Chemistry I Chapter 5 Surface Chemistry
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    NCERT Solution For Class 12 Chemistry Chemistry I

    Surface Chemistry Here is the CBSE Chemistry Chapter 5 for Class 12 students. Summary and detailed explanation of the lesson, including the definitions of difficult words. All of the exercises and questions and answers from the lesson's back end have been completed. NCERT Solutions for Class 12 Chemistry Surface Chemistry Chapter 5 NCERT Solutions for Class 12 Chemistry Surface Chemistry Chapter 5 The following is a summary in Hindi and English for the academic year 2021-2022. You can save these solutions to your computer or use the Class 12 Chemistry.

    Question 1
    CBSEENCH12006411

    Why are substances like platinum and palladium often used for carrying out electrolysis of aqueous solutions?

    Solution

    Answer:

    The Plantium and palladium are used for electrolysis of aqueous solution due to the chemically inert in nature and good adsorptive capacity for hydrogen.
    Because Gases like hydrogen are absorbed on the surface of platinum and palladium (adsorption) and then passes into the bulk of the adsorbent (platinum and palladium).

     
    Question 2
    CBSEENCH12006412

    Why does physisorption decrease with the increase of temperature?

    Solution
    Answer:

    It is because physical adsorption involves weak forces of attraction between adsorbent and adsorbent molecules, generally of Vander Waal's type. These forces decrease rapidly with increase in temperature.
    Question 3
    CBSEENCH12006413

    Why are powdered substances more effective adsorbents than their crystalline forms?

    Solution
    Answer:
    Powderded substance are more effective adsorbent than their crystalline forms because when a substance is powdered its surface area increase and physisorption is directly proportional to the surface area of adsorbent,
    Question 4
    CBSEENCH12006414
    Question 5
    CBSEENCH12006415

    Why is the ester hydrolysis slow in the beginning and becomes faster after sometime?

    Solution
    Answer:

    Ester + water ---> Acid + Alcohal
    The acid produced in the reaction acts as a catalysis and makes the reaction faster.

    Question 6
    CBSEENCH12006416

    What is the role of desorption in the process of catalysis?

    Solution
    Answer:

    The role of desorption in the process of catalysis is to release the adsorbed substance into the surrounding medium.
    Question 7
    CBSEENCH12006417

    Solution
    Answer;
    The greater the valence of the flocculating ion added, the greater is its power to cause precipitation.
    Question 8
    CBSEENCH12006418

    Why is it essential to wash the precipitate with water before estimating it quantitatively?

    Solution
    Answer:

    When a colloidal solution is prepared, quite often it contains certain impurities of electrolytes which are crystalloidal in nature and tend to destabilize the solution. Hence it is essential to wash the precipitate with water before estimating it quantitatively to remove impurities of electrolytes.
    Question 9
    CBSEENCH12006419

    What is adsorption?

    Solution
    Answer:

    The phenomenon of attracting and retaining the molecules of a substance on the surface of a solid or liquid resulting in a higher concentration of the molecules on the surface is called adsorption.
    Question 10
    CBSEENCH12006420

    What do you mean by adsorbent and adsorbate?

    Solution
    Answer:

    The substance adsorbed on the surface is called the adsorbate and the substance on which it is adsorbed is called adsorbent.
    Question 11
    CBSEENCH12006421

    What is desorption?

    Solution
    Answer:

    The process of removing an adsorbed substance from the surface on which it is adsorbed is called desorption.
    Question 12
    CBSEENCH12006422

    Define physical and chemical adsorption.

    Solution
    Answer:

    If the adsorbate is held on the surface by weak Van der Waal’s forces, the process is called physical adsorption.

    When an adsorbate is held on the surface of the adsorbent by chemical forces, it is called chemical adsorption.
    Question 13
    CBSEENCH12006423

    Is adsorption exothermic or endothermic?

    Solution
    Answer:
    Adsorption is always exothermic. This statement can be explained in two ways.

    (i)Adsorption leads to a decrease in the residual forces on the surface of the adsorbent. This causes a decrease in the surface energy of the adsorbent. Therefore, adsorption is always exothermic.


    (ii)ΔH of adsorption is always negative. When a gas is adsorbed on a solid surface, its movement is restricted leading to a decrease in the entropy of the gas i.e., ΔS is negative. Now for a process to be spontaneous, ΔG should be negative.

    ΔG= ΔH-TΔS
    Since ΔSis negative, ΔH has to be negative to make ΔG negative. Hence, adsorption is always exothermic.

    Question 14
    CBSEENCH12006424

    What is an adsorption isotherm and isobar?

    Solution
    Answer:

    The variation in the amount of gas adsorbed by the adsorbent with pressure at constant temperature can be expressed by means of a curve termed as adsorption isotherm.

    A plot of the amount of gas adsorbed x / m against the pressure at constant temperature is called an adsorption isotherm.


    A plot of the amount adsorbed x / m versus temperature at constant pressure is called an adsorption isobar.
    Question 15
    CBSEENCH12006425

    What are the physical states of dispersed phase and dispersion medium of froth?

    Solution
    Answer:

    in froth, the (i) dispersed phase is gas (ii) dispersion medium is liquid.
    Question 16
    CBSEENCH12006426

    Name a few common adsorbents.

    Solution
    Answer:

    Charcoal, silica gel, alumina gel, clay, etc. are common adsorbents.
    Question 17
    CBSEENCH12006427

    What property must a good adsorbent have?

    Solution
    Answer:

    They should have highly porous structure and hence has large surface area to show capillary condensation.

    Sponsor Area

    Question 18
    CBSEENCH12006428

    Why colloids are regarded as very good adsorbents?

    Solution

    Answer:


    Colloids possess high surface area per unit mass and are therefore called good adsorbents.

    Question 19
    CBSEENCH12006429

    What do you mean by sorption?

    Solution
    Answer:

    Sorption is a phenomenon in which adsorption and absorption takes place simultaneously.
    Question 20
    CBSEENCH12006430

    How do the surface molecules have the tendency of adsorption?

    Solution
    Answer:

    The molecules present on the surface of the liquid or solid experience unequal downward pull by bulk molecules and thus have strain 08 tension. This strain or tension is responsible for attracting and retaining the molecules on their surface.
    Question 21
    CBSEENCH12006431

    What are homogeneous and heterogeneous catalysts?

    Solution
    Answer:
    When the reactants and the catalyst are in the same phase (i.e., liquid or gas), the process is said to be homogeneous catalysis.

    2SO2(g) + O2(g)     NO(g)  2SO3(g)

    The catalytic process in which the reactants and the catalyst are in different phases is known as heterogeneous.

    2SO2(g)      Pt(s)  2SO3(g)

    Question 22
    CBSEENCH12006432

    What are Zeolites?

    Solution
    ANswer:

    Zeolites are aluminosilicates, i.e., three dimensional network silicates in which some silicon atoms are replaced by aluminium atoms. They are shape selective catalysts, i.e., only those molecules having a size, small enough to pass their pores are adsorbed by them.
    Question 23
    CBSEENCH12006433

    Write the Freundlich adsorption isotherm for the adsorption from solution.

    Solution
    Answer:

    For the adsorption from solution, Freundlich’s adsorption isotherm has the expression.


    xm=kc1/n       where n>1c = concentration.
    Question 24
    CBSEENCH12006434

    Give the Langmuir adsorption isotherm expression for the adsorption from solutions.

    Solution
    Answer:

    The expression for the adsorption from solution given by Langmuir is
    xm=aC1+bC,
    where a and b are Langmuir constants. c = concentration.
    Question 25
    CBSEENCH12006435

    Why catalyst are required in very small non-stoichiometric quantities?

    Solution
    Answer:
    Catalyst only alter the reaction thus 
    Catalysts are required in very small non-stoichiometric quantities because they are not consumed during the reaction.
    Question 26
    CBSEENCH12006436

    What are enzymes?

    Solution
    Answer:

    Enzymes are biological catalysts which increase the rate of cellular reactions.
    Example

    Inversion of cane sugar: The invertase enzyme converts cane sugar into glucose and fructose
    C12H22O11(Aq) + H2O(l) Invertase  C6H12O6 (aq) +  C6H12O6 (aq) Cane sugar                                        Glucose                Fructose

    Question 27
    CBSEENCH12006437

    Name some solid catalysts.

    Solution
    Answer:

    Metals like (Pt, Pd, Ni) metal oxides, metal sulphides, clay etc are common solid catalysts.
    Question 28
    CBSEENCH12006438

    What is meant by the term ‘peptization’?

    Solution
    Answer:

     It may be defined as a process of converting a precipitate into colloidal sol by shaking it with dispersion medium in the presence of small amount of electrolyte known as peptising agent and  the process is known as Peptization. 
    Question 29
    CBSEENCH12006439

    How does BF3 act as a catalyst in industrial process?

    Solution
    Answer:

    It is electron deficient i.e., Lewis acid, therefore used to generate electrophile in Friedel Craft's reaction.
    Question 30
    CBSEENCH12006440

    What happens when an electric field is applied to a colloidal dispersion?

    Solution
    Answer:

    The colloidal particles move towards one of the electrodes depending upon their charge. If they are + vely charged they move towards negative electrode i.e., electrophoresis takes place.
    Question 31
    CBSEENCH12006441

    Give an example of an associated colloid.

    Solution
    Answer:

    substances which behave as strong electrolytes at low concentration, but show colloidal properties at high concentration due to aggregated particle formation. The aggregated particles formed in such a manner are called associated colloids or micelles.
    In general, these associated colloids are formed by soaps and synthetic detergents.
    Question 32
    CBSEENCH12006442

    Mention an application of emulsions.

    Solution
    Answer:

    Emulsion of Cod liver oil is used as medicine.
    Question 34
    CBSEENCH12006444

    Why is a catalyst, in general in the form of finely divided powder?

    Solution
    Answer:

    Finely divided powders have large surface area. This increases the extent of reaction appereciably.
    Question 35
    CBSEENCH12006445

    How does the emulsification of fats take place in the intestines?

    Solution
    Answer:

    Digestion of fats in the intestines is aided by emulsification. A small quantity of the fat forms sodium soap with the alkaline solution of the intestine and this soap emulsifies the rest of the fat.
    Question 36
    CBSEENCH12006446

    Which colloidal system is represented by butter?

    Solution
    Water in solid fat: Gel.
    Question 37
    CBSEENCH12006447

    Why do colloidal solution exhibit Tyndall effect?

    Solution
    Answer:

    It is due to scattering of light by colloidal particles.It occur when the dimension of the particels that are causing the scattering are 10-9 m to 10-6m.
    Question 38
    CBSEENCH12006448

    State any one characteristic of enzymatic catalysis.

    Solution
    Answer:

    They are highly specific in their action.
    Question 39
    CBSEENCH12006449

    What is the cause of Brownian movement observed in colloidal solutions?

    Solution
    Answer:
    It is due to collision between molecules of colloidal particles among themselves as well as with particles of dispersion medium.

    Sponsor Area

    Question 40
    CBSEENCH12006450

    What is the sign of ΔH and ΔS when bromine gas gets absorbed on charcoal?

    Solution
    Answer:

    ΔH is negative and ΔS positive.
    Question 41
    CBSEENCH12006451

    Why is a lyophilic colloid more stable than a lyophobic colloid?

    Solution
    Answer:

    Lyophilic sols are relatively stable as strong forces of interaction exist between colloidal particles and liquid.
    lyophobic sols are less stable as weak forces of interaction exist between colloidal particles and liquid.
    Question 42
    CBSEENCH12006452

    What is an aerosol?

    Solution
    Answer:

    Aerosol is a colloidal solution of liquid dispersed in gaseous medium.
    Question 43
    CBSEENCH12006453

    What is a gel? Give one example?

    Solution
    Answer:

    Gel can be defined as  Liquid dispersed in solid is. For example: butter.
    Question 44
    CBSEENCH12006454

    What do you mean by the selectivity of the catalyst?

    Solution
    Answer:

    Selectivity is the ability of the catalyst to direct a reaction to yield a particular product.

    for example by using different catalyst we can get different product for the reaction between hydrogen and carbon monoxide.
    CO(g) + 3H2(g) Ni CH4(g) + H2O(g)CO(g) + 3H2(g)      CuZno-CrO3  CH3OHCO(g) + 3H2(g)  Cu HCHO(g)
    Question 45
    CBSEENCH12006455

    Deltas are formed where the river and sea water meet. Give reasons.

    Solution
    River water is a negatively charged colloidal solution of silicates dispersed in water and sea water contains Ca2+ and Mg2+, so coagulation takes place.
     thus resulting the depostion of particles forming a delta.
    Question 46
    CBSEENCH12006456

    What is the effect of increase of temperature on the adsorption of a gas on a solid surface?

    Solution
    Answer:

    With the increase of temperature the extent of physical adsorption of a gas on a solid surface decreases, while in case of chemical adsorption it first increases aand then decreases.
    Question 47
    CBSEENCH12006457

    Write the name of the states of (i) dispersed phase and, (ii) dispersion medium in the case of butter.

    Solution

    Answer:

    In butter, the
    (i) dispersed phase is water.
    (ii) dispersion medium is solid fat and proteins.

    Question 48
    CBSEENCH12006458

    Write a mathematical expression showing relationship between the amount of solute adsorbed per unit mass of the solid adsorbent and the concentration of the solute in solution.

    Solution
    Answer:

    Freundlich adsorption isotherm: Freundlich gave an
    empirical relationship between the quantity of gas adsorbed by unit mass of solid adsorbent and pressure at a particular temperature. The relationship can be expressed by the following equation


    xm=kP1/η.

    where x is mass of the gas absorbedon mass m of the absorbent at pressure P 
    k and n are constant depends on the nature of adsorbent and gas at particular temperature.
    Question 49
    CBSEENCH12006459

    What do x and m represent in the following expression:
    xm=kP1/n?

    Solution
    Answer:

    x represents the mass of adsorbate.
    m represents the mass of adsorbent.
    Question 50
    CBSEENCH12006460

    What are emulsifiers?

    Solution
    Answer:

    The substance added to stabilize the emulsions are called emulsifiers.
    Question 51
    CBSEENCH12006461

    What happens when a freshly precipitated Fe(OH)3 is shaken with little amount of dilute solution of FeCl3?

    Solution
    Answer;
    when freshly precipitated  Fe(OH)
    3 is shaken with little amount of dilute solution of FeCl3 (electrolyte ) peptization prcess take place by converting the Fe(OH)3 precipitate into colloidal solution. 
    Question 52
    CBSEENCH12006462

    Which will adsorbe more a lump of charcoal or charcoal powder, and why?

    Solution
    Answer:

    Adsorption is more in Charcoal powder because it has greater surface area, therefore greater Van der Waal's attraction.
    Question 53
    CBSEENCH12006463

    Draw a plot of variation in the quantity of the gas absorbed (x/m) with the pressure of the gas?

    Solution
    Answer:


    Freundlich adsorption isotherm the relationship is given by 

    xm = k.p1n 





     
    Question 54
    CBSEENCH12006464

    What is observed when sodium chloride is added to ferric hydroxide sol?

    Solution
    Answer:

    when sodium chloride is added to ferric hydroxide solution coagulation of reddish-brown precipitate of ferric hydroxide take place.
    Question 55
    CBSEENCH12006465

    Give one difference between sol and gel.

    Solution
    Answer:

    In sol dispersing phase is solid and dispersing medium is liquid.
    In gel dispersing phase is liquid and dispersing medium is soild. 
    Question 56
    CBSEENCH12006466

    What are macro-molecular colloids? Give one example.

    Solution
    Answer:

    In macro - molecular colloids, the colloidal particles are molecule having colloidal dimension. These particles have ahigh molecular mass, when these particles are dissolved in liquid sol is obtained. example of macro-molecule are  starch, protein fiber etc.
    Question 57
    CBSEENCH12006467

    Derive the variation of x/m versus temperature for physical adsorption process. Explain the nature of the curve.

    Solution

    Answer:

    Freundlich adsorption isotherm: Freundlich gave an empirical relationship between the quantity of gas adsorbed by a unit mass of solid adsorbent and pressure at a particular temperature. The
    relationship can be expressed by the following equation:
    straight x over straight m space equals straight k. straight p to the power of 1 divided by straight n end exponent
    where x is the mass of the gas adsorbed on mass m of the adsorbent at pressure P, k and n are constants which depend on the nature of the adsorbent and the gas at a particular

    temperature. The relationship is generally represented in the form of a curve where the mass of the gas adsorbed per gram of the adsorbent is plotted against pressure.


    At low pressures: x/m varies linearly with p 

    straight x over straight m space equals kP space
straight k space is space constant

    At high pressures :  x/m is independent of p 
     

    straight x over straight m proportional to space straight P
fraction numerator begin display style straight x end style over denominator begin display style straight m end style end fraction equals space space kP

    At intermediate pressures:  The variation of x/m vs p can be expressed as
    straight x over straight m proportional to space straight P to the power of 1 divided by straight n end exponent
fraction numerator begin display style straight x end style over denominator begin display style straight m end style end fraction equals space kP to the power of 1 divided by straight n end exponent
straight n greater than 1
Now comma space taking space log
log straight x over straight m space equals space log space straight k space plus space 1 over straight n space log space straight P
    comparing the above-given equation with the equation of a straight line 

    y = mx + c

    we know that, if we plot log p vs log x/m, we would get a straight line with slope equal to 1/n and intercept log k

    Since adsorption is always an exothermic process, therefore, increase in temperature should decrease the amount adsorbed.

