Chemical Kinetics

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Question
CBSEENCH12011433

A first-order reaction has a specific reaction rate of 10–2 s–1. How much time will it take for 20 g of the reactant to reduce to 5 g?

  • 238.6 second

  • 138.6 second

  • 346.5 second

  • 693.0 second

Solution

B.

138.6 second

straight t subscript 1 divided by 2 end subscript space equals space fraction numerator 0.693 over denominator 10 to the power of negative 2 end exponent end fraction
For the reduction of 20 g of reactant to 5 g, two t1/2 is required.
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Question
CBSEENCH12011172

Activation energy (Ea) and rate constants (k1 and k2) of chemical reaction at two different temperatures (T1 and T2) are related by

  • ln space k subscript 2 over k subscript 1 space equals negative E subscript a over R open parentheses 1 over T subscript 1 minus 1 over T subscript 2 close parentheses
  • ln space k subscript 2 over k subscript 1 space equals negative E subscript a over R open parentheses 1 over T subscript 2 minus 1 over T subscript 1 close parentheses
  • ln space k subscript 2 over k subscript 1 space equals negative E subscript a over R open parentheses 1 over T subscript 2 plus 1 over T subscript 1 close parentheses
  • ln space k subscript 2 over k subscript 1 space equals E subscript a over R open parentheses 1 over T subscript 1 minus 1 over T subscript 2 close parentheses

Solution

D.

ln space k subscript 2 over k subscript 1 space equals E subscript a over R open parentheses 1 over T subscript 1 minus 1 over T subscript 2 close parentheses

According to Arrhenius equation, activation energy (Ea) and rate constants (k1 and k2) of chemical reaction at two different temperatures (T1 and T2) are related as,
ln space k subscript 2 over k subscript 1 space equals E subscript a over R open parentheses 1 over T subscript 1 minus 1 over T subscript 2 close parentheses

Question
CBSEENCH12011401

Consider the reaction

N2 (g) + 3 H2 (g) → 2 NH3 (g) 

The equality relationship between  fraction numerator straight d left square bracket NH subscript 3 right square bracket over denominator dt end fraction space and space fraction numerator negative straight d left square bracket straight H subscript 2 right square bracket over denominator dt end fraction is:

  • fraction numerator straight d left square bracket NH subscript 3 right square bracket over denominator dt end fraction space equals space minus space 1 third fraction numerator straight d left square bracket straight H subscript 2 right square bracket over denominator dt end fraction
  • fraction numerator straight d left square bracket NH subscript 3 right square bracket over denominator dt end fraction space equals space minus space 2 over 3 fraction numerator straight d left square bracket straight H subscript 2 right square bracket over denominator dt end fraction
  • plus fraction numerator straight d left square bracket NH subscript 3 right square bracket over denominator dt end fraction space equals space minus 3 over 2 fraction numerator straight d left square bracket straight H subscript 2 right square bracket over denominator dt end fraction
  • fraction numerator straight d left square bracket NH subscript 3 right square bracket over denominator dt end fraction space equals space minus space fraction numerator straight d left square bracket straight H subscript 2 right square bracket over denominator dt end fraction

Solution

B.

fraction numerator straight d left square bracket NH subscript 3 right square bracket over denominator dt end fraction space equals space minus space 2 over 3 fraction numerator straight d left square bracket straight H subscript 2 right square bracket over denominator dt end fraction

For the reaction,
N2 (g) + 3 H2 (g) → 2 NH3 (g)
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Question
CBSEENCH12011286

During the kinetic study of the reaction, 2A + B --> C+ D,  following results were obtained 


 

[A]/mol L-

[B]/ mol L-

Initial rate of formation of D/ mol L- min-

I

0.1

0.1

6.0 x 10-3

II

0.3

0.2

7.2 x 10-2

III

0.3

0.4

2.88 x 10-1

IV

0.4

0.1

2.40 x10-2

 
based on the above data which one of the following is correct?
  • rate = k[A]2[B]

  • rate = k [A][B]

  • rate = k[A]2[B]2

  • rate = k[A][B]2

Solution

D.

rate = k[A][B]2

Let the order of reaction with respect to A is x and with respect to B is y. Thus,
rate = k[A]x[B]y
For the given cases,


(I) rate = k(0.1)x (0.1)y = 6.0 x 10-3
(II) rate = k (0.3)x (0.2)y = 7.2 x 10-2
(III) rate =k(0.3)x (0.40)y = 2.88 x 10-1
(IV) rate = k(0.4)x (0.1)y = 2.40 x 10-2

On dividing eq. (I) and (IV), we get
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Question
CBSEENCH12011274

For an endothermic reaction, energy of activation is Ea and enthalpy of reaction is ΔH (both of these in kJ/mol). Minimum value of Ea will be

  • less than ΔH

  • equal to ΔH

  • more than ΔH

  • equal to zero

Solution

C.

more than ΔH

In endothermic reactions, the energy of reactants is less than that of the products. Potential energy diagram for endothermic reactions is,
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Where Ea = activation energy of forwarding reaction
Ea' = activation energy of backwards reaction
ΔH = enthalpy of the reaction
From the above diagram,
Ea = Ea' + ΔH
Thus, Ea > ΔH