CO subscript 3 with Salt below space space space rightwards arrow with water on top space 2 Na to the power of plus left parenthesis aq right parenthesis space plus space CO subscript 3 superscript 2 minus end superscript left parenthesis aq right parenthesis
                      2 HOH space space rightwards harpoon over leftwards harpoon space space space stack 2 OH to the power of minus left parenthesis aq with downwards arrow below right parenthesis space plus space stack 2 straight H to the power of plus left parenthesis aq right parenthesis with on space dissolution below
space space space space space space space space space space space space space space space space space space space space 2 NaOH space plus space straight H subscript 2 CO subscript 3
    Hydration: It involves the addition of H2O to ions or molecules to form hydrated ions or hydrated salts. For example,
    stack straight K to the power of plus Cl to the power of minus with Salt below space plus space straight H subscript 2 straight O space space rightwards arrow space space space space straight K to the power of plus left parenthesis aq right parenthesis space plus space Cl to the power of minus left parenthesis aq right parenthesis
stack CuSO subscript 4 with left parenthesis Colourless right parenthesis below space plus space 5 straight H subscript 2 straight O space space rightwards arrow space space stack CuSO subscript 4. with left parenthesis Blue right parenthesis below space 5 straight H subscript 2 straight O
    Question 146
    CBSEENCH11006959

    How is hydrogen peroxide prepared in the laboratory?

    Solution

    Hydrogen peroxide (H2O2) can be prepared in laboratory by any one of the following methods:
    1. From sodium peroxide. By adding a small amount of sodium peroxide to ice cold water.
            

     Na subscript 2 straight O subscript 2 space plus space 2 straight H subscript 2 straight O space space rightwards arrow space space space 2 NaOH space plus space straight H subscript 2 straight O subscript 2
    In place of cold water, dilute sulphuric acid (20%) can also be used. Sodium peroxide in small amounts at a time is added to cold 20% H2SO4.

    Na subscript 2 straight O subscript 2 space plus space straight H subscript 2 SO subscript 4 space space space rightwards arrow space space space Na subscript 2 SO subscript 4 space plus space straight H subscript 2 straight O subscript 2On cooling to 271 K, crystals of hydrated sodium sulphate (Na2SO4.10H2O) separate out. The mother liquor contains about 30% hydrogen peroxide.

    An alternate method can also be employed for the preparation of hydrogen peroxide using phosphoric acid or sodium dihydrogen phosphate in place of sulphuric acid.
           space space space space space Na subscript 2 straight O subscript 2 space plus space straight H subscript 3 PO subscript 4 space space space rightwards arrow space space space space Na subscript 2 HPO subscript 4 space plus space straight H subscript 2 straight O subscript 2
Na subscript 2 straight O subscript 2 space plus space 2 NaH subscript 2 PO subscript 4 space space rightwards arrow space space space 2 Na subscript 2 HPO subscript 4 space plus space straight H subscript 2 straight O subscript 2
    On cooling, crystals of hydrated sodium hydrogen phosphate (Na2HPO4.12H2O) separate out.
    2. From barium peroxide. (i) H2O2 is prepared by the action of hydrated barium peroxide on dilute H2SO4.
    BaO subscript 2. space 8 straight H subscript 2 straight O space plus space stack straight H subscript 2 SO subscript 4 with 20 percent sign below space space rightwards arrow space space space BaSO subscript 4 downwards arrow space plus space stack straight H subscript 2 straight O subscript 2 with White space ppt. below space plus space space 8 straight H subscript 2 straight O
    A thin paste of hydrated peroxide (BaO2.8H2O) is made with ice cold water. It is added very slowly to an ice cold 20% sulphuric acid. Barium sulphate is precipitated and removed by filtration. The filtrate obtained contains about 5% hydrogen peroxide.
    Anhydrous barium peroxide is not used in the above method because barium sulphate forms a protective coating on barium peroxide thereby preventing the further reaction.
    (ii) An improved method for the preparation of hydrogen peroxide is by treating hydrated barium peroxide with phosphoric acid.
    3 BaO subscript 2 space plus space 2 straight H subscript 3 PO subscript 4 space space rightwards arrow space space space stack Ba subscript 3 left parenthesis PO subscript 4 right parenthesis subscript 2 with left parenthesis ppt. right parenthesis below space plus space 3 straight H subscript 2 straight O subscript 2
    Insoluble barium phosphate is filtered off. The filtrate consists of hydrogen peroxide. 
    (iii) BaO2 - Carbonic acid process: Hydrogen peroxide is most conveniently prepared by passing carbon dioxide gas into a suspension of barium peroxide in ice-cold distilled water.
    BaO subscript 2 space plus space straight H subscript 2 straight O space plus space CO subscript 2 space space rightwards arrow space space space BaCO subscript 3 space downwards arrow space plus space straight H subscript 2 straight O subscript 2
    Barium carbonate precipitate is removed by filtration. The filtrate obtained is a dilute solution of hydrogen peroxide.