    Question 58
    CBSEENCH12006468

    What is common in aqua-sols and solid aerosols? Also find the point of distinction between them.

    Solution

    Common: The dispersed phase which is a solid.
    Difference: In aqua-sols the dispersion medium is water while in aerosols it is air.

    Question 59
    CBSEENCH12006469

    What is electrophoresis due to?

    Solution
    Answer:

    It is due to charge on colloidal solution.
    Question 60
    CBSEENCH12006470

    Give one example each of positively charged sol and one example of negatively charged sol:

    Solution
    Answer:

    Fe(OH)
    3 is positively charged whereas As2 ,S2. is a negatively charged colloid.
    Question 61
    CBSEENCH12006471

    How does chemical adsorption of a gas on a solid vary with temperature?

    Solution
    Answer:

    Chemical adsorption of a gas on solid first increases and then decreases with increase in temperature.



    Question 62
    CBSEENCH12006472

    What is meant by ‘Shape selective’ catalysis?

    Solution
    Answer:

    The catalytic reaction that depends upon the structure of pores of the catalyst and the size of the reactant and product molecules is called shape/selective catalysis. Zeolites are good shape/selective catalysts because of their honeycomb-like structures.
    Question 63
    CBSEENCH12006473

    Define the enthalpy of adsorption.

    Solution
    Answer:
    It is defined as Amount of  heat released when 1 mole of substance get adsorbed on large amount of adsorbent.
    Question 64
    CBSEENCH12006474

    Write down the heterogeneous catalyst involved in the polymerisation of ethylene.

    Solution
    Answer:

    (R
    3Al + TiCl4), Zigglar Natta catalyst.
    Question 65
    CBSEENCH12006475

    Of NH3 and N2 which gas will be absorbed more readily on the surface of charcoal and why?

    Solution
    Answer:

    NH
    3 will be adsorbed more easily due to more surface area. Therefore, it has more Van der Waal's forces of attraction and easily liquefiable as compared to N2.
    Question 66
    CBSEENCH12006476

    What is the range for the enthalpy of adsorption for physisorption and chemisorption?

    Solution
    Answer:

    ΔH
    adsor for physisorption is in the range of 20-40 kJ/mol .
    This is because the attraction between gas molecules and solid surface is only due to weak van der Waals’ forces.

    chemisorption it is 40-400 kJ/mol.
    Enthalpy of chemisorption is highn as it involves chemical bond formation


    Question 67
    CBSEENCH12006477

    Lyophilic sols are reversible whereas lyophobic sols are irreversible. Why?

    Solution
    Answer:

    Lyophilic : Reversible, because on evaporating the liquid, the residue left will passes into colloidal state on addition of liquid.

    Lyophobic : Irreversible, because on evaporating the liquid, the residue left cannot be converted into solution on mere addition of liquid.

    Question 68
    CBSEENCH12006478

    Why does chemisorption have more heat of adsorption than physico-adsorption?

    Solution
    Answer:

    Chemisorption involves strong forces of attraction along with exchange of electrons at free valencies.
    Question 69
    CBSEENCH12006479

    Colloidal solution can be had in a water and in air as media. What distinctive names are given to these two types of sols?

    Solution
    Answer:

    Colloidal solutions with water as dispersion medium are called hydrosols and air as dispersion medium are called aerosols.
    Question 70
    CBSEENCH12006480

    Which sol is more stable-lyophilic or lyophobic?

     

    Solution
    Answer:

    Lyophilic : Lyophilic sols are relatively stable as strong forces of interaction exist between colloidal particles and liquid.
    Question 71
    CBSEENCH12006481

    Write one example of each category in which sols particles carry – ve and + ve charges.

    Solution
    Answer:

    Fe(OH)
    3 sol (+ ve)
    As
    2S3 sol (– ve).
    Question 72
    CBSEENCH12006482

    Give one example each of W / O and O / W emulsion.

    Solution
    Answer:

    Water in oil  W / O—Butter
    oil in water  O / W—Milk.
    Question 73
    CBSEENCH12006483

    Which names are given if sols have dispersion medium of (a) H2O, (b) alcohol, (c) benzene?

    Solution
    Answer:

    (a) Hydrosols
    (b) Alcosol
    (c) Benzosol.
    Question 74
    CBSEENCH12006484

    Write the order of effectiveness of the equimolar solutions of following electrolytes for coagulating a negatively charged sol.
    FeCl3, NaCl, BaCI2, Th(NO3)4.

    Solution
    Answer:
    Acoording to the Hardy- Schulz rule the coagulation capacity depends on the valence of the active ion.thus  order is:

    Th(NO
    3)4 > FeCl3 > BaCl2 > NaCl.
    Question 75
    CBSEENCH12006485

    Why are lyophilic sols self-stabilized?

    Solution
    Answer:

    It is due to force of attraction between dispersed phase and dispersion medium.
    Question 76
    CBSEENCH12006486

    A sol is prepared by addition of excess of AgNO3 solution in KI solution. What charge is likely to develop on the colloidal particles?

    Solution
    Answer:

    AgNO3 Solution is added to aqueous KI solution, negatively charged sol of AgI is formed this is due to selective adsorption of I- ion from the dispersion medium.

    AgI + I- ---> [AgI]I-
    Question 77
    CBSEENCH12006487

    How can a colloidal solution and true solution of the same colour be distinguished from each other?

    Solution
    Answer:

    A colloidal solution and true solution of the same colour can be distinguished from each other by  the help of Tyndall effect.
    Question 78
    CBSEENCH12006488

    Write the reaction in which bismuth molybdate is used as a catalyst.

    Solution
    CH3CH=CH2+O2 Bi Mo O4CH2 = CHCHO+H2O
    Question 79
    CBSEENCH12006489

    What is the difference in the nature of a dilute soap solution and a concentrated soap solution?

    Solution
    Answer:

    Dilute soap solution behaves like a true solution whereas concentrated soap solution behaves like a colloidal solution.

    Sponsor Area

    Question 80
    CBSEENCH12006490

    Give an example of (i) micelles system (ii) macromolecular colloid.

    Solution
    Answer:

    (i) Sodium stearate (C
    17H35COONa+)
    (ii) Proteins.
    Question 81
    CBSEENCH12006491

    What is colloidion?

    Solution
    Answer:

    Colloidion is cellulose nitrate peptized by ethanol.
    Question 82
    CBSEENCH12006492

    Which of the following is adsorbed preferably: O2, NH3, CO?

    Solution
    Answer:

    NH
    3. It is because more easily liquifiable gas is adsorbed preferably. Among given gases, NH3 is most easily liquified.
    Question 83
    CBSEENCH12006493

    Why is a substance more effective in colloidal state?

    Solution
    Answer:

    A substance of colloidal state is more effective due to large surface area.
    Question 84
    CBSEENCH12006494

    Why is catalyst, in general, taken in the form of finely divided powder?

    Solution
    Answer:

    Catalyst when taken in the form of finely divided powder, it has large surface area. Large the surface area, more will be activity as catalyst.
    Question 85
    CBSEENCH12006495

    Suggest a physical method for the preparation of phosphorus sol.

    Solution
    Answer:

    Method of solvent exchange. Prepare a saturate solution of phosphorus in alcohol and then water slowly.
    Question 86
    CBSEENCH12006496

    What name is given to sol in which benzene is dispersion medium?

    Solution
    Answer:
    When benzene is in dispersion medium,Sol is called benzosol.
    Question 87
    CBSEENCH12006497

    What is occulusion?

    Solution
    Answer:
    Adsorption of gases on the surface of metals is called occlusion.
    Question 88
    CBSEENCH12006498

    Give an example of a shape-selective catalyst.

    Solution
    Answer:

    Zeolites (ZSM-5 preparation of gasoline from methanol).
    Question 89
    CBSEENCH12006499

    How can dialysis be made fast?

    Solution
    Answer:

    Dialysis can be made faster in electric field.
    Question 90
    CBSEENCH12006500

    Give an example of peptizing agent?

    Solution
    Answer:
    FeCl
    3 is peptizing agent in Fe(OH)3 sol.
    Question 91
    CBSEENCH12006501

    Why are lyophilic sols self-stabilised?

    Solution
    Answer:

    It is due to force of attraction between dispersed phase and dispersion medium.They are self stabilised because of strong attractive forces operating between the suspended particels and dispersion medium. for example gums, gelatin etc.
    Question 92
    CBSEENCH12006502

    Sky appears blue in colour. Why?

    Solution
    Answer:

    Sky appears blue in colour due to scattering of light by colloidal particles. It is called Tyndall effect.
    Question 93
    CBSEENCH12006503

    Explain the following observations:
    (a) Cottrell’s smoke precipitator is fitted at the mouth of the chimney used in factories.
    (b) Physical adosption is multi layered, while chemisorption non-tayered. 

    Solution

    Answer:

    (a) Smoke contains positively charged colloidal particles which are separated by Cottrell’s smoke precipitator.

    (b) Physical adsorption is multilayered because forces between adsorbate and adsorbent molecules are of Vander Waal's type. Chemisorption is non-layers because forces of attraction are of chemical bond type.

    Question 94
    CBSEENCH12006504

    What causes Brownian movement in a colloidal solution?

    Solution
    Answer:

    Brownian movement is caused due to the collision between the molecules of dispersion medium and chemical particles.
    Question 95
    CBSEENCH12006505

    Which has a higher enthalpy of adsorption, physisorption or chemisorption? 

    Solution
    Answer:
    Chemisorption has a higher enthalpy of adsorption.  Because it involves chemical bond formation.
    Question 96
    CBSEENCH12006506

    Describe ‘electrophoresis briefly’.

    Solution
    The phenomenon of movement of colloidal particles under an applied electric field is called electrophoresis.

    When electric potential is applied across two palantium electrodes across two plantium electrodes depping in colloidal solution.
    The movement of colloidal particles move towards one or other electrode.
    positively charged particles move towards the cathode while negtive charged particles moves towards the anode.


    The given figure shows the phenomenon of electrophoresis.
    Question 97
    CBSEENCH12006507

    Distinguish between the meaning of the terms adsorption and absorption. Give one example of each.

    Solution
    Answer:

    Absorption

    Adsorption

    1. It is the phenomenon in which the particles of gas or liquid get uniformly distributed throughout the body of the solid.

    2. The concentration is the same through the material. Therefore, it is a bulk phenomenon.

    3. Absorption occurs at uniform rate.

    1. It is the phenomenon of higher concentra-tion of particles of gas or liquid on the surface than in the bulk of the solid.

    2. The concentration on the surface of the adsorbent is different from that in the bulk. Therefore, it is a surface phenomenon.

    3. Adsorption is rapidly in the beginning and its rate slowly increases.

    Example of adsorption: NH3, adsorbed by charcoal, H2O adsorbed by silica, ink adsorbed by chalk.
    Example of absorption: NH3 absorbed by water, water absorbed by anhydrous CaCl2, water absorbed by a sponge.

    Question 98
    CBSEENCH12006508

    What is the difference between physisorption and chemisorption?

    Solution
    Answer:

    Physisorption

    Chemisorption

    1. The forces of attraction between adsorbent and adsorbate are of Van der Waals type (weak forces).

    2. This predominates at low temperatures.

    3. Almost all gases show this type of adsorption at low temperatures.

    4. The heat of adsorption is low and has a value of about 40 kJ per mole or less.

    5. This type of adsorption attains equilibrium very rapidly on changing the temperature and pressure of the system.

    6. This is reversible in nature.

    7. The activation energy involved in this adsorption is small and is often less than 5 kJ. It is for this reason, this is even attained at low temperatures.

    8. Adsorption in this case is often multilayer.

    1. The forces of attraction between adsorbent and absorbate are of a chemical nature (strong forces).

    2. This usually occurs at high temperatures.

    3. It is highly specific in nature.

    4. The heat of adsorption is high and has a value of the order of 80 to 420 kJ per mole.

    5. This type of adsorption is relatively slower.

    6. This is usually irreversible in nature. For example, O2 adsorbed on charcoal, when adsorbed also releases CO and CO2.

    7. The activation energy involved in this adsorption is high. It is for this reason, it is attained only at high temperatures.

    8. Adsorption in this case in monolayer.

    Question 99
    CBSEENCH12006509

    Give reason why a finely divided substance is much more effective as an adsorbent. 

    Solution
    Answer:
    Adsorption is surface phenomenon therefore adsorption is directly proportional to the surface area.
    Finely divided substance has greater surface area. Greater is the surface area of the adsorbent, greater would be its absorbent power. That is why a finely divided surface is more effective as an absorbent.
    Question 100
    CBSEENCH12006510

    What are the factors which influence the adsorption of a gas on a solid?

    Solution

    Answer:
    The factors which influence the adsorption of a gas on a solid are:
    (1) The nature of a gas adsorbate and nature of solid adsorbent.
    (2) Surface area of adsorbent.
    (3) Pressure of gas.
    (4) Temperature.
    (5) Activation of adsorbent.

    Question 101
    CBSEENCH12006511

    What is an adsorption isotherm ? Describe Freundlich adsorption isotherm. 

    Solution
    Adsorption isotherm: A graph between the extent of adsorption (x / m) and the pressure ‘p’ of the gas at constant temperature is called adsorption isotherm.


    Freundlich Isotherm: The relationship between x/m and pressure of the gas at constant temperature is called adsorption isotherm and given as by  straight x over straight m space equals space kp to the power of 1 divided by straight n end exponent space left parenthesis straight n greater than 1 right parenthesis and n depend upon the nature of gas and the solid.

    x/m first increase with the increase in pressure at low pressure but becomes independent of pressure at high pressure.
    Thus three cases arise from the graph

    At low pressure, the extent of adsorption is directly proportional to pressure (raised to power one).

    straight x over straight m proportional to straight P to the power of 1
    At high pressure, the extent of adsorption is independent of pressure (raised to power zero).

    straight x over straight m proportional to straight P to the power of 0

    Therefore at an intermediate value of pressure, adsorption is directly proportional to pressure raised to power 1/n.Here n is a variable whose value is greater than one.

    therefore space straight x over straight m space proportional to space straight P to the power of 1 divided by straight n end exponent

    Using constant of proportionality, k, also known as adsorption constant we get

    straight x over straight m equals space kP to the power of 1 divided by straight n end exponent

    The above equation is known as Freundlich adsorption equation.

    As per Freundlich adsorption equation

    straight x over straight m equals space kP to the power of 1 divided by straight n end exponent


    Taking logarithm on both sides, we get
    log space straight x over straight m space equals space log space straight k space plus space 1 over straight n space log space straight p

    Here x is the weight of the gas absorbed by m mass of the adsorbent at a pressure p, k and n are constant (at a particular temperature) and for a particular adsorbate-adsorbent pair.

    The equation above equation is comparable with comparable with the equation of a straight line,
    y = m x + c where m represents the slope of the line and c represents intercept on y-axis.

    Plotting a graph between log(x/m) and log p, we will get a straight line with the value of slope equal to 1/n and log k as y-axis intercept.


    log(x/m) vs. log p graph.
    Question 102
    CBSEENCH12006512

    What do you understand by activation of adsorbent? How is it achieved?

    Solution

    Answer:
    Activation of adsorbent implies increasing its adsorbing power. It is achieved by the following ways:

    (i) Activation of the adsorbent is carried out by mechanical rubbing or by subjecting it to some chemical reaction.

    (ii) Some adsorbents are activated by strong heating in contact with super-heated steam. For example, charcoal which is commonly employed in adsorption of gases, is activated by subjecting it to the action of superheated steam. This will remove the molecules of gases like CH4, C2H6 (hydrocarbons) that are occupying these pores.

    (iii) To increase the adsorbing power, the adsorbent is sub divided into small fine pieces. By doing so, the surface area increases and so is the adsorbing power.

    Question 103
    CBSEENCH12006513

    What role does adsorption play in heterogeneous catalysis?

    Solution

    Answer:

    Adsorption plays an important role in heterogeneous catalysis. Adsorption is surface phenomenon in which the substances (reactants) get concentrated only on the surfaces of solid adsorbents and do not penetrate into it.This increases concentration of reactants and there is a great probability of occurrence of reaction. The catalyst adsorbs reactants and forms a intermediate compound known as activated complex. Following are various ways in which catalytic adsorption increases the reaction rate:
    (i) The concentration of reactants on surface of solid adsorbent increases and it becomes easier for molecules to attack each other for effective collisions, forming products.

    (ii) A particular part of reactant molecule may come in contact with other molecules which otherwise is difficult.

    (iii) Some adsorbed molecules dissociate into atoms or free radicals which are very reactive and thus increase the reaction rate.

    (iv) Heat of adsorption released provides activation energy for formation of activated complex and then increase the rate of reaction.

