Statistics For Economics Chapter 7 Correlation
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    NCERT Solution For Class 11 Statistics Statistics For Economics

    Correlation Here is the CBSE Statistics Chapter 7 for Class 11 students. Summary and detailed explanation of the lesson, including the definitions of difficult words. All of the exercises and questions and answers from the lesson's back end have been completed. NCERT Solutions for Class 11 Statistics Correlation Chapter 7 NCERT Solutions for Class 11 Statistics Correlation Chapter 7 The following is a summary in Hindi and English for the academic year 2021-2022. You can save these solutions to your computer or use the Class 11 Statistics.

    Question 1
    CBSEENST11024454
    Question 7
    CBSEENST11024460

    Why is r preferrred to co-variance as a measure of association?

    Solution

    r is preferred to co-variance as a measure of association because it studies and measures the direction and intensity of relationship among variables.

    Question 8
    CBSEENST11024461

    Can r lie outside -1 and 1 range depending on the type of data?

    Solution

    No, r cannot lie outside -1 and 1 range depending on the types of data. It lies between minus one and plus one. Symobtically.

    -1 ≤ r ≥ 1

    If in any exercise, r is outside this range it indicates error in calculation.

    Question 9
    CBSEENST11024462

    Does correlation imply causation?

    Solution

    No correlation does not imply causation. It implies covariation. It should never be interpreted as implying causes and effect relation.

    Question 10
    CBSEENST11024463

    When is rank correlation more precise than simple correlation coefficient?

    Solution

    Rank correlation is more precise than simple correlation when the variables cannot be measured meaningfully as in the case of price, income, weight etc. Ranking may be more meaningful when the measurement of the variables are suspect. Ranking may be a better alternative to quantification of qualities.

    Question 11
    CBSEENST11024464

    Does zero correlation mean independenc?

    Solution

    No, but there is possibility of independence.

    Question 13
    CBSEENST11024466

    Collect the price of five vegetables from your local market everyday for a week. Calculate their correlation coefficient. Interpret the result.

    Solution

    Students are suppose of collect the price of any five vegetables from the market everyday for a week. Then they should calculate their correlation of co-efficients.

    Question 14
    CBSEENST11024467

    List some variables where accurate measurement is difficult.

    Solution

    Impartiality, secularism, beauty, honesty, patriotism etc. are some variables where accurate measurement is difficult.

    Question 15
    CBSEENST11024468

    Interpret the values of r as 1, –1 and 0.

    Solution

    (i) r as 1 mean that it perfect positive relationship between two variables.

    (ii) r as –1 mean that there is perfect negative relationship between two variables.

    (iii) r as O mean that there is lack of correlation between two variables.

    Question 16
    CBSEENST11024469

    Why does rank correlation coefficient differ from Personian correlation co-efficient?

    Solution

    Because rank correlation co-efficient provides a measure of linear association between ranks assigned to these limits and not their values.

    Sponsor Area

    Question 18
    CBSEENST11024471

    Calculate Karl Pearson’s correlation co-efficient bv the assumed mean method.

    X

    14

    15

    18

    20

    25

    30

    Y

    40

    45

    65

    28

    30

    40

    Solution

    Calculate of Karl Pearson’s correlation co-efficient.

    X

    Y

    dX

    dY

    dXdY

    dX2

    dY2

    14

    40

    –6

    –5

    30

    36

    25

    15

    45

    –5

    0

    0

    25

    0

    18

    65

    –2

    20

    –40

    4

    400

    20

    28

    0

    –17

    0

    0

    289

    25

    30

    5

    –15

    –75

    25

    225

    30

    40

    10

    –5

    –50

    100

    25

    N= 6

     

    IΣdX = 2

    Σ dY = 22

    ΣdXdY = –13.5

    Σ dX2 = 190

    Σ dY2 = 964

    A.M. of X series =20 A.M. of Y series = 45

    Question 19
    CBSEENST11024472

    Calculate the correlation co-efficient between the heights of fathers in inches (X) and their son (Y)

    X

    65

    66

    57

    67

    68

    69

    70

    72

    Y

    67

    56

    65

    68

    72

    72

    69

    71

    Solution

    X

    dX (d from AM = 67)

    dX2

    Y

    dY (d from AM = 68)

    dY2

    dXdY

    65

    –2

    4

    67

    –1

    1

    2

    66

    –1

    1

    56

    –12

    144

    12

    57

    –10

    100

    65

    –3

    9

    30

    67

    0

    0

    68

    0

    0

    0

    68

    +1

    1

    72

    4

    16

    4

    69

    +2

    4

    72

    4

    16

    8

    70

    +3

    9

    69

    1

    1

    3

    72

    5

    25

    71

    3

    9

    15

    ΣX = 534

    ΣdX = –2

    Σ dX2 = 144

    ΣY = 540

    ΣdY = –4

    ΣrfY2 = 196

    ΣdXdY = 74

    Question 20
    CBSEENST11024473

    Calculate the correlation co-efficient between X and Y and comment on their relationship.

    X

    –3

    –2

    –1

    1

    2

    3

    Y

    9

    4

    1

    1

    4

    9

    Solution

    Hence, r = 0

    Two values X and Y are un-corrected.