    Question 147
    CBSEENCH11006960

    How is hydrogen peroxide manufactured?


    Solution

    Hydrogen peroxide can be prepared on a large scale by any of the following methods:
    1. Electrolytic process. In this process, the electrolysis of 50% sulphuric acid is carried out at low temperature using platinum electrodes and a current of high density. Persulphuric acid is formed.
    2 straight H subscript 2 SO subscript 4 space space rightwards harpoon over leftwards harpoon space space space 2 straight H to the power of plus space plus space 2 HSO subscript 4 superscript minus
At space cathode colon space space 2 straight H to the power of plus space plus space 2 straight e to the power of minus space space space rightwards arrow space space space straight H subscript 2
At space anode colon space space space 2 HSO subscript 4 superscript minus space space rightwards arrow space space space space 2 HSO subscript 4 space plus space 2 straight e to the power of minus
space space space space space space space space space space space space space space space space 2 HSO subscript 4 space space rightwards arrow space space space space stack straight H subscript 2 straight S subscript 2 straight O subscript 8 with Persulphric space acid below space space space space space space space space space space space
    Persulphuric acid is distilled. Hydrolysis occurs and a distillate containing about 30% H2O2 is obtained.
    straight H subscript 2 straight S subscript 2 straight O subscript 8 space space plus 2 straight H subscript 2 straight O space rightwards arrow space space space space 2 straight H subscript 2 SO subscript 4 space plus space straight H subscript 2 straight O subscript 2
    Modification. Recently, it has been observed that if instead of 50% H2SO4, an equimolar mixture of H2SO4 and ammonium sulphate is electrolyzed, a more concentrated solution of H2O2 is obtained.
    left parenthesis NH subscript 4 right parenthesis subscript 2 SO subscript 4 space plus space straight H subscript 2 SO subscript 4 space space rightwards arrow space space space stack 2 NH subscript 4 HSO subscript 4 with Ammonium space hydrogen space sulphate below
                      NH subscript 4 HSO subscript 4 space space rightwards arrow space space space NH subscript 4 SO subscript 4 superscript minus space plus space straight H to the power of plus
    At anode:
              2 NH subscript 4 SO subscript 4 superscript minus space rightwards arrow space space space stack left parenthesis NH subscript 4 right parenthesis subscript 2 straight S subscript 2 straight O subscript 8 space plus space 2 straight e to the power of minus with Ammonium space persulphate below
    At cathode: 2 straight H plus 2 straight e to the power of minus space rightwards arrow space space straight H subscript 2
     Ammonium persulphate formed around anode is withdrawn and heated at 43 mm pressure when its hydrolysis occurs forming hydrogen peroxide.
    left parenthesis NH subscript 4 right parenthesis subscript 2 straight S subscript 2 straight O subscript 8 space plus space 2 straight H subscript 2 straight O space space rightwards arrow space space space 2 NH subscript 4 HSO subscript 4 space plus space straight H subscript 2 straight O subscript 2

    Hydrogen peroxide along with water distills over. Ammonium bisulphate can be used again. This method gives 30-40% aqueous solution of hydrogen peroxide.

    2. From 2-ethylanthraquinone. This is the most recent process for the manufacture of hydrogen peroxide. 2-ethyl anthraquinone is catalytically reduced to 2-ethylanthraqinol in an organic solvent by passing hydrogen gas in the presence of palladium (catalyst). The reduced product i.e. 2-ethyl anthraquinol is dissolved in a mixture of benzene and cyclohexanol. On passing air through it, 2-ethylanthraquinone and hydrogen peroxide are formed.