    Question 104
    CBSEENCH12006514

    Why is adsorption always exothermic?

    Solution

    Answer:
    Adsorption is always exothermic, this statement can be explained by two.
    i) Adsorption leads to a decrease in the residual forces on the surface of the adsorption.
    This cause a decrease in the surface energy of the adsorption therefore adsorption is always exothermic.
     ii) ΔH of adsorption is always negtive.
    When a gas is adsorbed on a soild surface its movement is restricted leading to decrease in the entropy of the gas i.e. ΔS
    Adsorption is accompanised by decrease in entropy, i.e., ΔS = – ve. If it is spontaneous then ΔG should be negative.
    ΔG = ΔH – TΔS
    Since ΔS is – ve, ΔG will be – ve only if
    ΔH = – ve, i.e., if process is exothermic.

    Question 105
    CBSEENCH12006515

    How are the colloidal solutions classified on the basis of physical states of the dispersed phase and dispersion medium? 

    Solution

    Answer:
    A dispersed phase or dispersion medium in colloidal solution may be a solid, liquid or gas. Based on physical states, 8 types of colloidal systems are possible (gas in gas is not possible as gases are always miscible in all proportions forming homogeneous mixure). All other takes of combinations of gases, liquids and solids may exist as colloidal solutions. Examples are given in the following table:

    Internal phase of Dispersed phase

    External phase or Dispersion medium

    Colloidal name

    Example

    Solid

    Solid

    Solid sols

    Alloys, Ruby glass, Gems or precious stones, marbles, optical and vision glasses.

     

    Liquid

    sols

    Muddy water, gold sol, protein, starch, agar, gelatin in water, paints, pigments in water.

     

    Gas

    Aerosols (or solids

    Smoke, particulate clouds.

    Liquid

    Solids

    Gels

    Cheese, jems, jellies, plants, fruits, vegetables

     

    Liquid

    Emulsions

    Butter, milk, cosmetic products, e.g., shampoo, creams, emulsified oils, polish and medicines.

     

    Gas

    Aerosols (or liquids)

    Fog, clouds, mist.

    Gas

    Solid

    Solid foams

    Pumicestone, styrene foam, foamed rubber, porous pot. thermocole rubber pillows and mattresses.

     

    Liquid

    Foams and froths

    Lather, soap seeds, air bubble.

     

    Gas

    Homogeneous system

    Do not exist as colloids.

     

    Question 106
    CBSEENCH12006516

    Discuss the effect of pressure and temperature on the adsorption of gases on solids. 

    Solution

    Answer:

    Effect of pressure on adsorption. The extent of adsorption of a gas per unit mass of adsorbent (x / m) increases with increase of pressure at a constant temperature.
    (i) For a lower range of pressure (x / m) is directly proportional to the applied pressure. Larger the pressure more is the amount of gas adsorbed, lower the pressure small is the amount of a gas adsorbed. That is
    xmp (as a constant temperature)

    (ii) For a high pressure range the extent of adsorption of a gas per unit mass of the adsorbent (x / m) is independent of the applied pressure. That is


    (iii) For a moderate pressure range the value of x/m is proportional to a Fractional power of pressure. That is

    xmp1/n (where T is constant)            
    where 1 / n is a fraction. Its value may be between 0 and 1. Fig. (a) and (b) show the variations of the extent of adsorption of a gas on an adsorbent as predicted by Frundlich equations (i) and (ii) respectively.
                    xm= k p1/n                                 ...(i)

    and logxm = log k + 1nlog p                ...(ii)

    Effect of temperature on adsorption: The amount of a gas adsorbed per unit mass of a solid surface (x / m) decreases with increase of temperature in case of physical adsorption. However, in case of chemical adsorption as the temperature increases x / m increases, attains a maximum value then decreases.

    Question 107
    CBSEENCH12006517

    What are lyophilic and lyophobic sols? Give one example of each type. Why are hydrophobic sols easily coagulated?

    Solution

    Answer:
    On the basis of attraction between dispersed phase and dispersion medium colloids may be classified into lyophillic sol and lyophobic sol.

    If dispersed phase (solid) tends to attract (i.e., like or love) dispersion medium (liquid), the resultant sol is termed as lyophilic sol. Examples are: Sol of gum, gelatine, starch etc. are lyophilic sols.

    On the other hand if dispersed phase tends to repel (i.e., dislike or hatred) dispersion medium, the resultant sol is termed as lyophobic sol. Examples are: Sols of metals, metal hydroxides, metal sulphides etc. are lyophobic sols.

    Hydrophobic sols easily coagulated as in this dispersion medium has no apparent affinity or interaction with the dispersed phase.

    Question 108
    CBSEENCH12006518

    What is the difference between multimolecular and macromolecular colloids? Give one example of each. How are these two types of colloids different from these two types of colloids? 

    Solution

    Answer:

    Multimolecular colloids:
    (i) Consist of aggregates of atoms or molecules with diameter less than 10–9 m.
    (ii) The atom or molecules are held together by weak Vander Waals forces.

    Macromolecular colloids:
    (i) Are themselves large. Many behave as macromolecular colloids because of their large molecular masses.
    (ii) Since the molecules are flexible, they can take on various shapes.

    Associated colloids:

    (i) Behave as true solution in smaller concentrations and colloids at higher concentrations.

    (ii) Sodium stearate behaves as strong electrolyte in dilute solutions and shows the properties of sodium and stearate ions form aggregates and behave as colloids. The aggregates formed are called micelles which revert to individual ions on dilution.
    Example of multi-molecular colloid: Gold sol, Sulphur sol.
    Example of macro-molecular colloid:Cellulose, Starch.

    Question 109
    CBSEENCH12006519

    What are enzymes? Write in brief the mechanism of enzyme catalysis.

    Solution

    Answer:

    Enzymes are biological catalysts which increases the rate of cellular reactions.
    Mechanism of enzyme catalysis : Enzymes are proteins (globular proteins) and have large molecular masses ranging from 12000 to 40,000. Thus, these are much bigger than the molecules which they catalyse. The substances which are catalysed are known as substrates. The mechanism of the enzyme catalysed reaction is completed in the following steps:

    Step-1. Binding enzyme to substrate (reactant) to form a complex.

    E             +    S                 ESEnzyme       Substrate         Enzyme-Substrate                                                         Complex

    Step-2. Product formation in the complex:

    ES                                    EPEnzyme-Substrate             Enzyme-productComplex                                         Complex

    Step-3. Release of the product from the enzyme complex.


    EP                                  E           +   PEnzyme-product               Enzyme        ProductComplex


    Actually there are a number of cavities present on the surface of the molecules of enzymes. These cavities have specific shapes and contain in their active groups such as – NH
    2, – COOH, – SH, – OH etc. These function as active sites on the surface of enzyme. The molecules of the reactant (substrate) which have complementary shapes fit into these cavities in the same manner as a key fits into a lock. This results in an activated complex which breaks to give the product and releases the enzyme catalyst.

     

    Question 110
    CBSEENCH12006520

    How are colloids classified on the basis of
    (i) physical states of components
    (ii) nature of dispersed phase and
    (iii) interaction between dispersed phase and dispersion medium?

    Solution

    Answer:

    (i) Based on physical states of components. Depending upon whether the dispersed phase and the dispersion medium are solids, liquids or gases, eight types of colloidal system are possible. The examples of the various type of colloids along with their typical names are given following:

    Dispersed

    Dispersion

    Type of

    Examples

    phase

    medium

    colloid

     

    Solid

    Solid

    Solid

    Liquid

    Liquid

    Liquid

    Gas Gases

    Solid

    Liquid

    Gas

    Solid

    Liquid

    Gas

    Solid

    Liquid

    Solid Sol

    Sol

    Aerosol

    Gel

    Emulsion

    Aerosol

    Solid sol

    Foam

    Some coloured glasses and gem stones.

    Paints, cell fluids

    Smoke, dust

    Cheese, butter, jellies.

    Milk, hair cream

    Fog, mist, cloud, insecticide sprays.

    Pumice stone, form rubber

    Froth, whipped cream,soap-lather.

    (ii) Nature of dispersion medium. Depending upon the type of the particles of the dispersed pahse, colloids are classified as multimolecular, macromolecular and associated colloids.

    Multimolecular colloids. The colloids in which the colloidal particles consists of aggregate of atoms or small molecules with diameters of less than 1 mm and called multimolecular colloids e.g., sulphur sol.

    Macro molecular colloids. Macro molecules have large molecular masses. These on dissolution in a suitable solvent form a solution in which the size of the macromolecules may be in the colloidal range. Such systems are called macromolecular colloids. Example: proteins, starch and cellulose.

    Associated colloids. There are some substances which at low concentrations behave as normal, strong electrolytes but at higher concentrations exhibit colloidal behaviour due to the formation of aggregated particles. The aggregated particles thus formed are called micelles. These are also known as associated colloids.

    (iii) Interaction between dispersed phase and dispersion medium. Depending upon the nature of interaction between the dispersed phase and the dispersion medium, colloidal sols are divided into two categories, namely, lyophilic and lyophobic.
    Lyophilic colloids. The colloidal solution in which the particles of the dispersed phase have a greater affinity for the dispersion medium are called lyophilic colloids. The common example of lyophilic colloids are glue, gelatin, starch, protein, rubber, etc.
    Lyophobic colloids. The colloidal solutions in which the particles of the dispersed phase have no affinity or love rather have hatred for the dispersion medium are called lyophobic colloids.

    Question 111
    CBSEENCH12006521

    Explain what is observed
    (i) when a beam of light is passed through a colloidal sol.
    (ii) an electrolyte, NaCl is added to hydrated ferric oxide sol.
    (iii) electric current is passed through a colloidal sol?

    Solution

    (i) When a beam of light is passed through a colloidal solution, the path of light inside the colloidal solution is illuminated and becomes visible. The path of light inside a colloidal solution becomes visible because colloidal particles are big enough to scatter the light falling on them in all the directions. The scattering of light by colloidal particles is called Tyndall effect.

    (ii) When NaCl is added to ferric oxide sol it dissociate to give Na+ and Cl- ions. Particles of ferric oxide sol are positively charge.
    thus they get coagulated in the presece of negatively charge Cl- ion. 

    (iii)The colloidal particles are charged and carry either positive or negtive charged particles in colloidal solution. When an electric curent is passed through a colloidal, solution, then depending on the nature of their charge, the colloidal particles move either towards the anode or towards the cathode, lose their charges and get deposited on the electrode. The migration of colloidal particles towards the oppositely charged electrodes under the influence of an electric field is called elecrophoresis.

    Question 112
    CBSEENCH12006522

    What are emulsions ? What are their different types? Give example of each type. 

    Solution

    Answer:
    The colloidal solution in which both the dispersed phase and desperssion medium are liquid is called an emulsion.The emulsion droplets are somewhat larger than the particles of sol but smaller than coarse suspension.

    There are two types of emulsions:

    (i) Oil-in-water emulsion. In this type of emulsion the dispersed phase is oil and the dispersion medium is water. Milk is an example of this type of emulsion in which liquid fat is dispesed in water.

    (ii) Water-in-oil emulsion. In this type of emulsion the dispersed phase is water while the dispersion medium is oil. Butter is an example of this type of emulsion in which water is dispersed in oil.

    Question 113
    CBSEENCH12006523

    What is de-emulsification ? Name two demulsifiers.

    Solution

    Answer:

    The technique of breaking the emulsion and then causing the separations of its components is called de-emulsification. Emulsion can be de-emulsified by separating or destroying the emulsifier. Boiling, centrifusion, freezing and addition of electrolytes cause de-emulsification.

    Examples: (i) Centrifugation separation cream (fat) from milk which is an emulsion.
    (ii) When water is the dispersion medium, the presence of a dehydrating agent can result in the de-emulsification.

    Question 114
    CBSEENCH12006524

    Action of soap is due to emulsification and micelle formation. Comment.

    Solution
    Answer:
    The cleansing action of soap is due to emulsification and micelle formation. Soaps are sodium salts of higher fatty acids such as sodium stearate, C
    17H35COONa+, which ionises as


    The anionic head of stearate ion (—COO) is hydrophobic in nature and has great affinity for water, while the hydrocarbon part (C17H35) is hydrophobic in nature and great affinity for oil grease etc.


     When soap is added to water containing dirt, the soap molecules surround to dirt particles in such a manner that their hydrophobic parts attached to the dirt molecules and the hydrophillic parts point away from the dirt molecule.
    This is known as micelle formation thus we can say that the polar group dissolves in water while the non-polar group dissolves in the dirt particles.
    Now these micelles are negtively charged they do not coalesce and a stable emulsion is formed.
    Question 115
    CBSEENCH12006525

    Give four examples of heterogeneous catalysis. 

    Solution

    Answer:

    Heterognous catalysis :
    The catalytic process in which the reactant and the catalyst are in different phase is known as heterogenous catalyst.

    The examples of heterogeneous system are given below:

    1. Manufacture of NH3 from N2 and H2 by Haber’s process, using iron as catalyst.
    N2(g)+3H2(g) Fe(s) 2NH3(g)

    2. Oxidation of NH3 with O2 using Pt as catalyst in Ostwald process.
    4NH3+5O2HeatPt 4NO+6H2O
    3. Oxidation of CO in automobile exhaust by platinum catalyst.

    2CO+O2 Pt 2CO2
    4. Hydrogenation of oils to form vegetable ghee using finely divided nickel as catalyst
    Oil+H2 Ni Vegetable ghee

    Question 116
    CBSEENCH12006526

    What do you mean by activity and selectivity of catalysts?

    Solution
    Answer:
    Activity of a catalyst. The ability of a catalyst to increase the rate of a  particular reaction is called, catalytic activity. Chemisorption is the main factor in deciding the activity of a catalyst. The catalyst tungsten increases the rate of decomposition of ammonia to the extent of 10
    32 times which is otherwise slow process. The activity of a catalyst become more significant in the formation of water. Hydrogen and oxygen can be stored for years but not even a single drop of water will be produced in the absence of a catalyst. However, in the presence of platinum catalyst hydrogen and oxygen combine with explosion and form water.

    H2+12O2    No reactionH2+12O2+Pt    H2O + (Pt)........explosion

    Selectivity of a catalyst: The ability of a catalyst to affect only the desired reaction and to prevent any other side reaction is referred to as the selectivity of a catalyst. For example, both the dehydrogenation and dehydration of ethanol are possible. But in the presence of a suitable catalyst only one reaction occurs. Thus

    (i) when nickel is ‘used as a catalyst, only dehydrogenation of ethanol occurs.
    CH3CH2OH Ni CH3CHO + H2, dehydrogentatoinEthanol                      Ethanal
    (
    ii) When alumina (Al
    2O3) is used as catalyst only dehydration of ethanol occurs.
    CH3CH2OH  Al2O3 CH2 = CH2+H2O,                                    Ethene

    Question 117
    CBSEENCH12006527

    Describe some features of catalysis by zeolites.

    Solution

    Answer:
    The catalytic reaction that depends upon the pore structure of the catalytic and te size of the reactant and the sizes of the reactant and product molecule is called shap-selective catalysis.
    Zeolites are microporous complex silicates in which some of silicon atoms are replaced by Al3+ ions. These are sodium aluminum silicates or calcium aluminum silicates. Their general formula is Mx/m [(AlO2)x (SiO2)y] m H2O where, n is valency of metal cation, Mn+ These are found in nature as such and are also synthesised in laboratory.

    The characteristic features are:
    (i) These are shape-selective catalyst or can act as molecular sieves.
    (ii) These have honey-comb like structure.
    (iii) These have specific pore-size lying between 260 to 740 pm.

    Question 118
    CBSEENCH12006528

    What is shape selective catalysis?

    Solution
    Answer:
    The catalytic reaction that depends upon the pore structure of the catalysis and the size of the reactant and product moecule is called shape selective catalysis.
    A shape selective catalyst has a variety of active sites of different shape and size. Zeolite acts as a shape selective catalyst. In the crystal of a zeolite the pore size usually varies form 260 pm to 740 pm. If the reactant molecules are too large they can not fit into pores of zeolite and no reaction takes place. On the other hand. If the reactant molecules ZSM-5 is used as shape selective catalyst to produce gasoline of high octane number from methanol.
    xCH3OH Ni (CH2)x+xH2O                  gasoline
    where, x varies form 5 to 10. ZSM-5 stands for zeolite sieve of molecular porosity-5.
    Question 119
    CBSEENCH12006529

    Explain the following terms: (i) Electrophoresis (ii) Coagulation (iv) Dialysis (iv) Tyndall effect. 

    Solution
    Answer:
    The movement of colloidal particles under an applied electric potential is called electrophoresis.
    when electric potential is applied across two plantium electrodes depping in colloidal solution.
    positively charged particles moves towards the cathode while negtive charge particles moves towards anode.


    (ii) Coagulation. The precipitation of colloidal particles is known as coagulation. This is caused by the neutralization of charge on colloidal particles when an electrolyte is added to the sol.