    There is no linear correlation between them.

    Question 21
    CBSEENST11024474

    Calculate the correlation coefficient between X and Y and comment on their relationship.

    X 1 3 4 5 7 8

    Y 2 6 8 10 14 16

    Solution

    Calculation of Correlation:

    X

    R1

    y

    R2

    D(R1–R2)

    D2

    1

    6

    2

    6

    0

    0

    3

    5

    6

    5

    0

    0

    4

    4

    8

    4

    0

    0

    5

    3

    10

    3

    0

    0

    7

    2

    14

    2

    0

    0

    8

    1

    16

    1

    0

    0

             

    ΣD2= 0

    Question 22
    CBSEENST11024475

    Define correlation.

    Solution

    According to Croxton and Cowden, correlation is defined as “When the relationship is of a quantitative nature, the appropriate statistical tool for discovering and measuring the relationship and expressing it in a brief formula is known as correlation.”

    Question 23
    CBSEENST11024476

    What are the principal methods of calculating coefficient of correlation?

    Solution

    The principal methods are as under:

    (i) Scattered Diagram Method.

    (ii) Karl Pearson’s Co-efficient of Correlation.

    (iii) Spearman’s Rank Correlation Coefficient.

    Question 24
    CBSEENST11024477

    What is the difference between positive and negative correlation?

    Solution

    When two variables move in same direction, such a relation is called positive correlation. For example relationship between price and supply. When two variables change in diffdrent directions, it is called negative correlation. For example relationship between price and demand.

    Question 25
    CBSEENST11024478

    State the kinds of correlation.

    Solution

    (a) Positive and negative correlation.

    (b) Linear and non-linear correlation.

    (c) Simple and multiple correlation.

    Question 28
    CBSEENST11024481

    What is the principal shortcoming of scattered diagram as a method of estimating correlation?

    Solution

    A scattered diagram does not measure the precise extent of correlation. It gives only an approximate idea of the relationship. It is not a quantitative measure of the relationship.

    Question 29
    CBSEENST11024482

    When is Rank Correlation method used?

    Solution

    Rank Correlation method is used for the variables whose quantitative measurement is not possible, such as beauty, bravery, wisdom.

    Question 30
    CBSEENST11024483

    What does correlation measure?

    Solution

    Correlation measures the direction and intensity of relationship. It measures covariation and not causation.

    Question 31
    CBSEENST11024484

    What does the presence of correlation between two variables X and Y simply mean?

    Solution

    The presence of correlation between the variables X and Y simply means that when the value of one variables is found to change in one direction, the value of other variable is found to change either in the same direction (i.e. positive direction) or in the opposite direction (i.e. negative direction) but in a difinate way.

    Question 32
    CBSEENST11024485

    When is rank correlation preferred to Personian co-efficient?

    Solution

    Rank correlation is preferred to Personian co-efficient when extreme values are present.

    Question 33
    CBSEENST11024486

    What is the relationship between r and rk in general?

    Solution

    In general rk ≤ r.

    Question 34
    CBSEENST11024487

    What is the limitation of Spearman’s rank correlation?

    Solution

    Spearman’s rank correlation is not as accurate as the ordinary method. This is due to the fact that all the information concerning the data is not utilised.

    Question 35
    CBSEENST11024488

    When do r and rk give identical results?

    Solution

    r and rk give identical results when the first differences of the values of the items in the series arranged in the order of magnitude are constant.

    Question 36
    CBSEENST11024489

    In which situation is the use of rank correlation method suitable?

    Solution

    The use of rank correlation is suitable when data cannot be directly quantitatively measured.

    Question 37
    CBSEENST11024490

    Which type of correlation is indicated by the values of X and Y variables?

    X : 30 35 40 50 55 GO

    Y : 80 90 100 110 120 140

    Solution

    Here r = +1 as the values of X and Y variables move in the same direction.

    Question 38
    CBSEENST11024491

    Under what situation is r = –1.

    Solution

    r = –1, when the values of two variables X and Y move in the opposite directions.

    Question 39
    CBSEENST11024492

    When is the correlation called linear?

    Solution

    When the change ratio in values of two variables is constant.

    Sponsor Area

    Question 41
    CBSEENST11024494

    Where does correlation between two variables concentrate?

    Solution

    Correlaion between two variables concentrate between +1 and –1.

    Question 42
    CBSEENST11024495

    Which type of correlation is indicated by the following scatter diagram?


    Solution

    The scatter diagram given in the question indicates the positive relation.

    Question 43
    CBSEENST11024496
    Question 44
    CBSEENST11024497

    Which type of correlation is indicated by the values of X and Y variables?

    X : 1 2 3 4 5 6

    Y : 46 43 40 37 34 31

    Solution

    Here r = –1 because the value of X and Y variable move in the opposite direction.

    Question 45
    CBSEENST11024498

    What does a high value of r indicate?

    Solution

    A high value of r indicates linear relationship. Its value is said to be high when it is close to +1 or -1.

    Question 46
    CBSEENST11024499

    Give any one property of correlation coefficient (r).

    Solution

    The value of r is unaffected by the change of origin and change of scale.

    Question 47
    CBSEENST11024500

    What does a low value of r indicate?

