Motion In Straight Line
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A ball is dropped from a high-rise platform at t=0 starting from rest. After 6s another ball is thrown downwards from the same platform with a speed v. The two balls meet at t= 18s. What is the value of v? (take g= 10 ms-2)
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74 ms-2
-
55 ms-1
-
40 ms-1
-
60 ms-1
A.
74 ms-2
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A body of mass 3 kg is under a constant force which causes a displacement s in metres in it, given by the relation
, where t is in s. Work done by the force in 2 s is:
C.
If a constant force is applied on the object causing a displacement in it, then it is said that work has been done on the body to displace it.
Work done by the force = Force x Displacement
or W = F x s ...(i)
But from Newton's 2nd law, we have
Force = Mass x Acceleration
i.e., F = ma ...(ii)
Hence, from Eqs. (i) and (ii), we get
Hence, Eq (ii) becomes


We have given

A conveyor belt is moving at a constant speed of 2 m/s. A box is gently dropped on it. The coefficient of friction between them is μ = 0.5. The distance that the box - will move relative to belt before coming to rest on it taking
g= 10 ms-2 is
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1.2 m
-
0.6 m
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zero
-
0.4 m
D.
0.4 m
Force,
Retardation of the block on the belt

A particle covers half of its total distance with speed v1 and the rest half distance with speed v2. Its average speed during the complete journey is
-
v1v2 / v1 + v2
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2v1v2/v1 + v2
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2v12v22 / v12 + v22
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v1 + v2 / 2
B.
2v1v2/v1 + v2
Velocity v = s / t
s = vt
The average speed of particle
A particle is moving such that its position coordinates (x,y) are (2m, 3m) at time t = 0, (6m, 7m) at time t = 2 sec and (13 m, 14m) at time t= 5 sec. Average velocity vector (vav) from t = 0 to t = 5 s is,
D.
Average velocity vector,
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Mock Test Series
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