    (iii) Dialysis.It is a process of removing a dissolved substance from a colloidal solution by means of diffusion through a suitable membrane. Particles of true solution can pass through parchment paper or cellaphane membrane whereas sol particles cannot pass through these membrane.
    A bag made up of such a membrane is filled with colloidal solution and is then suspended in fresh water. The electrolyte particles pass out leaving behind the colloidal solution.
    Movement of ions across the membrane can be expedited by applying electric current through two electrodes. This method is very fast and is known as electro-dialysis.

    Fig.Electro-dialysis.

    (iv) Tyndall effect: It is observed that when a beam of light enters a dark room, the dust particles in its path become clearly visible. When a strong beam of light is passed through a colloidal solution and viewed at right angles, the path of light shows up as a hazy beam or cone. This is due to the fact that sol-particles absorb light energy and then emit it in all directions in space. This scattering of light, as it is called illuminates the path of the beam in the colloidal dispersion.


    “The phenomenon of the scattering of light by sol particles is called Tyndall effect”.

    True solutions do not exhibit Tyndall effect.

    Sponsor Area

    Question 120
    CBSEENCH12006530

    Give four uses of emulsions. 

    Solution

    Answer:
    The colloidal solution in whichboth the dispersed and dispersion  medium are liquid is called an emulsion.

    Uses of emulsification:

    (i) Removal of grease, oils and dirt from the skin, garments and utensils is due to the role of soap as an emulsifier during washing with water.

    (ii) Many pharmaceutical preparations like cod liver oil and Halibit liver oil are emulsions. The emulsifying agents used for this purpose are agar and gumacacia. The emulsified oil is readily acted upon by the digestive juices.

    (iii) Many lotions, creams and ointments are emulsions of O / W type or W / O type.

    (iv) The disinfectants like phenyl and lysol yield
    emulsions of O/W type when poured in water.

    (v) Emulsions are of physiological importance also. Emulsification facilitates the digestion of fats in the digestive tract by bringing the fats, water and digestive enzymes into contact with other.

    Question 121
    CBSEENCH12006531

    What are micelles? Give an example of a micellers system.

    Solution

    Answer:

    Micelle formation is done by substance such as soaps and detergent when dissolved in water. The molecules of such substance contain a hydrophobic and hydrophillic part. When present in water these substance arrange themseleves in spherical structure in such a manner that their hydrophobic parts are present towards the centre, while hydrophilic parts are pointing towards outside.
    This is known as micelle formation.






    A particle of colloidal size formed due to aggregation of several units of soap (surfactant) molecules in a dispersion medium is called micelle. A micelle usually consists of 50 to 100 molecules of the surfactants.

    Examples of Miceller system: (i) Sodium stearate + water
    [CH3(CH3)16 COO Na + H2O]
    (ii) Sodium dodecyl sulphate + water
    [CH3(CH2)11 OSO3 Na+ + H2O]
    (iii) Cetylrimethyl ammonium bromide + water

    Question 122
    CBSEENCH12006532

    Explain the terms with suitable examples:
    (i) Alcosol        (ii) Aerosol                   (iii) Hydrosol. 

    Solution

    Answer:

    (i) Alcosol: A colloidal solution having alcohol as the dispersion medium and soild substance as the dispersed phase is called an alcosol.
    for example:Colloidal sol of cellulose nitrate in ethyl alcohol is an alcosol.

    (ii) Aerosol. If the dispersion medium is gas the sol is called aerosol. Examples smoke. Dust.

    (iii) Hydrosol. When the dispersion medium is water, the sol is called hydrosol. Examples-paints, cell fluids.

    Question 123
    CBSEENCH12006533

    Comment on the statement that “colloid is not a substance a state of substance.” 

    Solution
    Answer:

    The nature of the substance whether colloid or crystalloid depends upon the particle size. When the size of the solute particles lies between 1000-10000 pm, it behaves like a colloid and in case it is less than this value, it gives the characteristics of crystalloid. Thus, colloid is not a substance but it is state of a substance which depends upon the particle size.
    Question 124
    CBSEENCH12006534

    What are emulsions? Write two applications of emulsification.

    Solution

    Answer:
    emulsion is a mixture of two liquids that would ordinarily not mix together, like oil and vinegar. Or in other word When liquid is dispersed in liquid this type of colloidal solution is called emulsion.

    There are two types of emulsions.
    (i) Oil dispersed in water (O/W type) and
    (ii) Water dispersed in oil (W/O type).


    Applications: (i) Soap emulsifies grease and takes it away in water along with the dirt.
    (ii) Digestion of fats in the intestines is aided by emulsification.

    Question 125
    CBSEENCH12006535

    Explain the following term:
    (i) Electro-dialysis
    (ii) Phases of a colloidal solution.

    Solution

    Answer:

    (i) It is a process in which colloidal solution is purified under influence of electric-field. The colloidal solution containing ionic impurities is put in a bag of parchment paper under electric field so that ions pass through parchment paper but colloidal solution does not.



    (ii) Colloidal solution is heterogeneous which consists of two phases, the dispersed phase and dispersion medium.
    (a) Dispersed phase. It is the component which is present in small amount and consists of particles (1 to 100 nm). It may be solid, liquid or gas.
    (b) Dispersion medium. The medium in which colloidal particles are dispersed is called dispersion medium. It may also be solid, liquid or gas.

    Question 126
    CBSEENCH12006536

    Taking two examples of heterogeneous catalytic reactions, explain how a heterogeneous catalyst helps in the reaction.

    Solution

    Answer:

    The catalytic process in which the reactants and the catalyst are in different phases is known as heterogeneous catalysis.
    Adsorption theory of heterogenous catalysis explained in two ways.

    (i) The reactants in gaseous state or in solutions, are adsorbed on the surface of the solid catalyst. The increase in concentration of the reactants on the surface increases the rate of reaction. Adsorption being an exothermic process, the heat of adsorption is utilised in enhancing the rate of the reaction.

    (ii) The catalytic activity is localised on the surface of the catalyst. The mechanism involves five steps:
    (i) Diffusion of reactants to the surface of the catalyst. 
    (ii) Adsorption of reactant molecules on the surface of the catalyst.
    (iii) Occurrence of chemical reaction on the catalyst’s surface through formation of an intermediate.
    (iv) Desorption of reaction products from the catalyst surface, and thereby, making the surface available again for more reaction to occur.
    (v) Diffusion of reaction products away from the catalyst’s surface.
    The surface of the catalyst unlike the inner part of the bulk, has free valencies which provide the seat for chemical forces of attraction. When a gas comes in contact with such a surface, its molecules are held up there due to loose chemical combination. If different molecules are adsorbed side by side, they may react with each other resulting in the formation of new molecules. Thus, formed molecules may evaporate leaving the surface for the fresh reactant molecules.


    (i) 2SO2(g) + O2(g) heatV2O5 2SO3(g)

    (ii) 4NH3(g)+5O2(g) 1120 KPt4NO(g) + 6H2O(l)

    Heterogeneous catalysts are V2O5 and platinum respectively. Reacting gases get adsorbed on heterogeneous solid catalyst and probability of collision increases which result in increase in number of effective collisions, resulting an increase in rate of reaction.
    Products formed get desorbed from the catalyst and get ‘absorbed and react, leading to increase in rate of reaction.

    Question 127
    CBSEENCH12006537

    Explain the following terms with an example of each:
    (i) Emulsification,
    (ii) Chemisorption.

    Solution

    Answer:

    (i) Emulsification. The process of making an emulsion in presence of emulsifying agent is called emulsification e.g., fats are emulsified by bile juice in our body and help in metabolism.

    (ii) Chemisorption. When the force of attraction between adsorbent and adsorbate is similar to that of chemical bond it is called chemisorption e.g., N2 and H2 get adsorbed on ‘Fe’ in manufacture of NH3 by Haber’s Process.

    Question 128
    CBSEENCH12006538

    What are micelles? How do they differ from ordinary colloid particles? Give two example of micelles forming substances.

    Solution
    Answer:

    Micells. Those substances which when dissolved in a medium at low concentrations behave like electrolytes but in high concentration it shows colloidal state due to formation of aggregated particles
    The formation of micelles takes place only above particular temperture ca;;ed kraft temperture and above a particular concentration called critical micellesation concentration (CMC). On dilution these colloids revert back to individual ion.
    e.g., soaps and detergents form micells.
    Question 129
    CBSEENCH12006539

    With the help of suitable diagram, describe the variation in (i) chemisorption (ii) physisorption with changes in temperature and pressure of adsorbed gas. How may these diagram be used to distinguish the two of adsorption?

    Solution
    Answer:

    If xm(extent of adsorption)
    first increases and then decreases with increase in temperature it is chemical adsorption.
    The initial unexpected increase in the extent of adsorption with temperature is due to the fact that the heat supplied acts as a activation energy required for chemical adsorption which is much more than that of physical adsorption.
    If it decreases with increase in temperature, it is physical adsorption.

    If xm increases with increase in pressure, it is physical adsorption. If it first increases and then becomes independent of pressure then it is chemical adsorption.



    Question 130
    CBSEENCH12006540

    Adsorption of a gas on the surface of solid is generally accompanied by decrease in entropy. Still it is a spontaneous process. Explain.

    Solution
    Answer:

    As adsorption is exothermic. it leads to a decrease in the residual force on the surface of  the adsorbent. This cause a decrease in the surface energy of the adsorbent. When gas is adsorbed on the surface of solid entropy decrease, i.e., ΔS = –ve. Since ΔH = –ve, ΔS= –ve, for adsorption to be spontaneous AG must be negative [ΔG = ΔH – TΔS].
    Question 131
    CBSEENCH12006541

    How does an increase in temperature affect both physical as well as chemical adsorption? 

    Solution
    Answer:

    In the case of physical adsorption the extent of adsorption (x/m) decrease with increase of temperture, as most of the adsorption processes are exothermic with increase n temperature the kinetic energy of the molecule increase and they try to escape from the surface and hence physical adsorption decreasewith increase in temperature.



    In case of chemical adsorption as the temperature increase the extent of adsorption (x/m) increase, attains a maximum value and then decrease.
    Chemical adsorption takes place as a result of chemical reaction between adsorbate and adsorbent hence with the increase in temperature the adsorption increase untill the total surface is covered with one layer after there is adsorption by increasing temperature.



    Question 132
    CBSEENCH12006542

    A colloidal solution of Agl is prepared by two different methods shown below:

    (i) What is the charge of AgI colloidal particles in the two test tube (A) and (B).
    (ii) Give reason for the origin of change. 

    Solution

    Answer:

    When silver nitrate solution is added to potassium iodide solution, negatively charged sol of AgI is formed this due to selective adsorption of I- ion from the dispersion medium.
    AgI + I- ---> [AgI]I-
    On other hand when KI is added to AgNO3 solution a positively charged sol of AgI is formed this is due to slective adsorption of Ag+ ion present in the dispersion medium.
    AgI + Ag+ ---> [AgI]Ag+.


    Question 133
    CBSEENCH12006543

    Explain why hydrophillic sols are relatively more stable than hydrophobic sols?

    Solution
    Answer:

    Hydrophilic sols are more stable than hydrophobic sols because they have stronger interactions between the dispersed phase and water (the dispersion medium). Due to stronger interactions with water hydrophilic sol particles get highly solvated. As a result the sol particles are not able to come near to each other to form aggregates. Hydrophobic sol particles have almost negligible interaction with water. As a result they easily form aggregates.
    Question 134
    CBSEENCH12006544

    (a) What is gel? Give an example.
    (b) How is gold sol prepared by reduction method ?

    Solution

    Answer:

    (a) Gel is a colloidal solution of liquid in a solid, i.e., liquid is dispersed phase and solid is the dispersion medium. A gel is a semi-solid which melts on heating. Examples of gels are: Thin jellies, gum arobic, processed cheese, silicic acid.

    (b) It is prepared by reduction of gold chloride (AuCl3) solution with stannous chloride
    2AuCl3 + 2SnCl → 3SnCl4 + 2Au
    (Violet gold sol.)

    Question 135
    CBSEENCH12006545

    Explain the process of peptization Name only one hydrosol.

    Solution

    Answer:

    Peptization may be defined as the process of
    converting a precipitate into colloidal sol by shaking it with dispersion medium in the presenceof a small amount of electrolyte. The electrolyte used for this purpose is called peptizing agent.

    For example, on treating a precipitate of iron (III) oxide with a small amount of FeCl3 solution gives a reddish brown coloured colloidal solution. During peptisation, the suitable ions from the added electrolyte are absorbed by the particles of the precipitate. The charged particles repel one another and form colloidal solution. In this case, Fe3+ ions from ferric chloride are absorbed by Fe(OH)3 precipitate:

    Fe(OH)3 + Fe3+                   Fe(OH)3+Fe3+Precipitate Electrolyte                  Colloidal sol.
    Question 136
    CBSEENCH12006546

    The adsorption of gases on solids can be described by Frundlich’s reaction:
    xm=kp1/4

    (i) How are the values of k and n determined experimentally?
    (ii) Explain why the value of n should be equal to or greater than one?

    Solution
    Answer:

    Freundlich gave anempirical relationship between the quantity of gas adsorbed by unit mass of solid adsorbent and pressure at a particular temperature. The relationship can be expressed by the following equation:

    xmkp1/n

    where x is the mass of the gas adsorbed on mass m of the adsorbent at pressure P, k and
    n are constants which depend on the nature of the adsorbent and the gas at a particular
    temperature.




    Fig. Linear graph between log x/m and log p. Taking logarithms on both sides, we get

    log xm = log k + 1nlog p.

    Thus, if we plot a graph between log (x/m) and log p, a straight line will be obtained. The slope of the line is equal to 1 / n and the intercept is equal to log k. Thus the values of k and n are determined.

    Freundlich isotherm explains the behaviour
    of adsorption in an approximate manner. The
    factor 1 n can have values between 0 and 1
    (probable range 0.1 to 0.5). Thus,  above equation

    When 1/n = 0, x/ m= constant, the adsorption is independent of pressure.
    When 1/n = 1, x/m= k p, i.e. x/m∝ p, the adsorption varies directly with pressure.

     

    Question 137
    CBSEENCH12006547

    Explain the following observations:
    (a) Ferric hydroxide sol gets coagulated on addition of sodium chloride solution.
    (b) Cottrell’s smoke precipitator is fitted at the mouth of the chimney used in factories.
    (c) Physical adsorption is multi layered, while chemisorption non layered.

    Solution

    Answer:
    (a) When sodium chloride is added to ferric hydroxide sol, the sol gets coagulated. This is because the Cl ions from NaCl neutralize the +ve charge on Fe(OH)3 sol.
          Fe2O3.xH2O/Fe3+

    (b) Smoke coming out of the chimenys contain a lot of unburnt carbon particles smoke is the colloidal solution of the solid particles such as carbon arsenic dust particles etc.
    These particles are injurious to health and have to be precipitated since carbon particlesare charged particles and cannot be precipitated, thus metal plate of oppositely charged particles is used for their precipitation.
    This is done by the cottrell smoke precipitator which neutralizes the charge on the carbon. 

    (c) Physical adsorption is multilayered because forces between adsorbate and adsorbent molecule are of Van der Waal’s type.
    Chemisorption is non-layers because forces of attraction are of chemical bond type.

    Question 138
    CBSEENCH12006548

    Differentiate between homogeneous catalysis and heterogeneous catalysis.

    Solution

    Homogeneous catalysis

    Heterogeneous catalysis

    1. When the reactants and the catalyst are in the same phase (i.e., liquid or gas), the process is said to be homogeneous catalysis.
    for example:

    Oxidation of sulphur dioxide into sulphur trioxide with dioxygen
    in the presence of oxides of nitrogen as the catalyst in the lead
    chamber process
    2SO2(g) + O2(g)NO(g) 2SO3(g)

    2. The reaction is assumed to proceed through the formation of an intermediate between the catalyst and one of the reactants.

     1. The catalytic process in which the reactant and the catalyst are in different phase is known as heterogenous.

    Oxidation of sulphur dioxide into sulphur trioxide in the
    presence of Pt.

    2SO2(g)   pt(s) 2SO3(g) 

    2. The reaction proceeds through the adsorption of one or more reactants over the surface of the catalyst.

    Question 139
    CBSEENCH12006549

    How will you prepare silver sol by Bredig’s Arc method?

    Solution
    Answer:

    It involves dispersion as well as condensation.
    colloidal sols of metal such as gold, silver, plantium etc. can be prepared by the this method.
    Colloidal solution of silver is prepared by the condensation of vapours. This is done by striking an electric arc between two rods of silver, the ends of which are kept immersed under water in a well cooled vessel, containing a stabilizer. (See Fig.) The intense heat of the arc tear off the end of the silver rods to form vapour of silver which then at once condense to give particles of colloidal size. The presence of a trace of KOH in water stabilizes the colloidal sol so formed.


    Fig. Bredig’s Arc Method.
    Question 140
    CBSEENCH12006550

    Why is smoke passed through charged plates before allowing it to come out of chimneys in factories?

    Solution
    Answer:

    Smoke coming out of the chimneys contain as lot of unburnt carbon particles. Smoke is the colloidal solution of the solid particles such as carbon arsenic dust particles etc.These particles are injurious to health and have to be precipitated.