    Solution

    A low value of r indicates a weak linear relation. Its value is said to be low when it is close to zero.

    Question 50
    CBSEENST11024503
    Question 52
    CBSEENST11024505

    r between two variables X and Y is zero? What does it indicate?

    Solution

    It implies that X and Y are independent variables.

    Question 53
    CBSEENST11024506

    How is Karl Pearson’s measure of correlation given?

    Solution

    Karl Pearson’s measure of correlation is given by is given by

    Question 54
    CBSEENST11024507

    Give the defination of correlation. Give the meaning of following :

    r = 0, r= +1, r = –1

    Solution

    According to Croxtion and Cowden, when the relationsip is of a quantitative nature, the appropriate statistical tool for discoverinng and the measuring the relationship and expressing it in a brief formula is knwon as statistics.

    (i) When r = 0, it implies that there exists no relationship between two variables X and Y. On other ways, r = 0 shows the absence of relationship.

    (ii) r = 1 shows that there is perfect correlation between two variables X and Y.

    (iii) r = –1 shows that there is perfect negative relationship between two variables X and Y.

    Question 55
    CBSEENST11024508

    Give the value of correlation under following position:

    (i) perfect correlation and negative.

    (ii) perfect correlation and positive.

    (iii) No correlation.

    Solution

    When correlation is perfect and negative then the value of r = –1

    (ii) When correlation is perfect and positive then the value of r = +1

    (iii) When there is no correlation then the value of r = 0.

    Question 56
    CBSEENST11024509

    Define positive and negative correlation with examples.

    Solution

    Positive Correlation : When two variables move in the same direction, that is when one increases the other also increases and when one decreases the other also decreases then such a relation is called Positive correlation. For example, the relation between price and supply.

    Increase in the value of both variables.

    X : 10 20 30 40

    Y : 100 150 200 250

    2. Negative Correlation : When two variables change different directions, it is called negative correlation. For example relationship between price and demand. When prices rises other things remaining constant demand falls and when price falls demand rises.

    X : 1 2 3 4

    Y : 5 4 2 1


    X : 10 20 30 40

    Y : 100 150 200 250

    Question 57
    CBSEENST11024510

    What is perfect correlation? Give two examples.

    Solution

    Perfect correlation is that where changes in two related variables are exactly proportional. It is of two types:

    (i) Positive perfect correlation and (ii) Negative perfect correlation.

    There is perfect positive correlation between the two variables of equal proportional changes are in the same direction. It is expressed as +1. If equal proportional changes are in the reverse direction. Then there is negative perfect correlation and it is described as –1.

    (a) Example of positive perfect correlation

    Price (Rs): 1 2 3 4 5

    Supply (units) : 10 20 30 40 50

    (b) Example of perfect negative correlaion

    Price (Rs): 1 2 3 4 5

    Demand (units) : 50 40 30 20 10 Q. 5. Define simple, and partly correlation.

    Ans. Simple Correlation : When the relationship between two variables is studied and of these two variables one is independent and the other is dependent, then such correlation is called simple correlation. For example, relationship between income and expenditure.

    Partial Correlation : When more than two variables are involved and out of these the relationship between two variables is studied only treating other variables as constant, then such correlation is partial.

    Question 58
    CBSEENST11024511

    What is multiple correlation?

    Solution

    Multiple Correlation : When relationship among three or more than three variables is studied simultaneously then such relationship is called multiple correlations. In case of such correlation the entire set of independent variables is studied. For example the effect of rainfall, manure, water etc. to increase the productivity of what are simultaneously studied.

    Question 59
    CBSEENST11024512

    What is co-efficient of correlation of Karl-Pearson’s? Give its formula and limited degree of correlation.

    Solution

    The co-efficient of correlation of Karl Pearson’s is the quantitative measure of the relationship of two variables X and Y. It is represented by r. It is based on arithmetic mean and standard deviation. The co-efflciant of correlation (r) of two variables is obtained by dividing the sum of the products of the corresponding deviations of the various items of the two series from their respective means by the product of their standard deviation and the number of pairs of observations. Symbolically.

    Limited degree of correlation coefficient: The value of correlation coefficient lies between minus one and plus one. The calculated result of correlation must valy between -1 to +1. Symbolically.

    Question 61
    CBSEENST11024514

    Draw scatter diagram with the help of following information.

    X : 8 10 12 11 9

    Y : 5 7 9 8 6

    Solution



    Form the scatter diagram it is clear that there is perfect positive correlation between X and Y variables.
    Question 64
    CBSEENST11024517

    How does rank correlation differ from Pearson correlation coefficient?

    Solution

    Rank collection co-efficient and simple correlation coefficient have the same interpretation. Its formula has been derived from simple correlation coefficient where individual values have been replaced by rank. These ranks are used for the calculation of correlation. This coefficient provides a measure of linear association between ranks assigned to units not their values correlation. Following formula is used for calculating rank correlation

    In Karl Pearson’s coefficient of correlation, the values of two series are not assigned rank. The correlation coefficient provides a measure of linear association to the values of the variables. Following formula i.e. used for calculating the correlation coefficient.

    Question 65
    CBSEENST11024518

    Inter the values of r as 1, –1 and r=0.