    H2O2 is extracted with water to give a 20% solution. 2-ethyl anthraquinone is reformed which is again used. The method, thus, involves alternate oxidation and reduction steps.

    Question 148
    CBSEENCH11006961

    Why is concenration of hydrogen peroxide difficult?

    Solution

    The hydrogen peroxide prepared whether in the laboratory or on a commercial scale is quite dilute. Hence, it has to be concentrated. The concentrated of hydrogen peroxide is done very carefully because it decomposes readily on heating to water and oxygen.
      2 straight H subscript 2 straight O subscript 2 space space rightwards arrow space space space 2 straight H subscript 2 straight O space plus space straight O subscript 2
    The explosive decomposition of hydrogen peroxide is catalysed by the presence of organic matter and metallic ions. The concentration of the aqueous dilute solution having H2O2 is done carefully by the following methods:
    (i) By cooling: The solution is frozen at 273 K. Some of the water in it separates as ice. The remaining liquid is now richer in hydrogen peroxide.
    (ii) By evaporation: Hydrogen peroxide obtained above is evaporated on a water bath at about 345K. Water evaporates slowly and hydrogen peroxide of about 50% strength is obtained.

    (iii) Vacuum desiccator evaporation: 50% hydrogen peroxide is placed in vacuum desiccator which contains concentrated H2SO4 (dehydrating agent). Concentrated sulphuric acid absorbs most of the water from hydrogen peroxide solution and nearly 90% hydrogen peroxide is obtained.
    (iv) Vacuum distillation: 90% hydrogen peroxide obtained above is subjected to distillation under reduced pressure when water distills over at about 308-313 K at a pressure of about 15 mm and the hydrogen peroxide left is about 99% pure.
    (v) Freezing with solid carbon dioxide : By freezing liquid H2O2 (99%) in a freezing mixture of solid carbon dioxide (dry ice) and ether, crystals of H2O2 separate out. These are dried and melted to get 100% pure hydrogen peroxide.

    Question 149
    CBSEENCH11006962

    What precautions are necessary while storing hydrogen peroxide?
    Or
    Explain why hydrogen peroxide is stored in coloured/plastic bottles.

    Solution

    (i) Hydrogen peroxide cannot be stored in glass bottles since the rough surface of glass, alkali oxides present in it and exposure to light catalyse its decomposition. H2O2is stored in vessels of pure aluminium or in stone jars in the dark. Concentrated solutions of hydrogen peroxide are stored these days in polyethene bottles kept in refrigerators.

    (ii) A small amount of phosphoric acid, glycerol or acetanilide must be added to retard the decomposition of H2O2. These are also called inhibitors.

    Question 150
    CBSEENCH11006963

    Explain why hydrogen peroxide cannot be stored for prolonged periods.

    Solution

    Hydrogen peroxide contains the weak peroxide (– O – O –) linkage. As a result, it is an unstable compound and decomposes easily into water and oxygen.
    straight H subscript 2 straight O subscript 2 left parenthesis straight l right parenthesis space space rightwards arrow space space straight H subscript 2 straight O left parenthesis straight l right parenthesis space plus space 1 half straight O subscript 2 left parenthesis straight g right parenthesis
    This process is further catalysed by the traces of metal impurities (Pt, Ag, Co, Fe, Cu, MnOetc.), dust particles, strong bases, rough surfaces and exposure to light. Thus, it cannot be stored for prolonged periods.

    Question 152
    CBSEENCH11006965

    Complete the following chemical reactions.
    MnO subscript 4 superscript minus left parenthesis aq right parenthesis space plus space straight H subscript 2 straight O subscript 2 left parenthesis aq right parenthesis space rightwards arrow

    Solution
    2 MnO subscript 4 superscript minus space plus space 6 straight H to the power of plus space plus space 5 straight H subscript 2 straight O subscript 2 space rightwards arrow space space 2 Mn to the power of 2 plus end exponent space plus space 8 straight H subscript 2 straight O space plus space 5 straight O subscript 2
    H2O2 is acting as a reducing agent in the acidic medium,thereby oxidising MnO4- Hence, the given reaction is a redox reaction.
    Question 153
    CBSEENCH11006966

    How does hydrogen peroxide act as bleaching agent?

