Kinetic Theory

Sponsor Area

Question
CBSEENPH11020711

A particle of mass M starting from rest undergoes uniform acceleration. If the speed acquired in time T is v, the power delivered to the particle is

  • Mv2/T

  • Mv2 / 2T2

  • Mv2/T2

  • Mv2 / 2T

Solution

D.

Mv2 / 2T

The kinetic energy of particle  = Mv2 / 2
Power = Energy /Time
P = Mv2 /2T

Sponsor Area

Question
CBSEENPH11020728

An engine pumps water continuously through a hose. Water leaves the hose with a velocity v and m is the mass per unit length of the water jet. What is the rate at which kinetic energy is imparted to water?

  • mv3 /2

  • mv3

  • mv2/2

  • m2v2 /2

Solution

A.

mv3 /2

Let m is the mass per unit length rate  of mass per sec = mx/t = mv
Rate of KE = (mv)v2/2  = mv3/2

Question
CBSEENPH11020761

At 10o C the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110o C this ratio is

  • x

  • 383x/283

  • 10x/110

  • 283x/383

Solution

D.

283x/383

Writing ideal gas law
PV = nRT
PV space equals space straight m over straight M RT
PV over straight m space equals space 1 over straight M RT
straight P over straight rho space equals space RT over straight M
straight rho over straight P space equals space 1 over straight T
Therefore comma
fraction numerator straight rho subscript 1 divided by straight P subscript 1 over denominator straight rho subscript 2 divided by straight P subscript 2 end fraction space equals space straight T subscript 1 over straight T subscript 2
fraction numerator straight x over denominator left parenthesis straight rho subscript 2 divided by straight P subscript 2 right parenthesis end fraction space equals space 383 over 283

straight rho subscript 2 over straight P subscript 2 space equals space 283 over 383 straight x

Question
CBSEENPH11020698

In producing chlorine by electrolysis 100 kW power at 125 V is being consumed. How much chlorine per minute is liberated (ECE of chlorine is 0.367 x 10-6 KgC-1)

  • 1.76 x 10-3 kg

  • 9.67 x 10-3 kg

  • 17.61 x 10-3 kg

  • 3.67 x 10-3 kg

Solution

C.

17.61 x 10-3 kg

Mass of the substance deposited at the cathode
 
m= zit

equals space straight z open parentheses straight W over straight V close parentheses straight t

equals space 0.367 space space straight x space 10 to the power of negative 6 end exponent space straight x space fraction numerator 100 space straight x space 10 cubed over denominator 125 end fraction space straight x space 60
equals space 17.6 space straight x space 10 to the power of negative 3 end exponent space kg

Question
CBSEENPH11020617

In the given (V-T )diagram, what is the relation between pressures p1 and p2?

  • p2 =p1

  • p2>p1

  • p2<p1

  • Cannot be predicted

Solution

C.

p2<p1

The slope of the graph directly proportional to 1/p