Problems On Numbers

Sponsor Area

Question
SSCCGLENQA12042438

Each member of a club contributes as much rupees and as much paise as the number of members of the club. If the total contribution is Rs. 2525, then the number of members of the club is

  • 60

  • 45

  • 55

  • 50

Solution

D.

50

Let Number of members in the club  = x
According to the question,
straight x squared plus straight x squared over 100 space equals space 2525
WiredFaculty

Sponsor Area

Question
SSCCGLENQA12042497

If the sum of squares of two real numbers is 41 and their sum is 9. Then the sum of cubes of these two numbers is

  • 169

  • 209

  • 189

  • 198

Solution

C.

189

Let the two real numbers be x and y.
According to the question,
       WiredFaculty
WiredFaculty
therefore space space straight x cubed plus straight y cubed space equals space left parenthesis straight x plus straight y right parenthesis space left parenthesis straight x squared minus xy plus straight y squared right parenthesis
              = (9) (41 - 20) = 9 x 21 = 189

Question
SSCCGLENQA12043325

The greater of the two numbers whose product is 900 and the sum exceeds their difference by 30 is

  • 60

  • 75

  • 90

  • 100

Solution

A.

60

Let the numbers be x and y where x > y.
According to the question,
    (x + y) -  (x - y) = 30
⟹   x + y - x + y = 30
⟹     2y = 30
WiredFaculty

Question
SSCCGLENQA12042848

The least positive integer that should be subtracted from 3011 x 3012 so that the difference is a perfect square is

  • 3009

  • 3010

  • 3011

  • 3012

Solution

C.

3011

The expression is:
 = 3011 x 3012
 = 3011 (3011 + 1)
 = (3011)2 + 3011
∴ Required answer = 3011

Question
SSCCGLENQA12042852

The product of two number is 1575 and their quotient is 9/7. Then the sum of the numbers is

  • 74

  • 78

  • 80

  • 90

Solution

C.

80

Let the numbers be x and y.
∴   (x) x (y) = 1575 (given)  ...(i)
And,
 straight x over straight y space equals space 9 over 7  (given)  ...(ii)
Multiply (i) x (ii)
WiredFaculty
WiredFaculty

5