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7 years ago, the ages (in years) of A and B were in the ratio 4 : 5; and 7 years hence they will be in the ratio 5 : 6. The present age of B is
56 years
63 years
70 years
77 years
D.
77 years
After 7 years, Required age
= 5x + 7 = 5 x 14 + 7 = 77 years
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In one hour, a boat goes 12 km along the stream and 8km against the stream. The speed of the boat in still water is
12 km/h
11 km/h
10 km/h
8 km/h
C.
10 km/h
Speed of boat = 
= 
The present ages of A and B are in the ratio 3 : 4. Ten years ago, this ratio was 4 : 7. The present age of A and B are respectively:
18 years, 24 years
21 years, 28 years
24 years, 32 years
27 years, 36 years
A.
18 years, 24 years
Let present age of A = 3x
And present age of B = 4x
According to the question,
∴ Present age of A = 3x = 3 x 6 = 18 years
Present age of B = 4x = 4 x 6 = 24 years
The sum of the age of mother and a mother and her daughter is 60 years. 12 years ago the mother was eight times as old as her daughter. How old is the daughter at present?
20 yr
28 yr
16 yr
12 yr
C.
16 yr
Let, present age of mother = M Years
and present age of daughter = D Years.
Now, according to the question,
M + D = 60 ...(i)
and (M − 12) = 8(D−12) 
M−12 = 8D−96
M − 8D = −84
Now, solving Eqs. (i) and (ii), we have
D = 16 years
Hence, the present age of daughter = 16 years.
The sum of the ages of two brothers, having a difference of 8yr between them, will double after 10 yr. What is the ratio of the age of the younger brother to that of the elder brother?
7 : 11
3 : 7
8 : 9
10 : 13
B.
3 : 7
Let the present age of two brother's be x yr and (x + 8) yr.
After 10 yr,
Ages of two brothers (x + 10)
and (x + 8 + 10)
According to the question,
x + 10 + x + 18 = (x + x + 8) x 2
2x + 28 = (2x + 8) x 2
2(x + 14) = (2x + 8) x 2
x + 14 = 2x + 8
x - 2x = 8 - 14
-x = -6 or x = 6
Required ratio = 
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