    Solution
    H2O2 is used as a mild bleaching agent due to the nascent oxygen which it liberates upon decomposition.
    straight H subscript 2 straight O subscript 2 space space rightwards arrow space space straight H subscript 2 straight O space space plus space space straight O
    The nascent oxygen combines with a colouring matter which in turn gets oxidised.
    Colouring matter + [O] → Colourless matter
    It is used for the bleaching of delicate materials like ivory, feather, silk, wool etc.
    Question 154
    CBSEENCH11006967

    Give two chemical reactions which show the acidic character of hydrogen peroxide. 

    Solution
    Pure hydrogen peroxide turns blue litmus red indicating its acidic nature. The acidic character of hydrogen peroxide is indicated by the following reactions:
    (i) Action with hydroxides. Hydrogen peroxide reacts to give peroxides:
    2 NaOH space plus space stack straight H subscript 2 straight O subscript 2 with Acid below space space rightwards arrow space space space stack Na subscript 2 straight O subscript 2 with Sodium space peroxide below space plus space 2 straight H subscript 2 straight O
Ba left parenthesis OH right parenthesis subscript 2 space plus space stack straight H subscript 2 straight O subscript 2 with Acid below space rightwards arrow space space space stack BaO subscript 2 space plus space 2 straight H subscript 2 straight O with Barium space peroxide below
    (ii) Action with carbonates. Hydrogen peroxide decomposes carbonates to yield carbon dioxide.
    Na subscript 2 CO subscript 3 space plus space straight H subscript 2 straight O subscript 2 space space rightwards arrow space space stack Na subscript 2 straight O subscript 2 space plus space CO subscript 2 with Sodium space peroxide below space plus space straight H subscript 2 straight O
    Question 155
    CBSEENCH11006968

    Hydrogen peroxide is used to restore the colour of old oil paintings containing lead oxide. Write a balanced equation for the reaction that takes place in this process.

    Solution

    When an oil painting is constantly exposed to the atmosphere, the traces of hydrogen sulphide gas present in the atmosphere slowly blackens the painting by converting lead oxide (white) to lead sulphide (black).
    PbO with White below space plus space straight H subscript 2 straight S space space rightwards arrow space space space PbS with Black below space plus space straight H subscript 2 straight O
    Now, when the painting is dipped in a dilute solution of H2O2 for some time, lead sulphide is slowly oxidised to white lead sulphate.
    PbS space plus space 4 straight H subscript 2 straight O subscript 2 space space rightwards arrow space space space PbSO subscript 4 space plus space 4 straight H subscript 2 straight O
    Thus the colour of lead painting is restored. 

    Question 156
    CBSEENCH11006969

    What is the structure of hydrogen peroxide? Draw a schematic diagram indicating the shape of the molecule clearly. 

    Solution

    The structure of hydrogen peroxide has been established by X-ray studies.
    (i) The molecule of hydrogen peroxide is not planar. It is described as an ‘open book structure.
    (ii) The O – O part of the molecule can be thought of as lying on the spine of a book open at an angle of 90°.
    (iii) The hydrogen atoms are placed one on each cover.
    (iv) The H – O bonds make an angle of about 101.5° with the O – O bond as shown.
    (v) The O – O linkage present between two oxygen atoms is called peroxybond (peroxide linkage).

    (vi) This O – O linkage results from a p-p overlap of the p-orbitals of the two oxygen atoms.
    (vii) Each H – O bond results from an s-p overlap between s-orbital of hydrogen and p-orbital of the oxygen atom.

    Question 157
    CBSEENCH11006970

    Compare the structure of H2O and H2O2

    Solution

    (i) In H2O molecule, the central oxygen atom is sp2 hybridised and it is surrounded by two bond pairs and two lone pairs. The presence of two lone pairs brings distortion in the geometry of the molecule. Since the lone pairs repel the bond pairs more effectively resulting in the decrease of H – O - H bond angle from 109.5° to 104.5°, thus water is a bent molecule.

    (ii) The structure of H2O2 is like that of an open book. The O – O part of the molecule can be thought of as lying on the spine of a book open at an angle of 90°. The hydrogen atoms are placed one on each cover. The H – O bonds make an angle of about 101.5° with the O – O bond as shown. The O – O linkage present between two oxygen atoms is called peroxide linkage. The structure of hydrogen peroxide in the gas phase and the crystalline state are as shown below.



    Question 158
    CBSEENCH11006971

    Enlist the important uses of hydrogen peroxide.