    Solution

    (i) r as 1 indicates that there is perfect positive correlation between the two values.

    (ii) r as –1 indicates that there is perfect negative correlation between the two values.

    (iii) r = 0 indicates that there is no relation between the values.

    Question 66
    CBSEENST11024519

    If the points in a scatter diagram tend to cluster about a straight line. Which makes and angle of 30° with the X axis, what would you say about the strength of assication between X and Y.

    Solution

    The points in the scatter diagram tendering about a st. line which makes an angle of 30° with the X axis indicate the less than proportionate changes. There exists a low degree of association between X and Y.

    Question 68
    CBSEENST11024521

    What kind of relation between X and Y is indicated of the points of scatter diagram tend to cluster?

    (a) A st. line parallel to the X axis

    (b) A st. line parallel to the Y axis

    (c) A st. line stepping upwards.

    (d) A st. line stepping downwords.

    Solution

    (a) No relationship between two variables.

    (b) No relationship between two variables.

    (c) Perfect Positive correlation ( r = +1)

    (d) Perfect Negative correlation ( r = –1)

    Question 69
    CBSEENST11024522

    What is Karl Pearson’s coefficient of correlation defined?

    Solution

    Karl Pearson’s coefficient of correlation : Karl Pearsons’s coefficient of correlation, is used to measure the degree of relationship between two or more variabless. It is represented by r. It is based on arithmetic mean and standard deviation. The coefficient of correlation (r) of two variables is obtained by dividing the sum of the products of the corresponding deviations of the various items of two series from their respective means by the product of their standard deviations and the number of pairs of observaions.

    Question 70
    CBSEENST11024523

    (i) What are the limits of r?

    (ii) If r = +1 or r = –1, what kind of relation exists between X and Y?

    Solution

    (i) r is always between –1 and +1 that is –1 ≤ r ≤ 1

    (ii) If r = +1 or r=–l it means that there is perfect relation between the variables. In other ways the relation between two variables is exact.

    Question 71
    CBSEENST11024524

    Write down the characteristics of (properties) of correlation coefficient.

    Solution

    Properties of correlation coefficient:Following are main properties of correlation coefficient:

    1. r has no unit. It is a pure number.

    2. A negative value of r indicates an inverse relation. A change in one variable is associated with change in the other variable in the opposite direction.

    3. If r is positive the two variables move in the same direction.

    4. If, r = 0, the two variables ate uncorrelated. There in no linear relation between them.

    5. If r = 1 r = –, the correlation is perfect. The relation between two variables is extact.

    6. A high value of r indicates strong linear relationship. Its value in said to be high when it is close to+1 or –1.

    7. A low value of r indicates a weak linear relation. Its value is said to be low when it is close to zero.

    8. The value of correlation coefficient lies between minus one and pluse one symbolically:

    –1 ≤ r ≤ 1

    9. The value of r is unaffected by the change of origin and change of scale.

    Question 72
    CBSEENST11024525

    What do you mean by a scatter diagram? How is correlation measured by this method?

    Solution

    A scatter diagram : A scatter diagram is a simple visual method for getting some idea about the presence of correlation between two variables. In a scatter diagram, we plot the values of two variables as a set of points on a graph paper, the cluster of points is called scatter diagram.

    Drawing of a scatter diagram involves following steps:

    1. Writting down the independent variables on X axis.

    2. Writting down the dependent variables on Yaxis.

    3. Points with the help of given data are marked on the graph paper.

    4. When the plotted points show some trend upward or downward, we know that there is some correlation between the variables. When the trend is upward, the correlation is positive. On the other hand, when the trend is downward, the correlation is negative as shown in fig.

    Question 73
    CBSEENST11024526

    Write down the merits and demerits of a scatter diagram.

    Solution

    Merits of Scatter Diagram:

    (i) Scatter diagram is a very simple method of studying correlation between two variables.

    (ii) Just a glance of the diagrams is enough to know if the values of the variables have any relation or not.

    (iii) Scatter diagram also indicates whether the relationship is positive or negative.

    2. Demerits of Scatter Diagram:

    (i) A scatter diagram does not measure the precise extent of correlation.

    (ii) It gives only an approximate idea of the relationship.

    (iii) It is only an qualitative expression of the quantitative change.

    Question 75
    CBSEENST11024528

    Calculates with the help of following data by using step deviation. Price Index X : 120, 150, 190, 220, 230

    Money supply in Rs. crores (y) : 1800, 2000, 2500, 2700, 3000

    Solution

    Let A = 100 H = 10 B = 13.0 R = 100

    The table of transformed variables are as follows

    Calculation of r between price Index and money supply using step deviation method

    U2

    V2

    UV

    2

    1

    4

    1

    2

    5

    3

    25

    9

    15

    9

    8

    81

    64

    72

    12

    10

    144

    100

    120

    13

    13

    169

    169

    169

    ΣU = 41

    ΣV = 35

    ΣU2 = 423

    ΣV2 = 343

    ΣUV = 378

    Substituting these value in the formula

    It shows that is strong positive correlation between price index and money supply

    Question 76
    CBSEENST11024529

    What steps are involved in the procedure of calculating Karl Pearson’s coefficient of correlation by direct method?