    Smoke contains electrically charged particles of carbon along with other fuel gas. When it is passed through electrically charged plates, the charged carbon particles are attracted to the charged plate, where they lose their charge, coagulate and drop down as dust. The smoke coming out of chimneys now is free from carbon particles and hence do not cause pollution. The apparatus used for the purpose is known as Cotrell precipitator.
    Question 141
    CBSEENCH12006551

    Explain the chemical phenomenon involved in the purification of water using potash alum.

    Solution
    Answer:

    The purification of water involves the coagulation (precipitation) of suspended colloidal particles of clay, sand etc., by the addition of potash alum. Alum gives Al
    3+ ions in water, which discharge the negatively charged dirt or clay particles suspended in water, causing them to coagulate.
    Further Al2(SO4)3 present in alum is partly hydrolysed by water to give colloidal Al(OH)3which absorbs the suspended particles also.

    Question 142
    CBSEENCH12006552

    Justify the use of gelatin as a protective colloid.

    Solution
    Answer:

    Gelatin is made from soft bone and cartilages of an animal which have ability to form thermo- reversible gelsand amphoteric character make it as protactive colloid.
    The process by which the lyophobic sols are protected from coagulation by electrolytes, because of the previous addition of lyophilic colloid is called protection; and the lyophilic colloid employed for imparting this protection, is called protective colloid, Thus when a little gelatin is added to As
    2S3 sol, the latter becomes very stable towards electrolytes and the resulting sol is not coagulated, until a large excess of electrolyte is added. Here, gelatin acts as a protective colloid.
    Question 143
    CBSEENCH12006553

    Some zeolites are used to separate long straight chain hydrocarbons from branched chain hydrocarbons in petrochemical industry. Explain how this separation becomes possible.

    Solution
    Answer:

    The separation of long straight chain hydrocarbons from branched chain hydrocarbons in petrochemical industry is possible due to shape selectivity of zeolites. Shape selective catalysis depends on the pore structure. The pore size in zeolites generally varies between 260 pm to 740 pm. Depending on the size of the reactant and product molecules compared to size of the cages, reactions proceed in a specific manner.
    For the separation of the above catalyst ZSM-5 is used.
    Question 144
    CBSEENCH12006554

    How is a colloidal solution purified by ultrafiltration?

    Solution
    Answer:

    Ultrafiltration is the process of separating solute impurities of different sizes. It is done by treating a filter paper with collodion that reduces the pore sizes and hence permits the electrolyte solution to pass through but retains the colloidal particles.
    Question 145
    CBSEENCH12006555

    Consider the adsorption isotherm given below and interpret the variation in the extent of adsorption (x/m) when:
     

    (i) temperature increases at constant pressure.
    (ii) pressure increases at constant temperature.

    Solution

    Answer:

    (i) The extent of absorption (x/m) decreases with the increase in temperature.

    (ii) The extent of absorption (x/m) increases with the increase in pressure.

    Question 146
    CBSEENCH12006556

    What is the coagulating power of an electrolyte? What is the cause of coagulation?

    Solution
    Answer:

    Coagulating power of an electrolyte is the minimum amount of electrolyte in millimoles that must be added to one litre of a colloidal solution to bring about its coagulation.

    Coagulation is caused by
    (i) Electrophoresis,
    (ii) Mutual precipitation by mixing oppositely charged sols in proper proportion.
    Question 147
    CBSEENCH12006557

    What are the different steps involved in a heterogeneously catalysed reaction?

    Solution

    Answer:

    The catalytic activity is localised on the surface of the catalyst. The mechanism involves five steps:
    (i) Diffusion of reactants to the surface of the catalyst.
    (ii) Adsorption of reactant molecules on the surface of the catalyst.
    (iii) Occurrence of chemical reaction on the catalyst’s surface through formation of an intermediate.
    (iv) Desorption of reaction products from the catalyst surface, and thereby, making the surface available again for more reaction to occur.
    (v) Diffusion of reaction products away from the catalyst’s surface. The surface of the catalyst unlike the inner part of the bulk, has free valencies which provide the seat for chemical forces of attraction. When a gas comes in contact with such a surface, its molecules are held up there due to loose chemical combination. If different molecules are adsorbed side by side, they may react with each other resulting in the formation of new molecules. Thus, formed molecules may evaporate leaving the surface for the fresh reactant molecules.

    Question 148
    CBSEENCH12006558

    What are Brownian movement?

    Solution
    Answer:

    Brownian movement. When a colloidal solution is examined with an ultra-microscope, the suspended particles are seen to be in a constant rapid zig-zag motion. This constant rapid zig-zag motion of colloidal particles is known as Brownian movement after the name of the discoverer Sir Robert Brown (1827).



    Fig.  Brownian movement.
    Causes: It is due to the unequal bombardment of colloidal particles by the molecules of the dispersion medium. With increase in the size of the particles, the probabilities of unequal bombardment decreases and the Brownian movement disappears. This is why coarse suspensions do not exhibit Brownian movement.
    Question 149
    CBSEENCH12006559

    Explain the purification of colloidal solutions by dialysis and ultrafiltration.

    Solution

    Answer:

    Purification of colloidal solutions:

    Dialysis: It is the process of separating colloidal particles from those of crystalloids by diffusing the mixture through a parchment or animal membrane. Colloidal particles do not pass through while those of crystalloids do. The impure sol is filled into a cellophane bag, which is suspended in a vessel containing distilled water. The crystalloid particles pass through while colloidal particles do not.





    Ultra filtration: It is the process of purifying a colloidal particle by treatment with a filter paper treated with colloidion which reduces the pore size of the filter paper. The sol is poured over the ultrafilter which permits the electrolytic solution to pass but retains the colloidal particles.

    Question 150
    CBSEENCH12006560

    Give applications of colloids in detail.

    Solution

    Answer:

    Colloids including emulsions have great number of uses in day to day life, such as
    (i) Sewage disposal Sewage water contains charged colloidal particles of dirt, rubbish etc. which are removed by electrophoresis.
    (ii) Rubber planting. The negatively charged rubber particles from rubber sol are deposited on handles of tools.
    (iii) Cottrell smoke precipitator. Smoke contains positively charged colloidal particles which are separated by Cottrell smoke precipitation.
    (iv) In preparing nano-material Nano material are used as catalysts and are prepared by using reverse micelles.
    (v) Building roads Emulsified asphalt in water is used in making roads.
    (vi) In disinfectants Dettol, lysol etc. disinfectants forms emulsions of oil in water and are then used.
    (vii) In medicine Medicines and pharmaceutical preparation in the form of emulsions are more easily assimilated.
    (viii) In metallurgical operations Froth floatation process involves treatment of pulverised ore in emulsion of pure oil.

    Question 151
    CBSEENCH12006561

    Define the terms colloid and colloidal state. How does the theory of selective adsorption explain the origin of charge on colloidal particles?

    Solution

    Answer:

    Colloids and colloidal state: In the light of present day researches, Thomas Graham's classification of substances into colloids and crystalloids has been found to be wrong. Graham thought of colloids as substances. Now-a-days the term is applied not so much to the substance but rather to a state in which that substance exists. The same substance can behave as a crystalloid in one solvent and a colloid in another.
    Origin of charge on colloidal particles:
    According to the modern theory of electrical double layer (proposed by Helmholtz) the charge on colloidal particles is due to the preferential adsorption of common ion on their surface and consequently an electrical double layer is formed, in which adsorbed ions form one layer; while the remaining oppositely charged ions form the second diffused layer. Examples:

    (i) When freshly precipitated ferric hydroxide is peptized with dilute FeCI3, a +ve sol is formed, due to the adsorption of Fe3+ ions of FeCl3 on the surface of Fe(OH)3 colloid particles, while the negative CI ions form the diffused layer. This may be shown as:

    Fe(OH)3Fe3+                  :         3CI-   + ve sol solution                     -ve diffused layer


    (ii) As
    2S3 sol prepared by passing H2S gas through As2O3 solution., is – ve due to preferential adsorption of common ions S2– on its surface, while the H+ ions forming the diffused layer. This may be shown as:

    A2S3S2-                       :      2H++ve sol solution                   -ve diffused layer

    Question 153
    CBSEENCH12006563

    In an aerosol __________ is dispersed in ________.

    Solution
    liquid/solid, gas
    Question 154
    CBSEENCH12006564

    In foams,________ is dispersed in __________.

    Solution
    Gas, liquid
    Question 157
    CBSEENCH12006567

    Blood is a _______ charged sol.

    Solution
    negatively
    Question 158
    CBSEENCH12006568
    Question 159
    CBSEENCH12006569

    ______ Sols are irreversible.

    Solution
    lyophobic
    Question 160
    CBSEENCH12006570

    Milk is an example of _______.

    Solution
    Emulsion
    Question 162
    CBSEENCH12006572
    Question 164
    CBSEENCH12006574
    Question 165
    CBSEENCH12006575

    Soap acts as ________ in its cleansing action.

    Solution
    emulsifier
    Question 170
    CBSEENCH12006580
    Question 172
    CBSEENCH12006582
    Question 177
    CBSEENCH12006587
    Question 182
    CBSEENCH12006592
    Question 185
    CBSEENCH12006595

    Define enthalpy of adsorption.

    Solution

    Answer:

    Adsorption involves attracting molecules of adsorbate on surface of the adsorbent. Due to this, energy is released and thus heat of adsorption is negative i.e. adsorption is always exothermic.

    Question 186
    CBSEENCH12006596

    State one difference betwen an emulsion and a sol.

    Solution

    Answer:

    In sol dispersed medium is liquid and dispersed phase is solid. for example paints, cell fluid

    In emulsion both dispersed phase and dispersion phase are in liquid foam. for example milk,butter.

    Question 187
    CBSEENCH12006597

    Out of NH3 and N2 which gas will be adsorbed more readily on the surface of charcoal and why?

    Solution

    Answer:

    This can be explained as the higher the critical temperture the more easily gas is liquified that is larger the vander waal's force of attraction and hence more readily it will be adsorbed.
    NH3 gas has higher critical temperature than N2
    thus NH3 adsorbed more readily on the surface of charcoal.

    Question 188
    CBSEENCH12006598

    What is the cause of Brownian movement observed in colloidal solution?

    Solution

    Answer:

    The brownian movement has been explained to be due to the unblanced bombardment of the particles by the molecules of the dispersion medium.

    When colloidal solutions are viewed under
    a powerful ultramicroscope, the colloidal particles appear to be in a state of continuous zig-zag motion all over the field of view. This motion was first observed by the British botanist, Robert Brown, and is known as Brownian movement.
    This motion isindependent of the nature of the colloid but depends on the size of the particels and viscosity of the solution samller the size and lesser the viscosity faster is the motion.

    Question 189
    CBSEENCH12006599

    How can colloidal solution of sulphur in water be prepared?

    Solution

    Answer:

    A colloidal sol of sulphur can be obtained by passing hydrogen sulphide into solution of sulphur dioxide in water or through a solution of an oxidising agent.

    SO2 + 2H2S --------> 3S + 2H2O

    Question 190
    CBSEENCH12006600

    Tyndall effect is due to?

    Solution

    Answer:


    when we pass a beam of light through the colloidal solution tyndall effect shows.
    tyndall effect is due to the fact that colloidal particles scatter light in all direction in space.

    Question 191
    CBSEENCH12006601

    Define ultrafiltration.

    Solution

    Answer:

    Ultra- filtration is the physical removal of particles and microbiological cotaminates from an aqueous solution using a membrane filter with pore size less than 0.1 micron . It does not remove dissolved ion and small molecules.
    membrane may be supplied as flat sheet sprialwound or hollow fibre modules.

    Question 192
    CBSEENCH12006602

    Define peptization.

    Solution

    Answer:

    Peptization may be defined as the process of converting a precipitate into colloidal soln by shaking it with dispersion medium in the presence of a small amount aof electrolyte.
    The electrolyte is used for this purpose called peptizing agent.
    This method is applied generally to convert a freshly prepared precipitate into a colloidal sol.

    Question 193
    CBSEENCH12006603

    What is an adsorption isotherm?

    Solution

    Answer:

    The variation in the amount of gas adsorbed by the adsorbent with pressure at constant temperature can be expressed by means of a curve termed as adsorption isotherm.

    Freundlich gave an empirical relationship between the quantity of gas adsorbed by unit mass of solid adsorbent and pressure at a particular temperature. The relationship can be expressed by the following equation:


    x/m = k.p1/n (n > 1)

    where x is the mass of the gas adsorbed on mass m of the adsorbent at pressure P, k and n are constants which depend on the nature of the adsorbent and the gas at a particular
    temperature.



    Question 194
    CBSEENCH12006604

    On passing H2S gas through dilute HNO3 the colourless solution becomes turbid, why?

    Solution

    Answer:

    3H2S + 2HNO3 -----> 3S + 2NO + 4H2O
    Due to the formation of colloidal sulphur the colourless solution turned to turbid.

    Question 195
    CBSEENCH12006605

    What is the function of emulsifying agent?

    Solution

    Answer:

    Emulsifying Agents are the substances added to an emulsion to prevent the coalescence of the globules of the dispersed phase. They are also known as emulgents or emulsifiers. They act by reducing the interfacial tension between the two phases and forming a stable interfacial film. The choice of selection of emulsifying agent plays a very important role in the formulation of a stable emulsion. 
    Substances that are soluble in both fat and water and enable fat to be uniformly dispersed in water as an emulsion.

    Question 196
    CBSEENCH12006606

    Why are lyophillic sols self-stabilised?

    Solution

    Answer:

    Particles of dispersed phase have great affinity for the dispersion medium.
    They are self stabilised because of strong attractive forces operating and the dispersion medium. for example gums, gelatin etc.

    Question 197
    CBSEENCH12006607

    What is sorption?

    Solution

    Answer:

    Sorption is the process in which adsorption and absorption take place simultaneously, example dyeing of cotton fibres by azo dyes.

    Question 198
    CBSEENCH12006608

    What happens when freshly prepared Fe(OH)3 is shaken with a little amount of dilute FeCl3?

    Solution

    Answer:

    When freshly precipitated Fe(OH)3 is shaken with little amount of dilute solution of FeCl3(electrolyte).
    Peptization process (ions of the electrolyte are adsorbed by the precipitate particles) takes place by converting the Fe(OH)3 precipitate into colloidal solution positively charged solution of Fe(OH)3.


    Question 199
    CBSEENCH12006609

    How can dialysis be made fast?

    Solution

    Answer:

    The process of dialysis is quite slow it can be made faster by applying an electric field.

    Question 200
    CBSEENCH12006610

    Explain the following term giving a suitable example: Emulsification.

    Solution

    Answer:

    An emulsion may be defined as a colloidal dispersion of two immiscible or partially immiscible liquids, in which one liquid acts as the dispersion medium and the other as the dispersed phase.

    Depending on the nature of the dispersed phase, emulsions are broadly classified into two types

    i) Oil in water type emulsion.
    Oil acts as the dispersed phase water acts as a dispersion medium. e.g. milk.
    ii) Water in oil type emulsion
    water acts the dispersed phase and oil acts as the dispersion medium e.g. butter.
    Emulsion are generally unstable and separate in two layer on standing.
    Thus, to stabilise an emulsion small amount of certain other substance, called emulsifier or emulsifying agent are added. 
    Protein are the principal emulsifying agent for oil in water types of emulsion.

    Question 201
    CBSEENCH12006611

    How does chemical adsorption of a gas on a solid vary with temperature?

    Solution

    Answer:

    The process of Adsorption is an Exothermic Reaction. Thus according to Le-chatlier’s Principle, the magnitude of adsorption should increase with decrease in temperature. Infact it is found to be so in case of physical adsorption because vanderwaal’s forces are strong at low temperatures.

    However, the chemisorption first increases with rise in temperature and then starts decreasing. The initial increase shows that like chemical reactions, chemisorption also needs activation energy.


    If a plot is drawn between amount of gas adsorbed (x/m) and temperature at constant equilibrium pressure, then curve obtained for physical adsorption shows there is a regular decrease in adsorption with temperature rise. While for chemisorption it first increases and then shows regular decrease. Such curves are known as Adsorption Isobars.

    Question 202
    CBSEENCH12006612

    How does the addition of alum purify water?

    Solution

    Answer:

    When alum (Al2(SO4)3 is added into water. It forms a gel like precipitate such as Al(OH)3 . The alum precipitate then forms small bundles that trap suspended particles as they fall through water.
    This process is known as floculation.
    After floculation the particles will be large enough to settle and can be removed. 

    Question 203
    CBSEENCH12006613

    State one difference between an emulsion and a sol.

    Solution

    Answer:

    In gel Dispersing phase is liquid and Dispersing medium is solid. for example cheese, butter.

    In emulsion both dispersing phase asnd dispersing medium are in liquid . for example milk.

    Question 204
    CBSEENCH12006614

    Give an example of heterogeneously catalysed reaction.

    Solution

    Answer:

    The catalytic process in which the reactants and the catalyst are in different phases is known as heterogeneous catalysis.

    examples of heterogeneous catalysis are given below:
    Oxidation of sulphur dioxide into sulphur trioxide in the
    presence of Pt.