    Solution

    Uses of hydrogen peroxide:
    (i) As a dilute solution of hydrogen peroxide is used as antiseptic in medicine and surgery.
    (ii) It is used to bleach silk, wool, ivory, hair etc.
    (iii) It is used to restore the colour of old and spoiled lead paintings.
    (iv) 90% solution of hydrogen peroxide is used as a propellant or fuel in torpedoes, submarines and rockets.
    (v) It is used as an antichlor in bleaching.

    Question 159
    CBSEENCH11006972

    How is strength of hydrogen peroxide expressed? Calculate the strength of 20 volume hydrogen peroxide in grams per litre.

    Solution

    Strength of hydrogen peroxide:
    (i) As percentage. It is expressed as W/V percentage of H2O2 in solution. Thus, 30% solution of H2O2 means 30 grams of H2O2 are present in 100 ml of solution.
    (ii) In terms of volume. The strength of hydrogen peroxide is expressed in terms of volume i.e. the bottles containing hydrogen peroxide are generally marked as 10 volumes or 20 volumes or 30 volumes etc. A solution of hydrogen peroxide labelled as 20 volume actually means that 1 ml of hydrogen peroxide solution on decomposition by heat produces 20 ml of oxygen at NTP.
    Let us now calculate the strength of 20 volume H2O2 in gram/litre.
    Hydrogen peroxide decomposes on heating as:
    stack 2 straight H subscript 2 straight O subscript 2 with 2 space cross times space 34 space equals space 68 space straight g below space space space rightwards arrow space 2 straight H subscript 2 straight O space plus space stack straight O subscript 2 with 22400 space ml space at space straight N. straight T. straight P. below
We space know comma space
224400 space ml space of space oxygen space at space NTP
are space produced space from space straight H subscript 2 straight O subscript 2 space equals space 68 space straight g
space space
    space space therefore space
20 space ml space of space oxygen space at space NTP space would space be space produced space from space straight H subscript 2 straight O subscript 2
space space space space space space equals space 68 over 22400 cross times 20 space equals 0.06 space straight g
But space 20 space ml space of space straight O subscript 2 space at space NTP space are space produced space from space 1 space ml space of space
20 space volume space of space straight H subscript 2 straight O subscript 2 space solution. space
space
space Thus comma space 1 space ml space of space 20 space volume space straight H subscript 2 straight O subscript 2 space solution space contains
space equals space 0.06 space straight g space of space straight H subscript 2 straight O subscript 2
    space therefore space space space 1000 space ml space of space 20 space volume space of space straight H subscript 2 straight O subscript 2 space solution space will space contain
space equals space 0.06 space cross times space 1000 space of space straight H subscript 2 straight O subscript 2
space space space space space space equals space 60 space straight g space of space straight H subscript 2 straight O subscript 2
therefore space space Strength space of space 20 space volume space of space straight H subscript 2 straight O subscript 2 space equals space 60 space straight g divided by litre

    Question 160
    CBSEENCH11006973

    Calculate the strength of 10 volume solution of hydrogen peroxide.

    Solution

    Hydrogen peroxide decomposes on heating as,
                2 straight H subscript 2 straight O subscript 2 left parenthesis straight l right parenthesis space space space space space space space rightwards arrow space space space space 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis space plus space space straight O subscript 2 left parenthesis straight g right parenthesis
2 space straight x space 34 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space STP space space space space space space space space space space space
equals space 68 straight g space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 22400 space mL
space space space space space space space space space space space space space space space space space space
    We know, 
         22400 mL of O2 at STP are produced from H2O2 = 68 g
    therefore    10 ml of O2 at STP would be produced from H2O2fraction numerator 68 space cross times space 10 over denominator 22400 end fraction straight g space equals space 0.03036 space straight g
    But 10 ml of oxygen at STP are produced from 1 ml of 10 volume of H2O2 solution.
    Thus 1 ml of 10 volume at H2O2 solution contains  = 0.03036 g H2O2.

    therefore   1000 ml of 10 volume of H2O2 solution
    would contain = 0 .03036 x 1000 = 30.36g H2O2
    therefore   Strength of 10 volume H2O2 = 30.36g L-1

    Question 161
    CBSEENCH11006974

    What is the mass of hydrogen peroxide present in 1 litre of 2M solution? Calculate the volume of oxygen at STP liberated upon the complete decomposition of 100 cmof the above solution.