    Solution

    Steps involved in the procedure of calculation of Karl Pearson’s coefficient of correlation by direct method.

    1. Calculate mean value x and y.

    2. Calculate deviations of values of x series from mean value.

    3. Square the deviations.

    4. Calculate deviation of values of y series from mean value.

    5. Square the deviation.

    6. Multiply the square of deviation of X series with the square of deviations of Y series.

    7. Use the following formula for calculating correlation coefficient

    Question 77
    CBSEENST11024530

    Calculate height and weight of the students of a class.

    Height (in inches)

    57

    59

    62

    63

    64

    65

    55

    58

    57

    Weight in (Pounds)

    113

    117

    126

    126

    130

    129

    111

    116

    112

    Solution

    X

    dx (x-60)

    d2x

    y

    dy(y–120)

    d2y

    dxdy

    37

    –3

    9

    113

    –7

    49

    21

    59

    –1

    1

    117

    –3

    9

    3

    62

    + 2

    4

    126

    + 6

    36

    12

    63

    + 3

    9

    126

    + 6

    36

    18

    64

    + 4

    16

    130

    + 10

    100

    40

    65

    + 5

    25

    129

    + 9

    81

    45

    55

    –5

    25

    111

    –9

    16

    6

    58

    –2

    4

    116

    –4

    16

    8

    57

    –3

    9

    112

    –8

    64

    24

     

    ΣdX = 0

    Σd2X = 100

    dy = 0 d2y = 472

    ΣdXd = 216

    Question 78
    CBSEENST11024531

    Calculate Karl pearson’s co-efficint of correlation with the help of following data.

    X

    6

    8

    12

    15

    18

    20

    24

    18

    31

    Y

    10

    12

    15

    15

    18

    25

    22

    26

    28

    Solution

    Calculation of Pearson’s co-efficient of correlation

    X

    X'(X-8)

    X2

    Y

    Y =(Y-19)

    Y2

    XY

     

    6

    –12

    144

    10

    –9

    81

    +108

     

    8

    –10

    100

    12

    –7

    49

    +70

     

    12

    –6

    36

    15

    –4

    16

    +24

     

    15

    –3

    9

    15

    –4

    16

    +12

     

    18

    0

    0

    18

    –1

    1

    0

     

    20

    + 2

    4

    25

    + 6

    36

    +12

     

    24

    + 6

    36

    22

    + 3

    9

    +18

     

    18

    + 10

    100

    26

    + 7

    49

    +70

     

    31

    + 13

    169

    28

    + 9

    81

    +117

     

    ΣX = 162

    XX = 0

    ΣX2 = 598

    ΣY= 171

    Σ Y= 171

    Σ Y2 = 338

    Σ XY= 431

     

    Sponsor Area

    Question 81
    CBSEENST11024534

    Calculate Karl Pearson’s correlation co-effcient.

    Income (lakh Rs.)

    23

    27

    28

    29

    30

    31

    33

    35

    36

    39

    Expenditure (lakh Rs.)

    18

    22

    23

    24

    25

    26

    28

    29

    30

    32

    Solution

    Income X

    dX (X – A)

    dX2

    Expenditure Y

    dY (Y – A)

    dY2

    dXdY

    23

    –8

    64

    18

    –7

    49

    56

    27

    –4

    16

    22

    –3

    9

    12

    28

    –3

    9

    23

    –2

    4

    6

    29

    –2

    4

    24

    –1

    1

    2

    30

    –1

    1

    25

    0

    0

    0

    31

    0

    0

    26

    1

    1

    0

    33

    2

    4

    28

    3

    9

    6

    35

    4

    16

    29

    4

    16

    16

    36

    5

    25

    30

    5

    25

    25

    39

    8

    64

    32

    7

    49

    56

    N = 10 AM = 31

    ΣdX = 1

    dX2 = 203

    N = 10 A = 25

    ΣdY = 7

    ΣdY2 = 163

    ΣdXdY = 179

    Question 82
    CBSEENST11024535

    Write down the steps involved in calculating correlation co-efficient by short cut method.

    Solution

    Steps involved in calculating correlation co-efficient by short cut method.

    1. Take any convenient value in X and Y series as assumed mean.

    2. Calculate the deviation of the values of individual variable from assumed mean and denote them by dx and dy respectively.

    3. Add the deviation of both series seperately and denote them by Σdx and Σdy.

    4. Multiply the deviation of the two series and denote them by dx dy.

    5. Add the dx dy to obtain Σdxdy.

    6. Square the deviation and denote them by dx2 and dy2.

    7. Add dx2 and dy2 to find out Σdx2 and Σdy2.

    8. Calculate correlation co-efficient by using the following formula :

    Here

    (i) dX = deviation of X series from the assumed mean (X - A).

    (ii) dY = deviation of y series from the assumed mean (Y – A).