    2SO2 (g) Pt(s)   2SO3 (g) 

    The reactant is in gaseous state while the catalyst is in the solid state.

    Question 205
    CBSEENCH12006615

    (a) How can a colloidal solution and true solution of the same colour be distinguished from each other ?
    (b) List four applications of adsorption.

    Solution
    Answer:

    a) True solution posses molecular dimensin 10-10 to 10-9m. Whereas in colloidal solution the sizes of particles is 1-100nm thus colloidal solution show tyndall effect. thus we can distinguised true solution and colloidal solution by tyndall effect.

    b) 
    (i) Production of high vacuum: The remaining traces of air can be adsorbed by charcoal from a vessel evacuated by a vacuum pump to give a very high vacuum.

    (ii) Gas masks: Gas mask (a device which consists of activated charcoal or mixture of adsorbents) is usually used for breathing in coal
    mines to adsorb poisonous gases.

    (iii) Control of humidity: Silica and aluminium gels are used as adsorbents for removing moisture and controlling humidity.

    (iv) Removal of colouring matter from solutions: Animal charcoal removes colours of solutions by adsorbing coloured impurities.
    Question 206
    CBSEENCH12006616

    Explain the following observations:
    (a) Lyophilic colloids are more stable than lyophobic colloid.
    (b) Coagulation takes place when sodium chloride solution is added to a colloidal solution of ferric hydroxide.
    (c) Sky appears blue in colour.

    Solution

    Answer:

    a) Particles of dispersed phase have great affinity for the dispersion medium. They are self stabilised because of strong attractive forces operating between the suspended particles and the dispersion medium. e.g. gums gelatin.

    b) When freshly precipitate Fe(OH)3 is shaken with little amount of dilute solution of FeCl3 (electrolyte)
    Peptization process takes place by converting the Fe(OH)3 precipitate into colloidal solution positively charged solution of Fe(OH)3.

    c)  Transmitted light is made up of a spectrum of colors the longest wavelength of light are on red end of spectrum and the shortest wavelength areon the blue/ violet end of the spectrum.
    When transmitted light such as sunlight enters ours atmosphere it colloide with dust and water droplet and scattered violet/blue light.
    But because our eyes are more sensitive to blue color thus we see blue color of sky.

    Question 207
    CBSEENCH12006617

     (a) In which of the following does adsorption take place and why?
    (i) Silica gel placed in the atmosphere saturated with water.
    (ii) Anhydrous CaCl2 placed in the atmosphere saturated with water.
    (b) How does BF3 act as a catalyst in industrial process?
    (c) Give an example of shape selective catalysis.

    Solution
    Answer:
    a)

    i) In silica gel adsorption take place due to attraction and retention of water  molecule on at the surface

    ii) Anhydrous CaClundergoes adsorption because it combine with water molecule to form hydrated calcium chloride CaCl2.2H2

    b) It is because BF3 is an electron deficient compound and helps to generate electrophile.
    thus it is act as a catalyst in industrial process.

    c) The catalytic reaction that depends upon the pore structure of the catalyst and the size of the reactant and product molecules is called shape-selective catalysis. Zeolites are good shape-selective catalysts.
    An important zeolite catalyst used in the petroleum industry is ZSM-5. It converts
    alcohols directly into gasoline (petrol) by dehydrating them to give a mixture of hydrocarbons.
    Question 208
    CBSEENCH12006618

    What are micelles? How do they differ from ordinary colloidal particles ? Give two examples of micelles forming substances.

    Solution

    Answer:

    When soap molecule are present in water the molecules arrange themselves in the form of culster in such a manner that their hydrophobic ends are away from the water molecules and their hydrophillic or ionic end are towards the water molecules.
    This is known as micelle formation and the cluster that is formed is called as micelle.
    micelle system behaves as a true solution in low concentration and as colloidal solution as high concentration.



    Question 209
    CBSEENCH12006619

    State Hardy-Schulze rule.

    Solution

    Answer:

    i)The ions carrying charge opposite to that of sol particles are effective in bringing about the coagulation sol.

    ii)coagulation power of the fourth power of the valency of the ions causing coagulation.


    Question 210
    CBSEENCH12006620

    (a) Of NH3 and CO2 which will be adsorbed more readily on the surface of charcoal and why?
    (b) How are multimolecular colloids different from macro-molecular colloids?
    (c) State the principle of electro-dialysis.

    Solution
    Answer:

    a) NH3 has higher critical temperature than CO2 i.e. NH3 has greater intermolecular forces of attraction hance will be adsorbed more readily.

    b) In this type of colloids, colloidal particles are aggregates of atom or molecules each having size less than 1 nm e.g. sulphur sol. gold sol.
    multimolecular colloids are generally lyophobic in nature.
    In this type of colloids, colloidal particles are themselves large molecules of colloidal dimension e.g. strach protein.

    c)The movement of colloidal particles towards oppositely charged electrode in an electric field is called electrophoresis.
    When electric potential is applied across two platinum electrodes dipping in a colloidal solution, the colloidal particles move towards one or the other electrode.
     
    Question 211
    CBSEENCH12006621

    What is the adsorption isotherm ? Distinguish between Freundlich adsorption isotherm and Langmuir adsorption isotherm with the help of appropriate graphs.

    Solution

    Answer:

    The variation in the amount of gas adsorbed by the adsorbent with pressure at constant temperature can be expressed by means of a curve termed as adsorption isotherm.

    Freundlich adsorption isotherm: Freundlich gave an empirical relationship between the quantity of gas adsorbed by unit mass of solid adsorbent and pressure at a particular temperature. The
    relationship can be expressed by the following equation:

    x/m = k.p1/n (n > 1) 

    where x is the mass of the gas adsorbed on mass m of the adsorbent at pressure P, k and n are constants which depend on the nature of the adsorbent and the gas at a particular
    temperature.


    LANGMUIR ADSORPTION:
    It tells about the number of active site of the surface undergoing adsorption and pressure.

    Θ = kP1+KP

    Where,

    θ= the number of sites of the surface which are covered with gaseous molecule,

    P= pressure 

    K =is the equilibrium constant for distribution of adsorbate between the surface and the gas phase .

    The basic limitation of Langmuir adsorption equation is that it is valid at low pressure only.

    At lower pressure, KP is so small, that factor (1+KP) in denominator can almost be ignored. So Langmuir equation reduces to


    θ=KP
     

    At high pressure KP is so large, that factor (1+KP) in denominator is nearly equal to KP. So Langmuir equation reduces to

    θ=KPKP=1



    Question 212
    CBSEENCH12006622

    (a) Which will absorb more gas, a lump of charcoal or its powder and why?
    (b) Describe the preparation of the following colloidal solutions. Name the method used in each case (i) silver sol, (ii) sulphur sol.

    Solution

    Answer:

    The accumulation of molecular species at the surface rather than in the bulk of a solid or liquid is termed adsorption. The molecular species or substance, which concentrates or accumulates at the surface is termed adsorbate and the material on the surface of which the adsorption takes place is called adsorbent.
    There are mainly two types of adsorption of gases on solids:
    i)physisorption
    ii)chemisorption

    The extent of adsorption increases with the increase of surface area of the adsorbent. Thus, finelydivided lamp of charcoal powder and porous substances having large surface areas are good adsorbents.

    b)
    Silver sol can be prepared by the double decomposition reaction.
    In this dilute solution of silver nitrate react with potassium chloride to give silver chloride solution.

    AgNO3 + KCl -----> AgCl + KNO3

    sulphur sol may be prepared by oxidation of hydrogen sulphide by bromine.

    H2S +Br2---> S + 2HBr

    Question 213
    CBSEENCH12006623

    Explain What is observed when:
    (a) A beam of light is passed through a colloidal solution of As2S3
    (b) An electrolyte (NaCl) is added to ferric hydroxide sol.
    (c) An electric current is passed through a colloidal solution.

    Solution

    a) When beam of light passed through a colloidal solution of As2S3. the path of the light become visible beacuse of the tyndall effect.

    b) When freshly precipitated Fe(OH)3 is shaken with little amount of dilute solution of NaCl (electrolyte).
    Peptization process  take place by converting the Fe(OH)3 into colloidal solution.
    As ferric hydroxide Fe(OH)3 is positively charged sol it gets coagulated by Cl- ion released by NaCl

    c)The movement of colloidal particles under an applied electric potential is called electrophoresis. Positively charged particles move towards the cathode while negatively charged particles move towards the anode.

    Question 214
    CBSEENCH12006624

    What do you mean by homogeneous and heterogeneous catalysts? Give two examples of each.

    Solution

    When the reactants and the catalyst are in the same phase (i.e., liquid or gas), the process is said to be homogeneous catalysis. The following are some of the examples of homogeneous catalysis:
    (i) Oxidation of sulphur dioxide into sulphur trioxide with dioxygen in the presence of oxides of nitrogen as the catalyst in the lead chamber process.

    2SO2(g) + O2(g) NO(g) 2SO3(g)

    The reactants, sulphur dioxide and oxygen, and the catalyst, nitric oxide, are all in the same phase.

    (ii) Hydrolysis of methyl acetate is catalysed by H+ ions furnished by hydrochloric acid.
    CH3COOCH3(l) + H2O(l) HCl (l) CH3COOH(aq) + CH3OH(aq)

    The catalytic process in which the reactants and the catalyst are in different phases is known as heterogeneous catalysis. Some of the examples of heterogeneous catalysis are given below:

    (i) Oxidation of sulphur dioxide into sulphur trioxide in the presence of Pt.

    2SO2 Pt(s) 2SO3
     The reactant is in gaseous state while the catalyst is in the solid state.


    (ii) Combination between dinitrogen and dihydrogen to form ammonia in the presence of finely divided iron in Haber’s process.

    N2(g) +3H2(g) Fe(s) 2NH3(g)

    The reactants are in gaseous state while the catalyst is in the solid state.

    Question 215
    CBSEENCH12006625

    Illustrate with example:
    (i) Lyophilic and Lyophobic sols.
    (ii) Multimolecular and macromolecular colloids.
    (iii) Homogeneous and Heterogeneous catalysis.

    Solution
    (i)

    property

    Lyophilic sols (suspensoid)

    Lyophobic sols (Emulsoid)

    Surface tension

    Lower than that of the medium

    Same as that of the medium

    Viscosity

    Much higher than that of the medium

    Same as that of the medium

    Reversibility

    Reversible

    Irreversible

    Stability

    More stable

    Less stable

    Visibility

    Particles can’t be detected even under ultramicroscope

    Particles can be detected under ultramicroscope.



    (ii) Multimolecular Colloids: When a large number of atoms or small molecules (having diameters of less than 1nm) of a substance combine together in a dispersion medium to form aggregates having size in the colloidal range, the colloidal solutions thus formed are called multimolecular colloids. The species (atoms or molecules) constituting the dispersed particles in multimolecular colloids are held together by Vander Waals’ forces. 
    The gold sol, sulphur sol etc. are some examples of multimolecular colloids. A gold sol may contain particles of various size composed of several atoms of gold. Similarly, sulphur sol consists of particles containing about a thousand of S8molecules. 
     
    Macromolecular Colloids: Certain substances form large molecules whose dimensions are comparable to those of colloidal particles. Such molecules have very high molecular masses and are termed as macromolecules. When such substances are dispersed in suitable dispersion medium, the resulting colloidal solutions are known as macromolecular colloids. Thus, in macromolecular colloids, the dispersed particles are themselves large molecules having very high molecular masses. 

    (iii)
    When the reactants and the catalyst are in the same phase (i.e., liquid or gas), the process is said to be homogeneous catalysis. The
    following are some of the examples of homogeneous catalysis:

    (i) Oxidation of sulphur dioxide into sulphur trioxide with dioxygen in the presence of oxides of nitrogen as the catalyst in the lead chamber process.
    2SO2(g) + O2(g) NO(g) 2SO3(g)


    The reactants, sulphur dioxide and oxygen, and the catalyst, nitric oxide, are all in the same phase.


    The catalytic process in which the reactants and the catalyst are in different phases is known as heterogeneous catalysis. Some of the
    examples of heterogeneous catalysis are given below:

    (i) Oxidation of sulphur dioxide into sulphur trioxide in the presence of Pt.
    2SO2 (g) Pt(s)  2SO3(g)
    The reactant is in gaseous state while the catalyst is in the solid state.
    Question 216
    CBSEENCH12006626

    How do size of particles of adsorbent, pressure of gas and prevailing temperature influence the extent of adsorption of a gas on a solid?

    Solution

    The extent of adsorption of gases on a solid surface depend on following factor:

    Surface area of adsorbent: The extent of adsorption increases with the increase of surface area of the adsorbent. Thus, finely divided metals and porous substances having large surface areas are good adsorbents.

    It depends on the nature of  gas. More easily  liquefiable gases are adsorbed readily.

    Low temperature is favourable for adsorption. It decreases with increase of temperature

    Question 217
    CBSEENCH12006627

    What is the difference between multimolecular and macro molecular colloids? Give one example of each. How are associated colloids different from these two types of colloids?

    Solution
    MULTIMOLECULAR COLLOIDS MACROMOLECULAR COLLOIDS ACCOCIATED COLLOIDS
    They are formed by the aggregate of a large number of atoms or molecules which generally have diameters less than 1nm, e.g. Sols of gold, sulpher etc. They are molecules of large size e.g. polymers like rubber, nylon, starch. They are formed by of aggregation of a large number of ions in concentrated solution e.g. soap sol.
    Their molecular masses are not very high. They have high molecular masses. Their molecular masses are generally high.
    Their atoms or molecules are held together by weak vander Waal’s forces. Due to long chain, the vander Waal’s forces holding them are comparatively stronger. Higher is the concentration; greater are the vander Waal’s forces.
    They usually have lyophilic character. They usually have lyophobic character. Their molecules contain both lyophobic and lyophilic characters

     

    Question 218
    CBSEENCH12006628

    What are enzymes? Discuss the mechanism of enzymes catalysed reaction.

    Solution

    Enzymes are complex nitrogenous organic compounds which are produced by living plants and animals. They are actually protein molecules of high molecular mass and form colloidal solutions inwater.

    There are a number of cavities present on the surface of colloidal particles of enzymes. These cavities are of characteristic shape and possess active groups such as -NH2 , -COOH, -SH, -OH, etc. These are actually the active centres on the surface of enzyme particles. The molecules of the reactant (substrate), which have complementary shape, fit into these cavities just like a key fits into a lock. On account of the presence of active groups, an activated complex is formed which then decomposes to yield the products.

    Thus, the enzyme-catalysed reactions may be considered to proceed in two steps.
    Step 1: Binding of enzyme to substrate to form an activated complex.
    E + S → ES≠
    Step 2: Decomposition of the activated complex to form product.
    ES≠ → E + P

    Question 219
    CBSEENCH12006629

    Show by a graphic diagram how at a constant pressure a rise in temperature will influence adsorption of a gas on solid when (i) No compound formation occurs, (ii) Chemisorption takes place.

    Solution

    The process of Adsorption is an Exothermic Reaction. Thus according to Le-chatlier’s Principle, the magnitude of adsorption should increase with decrease in temperature. Infact it is found to be so in case of physical adsorption because vanderwaal’s forces are strong at low temperatures. However, the chemisorption first increases with rise in temperature and then starts decreasing. The initial increase shows that like chemical reactions, chemisorption also needs activation energy.



     If a plot is drawn between amount of gas adsorbed (x/m) and temperature at constant equilibrium pressure, then curve obtained for physical adsorption shows there is a regular decrease in adsorption with temperature rise. While for chemisorption it first increases and then shows regular decrease. Such curves are known aAdsorption Isobars.

    Question 220
    CBSEENCH12006630

    Explain the following in connection with colloids (i) Hardy-Schulze rule, (ii) Dialysis.

    Solution

    The quantity of the electrolyte which is required to coagulate a definite amount of a colloidal solution depends upon the valency of the ion having a charge opposite to that of the colloidal particles. This observation of Hardy and Schulze are known as Hardy Schulze law.

    Dialysis:It is a process of removing a dissolved substance from a colloidal solution by means of diffusion through a suitable membrane.
    Since particles ions or smaller molecules) in a true solution can pass through animal membrane (bladder) or parchment paper or cellophane sheet but not the colloidal particles, the membrane can be used for dialysis.

    A bag of  suitable membrane containing the colloidal solution is suspended in a vessel through which fresh water is continuously flowing.  The molecules and ions diffuse through membrane into the outer water and pure colloidal solution is left behind.

    Question 221
    CBSEENCH12006631

    Explain the term adsorption. How does adsorption differ from absorption? What are the different types of adsorption?

    Solution

    The accumulation of molecular species
    at the surface rather than in the bulk of a solid or liquid is termed adsorption. The molecular species or substance, which concentrates or accumulates at the surface is termed adsorbate and the material on the surface of which the adsorption takes place is called adsorbent.