    Solution

    (i) To calculate the mass of H2O2 in 1 litre of 2 M solution:
        Moleuclar mass of H2O2 = 2 x 1 + 2 x 16 = 34 amu
      Now 1 litre of 1 M solution contains
              H2O2 = 34 g
    therefore space space space 1 litre space of space 2 space straight M space solution space contains space straight H subscript 2 straight O subscript 2 space equals space 34 space cross times space 2 space equals space 68 space straight g
    (ii) To calculate the volume of O2 liberated at STP from 1000 cm3 of 2M solution:
                 Decomposition of H2O2 can be represented as:
                          2 straight H subscript 2 straight O subscript 2 space rightwards arrow space space 2 straight H subscript 2 straight O space plus space straight O subscript 2
2 space straight x space 34 space equals space 68 space straight g space space 22400 space cm cubed space at space STP
1 space litre space of space 2 MH subscript 2 straight O subscript 2 space solution space contains space straight H subscript 2 straight O subscript 2 space equals space 68 space straight g
therefore space space space space 100 space cm cubed space of space 2 straight M space straight H subscript 2 straight O subscript 2 space solution space contains space space straight H subscript 2 straight O subscript 2 space equals space 68 space straight g
space
                                    straight H subscript 2 straight O subscript 2 space equals space 68 over 1000 cross times 100 space equals space 6.8 space straight g
    Now 68 g of straight H subscript 2 straight O subscript 2 at S.T.P. given O2 = 22400 cm3
    therefore space space 6.8 space straight g space of space straight H subscript 2 straight O subscript 2 space at space STP space would space give space straight O subscript 2
space space space space space space equals space 22400 over 68 cross times 6.8 space equals space 2240 space cm cubed space equals space 2.24 space litre.

                               

    Question 162
    CBSEENCH11006975

    Give reason for the fact that a mixture of H2O2 and hydrazine (H2NNH2) is used as propellant.

    Solution
    straight H subscript 2 straight O subscript 2 oxides H2N NH2 to free nitrogen and water.
    straight H subscript 2 straight N. space NH subscript 2 left parenthesis straight l right parenthesis space plus space 2 straight H subscript 2 straight O subscript 2 left parenthesis straight l right parenthesis space rightwards arrow space space straight N subscript 2 left parenthesis straight g right parenthesis space plus space 4 straight H subscript 2 straight O left parenthesis straight g right parenthesis space plus space Heat

    The reaction is exothermic and the products being gases at the temperature of reaction, there is a tremendous increase in pressure. Hence this mixture is used as a rocket propellant.
    Question 163
    CBSEENCH11006976

    Is demineralised or distilled water useful for drinking purposes? If not, how can it be made useful?

    Solution

    Water is an important part of life. It contains several dissolved nutrients that are required by human beings, plant, and animals for survival. Demineralised water is of all soluble minerals. Hence, it is not fit for drinking. It can be made useful only after the addition of desired minerals in specific amounts which are important for growth.

    Question 164
    CBSEENCH11006977

    Knowing the properties of H2O and D2O, do you think that D2O can be used for drinking purposes? 

    Solution
    Heavy water decomposes more slowly than ordinary water i.e. slows down the rates of reactions occurring in human beings, plants and animals, therefore it is injurious to living organisms. Hence heavy water does not support life so well as ordinary water does.
    Question 165
    CBSEENCH11006978

    How does H2Obehave as a bleaching agent?

    Solution
    H2O2 is used as a mild bleaching agent due to the nascent oxygen which it liberates upon decomposition.
    straight H subscript 2 straight O subscript 2 space rightwards arrow space space straight H subscript 2 straight O space plus space straight O
    The nascent oxygen combines with a colouring matter which in turn gets oxidised. 
    Colouring matter  + [O]  →  Colourless matter
    It is used for the bleaching of delicate materials like ivory, feather, silk, wool etc.
    Question 167
    CBSEENCH11008046

    The concentration of fluoride, lead, nitrate and iron in a water sample from an underground lake was found to be 1000 ppb, 40 ppb, 100 ppm and 0.2 ppm, respectively. This water is unsuitable for drinking due to the high concentration of:

    • Lead

    • Nitrate

    • Iron

    • Fluoride

    Solution

    B.