    (iii) Σ dXdY Sum of the multiple of dX and dY

    (iv) ΣdX2 sum of square of dX

    (v) ΣdY2 sum of square of dY

    (vi) Σ dX sum of deviation of X series

    (vii) Σ dY = sum of deviation of Y series

    (viii) Total Number of observations
    Question 83
    CBSEENST11024536

    Calculate Karl Pearson’s Correlation co-efficient from the following data:

    X

    78

    89

    97

    69

    59

    79

    68

    61

    Y

    125

    137

    156

    112

    107

    136

    123

    108

    Solution

    Calculation of Karl Pearson’s correlation co-efficient

    X

    dX

    dX2

    Y

    dY

    dY2

    dXdY

    78

    9

    81

    125

    13

    169

    117

    89

    20

    400

    137

    25

    625

    500

    97

    28

    784

    156

    44

    1936

    1232

    69

    0

    0

    112

    0

    0

    0

    59

    –10

    100

    107

    –5

    25

    50

    79

    10

    100

    136

    24

    576

    240

    68

    –1

    1

    123

    11

    121

    –11

    61

    –8

    64

    108

    –4

    16

    32

    N=8

    ΣdX = 48

    ΣdX2 =1530

    N = 8

    ΣdY = 108

    ΣdY2 = 3468

    ΣdXdY = 2160

    A.M. of X series 69 assumed mean of Y series = 112

    Question 84
    CBSEENST11024537

    alculate Karl Pearson’s correlation co-efficient bv the assumed mean method.

    X

    14

    15

    18

    20

    25

    30

    Y

    40

    45

    65

    28

    30

    40

    Solution

    Calculate of Karl Pearson’s correlation co-efficient.

    X

    Y

    dX

    dY

    dXdY

    dX2

    dY2

    14

    40

    –6

    –5

    30

    36

    25

    15

    45

    –5

    0

    0

    25

    0

    18

    65

    –2

    20

    –40

    4

    400

    20

    28

    0

    –17

    0

    0

    289

    25

    30

    5

    –15

    –75

    25

    225

    30

    40

    10

    –5

    –50

    100

    25

    N= 6

     

    IΣdX = 2

    Σ dY = 22

    ΣdXdY = –13.5

    Σ dX2 = 190

    Σ dY2 = 964

    A.M. of X series =20 A.M. of Y series = 45

    Question 85
    CBSEENST11024538

    Calculate the Karl Pearson’s correlation co-efficient by the assumed mean method.

    X

    85

    82

    82

    79

    80

    45

    65

    49

    85

    85

    Y

    62

    80

    80

    63

    64

    61

    68

    70

    80

    80

    Solution

    X

    Y

    dX (X-85)

    dY(Y–82)

    dXdY

    dX2

    dY2

    85

    62

    0

    – 18

    0

    0

    324

    82

    80

    –3

    0

    0

    9

    0

    82

    80

    –3

    0

    0

    9

    0

    79

    63

    –6

    – 17

    102

    36

    289

    80

    64

    –5

    – 16

    80

    25

    256

    45

    61

    – 40

    – 19

    360

    1600

    361

    65

    68

    – 20

    – 12

    240

    400

    144

    49

    70

    – 36

    – 10

    360

    1296

    100

    85

    80

    0

    0

    0

    0

    0

    85

    80

    0

    0

    0

    0

    0

       

    ΣdX= –113

    Σ dY= –92

    Σ dXdY = 1542

    Σ dX2= 3375

    ΣdY2= 1474

    Assumed mean of X = 85 Assumed mean of Y = 80

    Question 86
    CBSEENST11024539

    Write down the steps involved in calculating correlation co-efficient by step deviation method.

    Solution

    Steps involved in calculating correlation Co- efficient by step - deviation:

    1. Take the assumed mean of X series.

    2. Take the assumed mean of Y series.

    3. Calculate deviations of X and Y from assumed mean and name them dX and dY respectively.

    4. Divide dX and dY by convenient common factor to reduce the calculations. This is also called change of origin and change of scale of the values of X and Y. The value of co- efficient of correlation is unaffected by the change in origin and change of scale if X and Y. After changing the deviations we apply the same formula of assumed mean method.

    Question 87
    CBSEENST11024540

    Write down the steps involved in step deviation method of calculating correlation co-efficient.

    Solution

    Step deviation method of calculating correlation co-efficient: This method involves the following steps:

    1. Take any convenient value in X and Y series as assumeed value Ax and Ay.

    2. With the help of assumed mean of both the series, deviation of the values of individual variable i.e. dx (X-A) and dy (Y-A) are calculated.

    3. Now divide dx and dy by some common factor as dx = dx/cl and dy/c2 = where c1 is common factor for series X and C2 is common factor for series. Y ‘dx’ and dy are step deviations.

    4. Multiply the step deviations of the two series and get dx' dy'

    5. Add the dx', dy', and get Σdx'edy'

    6. Square the dx and dy' and add to find out Σdx 2 and Σdy 2

    7. Apply the following formula to calculate co- efficient of correlation.

    Question 88
    CBSEENST11024541

    Calculate correlation co-efficient by step deviation method.

    Price (Rs.)

    5

    10

    15

    20

    25

    Demand (Kg.)

