States Of Matter

Sponsor Area

Question
CBSEENCH11008461

20-litre container at 400 K contains CO2(g) at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO). The volume of the containers is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when pressure of CO2 attains its maximum value, will be

Given that: SrCO3 ⇌ SrO(s) + CO2(g) kp = 1.6 atm)

  • 5 litre

  • 10 litre

  • 8 litre

  • 3  litre

Solution

A.

5 litre

Max. the pressure  of CO2= Pressure of CO2 at equilibrium
For reaction, SrCO3 ⇌ SrO(s) + CO2(g)
Kp= PCO2 = 1.6 atm = maximum pressure of CO2
Volume Container at this stage,
V= nRT/P .... (i)

Since container is sealed and reaction was not  earlier at equilibrium
therefore, n = constant
n= Pv/RT  .... (ii)
from equation (i) and (ii) we get
V = (0.4 x 20)/RT = 5 Litre

Sponsor Area

Question
CBSEENCH11008272

50 mL of each gas A and of gas B takes 150 and 200 s respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas B is 36, the molecular mass of gas A will be

  • 96

  • 128

  • 20.2

  • 64

Solution

C.

20.2

Given,
VA =VB = 50 mL
TA = 150 s
TB = 200 s
MB = 36
MA = ?
From Graham's law of effusion
WiredFaculty

Question
CBSEENCH11008289

A  certain gas takes three times as long to effuse out as helium. Its molecular mass will be 

  • 27 u

  • 36 u 

  • 64 u

  • 9 u

Solution

B.

36 u 

From Graham's diffusion law,
WiredFaculty

Question
CBSEENCH11008342

A bubble of air is underwater at temperature 15o C  and the pressure 1.5 bar. If the bubbles rises to the surface where the temperature is 25o C and the pressure is 1.0 bar, what will happen to the volume of the bubble?

  • Volume will become greater by a factor of 1.6 

  • Volume will become  greater by a factor of 1.1

  • Volume will become  smaller by a factor of 0.70

  • Volume will become greater by a factor of 2.9

Solution

A.

Volume will become greater by a factor of 1.6 

WiredFaculty
i.e., volume of bubble will be almost 1.6 times to initial volume of bubble.

Question
CBSEENCH11008322

A gas such as carbon monoxide would be most likely to obey the ideal gas law at

  • high temperatures and low pressures

  • low temperatures and high pressures

  • high temperatures and high pressures

  • low temperatures and low pressures

Solution

A.

high temperatures and low pressures

Real gases show ideal gas behaviour at high temperatures and low pressures.
 
PV = nRT

3