Question
If the number of items of a set A be n(A) = 40, n(B) = 26 and n(A∩B) = 16, then n (A∪B) is equal to
-
30
-
40
-
50
-
60
Solution
C.
50
n(A ∪ B) = n(A) + n(B) - n(A ∩ B)
= 40 + 26 - 16 = 50