    ADSORPTION

    ABSORPTION

    It is surface phenomenon i.e. it occurs only at the surface of the adsorbent. It is bulk phenomenon i.e. it occurs throughout the body of the material.
    In this phenomenon, the concentration on the surface of adsorbent is different from that in the bulk. In this phenomenon, the concentration is same throughout the material.
    Its rate is high in the beginning and then decreases till equilibrium is attained. Its rate remains same throughout the process.
    Question 222
    CBSEENCH12006632

    Explain the two terms: adsorption isotherm and adsorption isobar. Describe the Freundlich adsorption isotherm. What is the major point of its application?

    Solution

    The variation in the amount of gas adsorbed by the adsorbent with pressure at constant temperature can be expressed by means of a curve termed as adsorption isotherm.
    Most of the adsorptions are exothermic reactions, Hence adsorption generally depends on temperature. Exothermic reactions are mostly spontaneous at low temperature. Hence the extent of adsorption decreases with the increase of temperature at constant pressure. A plot of the extent of adsorption versus temperature at constant pressure is known as adsorption Isobar.

    Freundlich adsorption isotherm: Freundlich gave an empirical relationship between the quantity of gas adsorbed by a unit mass of solid adsorbent and pressure at a particular temperature. The

    the relationship can be expressed by the following equation:



    Freundlich Isotherm: The relationship between x/m and pressure of the gas at constant temperature is called adsorption isotherm and given as by  straight x over straight m space equals space kp to the power of 1 divided by straight n end exponent space left parenthesis straight n greater than 1 right parenthesis and n depend upon the nature of gas and the solid.
    x/m first increase with the increase in pressure at low pressure but becomes independent of pressure at high pressure.
    Thus three cases arise from the graph

    At low pressure, the extent of adsorption is directly proportional to pressure (raised to power one).

    straight x over straight m proportional to straight P to the power of 1
    At high pressure, the extent of adsorption is independent of pressure (raised to power zero).

    straight x over straight m proportional to straight P to the power of 0

    Therefore at an intermediate value of pressure, adsorption is directly proportional to pressure raised to power 1/n.Here n is a variable whose value is greater than one.

    therefore space straight x over straight m space proportional to space straight P to the power of 1 divided by straight n end exponent

    Using constant of proportionality, k, also known as adsorption constant we get

    straight x over straight m equals space kP to the power of 1 divided by straight n end exponent

    The above equation is known as Freundlich adsorption equation.

    As per Freundlich adsorption equation

    straight x over straight m equals space kP to the power of 1 divided by straight n end exponent


    Taking logarithm on both sides, we get
    log space straight x over straight m space equals space log space straight k space plus space 1 over straight n space log space straight p
    Here x is the weight of the gas absorbed by m mass of the adsorbent at a pressure p, k and n are constant (at a particular temperature) and for a particular adsorbate-adsorbent pair.

    The equation above equation is comparable with comparable with the equation of a straight line, 
    y = m x + c where m represents the slope of the line and c represents intercept on y-axis.

    Plotting a graph between log(x/m) and log p, we will get a straight line with the value of slope equal to 1/n and log k as y-axis intercept.


    log(x/m) vs. log p graph.

    Question 223
    CBSEENCH12006633

    What do you mean by colloidal solution and colloidal state? How do collodal solutions differ from true solutions with respect to dispersed particles size, homogenecity, Brownian movement and Tyndall effect.

    Solution

    Colloidal Solution is a heterogeneous mixture in which particle size of substance is intermediate of true solution and suspension i.e. between 1-1000 nm. Smoke from a fire is example of colloidal system in which tiny particles of solid float in air.

    Property

    True Solution

    Colloidal Solutions

    Size of the particles

    1nm– 1000nm

    1000nm

    Nature

    Homogeneous 

    Heterogeneous

    Filterability

    Particles of true Solution diffuse rapidly through filter paper as well as parchment paper.

    Colloidal particles pass through filter paper but not through parchment paper

    VisibilityParticles

    True Solution are not visible to naked eye.

    Colloidal particles are not seen to naked eye but can be studied through ultra microscope

    Tyndall effect

    Solution does not show Tyndall effect.

    Colloids shows Tyndall effect.

     

    Brownian movement

    True solution does not show Brownian movement.

    Brownian movement shown in colloidal solution

    Question 224
    CBSEENCH12006634

    How are colloids classified on the basis of (a) physical states of components, (b) nature of dispersion medium and (c) association between dispersed phase and dispersion medium.

    Solution

    Since the colloidal solutions consist of dispersed phase and dispersion medium, the components of these phases have certain specific characteristics of their own. 

    a) CLASSIFICATION BASED ON PHYSICAL STATE OF DISPERSED PHASE AND DISPERSION MEDIUM

    Based on the physical state of dispersed phase and dispersion medium, there are eight types of colloidal solutions. Either these phases may be solid, liquid or gas. Since gases gives homogeneous mixture in all proportions, hence colloidal solution can not be obtained in which dispersed phase and dispersion medium are gases.

    S.No.
    Dispersed Phase
    Dispersion Medium
    Name of Colloidal Solution
    Examples
    1.
    Gas
    Liquid
    Foam
    Soap lather, whipped cream, soda water, froth on beer.
    2.
    Gas
    Solid
    Solid foam
    Cake, Bread, Pumice stone lava.
    3.
    Liquid
    Gas
    Aerosol
    Mist, fog, Clouds.
    4.
    Liquid
    Liquid
    Emulsion
    Milk, cream, butter, oil in water
    5.
    Liquid
    Solid
    Gel.
    Curd, Cheese, Jellies, boot polish.
    6.
    Solid
    Gas
    Solid Aerosol
    Smoke, dust.
    7.
    Solid
    Liquid
    Sols
    Paints, gold sol, inks.
    8.
    Solid
    Solid
    Solid Sols
    Alloys, coloured glass, gem stones.
     


    b)

    CLASSIFICATION BASED ON APPEARANCE OF THE COLLOIDS

    On this basis, the colloidal solutions can be divided into two types;

    (a)Sol When a colloidal solution appears as fluid it is referred to as Sol. The sols are generally named after dispersion medium. For Instance, when the dispersion medium is water, the sol is known as Hydrosol or Aquosol. When the dispersion medium is alcohol and benzene, the sols are called Alcosol and Benzosol respectively.

     (b)Gels When a colloidal has solid like appearance it is called Gel. The rigidity of gels varies from substance to substance. Some examples of gels are: Jelly, butter, cheese, curd.

    c) CLASSIFICATION BASED ON MOLECULAR SIZE OF THE DISPERSED PHASE
    On the basis of molecular size the colloids can be divided into three types:
    (a)Multimolecular Colloids       
    In these colloids, the Individual particles of the dispersed phase consists of aggregates of atoms or small molecules having diameter less than 10–7cm. For instance a gold sol consists of particles of various size containing several atoms. Likewise, a sulphur sol contains particles each having eight sulphur atoms (S8). In these colloids, the particles are held by weak vanderwaal’s forces.

    (b)Macro Molecular Colloids:
    In these colloids, the particles of dispersed phase are sufficiently large in size enough to be of colloidal dimensions. These are called Natural Polymers. Some typical examples are starch, cellulose and proteins. Some artificial or synthetic polymers are polythene, polystyrene, nylon and plastics.

    (c) Associated Colloids

    These colloids behave as normal electrolytes at low concentrations but behave as colloids at higher concentration. These associated colloids are also referred asMicelles. Sodium Stearate behaves as electrolyte in dilute solution but as colloid at higher concentration. Some other examples of associated colloids are; Soaps, higher alkyl sulphonates, polythene oxide etc.



    Question 225
    CBSEENCH12006635

    (i) Explain the meaning of the statement. ‘Adsorption is a surface phenomenon.’
    (ii) State two features of chemical adsorption which are not found in physical adsorption.
    (iii) Explain the terms with suitable examples: (i) Gel, (ii) Aerosol and (iii) Hydrosol.

    Solution

    i)The accumulation of molecular species at the surface rather than in the bulk of a solid or liquid is termed adsorption.

    Adsorption is essentially a surface phenomenon. Solids, particularly in finely divided state, have large surface area and therefore, charcoal, silica gel, alumina gel, clay, colloids, metals in finely divided state, etc. act as good adsorbents.

    ii)

    Physisorption

    Chemisorption

    It arises because of van der
    Waals’

    It is caused by chemical bond
    formation.

    It is not specific in nature.

    It is highly specific in nature.

    It is reversible in nature

    It is irreversible.

     
    iii)
    i) gel: a solution having a liquid as dispersion medium and a solid as dispersed phase is called gel. For example gum Arabic, agar.

    ii) Aersol: A colloidal solution having a gas as the dispersion medium and a solid as dispersed phase is called an aerosol. For example fog.

    iii) Hydrodol: A colloidal solution having water as the dispersion medium and a solid as the dispersed phase is called a hydrosol. For example starch sol, gold sol.

    Question 226
    CBSEENCH12010036

    Out of BaCl2 and KCl, which one is more effective in causing coagulation of a negatively charged colloidal Sol? Give reason.

    Solution

    According to the Hardy–Schulze rule, the greater the valency of a flocculating ion, the greater will its coagulating power. In Between Ba2+ (from BaCl2) and K+ (from KCl), Ba2+ has greater valency 2 whereas KCl has valency 1. Therefore, BaCl2 will be more effective in causing the coagulation of a negatively charged colloidal sol.

    Question 227
    CBSEENCH12010086

    Give one example each of 'oil in water' and 'water in oil' emulsion.

    Solution

    Type of emulsion

    Example

    Oil in water

     Milk, vanishing cream

    Water in oil

     Butter, cold cream, cod liver oil

    Question 228
    CBSEENCH12010107

    In reference to Freundlich adsorption isotherm, write the expression for adsorption of gases on solids in the form of an equation.

    Solution

     Freundlich adsorption isotherm for adsorption of gases on solids:

      straight x over straight m space equals space straight K subscript straight p superscript 1 over straight n end superscript
It space can space also space be space written space as comma

log straight x over straight m equals log space straight K space plus 1 over straight n log space straight p

    where, x is the mass of the adsorbate, m is the mass of the absorbent and p is the pressure of the gas and n is a constant which is greater than 1.

    Question 229
    CBSEENCH12010108

    Write an important characteristic of lyophilic sols.

    Solution

    Lyophilic sols are sols that are solvent-attracting. An important characteristic of these sols is that if the dispersion medium is separated from the dispersion phase by any method, the sol can be reconstituted by simply remixing the two again. That is why these sols are also known as reversible sols

    Question 230
    CBSEENCH12010109

    Based on the type of particles of dispersed phase, give one example each of associated colloid and multimolecular colloid. 

    Solution

    Example of associated colloid:  Soap solution


    Example of multimolecular colloid:  Gold sol, sulphur sol

    Question 231
    CBSEENCH12010147

    Write the dispersed phase and dispersion medium of the following colloidal systems: 

     (i) Smoke (ii) Milk

    Solution

    Dispersion medium means the medium in which the substance in form of colloidal particles and dispersed phase means the substance distributed in the dispersion medium in form of colloidal particles.

     

    (i) Dispersed phase in smoke: Solid and dispersion medium in smoke: Gas

    (ii) Dispersed phase in milk: Liquid Fat and dispersion medium in milk: Water

    Question 232
    CBSEENCH12010148

    What are lyophilic and lyophobic colloids? Which of these sols can be easily coagulated on the addition of small amounts of electrolytes?

    Solution

    Lyophilic colloids: It is made up of two words; ‘Lyo’ meaning liquid and ‘Phillic’ meaning loving, so those colloids which are attracted by the liquid (solvent), are called as lyophilic colloids. These are also called reversible sols. These are quite stable and cannot be easily coagulated. Example are Sols of organic substances like gelatin, gum, starch and proteins

    Lyophobic colloids: It is made up of two words; ‘Lyo’ meaning liquid and ‘Phobic’ meaning repelling, so those colloids which are repelled by the liquid ( solvent), are called as lyophobic colloids. These are also called irreversible sols and these are unstable and can be easily coagulated due to lack of protecting layer around charged colloidal particles, they easily form a cluster. Hence, they got easily coagulated on the addition of small amount of electrolyte. Examples are Sols of inorganic substances like Arsenic (As2S3), Iron (Fe(OH)3) and Platinum.

    Question 233
    CBSEENCH12010149

    Write the differences between physisorption and chemisorption with respect to the following:

    (i) Specificity

    (ii) Temperature dependence

    (iii) Reversibility and

    (iv) Enthalpy change

    Solution

    Chemisorption is a kind of  adsorption which involves a chemical reaction between the surface and the adsorbate.

    Physiosorption, also called physical adsorption, is a process in which the electronic structure of the atom or molecule is barely perturbed upon adsorption.

     

     

    S. No.

     

    Point of difference

     

    Physiosorption

     

    Chemisorption

    (i)

    Specificity

    This is not specific in nature.

    This is highly specific in nature.

    (ii)

    Temperature dependence

    Low temperature is favourable for physisorption. It decreases with increase in temperature.

    High temperature is favourable for chemisorption. It increases with the increase in temperature.

    (iii)

    Reversibility

    This is reversible in nature.

    This is irreversible in nature.

    (iv)

    Enthalpy change

    Enthalpy of adsorption is low.

    Enthalpy of adsorption is high.

    Question 234
    CBSEENCH12010195

    What is meant by coagulation of a colloidal solution? Describe briefly any three methods by which coagulation of lyophobic sols can be carried out.

    Solution

    Coagulation is a process of aggregating together the colloidal particles so as to change them into large sized particles which ultimately settle as a precipitate. It can also be called as precipitation.

    Coagulation is generally brought about by the addition of electrolyte.

    When an electrolyte is added to the colloidal solution, the particles of the sol take up the ion which is oppositely charged and thus get neutralised.

     

    Following are the three methods by which coagulation of lyophobic sols can be carried out.

    (i) Electrophoresis: In this process, the colloidal particles move towards oppositely charged electrodes and get discharged resulting in coagulation.

    (ii) Mixing of two oppositely charged sols: When equal proportions of oppositely charged sols are mixed, they neutralise each other resulting in coagulation.

    (iii) Dialysis: By this method, electrolytes present in sol are removed completely and colloid becomes unstably resulting in coagulation.

    Question 235
    CBSEENCH12010244

    Define each of the following terms:

    (i) Micelles

    (ii)Peptization

    (iii)Desorption

    Solution

    (i) A micelle is an aggregate of surfactant molecules dispersed in a liquid. A micelle in aqueous solution forms an aggregate such that the hydrophilic 'head' regions are in contact with the surrounding solvent and the hydrophobic tail regions are in the center of micelle.

    (ii) Peptization is the process of conversion of a precipitate into a colloidal sol by shaking it with the dispersion medium in the presence of an electrolyte. The electrolyte used in this reaction is known as a peptizing agent.

    (iii) Desorption is the process of removing an adsorbed substance from the surface through which it was adsorbed.

    Question 236
    CBSEENCH12010261

    Write the dispersed phase and dispersion medium of butter.

    Solution

    In colloidal dispersion, one substance is dispersed as very fine particles in another substance called dispersion medium. In the case of dust, solid particles are dispersed in air as the dispersion medium.

    Dispersed phase: Liquid
    Dispersion medium: Solid

    Question 237
    CBSEENCH12010281

    Define the following terms:
    (i) Brownian movement
    (ii) Peptization
    (iii) Multimolecular colloids

    Solution

    (i) The continuous random zigzag motion of colloidal particles in the colloidal solution, when observed under an ultramicroscope, is called Brownian movement/motion.
    (ii) Peptization is defined as the process of conversion of a precipitate into a colloidal solution by shaking it with the dispersion medium in presence of small amount of an electrolyte.
    (iii) Multimolecular colloids are species having a size in the colloidal range (diameter < 1 nm) that are formed by the aggregation of a large number of atoms or small molecules of substances when dissolved in the dispersion medium.

    Question 238
    CBSEENCH12010291

    Of physisorption or chemisorption, which has a higher enthalpy of adsorption? 

    Solution

    Chemisorption has a higher enthalpy of adsorption as compared to physisorption.

    Question 239
    CBSEENCH12010308

    Define the following terms giving an example of each:

    (i) Associated colloids

    (ii) Lyophilic sol

    (iii) Adsorption

    Solution

    (i) Associated colloids: Associated colloids are those colloids which behave as normal strong electrolytes at low concentrations but exhibit colloidal properties at higher concentrations due to the formation of aggregated particles thus formed are micelles. For e.g. grease droplet surrounded by stearate ions.

    (ii) Lyophilic sol: Lyophilic means liquid-loving colloidal sols directly formed by mixing substances like gum, gelatine etc. with a suitable liquid (the dispersion medium) are called lyophilic sols. If the dispersion medium is separated from dispersed phase (say by evaporation), the sol can be reconstituted by simply remising with the dispersion medium that is why these sols are also known as reversible sols.

    (iii) Adsorption: The accumulation of molecular species at the surface rather than in the bulk of a solid or liquid is known as adsorption. The molecular species which accumulates on the surface is termed as adsorbate and the material on the surface of which the adsorption takes place is called adsorbent.

    For the e.g. aqueous solution of raw sugar, when passed over beds of animal charcoal, becomes colourless as the colouring substances are adsorbed by the charcoal.

    Question 240
    CBSEENCH12010325

    Define ‘peptization’.

