Heights and Distances

Sponsor Area

Question
SSCCGLENQA12042405

129 m from the foot of a cliff on level of ground, the angle of elevation of the top of a cliff is 30 degree. The height of this cliff is

  • 50 square root of 3 straight m
  • 45 square root of 3 space straight m
  • 43 square root of 3 space straight m
  • 47 square root of 3 space straight m

Solution

C.

43 square root of 3 space straight m

In increment ABC comma
tan space 30 degree space equals space AC over BC
fraction numerator 1 over denominator square root of 3 end fraction equals space straight h over 129
space space space space space straight h space equals space fraction numerator 129 over denominator square root of 3 end fraction cross times fraction numerator square root of 3 over denominator square root of 3 end fraction
space space space space space straight h space equals space 129 over 3 square root of 3
space space space space space straight h space equals space 43 square root of 3 space straight m

Sponsor Area

Question
SSCCGLENQA12042352

A 25m long ladder is rested on a wall. The foot of the ladder is 7m away from the wall. If the end of the ladder (resting on the wall) slides down 4m, then how far will its foot move away?

  • 5 m

  • 8 m

  • 9 m

  • 10 m

Solution

B.

8 m


In increment ABC
   left parenthesis AB right parenthesis squared space equals space left parenthesis BC right parenthesis squared plus left parenthesis AC right parenthesis squared
left parenthesis 25 right parenthesis squared space equals space left parenthesis 7 right parenthesis squared plus AC squared
625 space equals space 49 space plus space AC squared
AC squared space equals space 576
AC space equals space 24 space straight m
So, the height of ladder from ground  = 24 m
When, the end of the ladder slides down 4 m, then
The height of ladder from ground = 24 - 4 = 20 m
In increment ABC comma
left parenthesis AB right parenthesis squared space equals space AC squared plus BC squared
left parenthesis 25 right parenthesis squared space equals space left parenthesis 20 right parenthesis squared plus BC squared
625 space equals space 400 space plus space BC squared
BC squared space equals space 225
BC space equals 15 space straight m
therefore The foot of ladder will move away = 15 - 7 = 8 m
                

Question
SSCCGLENQA12043335

A man on the top of a tower, standing on the sea shore, finds that a boat coming towards him takes 10 minutes for the angle of depression to change from 30° to 60°. How soon the boat reach the sea-shore?

  • 5 minutes

  • 7 minutes

  • 10 minutes

  • 15 minutes

Solution

A.

5 minutes


Let speed of boat  = v metre/minute
Time taken to reach B from D = t minutes
angle ACB space equals space 30 degree semicolon space space space angle ADB space equals space 60 degree [given]
Now in increment ABC comma
tan space 30 degree space equals space AB over BC
rightwards double arrow space fraction numerator 1 over denominator square root of 3 end fraction space equals space fraction numerator AB over denominator vt space plus space 10 straight v end fraction
rightwards double arrow space AB space equals space fraction numerator vt space plus space 10 straight v over denominator square root of 3 end fraction
In increment ABD comma
tan space 60 degree space equals space AB over BD
rightwards double arrow space space square root of 3 space equals space AB over vt
rightwards double arrow space space square root of 3 space vt space equals space AB
rightwards double arrow space space square root of 3 space vt space equals space fraction numerator 10 straight v space plus space vt over denominator square root of 3 end fraction
rightwards double arrow space space space 3 straight t space equals space 10 space plus space straight t
rightwards double arrow space space space 2 straight t space equals space 10
rightwards double arrow space space space straight t space equals space space 5 space minutes

Question
SSCCGLENQA12043356

A man standing on the bank of a river observes that the angle of elevation of the top of a tree just on the opposite bank is 60°. But the angle of elevation is 30° from a point which is at a distance of 20 square root of 3 space ft from the bank. Then the height of the tree

  • 60 ft

  • 45 ft

  • 30 ft

  • 15 ft

Solution

C.

30 ft

A man standing on the bank of a river observes that the angle of eleva
Let the height of the tree be h ft
In ΔBDC,
tan space 60 degree space equals space straight h over straight x
rightwards double arrow space space square root of 3 space equals space straight h over straight x
rightwards double arrow space space space straight x space equals space fraction numerator straight h over denominator square root of 3 end fraction space space space... left parenthesis straight i right parenthesis
 
In ABC,
tan space 30 degree space equals space fraction numerator straight h over denominator straight x plus 20 square root of 3 end fraction
rightwards double arrow space space fraction numerator 1 over denominator square root of 3 end fraction space equals space fraction numerator straight h over denominator straight x plus 20 square root of 3 end fraction
rightwards double arrow space space space straight x space plus space 20 square root of 3 space equals space straight h square root of 3
rightwards double arrow space space fraction numerator straight h over denominator square root of 3 end fraction space plus space 20 square root of 3 space equals space straight h square root of 3 space space space space left square bracket using space left parenthesis straight i right parenthesis right square bracket space
rightwards double arrow space space straight h square root of 3 minus fraction numerator straight h over denominator square root of 3 end fraction space equals space 20 square root of 3
rightwards double arrow space space 3 straight h space minus space straight h space equals space 20 square root of 3 space cross times space square root of 3
rightwards double arrow space space space space 2 straight h space equals space 60 comma space space space straight h space equals space 30 space ft

Question
SSCCGLENQA12042383

A man standing on the bank of river observes that the angle subtended by a tree on the opposite bank is 60 degree. When he retires 36 m from the bank, he finds that the angle is 30o. The breadth of the river is

  • 15 m

  • 18 m

  • 16 m

  • 11 m

Solution

B.

18 m


In increment ABD comma
  tan space 60 degree space equals space straight h over straight x
space space space square root of 3 space equals space straight h over straight x
    straight h space equals space square root of 3 straight x
 In increment ABC
tan space 30 degree space equals space fraction numerator straight h over denominator 36 plus straight x end fraction
   fraction numerator 1 over denominator square root of 3 end fraction space equals fraction numerator straight h over denominator 36 plus straight x end fraction
36 plus straight x space equals straight h square root of 3
space 36 plus straight x space equals space square root of 3 space cross times space square root of 3 straight x
space 36 plus straight x space equals space 3 straight x
space space 2 straight x space equals space 36
space space space straight x space equals space 18 space straight m

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