    Nitrate

    This water unsuitable for drinking due to the high concentration of nitrate. In drinking water, maximum permissible concentration of 
    Lead = 50 ppm
    Nitrate = 50 ppm
    Iron = 0.2 ppm
    Fluoride = 1 ppm

    Question 169
    CBSEENCH11008063

    In which of the following reactions H2O2 acts as a reducing agent?
    I. H2O2 + 2H+ + 2e- →2H2O
    II. H2O- 2e- →O2 + 2H+
    III. H2O2 +2e- 2OH-
    IV. H2O2+ 2OH- -2e- →O2 + 2H2O

    • I and II

    • III and IV

    • I and III

    • II and IV

    Solution

    D.

    II and IV

    The release of the electron is known as reduction. So, H2O2 acts as a reducing agent when it releases electrons.
    Here, in reactions (II) and (IV), H2O2 release two electrons, hence reactions (II)  and (IV) is known as reduction. In reactions (I) and (III), two electrons are being added so (I) and (III) represents oxidation.

    Question 172
    CBSEENCH11008233

    Which of the following statement about hydrogen is incorrect?

    • Hydrogen never acts as cation in ionic salts

    • Hydronium ion, H3O+ exist freely in solution

    • Dihydrogen does not act as a reducing agent

    • Hydrogen has three isotopes of which tritium is the most common

    Solution

    C.

    Dihydrogen does not act as a reducing agent

    We can have both answers (C, D) 
    For ionic salts, hydrogen never behaves as cation, but behaves as anion (H-)
    H3O+ exist freely in solution
    Dihydrogen acts as a reducing agent.
    Hydrogen has three isotopes. Protium, Deuterium and Tritium. Protium is the most common isotopes of hydrogen with an abundance of 99.98%.

    Question 173
    CBSEENCH11008247

    The reaction of aqueous KMnO4 with H2O2 in acidic conditions gives.

    • Mn4+ and O2

    • Mn2+ and O2

    • Mn2+ and O3

    • Mn4+ and MnO2

    Solution

    B.

    Mn2+ and O2

    The reaction of aqueous KMnO4 with H2O2 in acidic medium is 
    3H2SO4 + KMnO4 +5 H2O2 --> 5O2 +2MnSO4 +8H2O +K2SO4
    In the reaction, KMnO4 oxidise H2O2 to O2 and itself [MnO4-] gets reduced to Mn2+ ions as MnSO4. Hence, aqueous solution of KMnO4 with H2O2 yields Mn2+ and O2 in acidic conditions.

    Question 175
    CBSEENCH11008352

    Which one of the following molecular hydrides acts as a Lewis acid? 

    • NH3

    • H2O

    • B2H6

    • CH4

    Solution

    C.

    B2H6

    Electron deficient molecules behave as Lewis acid.
    Among the given molecules, only diborane is electron deficient, ie, does not have a complete octet. Thus, it acts as a Lewis acid. 
    NH3 and H2O being electron rich molecules behave as Lewis base.

    Question 176
    CBSEENCH11008375

    Some statement about heavy water are given below

    A) Heavy water is used as a moderator in nuclear reactors.

    B) Heavy water is more associated than ordinary water.

    C) Heavy water is more effective solvent than ordinary

    • A and B

    • A, B and C

    • B and C

    • A and C

    Solution

    A.

    A and B

    Heavy water is used as a moderator in nuclear reactors. Its boiling point is higher as compared to the ordinary water. Thus, it is more associated as compared to ordinary water. The dielectric constant is however higher for H2O, thus, H2O is a more effective solvent than heavy water (D2O).

    Question 177
    CBSEENCH11008470

    In which case is a number of molecules of water maximum?

    • 18 mL of water

    • 0.18 g of water

    • 10-3 mol of water

    • 0.00224 L of water vapours at 1 atm and 273K

    Solution

    A.

    18 mL of water

    a) Mass of water = 18 x 1 = 18 g

    Molecules of water = mole x NA

    =1818NA = NA

    b) Molecules of water = mole x NA

    =0.1818 NA =10-2 NA

    c) Molecules of water = mole x NA = 10-3 NA
    d) Moles of water = 0.00224/22.4 = 10-4

    Molecules of water = mole x NA = 10-4 NA

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