    40

    35

    30

    25

    20

    Solution

    Calculation of correlation:

    Co-efficient by step deviation method

    X

    dX (.X-A)

    dX’ C1 =5

    dXz

    Y

    dY (Y-A)

    dY'C2 = 5

    dY'2

    dX'dY'

    5

    – 10

    –2

    4

    40

    10

    2

    4

    –4

    10

    –5

    – 1

    1

    35

    5

    1

    1

    – 1

    15

    0

    0

    0

    30

    0

    0

    0

    0

    20

    5

    1

    1

    25

    –5

    – 1

    1

    – 1

    25

    10

    2

    4

    20

    – 10

    -2

    4

    –4

    N = 5

     

    Σ dX' = 0

    Σ dX'2 = 10

    N = 5

     

    Σ dY' = 0

    Σ dY'2 = 10

    ΣdX' dY' = –10

    A.M. of X series = 15 A.M. of Y series = 30

    There is a perfectly negative correlation between price and quantity demanded.

    Question 90
    CBSEENST11024543

    Calculate rank correlation between A and C ranks given below.

    A

    1

    2

    3

    4

    5

    C

    1

    3

    5

    2

    4

    Solution

    A

    C

    D(A-C)

    D2

    1

    1

    0

    0

    2

    3

    – 1

    1

    3

    5

    –2

    4

    4

    2

    2

    4

    5

    4

    1

    1

         

    Σ D2 = 10

    Question 91
    CBSEENST11024544

    Two Judges in a beauty contest grant ten entries as follows. What degree of agreement is their between the judges.

    x

    1

    2

    3

    4

    5

    6

    7

    8

    9

    10

    y

    8

    4

    5

    3

    2

    1

    6

    7

    9

    10

    Solution

    Calculation of rank correlation:

    R1

    R2

    D1

    D2

    1

    8

    –7

    49

    2

    4

    –2

    4

    3

    5

    – 2

    4

    4

    3

    1

    1

    5

    2

    3

    9

    6.

    1

    5

    25

    7

    6

    1

    1

    8

    7

    1

    1

    9

    9

    0

    0

    10

    10

    0

    0

    1

    N = 10

       

    Σ D2 = 94

    Question 92
    CBSEENST11024545

    Five students have been assiemed ranks on the basis of their ability.

    Students

    A

    B

    C

    D

    E

    Ranks in Maths

    1

    2

    3

    4

    5

    Rank in Economics

    4

    2

    1

    3

    5



    Calculate rank correlation coefficient.

    Solution

    Students

    Rank in Maths R1

    Rank in Economicsn R2

    D (R2-R2)

    D2

    A

    1

    4

    –3

    9

    B

    2

    2

    0

    0

    C

    3

    1

    2

    1

    D

    4

    3

    1

    4

    E

    5

    5

    0

    0

    N = 5

         

    ΣD2=14

    Question 93
    CBSEENST11024546

    Calculate rank correlation between A and B from the following data:

    Rank A

    1

    2

    3

    4

    5

    Rank B

    2

    4

    1

    5

    3

    Solution

    Calculation of Rank correlation

    A

    B

    D

    D2

    1

    2

    – 1

    1

    2

    4

    –2

    4

    3

    1

    2

    4

    4

    5

    – 1

    1

    5

    3

    2

    4

    Total

       

    14

    Substituting these values in formula

    Question 94
    CBSEENST11024547

    We are given the percentage of marks secured by 5 students in Economics and Statistics calculate rank correlation.

    Solution

    Student

    Marks in Statistics (X)

    Marks in Economics (Y)

    Ranking in Statistics (Rx)

    Ranking in Economics (R)y

    (RD–R1)

    D2

    A

    85

    60

    1

    I

    0

    0

    B

    60

    48

    4

    5

    – 1

    1

    C

    55

    49

    5

    4

    1

    1

    D

    65

    50

    3

    3

    0

    0

    E

    75

    55

    2

    2

    0

    0

               

    Σ D2 = 2

    Question 95
    CBSEENST11024548
    Question 96
    CBSEENST11024549

    alculate rank correlation from the following:

    X

    64

    63

    39

    40

    97

    31

    07

    84

    46

    82

    Y

    26

    44

    04

    48

    65

    43

    40

    51

    11

    58

    Solution

    X

    R1

    Y

    R2

    D (R1–R2)

    D2

    64

    4

    26

    8

    –4

    16

    63

    5

    44

    5

    0

    0

    39

    8

    04

    10

    –2

    4

    40

    7

    48

    4

    3

    9

    97

    1

    65

    1

    0

    0

    31

    9

    43

    6

    3

    9

    07

    10

    40

    7

    3

    9

    84

    2

    51

    3

    – 1

    1

    46

    6

    11

    9

    – 3

    9

    82

    3

    58

    2

    1

    1

             

    Σ D2 = 58

    Question 97
    CBSEENST11024550

    Marks obtained in Maths and Economics obtained by six students are given below. Calculate rank co-efficient.

