Mechanical Properties of Solids

Sponsor Area

Question
CBSEENPH11020833

A rope is wound around a hollow cylinder of mass 3 kg and radius 40 cm. What is the angular acceleration of the cylinder if the rope is pulled with a force of 30 N?

  • 25 m/s2

  • 0.25 rad/s2

  • 25 rad/s2

  • 5 m/s2

Solution

C.

25 rad/s2


τ = I α
F × R = MR2α
30 × 0.4 = 3 × (0.4)2 α
12 = 3 × 0.16 α
400 = 16 α
α = 25 rad/s2

Sponsor Area

Question
CBSEENPH11020578

Copper of fixed volume V is drawn into wire of length l. When this wire is subjected to a constant force F, the extension produced in the wire is increment straight l. Which of the following graphs is a straight line?

  • increment straight l space versus space 1 over straight l
  • increment straight l space versus space straight l squared
  • increment straight l space versus space 1 over straight l squared
  • increment straight l space versus space straight l

Solution

B.

increment straight l space versus space straight l squared

According to Hooke's law,
Young's Modulus is given by,
straight y space equals space fraction numerator begin display style bevelled straight F over straight A end style over denominator begin display style bevelled fraction numerator increment straight l over denominator straight l end fraction end style end fraction space equals space fraction numerator straight F space xl over denominator increment straight l space straight x space straight A end fraction     ... (i)
V = A xl = constant             ... (ii)
From equations (i) and (ii), we have
space space space straight y space equals space fraction numerator straight F space straight x space straight l space straight x space straight l over denominator increment straight l space straight x space straight V end fraction
increment straight l space equals space fraction numerator straight F over denominator straight V space straight x space straight y end fraction space straight l squared

space increment straight l space proportional to space straight l squared

Question
CBSEENPH11020779

For a cubic structure which one of the following relations indicating the cell characteristic is correct?

  • straight a not equal to straight b not equal to straight c space and space space straight alpha space not equal to straight beta space and space straight gamma space space 90 to the power of straight o
  • straight a not equal to straight b not equal to straight c space and space space straight alpha space equals space straight beta space equals straight gamma space equals space 90 to the power of straight o
  • straight a equals straight b equals straight c space and space space straight alpha space not equal to straight beta space not equal to straight gamma space not equal to space 90 to the power of straight o
  • straight a equals straight b equals straight c space and space space straight alpha space equals straight beta space equals straight gamma space equals space 90 to the power of straight o

Solution

D.

straight a equals straight b equals straight c space and space space straight alpha space equals straight beta space equals straight gamma space equals space 90 to the power of straight o

In cubic crystal, the crystal axes are perpendicular to one another (α= β =γ=90) and the repetitive interval is the same along the three axes (a= b=c).

Question
CBSEENPH11020733

Sodium has body centred packing.Distance between two nearest atoms is 3.7 A. The lattice parameter is

  • 6.8 A

  • 4.3 A

  • 3.0 A

  • 8.6 A

Solution

B.

4.3 A

The neighbour distance of a body centred cubic cell,straight d space equals space fraction numerator square root of 3 straight a end root over denominator 2 end fraction where a is the lattice parameter.

3.7 space equals space square root of fraction numerator 3 straight a over denominator 2 end fraction end root
straight a space equals space fraction numerator 2 space straight x space 3.7 over denominator square root of 3 end fraction space equals space 4.3 space straight A

Question
CBSEENPH11020531

The approximate depth of an ocean is 2700 m.The compressibility of water is 45.4 x 10-11 Pa-1 and density of water is 103 kg/m3. What obtained at  the bottom of the ocean?

  • 0.8 x10-2

  • 1.0 x 10-2

  • 1.2 x 10-2

  • 1.4 x 10-2

Solution

C.

1.2 x 10-2

Given d = 2700m
straight rho space equals space 10 cubed space kg divided by straight m cubed
Compressibility =454 x 10-11 per pascal
The pressure at the bottom of ocean is given by
straight p equals ρgd
= 103 x 10 x 2700 = 27 x 106 Pa
 So,fractional compression =compressibilty x pressure
= 45.4 x 10-11 x 27 x 106 = 1.2 x 10-2