Aldehydes, Ketones and Carboxylic Acids

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Question
CBSEENCH11008498

A carbonyl compound reacts with hydrogen cyanide to form cyanohydrin which on hydrolysis forms a racemic mixture of alpha -hydroxy acid. The carbonyl compound is: 

  • CH3-CH2-CH2COCH3

  • (CH3)2C=O

  • CH3CH2CHO

  • CH3CHO

Solution

D.

CH3CHO


The carbonyl compounds undergo nucleophilic addition reaction because oxygen is more electronegative than carbon. As such, it withdraws share pi electron pair towards itself and gets a partial negative charge, therefore carbon gets a partial positive charge and becomes susceptible to nucleophilic attack.
The aldehyde is more reactive than ketones towards nucleophiles. This can be explained on the basis of inductive effect as well as steric effect. The addition of nucleophiles is based upon the positive charge present on a carbon atom of > C =O group.
In aldehyde >C=O group is present at least one alkyl group (except formaldehyde) which has +I effect (electron donating effect) and which decreases the positive charge of carbon, thereby making the attack to nucleophile difficult. The nucleophilic attack becomes more difficult in ketones having a minimum of two alkyl groups.
Hence, by means of attachment of alkyl groups (due to +I effect) rate of nucleophiles addition decreases.
Order of +I effect in an alkyl group.

order of nucleophilic addition in given carbonyl compound is 
CH3CHO > CH3-CH2- CHO > (CH3)2CO> CH3CH2CH2COCH3

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Question
CBSEENCH11008497

A carbonyl compound reacts with hydrogen cyanide to form cyanohydrin which on hydrolysis forms a racemic mixture of alpha-hydroxy acid. The carbonyl compound is:

  • acetaldehyde

  • acetone

  • diethyl ketone

  • formaldehyde

Solution

A.

acetaldehyde


If it is a racemic mixture, therefore such 'C' atom must be the asymmetric carbon atom.

Question
CBSEENCH12011249

A organic compound 'A' on treatment with NH3 gives 'B' which on heating gives 'C', 'C" when treated with Br2 in the presence of KOH produces ethylamine. Compound ' A' is

  • CH3COOH

  • CH3CH2CH2COOH

  • CH3(CH3)CHCOOH

  • CH3CH2COOH

Solution

D.

CH3CH2COOH

The space organic space compound space apostrophe straight A apostrophe space is space propanoic space acid space thin space left parenthesis CH subscript 3 CH subscript 2 COOH right parenthesis.
stack CH subscript 3 CH subscript 2 COOH with propanoic space acid space left parenthesis straight A right parenthesis below space rightwards arrow with NH subscript 3 on top space stack CH subscript 3 CH subscript 2 COO to the power of minus NH subscript 4 space with ammonium space propanoate space left parenthesis straight B right parenthesis below rightwards arrow from negative straight H subscript 2 straight O to increment of space stack CH subscript 3 minus CH subscript 2 CONH subscript 2 with propanamide space left parenthesis straight C right parenthesis below

rightwards arrow from Hoffmann space bromamide space reaction to KOH space plus space Br subscript 2 of space CH subscript 3 minus CH subscript 2 NH subscript 2 The space organic space compound space apostrophe straight A apostrophe space is space propanoic space acid space thin space left parenthesis CH subscript 3 CH subscript 2 COOH right parenthesis.
stack CH subscript 3 CH subscript 2 COOH with propanoic space acid space left parenthesis straight A right parenthesis below space rightwards arrow with NH subscript 3 on top space stack CH subscript 3 CH subscript 2 COO to the power of minus NH subscript 4 space with ammonium space propanoate space left parenthesis straight B right parenthesis below rightwards arrow from negative straight H subscript 2 straight O to increment of space stack CH subscript 3 minus CH subscript 2 CONH subscript 2 with propanamide space left parenthesis straight C right parenthesis below

rightwards arrow from Hoffmann space bromamide space reaction to KOH space plus space Br subscript 2 of space CH subscript 3 minus CH subscript 2 NH subscript 2

Question
CBSEENCH12011223

A reaction of a carbonyl compound with one of the following reagents involves nucleophilic addition followed by the elimination of water. The reagents is 

  • a Grignard reagent

  • hydrazine in presence of feebly acidic solution

  • hydrocyanic acid

  • sodium hydrogen sulphite

Solution

C.

hydrocyanic acid

Reaction of carbonyl compounds with ammonia derivatives give addition product followed by the elimination reaction. Slightly acidic medium generate a nucleophilic centre for the attack of weak base like ammonia derivatives.

Question
CBSEENCH12011272

Acetamide is treated with the following reagents separately. Which one of these would yield methylamine? 

  • NaOH - Br2

  • Sodalime

  • Hot conc. H2SO4

  • PCl5

Solution

A.

NaOH - Br2

The reagent which can convert -CONH2 group into - NH2 group is used for this reaction.
Among the given reagents only NaOH/ Br2 converts -CONH2 group to -NHgroup, thus it is used for converting acetamide to methylamine. This reaction is called Hoffman bromide reaction.
CH3CONH2 + NaOH  +Br2 --> CH3NH2 +NaBr + Na2CO3 + H2O