    Students

    Marks in Maths

    Marks in Economics

    A

    85

    60

    B

    60

    48

    C

    55

    49

    D

    65

    50

    E

    75

    55

    F

    90

    62

    N = 6

     

    Solution

    Calculation of Rank Correlation

    Marks in Maths X

    R1

    Marks in Economics Y

     

    D1(R1–R2)

    D2

    85

    2

    60

    2

    0

    0

    60

    5

    48

    6

    –1

    1

    55

    6

    49

    5

    1

    1

    65

    4

    50

    4

    0

    0

    75

    3

    55

    3

    0

    0

    90

    1

    62

    1

    0

    0

    1

           

    ΣD2 = 2

    Question 98
    CBSEENST11024551

    Calculate rank correlation co-efficient from the following table:

    X

    10

    12

    8

    15

    20

    25

    50

    Y

    15

    10

    6

    25

    16

    12

    8

    Solution

    X

     

    Y

     

    D (R1–R2)

    D2

    10

    6

    15

    3

    3

    9

    12

    5

    10

    5

    0

    0

    8

    7

    6

    7

    0

    0

    15

    4

    25

    1

    3

    9

    20

    3

    16

    2

    1

    1

    25

    2

    12

    4

    –2

    4

    50

    1

    8

    6

    –5

    25

             

    Σ D2 = – 48

    Question 100
    CBSEENST11024553

    Calculate the rank correlation coefficient between X and Y from the following table:

    X

    10

    20

    35

    14

    18

    21

    16

    Y

    15

    25

    18

    19

    20

    26

    17

    Solution

    X

    R1

    Y

    R2

    D(R1–R2)

    D2

    10

    7

    15

    7

    0

    0

    20

    3

    25

    2

    1

    1

    35

    1

    18

    5

    –4

    16

    14

    6

    19

    4

    2

    4

    18

    4

    20

    3

    1

    1

    21

    2

    26

    1

    1

    1

    16

    5

    17

    6

    –1

    1

             

    ΣD2 = 24

    Question 101
    CBSEENST11024554

    Calculate the co-efficient of rank correlation from the following data.

    X

    48

    33

    40

    9

    16

    16

    65

    25

    15

    57

    Y

    13

    13

    24

    6

    15

    14

    20

    9

    6

    19

    Solution

    X

    Y

    R1

    R2

    D(R1 – R2)

    D2

    48

    13

    8

    5.5

    +2.5

    6.25

    33

    13

    6

    5.5

    +0.5

    0.25

    30

    24

    7

    10

    –3.0

    9.00

    9

    6

    1

    2.5

    –1.5

    2.25

    16

    15

    3.5

    7

    –3.5

    12.25

    16

    14

    3.5

    1

    +2.5

    6.25

    65

    20

    1

    9

    +1.0

    1.00

    25

    9

    5

    4

    +1.0

    1.00

    15

    6

    7

    2.5

    –0.5

    0.25

    57

    19

    9

    8

    +1.0

    1.00

             

    Σ D2 = 39.5

    Question 102
    CBSEENST11024555

    Calculate the co-efficient of rank correlation from the following data:

    Marks in Maths

    29

    32

    53

    47

    45

    32

    70

    45

    70

    53

    Marks in Hindi

    36

    60

    72

    48

    72

    35

    67

    67

    75

    31

    Solution

    Calculation of co-efficient of Rank correlation

    X

    Y

    R1

    R2

    D(R1– R2)

    D2

    29

    36

    10

    7.0

    +3.0

    9.00

    32

    60

    8.5

    6.0

    +2.5

    6.25

    53

    72

    3.5

    2.5

    +1.0

    1.00

    47

    48

    5.0

    8.0

    +3.0

    9.00

    45

    72

    65

    2.5

    +4.0

    16.00

    32

    35

    8.5

    9.0

    –0.5

    0.25

    70

    67

    1.5

    4.5

    –3.0

    9.00

    45

    67

    6.5

    4.5

    +2.0

    4.00

    70

    75

    1.5

    1.0

    +0.5

    0.25

    53

    31

    3.5

    19.0

    –6.5

    42.25

             

    Σ D2 = 97.00

    Question 104
    CBSEENST11024557

    Write down the degree of correlation.

    Solution

    Degree of correlation:1. Perfect correlation, 2. Absence of correlation, 3. Limited degree of correlation.

    Question 105
    CBSEENST11024558

    Write down the types of limited degree of correlation.

    Solution

    Types of limited degree of correlation:

    1. High degree of correlation, 2. Moderate degree of correlation, 3. Low degree of correlation.

    Question 106
    CBSEENST11024559

    What do you mean by positive correlation?

    Solution

    Positive correlation means that related variables move in the same direction.

    Question 108
    CBSEENST11024561

    Write down the methods of measurement of correlation.

    Solution

    Methods of measurement of correlation : (i) Scatter diagram, (ii) Graphic method, (iii) Karl Pearson’s coefficient of correlation, (iv) Spearman’s rank difference method.

     

    Question 109
    CBSEENST11024899

    Define correlation.

    Solution

    According to Croxton and Cowden, correlation is defined as “When the relationship is of a quantitative nature, the appropriate statistical tool for discovering and measuring the relationship and expressing it in a brief formula is known as correlation.”

    Question 110
    CBSEENST11024900

    What are the principal methods of calculating coefficient of correlation?

    Solution

    These are principal methods as under:

    (i) Scattered Diagram Method.

    (ii) Karl Pearson’s Co-efficient of Correlation.

    (iii) Spearman’s Rank Correlation Coefficient.

    Question 111
    CBSEENST11024901

    What is the difference between positive and negative correlation?

    Solution

    When two variables move in same direction, such a relation is called positive correlation. For example relationship between price and supply. When two variables change in diffdrent directions, it is called negative correlation. For example relationship between price and demand.

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