    Solution

    Peptization can be defined as a process of converting a precipitate into colloidal sol by shaking it with dispersion medium in the presence of small amount of electrolyte.The electrolyte used in this process is known as a peptizing agent.

    Question 241
    CBSEENCH12010347

    Write three distinct features of chemisorptions which are not found in physisorptions.

    Solution

    Chemisorption is a kind of adsorption which involves a chemical reaction between the surface and the adsorbate.

    Physisorption, also called physical adsorption, is a process in which the electronic structure of the atom or molecule is barely perturbed upon adsorption.

     

              

    S. No.

     

    Point of difference

     

    Physiosorption

     

    Chemisorption

    (i)

    Specificity

    This is not specific in nature.

    This is highly specific in nature.

    (ii)

    Temperature dependence

    Low temperature is favourable for physiosorption. It decreases with increase in temperature.

    High temperature is favourable for chemisorption. It increases with the increase in temperature.

    (iii)

    Reversibility

    This is reversible in nature.

    This is irreversible in nature.

    (iv)

    Enthalpy change

    Enthalpy of adsorption is low.

    Enthalpy of adsorption is high.

     
    Question 242
    CBSEENCH12010362

    Write the main reason for the stability of colloidal sols.

    Solution

    There are two main reasons for the stability of colloidal sols:
    Solvation: Colloidal particles are covered by a sheath of liquid in which they are extensively solvated, thereby providing stability.

    Electrostatic stabilisation: Presence of equal and similar charges on the colloidal particles prevents coagulation of the colloidal sol.

    Question 243
    CBSEENCH12010370

    (i) Differentiate between adsorbtion and absorption.

    (ii)Out of MgCl2 and AlCl3, which one is more effective in causing coagulation of negatively charged sol and why?

    (iii)Out of sulphur sol and proteins, which one form multimolecular colloids?

    Solution

    (i) Adsorption is a surface phenomenon that causes the accumulation of molecules of a substance at the surface of a solid or liquid rather than in the bulk. In adsorption, the substance gets concentrated at the surface only. It does not penetrate through the surface to the bulk of the solid or liquid. For example, when a chalk stick is dipped into an ink solution, only its surface becomes coloured.

    On the other hand, the process of absorption is a bulk phenomenon. In absorption, the absorbed substance gets uniformly distributed throughout the bulk of the solid or liquid. For example, when a sponge is dipped in water the whole sponge gets wets.

    (ii)According to the Schulze-Hardy rule, the effectiveness of the salt causing flocculation depends on the charge on the ion of opposite sign to the charge on the sol particles. The greater the magnitude of the opposite charge, the higher the ability of a salt to coagulate the sol.
    Thus, trivalent salt AlCl3 is more effective in causing the coagulation of a negatively charged sol than divalent salt MgCl2.

    (iii)Out of sulphur sol and proteins, sulphur sol forms multimolecular colloids. Sulphur sol consists of particles containing a thousand or more S8 molecules. On the other hand, proteins form macromolecular colloids.

     

    Question 244
    CBSEENCH12010385

    What is the reason fo the stability of colloidal sols ?

    Solution

    In colloidal sols, the colloidal particles carry a particular charge and the dispersion medium carries an equal but opposite charge. Due to the presence of these similar and equal charges, the particles of the colloid sol  repel one another and cannot combine together to form larger particles which keep them dispersed in the medium and the colloidal remains stable.

    Question 245
    CBSEENCH12010404

    Define the following terms:
    i)Lyophilic colloid
    ii) Zeta potential
    iii) Associated colloids

    Solution

    i) Lyophilic colloids are liquid loving colloids (Lyo means solvent and philic means loving). When these colloids are mixed with the suitable liquid, high force of attraction exists between colloidal particles and liquid. This result in the formation of very stable solution called lyophilic sol. These sols are formed by substances like gums, starch and proteins.

    ii) Zeta Potential : zeta potential is the potential difference between the dispersion medium and the stationary layer of fluid attached to the dispersed particle.

    iii) Association colloids are microheterogeneous systems in which the particles of the colloidal dispersed phase (micelles) are formed by the agglomeration of molecules or ions of the substance dissolved in the dispersion medium.

    Question 246
    CBSEENCH12010431

    Classify colloids where the dispersion medium is water. State their characteristics and write an example of each of these classes.

    OR

    Explain what is observed when

    (i) An electric current is passed through a sol

    (ii) A beam of light is passed through a sol

    (iii) An electrolyte (say NaCl) is added to ferric hydroxide sol

    Solution

    Colloids containing dispersion medium as water can be classified as follows:

    Dispersed phase

    Dispersion medium

    Type of colloid

    Example

    Solid

    Liquid

    Sol

    Paints, cell fluids

    Liquid

    Liquid

    Emulsion

    Milk, hair cream

    Gas

    Liquid

    Foam

    Froth, soap lather

     OR

    (i) The colloidal particles are charged and carry either a positive or a negative charge. The dispersion medium carries an equal and opposite charge. This makes the entire system neutral. Under the influence of an electric current, the colloidal particles move towards the oppositely charged electrode. When they come in contact with the electrode, they lose their charge and coagulate.

    (ii) When a beam of light is passed through a colloidal solution, a scattering of light is observed. This is known as Tyndall effect. This scattering of light illuminates the path of the beam in the colloidal solution.

    (iii) When NaCl is added to hydrated ferric hydroxide sol, it dissociates to give Na+ and Cl- ions. Particles of ferric hydroxide sol are positively charged. This neutralises the colloidal particles which then unite to form bigger particles that are consequently precipitated. Thus, they get coagulated in the presence of negatively charged Cl- ions.

    Question 247
    CBSEENCH12010462

    What are emulsions? What are their different types? Give one example of each type.

    Solution

    Emulsions are the liquid−liquid colloidal systems, obtained on mixing two immiscible or partially miscible liquids.

    There are two types of emulsions.

    (1) Oil dispersed in the water type (O/W) : Here water is the dispersion medium, e.g. milk.

    (2) Water dispersed in oil type (W/O) : Here oil is the dispersion medium, e.g. butter.

    Question 248
    CBSEENCH12010476

    Write one similarity between Physisorption and Chemisorption?

    Solution

    (i) Physisorption and Chemisorption both are a surface phenomenon.
    (ii) Physisorption and Chemisorption both increase with increase in surface area

    Question 249
    CBSEENCH12010494

    Write one difference in each of the following :
    Lyophobic sol and Lyophilic sol

    Solution

    Lyophilic sol: These are also called reversible sols. These are quite stable and cannot be easily coagulated. Example are Sols of organic substances like gelatin, gum, starch and proteins

    Lyophobic sol: These are also called irreversible sols and these are unstable and can be easily coagulated due to lack of protecting layer around charged colloidal particles, they easily form a cluster. Hence, they got easily coagulated on the addition of small amount of electrolyte. Examples are Sols of inorganic substances like Arsenic (As2S3), Iron (Fe(OH)3 and platinum.

    Question 250
    CBSEENCH12010496

    Write one difference in each of the following :
    Homogeneous catalysis and Heterogeneous catalysis

    Solution

    Homogeneous catalysis: When the reactants and the catalyst are in same phase (i.e., Liquid or gas), the process is said to be homogeneous catalysis. For example, Oxidation of sulphur dioxide into sulphur trioxide with dioxygen in presence of oxides of nitrogen as the catalyst in the process.
    2SO2(g) + O2(g)→ NO(g) +2SO3(g)

    Heterogeneous catalysis: The catalytic process in which the reactant and the catalyst are in different phase is known as heterogeneous.For example Oxidation of sulphur dioxide into sulphur trioxide in the presence of Pt.
    2SO2(g) + pt(s)→ 2SO3 (g)

    Question 251
    CBSEENCH12010546

    CO(g) and H2 (g) react to give different products in the presence of different catalysts. Which ability of the catalyst is shown by these reactions?

    Solution

    The characteristic shown by the catalyst is known as catalytic selectivity, i.e, the catalyst determines the products formed. For example,

    1. If CO and H2 react in the presence of Ni (nickel) as catalyst the product is methane.
    2. If CO and H2 react in the presence of Cu (copper) as catalyst the product formed is methanol.

    Question 252
    CBSEENCH12010586

    What happens when

    A freshly prepared precipitate of Fe(OH)3 is shaken with a small amount of FeCl3 solution?

    Solution

    When freshly precipitated Fe(OH)3 is shaken with the little amount of dilute solution of FeCl3(electrolyte).
    Peptization process (ions of the electrolyte are adsorbed by the precipitate particles) takes place by converting the Fe(OH)3 precipitate into a colloidal solution positively charged solution of Fe(OH)3.

    Question 253
    CBSEENCH12010587

    What happens when

    Persistent dialysis of a colloidal solution is carried out?

    Solution

    On persistent dialysis, the electrolyte present in the sol is removed completely, the colloid becomes unstable and coagulates.

    Question 254
    CBSEENCH12010588

    What happens when

    An emulsion is centrifuged?

    Solution

    When an emulsion is centrifuged, demulsification takes place, i.e. the emulsion is broken into constituent liquids.

    Question 255
    CBSEENCH12010614

    For a linear plot of log (x/m) versus log p in a Freundlich adsorption isotherm, which of the following statements is correct? (k and n are constants)

    • 1/n appears as the intercept.

    • Only 1/n appears as the slope.

    • log (1/n) appears as the intercept.

    • Both k and 1/n appear in the slope term

    Solution

    B.

    Only 1/n appears as the slope.

    According to Freundlich adsorption isotherm,
    straight x over straight m space equals space kp to the power of 1 divided by straight n end exponent
    On taking logarithm both sides, we get
    log space straight x over straight m space equals space log space straight k space plus space log space straight p to the power of 1 divided by straight n end exponent
or
straight x over straight m space equals space log space straight k space plus space 1 over straight n space log space straight p

    straight y space equals space log space straight x over straight m comma c= intercept = log k, m =slope = 1/n and x = log p

    Question 256
    CBSEENCH12010685

    The coagulating power of electrolytes having ions Na+, Al3+ and Ba2+ for arsenic sulphide sol increases in the order:

    • Al3+<Ba2+<Na+

    • Na+<Ba2+<Al3+

    • Ba2+< Na2+<Al3+

    • Al3+< Na+<Ba2+

    Solution

    B.

    Na+<Ba2+<Al3+

    As2S3 is an anionic sol (negative sol) hence coagulation will depend upon coagulating power of cation, which is directly proportional to the valency of cation (Hardy-Schulze rule). 

    Question 257
    CBSEENCH12010697

    According to Freundlich adsorption isotherm, which of the following is correct?

    • straight x over straight m space proportional to space straight p to the power of 0
    • straight x over straight m space proportional to space straight p to the power of 1
    • straight x over straight m space proportional to space straight p to the power of 1 divided by straight n end exponent
    • All of the above are correct for a different range of pressure

    Solution

    D.

    All of the above are correct for a different range of pressure


    straight x over straight m space equals space kp to the power of 1 divided by straight n end exponent space left parenthesis in space between space low space and space high space pressure right parenthesis

When comma space straight n equals space 1 space straight x over straight m proportional to straight p to the power of 1 space left parenthesis inlower space pressure space range right parenthesis
space straight x over straight m space equals straight k space left parenthesis independent space of space pressure right parenthesis
Thus comma space straight x over straight m proportional to space straight p to the power of 0 space left parenthesis in space high space pressure space range space when space saturation space point space is space reached right parenthesis
    Question 259
    CBSEENCH12010776

    Which of the following statements is incorrect regarding physissorptions?

    • It occurs because of vander Waal’s forces.

    • More easily liquefiable gases are adsorbed readily.

    • Under high pressure, it results into multimolecular layer on the adsorbent surface.

    • Enthalpy of adsorption ( ∆Hadsorption)  is low and positive

    Solution

    D.

    Enthalpy of adsorption ( ∆Hadsorption)  is low and positive

    Enthalpy of adsorption in physisorption is negative
    ∆G = ∆H - T∆S
    As the entropy decreases (∆S = –ve) the ∆H must be negative having a high magnitude. Therefore, the spontaneous adsorption will have negative enthalpy change.

    Question 262
    CBSEENCH12011043

    Fog is a colloidal solution of 

    • Gas in liquid

    • Solid in gas

    • Gas in gas

    • Liquid in gas

    Solution

    D.

    Liquid in gas

    Fog is a colloidal solution of liquid in a gas in which liquid is the dispersed phase whereas gas is the dispersion medium.

    Question 263
    CBSEENCH12011077

    Which property of colloidal solution is independent of charge on the colloidal particles?

    • Coagulation

    • Electrophoresis

    • Electroosmosis

    • Tyndall effect

    Solution

    D.

    Tyndall effect

    Coagulation is generally brought about by the addition of electrolytes. When an electrolyte is added to a colloidal solution, the particles of the sol take up the ions which are oppositely charged. As a result, their charge gets neutralised.
    Electrophoresis: The movement of colloidal particles under an applied electric potential is called electrophoresis. Electroosmosis may be defined as a phenomenon in which the molecules of the dispersion medium are allowed to more under the influence of an electric field whereas colloidal particles are not allowed to more.
    Tyndall effect is the scattering of light by sol particles, which cannot be affected by change on them

    Question 264
    CBSEENCH12011092

    Which property of colloids is not dependent on the charge on colloidal particles?

    • Coagulation

    • Electrophoresis

    • Electro-osmosis

    • Tyndall effect

    Solution

    D.

    Tyndall effect

    Tyndall effect is an optical phenomenon which occurs due to the scattering of light by the colloidal particles. Hene, it is independent of charge.

    Question 265
    CBSEENCH12011157

    The ease of adsorption of the hydrated alkali metal ions on an ion exchange resins follows the order

    • Li+ > K+ >Na+> Rb+

    • Rb+ < K+ < Na+ < Li+

    • K+ >Na+>  Rb+ > Li+

    • Na+ < Li+ < K+ < Rb+

    Solution

    B.

    Rb+ < K+ < Na+ < Li+

    Ease of adsorption of the hydrated alkali metal ions on an ion-exchange resin decreases as the size of alkali metal ion increases.
    since, the order of the size of alkali metal ions
    Li+ < Na+ < K+ < Rb+

    Thus,  the ease of adsorption follows the order
    Rb+ < K+ < Na+ < Li+

    Question 266
    CBSEENCH12011160

    The protecting power of lyophilic colloidal sol is expressed in terms of 

    • Coagulation value

    • Gold number

    • Critical micelle concentration

    • Oxidation number

    Solution

    B.

    Gold number

    Lyophobic sols are unstable, so they re-stabilised by adding some lyophilic colloids which protect them from precipitation. Thus, lyophilic colloids are called protecting colloids. Their protecting power is expressed in terms of gold number.
    [Lesser the gold number, higher si the protecting power,]

    Question 267
    CBSEENCH12011362

    The Langmuir adsorption isotherm is deduced using  the assumption: 

    • the adsorption takes place in multilayers

    • The adsorption sites are equivalent in their ability to adsorb the particles

    • The adsorbed molecules interact with each other

    • The adsorbed molecules interact with each other

    Solution

    A.

    the adsorption takes place in multilayers

    The main points  of Langmuir theroy of adsorption are as:
    i) Adsorption takes place on the surface of the solid only till the whole of the surface is completely covered with a unimolecular layer of the adsorbed gas.
    ii) Adsorption consist fo two opposing processes (a) condensation, and (b) evaporation.
    iii) The rate of condensation depend upon  the uncovered surface of the adsorbent available for condensation.

    Question 268
    CBSEENCH12011387

    A plot of log x/m versus log p for the adsorption of a gas on a solid gives a straight line with slope equal to:

    • -log k

    • n

    • 1/n

    •  log k

    Solution

    C.

    1/n

    The empirical relation x/m = kp1/n put forward by Freundlich is known as Freundlich adsorption isotherm. Taking logarithm
    log space straight x over straight m space equals space log space straight k space plus 1 over straight n space log space straight p
    If the following curve is plotted

    Question 269
    CBSEENCH12011466

    On which of the following properties does the coagulating power of an ion depend?

    • The magnitude of the charge on the ion alone

    • Size of the ion alone

    • The sign of the charge on the ion alone

    • Both magnitude and sign of the charge on the ion

    Solution

    D.

    Both magnitude and sign of the charge on the ion

    According to Hardy Schulze rule, coagulating power of an ion depends on both magnitude and sign of the charge on the ion.

    Question 270
    CBSEENCH12011467

    Given van der Waals constant for NH3, H2, O2 and CO2 are respectively 4.17, 0.244, 1.36 and 3.59, which one of the following gases is most easily liquefied?

    • NH3

    • H2

    • CO2

    • O2

    Solution

    A.

    NH3

    Vander Waal constant 'a', signifies intermolecular forces of attraction.

    Higher is the value of 'a', easier will be the liquefaction of gas.

    Question 271
    CBSEENCH12011492

    Which of the following is not applicable to the phenomenon of adsorption?

    • ΔH> 0

    • ΔG<0

    • ΔS<0

    • ΔH<0

    Solution

    D.

    ΔH<0

    Due to adsorption attractive forces increases, thus ΔH<0 i.e. (-) ve.

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