Redox Reactions

Sponsor Area

Question
CBSEENCH11008246

(I)H2O2 +O3 --> H2O +2O2
(II) H2O2 +Ag2O +--> 2Ag +H2O +O2
Role of hydrogen peroxide in the above reaction is respectively

  • oxidising in (I) and reducing (II)

  • reducing (I) and oxidizing in (II)

  • reducing in (I) and (II)

  • oxidising in (I) and (II)

Solution

A.

oxidising in (I) and reducing (II)

In the reaction,

since H2O2 oxidise, O3 into O2 thus it behaves as an oxidising agent.
the further reaction, in the reaction,

Here H2O2 reduces Ag2O into metallic silver [Ag] (as oxidation number is reducing from +1 to 0).Thus, H2O2 behaves as a reducing agent. 

Sponsor Area

Question
CBSEENCH12011022

A mixture of potassium chlorate, oxalic acid and sulphuric acid is heated. During the reaction which element undergoes a maximum change in the oxidation number?

  • S

  • H

  • Cl

  • C

Solution

C.

Cl

When a mixture of potassium chlorate, oxalic acid and sulphuric acid is heated, the following reaction occurs:
straight K with plus 1 on top Cl with plus 5 on top straight O with negative 2 on top subscript 3 space plus straight H with plus 1 on top subscript 2 straight C with plus 3 on top subscript 2 straight O with negative 2 on top subscript 4 space plus straight H with plus 1 on top subscript 2 straight S with plus 6 on top straight O with negative 2 on top subscript 4
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space rightwards arrow space straight K with plus 1 on top subscript 2 straight S with plus 6 on top straight O with negative 2 on top subscript 4 space plus straight K with plus 1 on top Cl with negative 1 on top space plus straight C with plus 4 on top straight O with negative 2 on top subscript 2 space plus straight H with plus 1 on top subscript 2 straight O with negative 2 on top
Thus, Cl is the element which undergoes a maximum change in the oxidation state.

Question
CBSEENCH11008274

In which of the following compounds, nitrogen exhibits highest oxidation state?

  • N2H4

  • NH3

  • N3H

  • NH2OH

Solution

C.

N3H

straight a right parenthesis space stack straight N subscript 2 with straight x on top stack straight H subscript 4 with plus 1 on top
2 left parenthesis straight x right parenthesis space plus left parenthesis plus 1 right parenthesis 4 space equals space 0
2 straight x space equals space minus 4
straight x equals negative 2
space straight b right parenthesis space straight N with straight x on top stack straight H subscript 3 with plus 1 on top
straight x plus left parenthesis plus 1 right parenthesis space 3 space equals space 0
straight x equals negative 3

straight c right parenthesis stack straight N subscript 3 with straight x on top straight H with plus 1 on top space
straight x plus left parenthesis plus 1 right parenthesis 3 space equals space 0
straight x equals negative 3

straight d right parenthesis space straight N with straight x on top straight H with plus 1 on top subscript 2 straight O with negative 2 on top straight H with plus 1 on top
straight x plus left parenthesis plus 1 right parenthesis 2 space plus left parenthesis negative 2 right parenthesis space plus left parenthesis plus 1 right parenthesis space equals space 0
straight x plus 2 minus 2 plus 1 space equals 0
straight x plus 1 space equals space
straight x equals negative 1
Thus, oxidation state of nitrogen is highest in N3H.

Question
CBSEENCH11008268

When Cl2 gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from

  • zero to +1 and zero to -5

  • zero to -1 and zero to +5

  • zero to -1 and zero to +5

  • zero to +1 and zero to -3

Solution

B.

zero to -1 and zero to +5

When chlorine gas reacts with hot and concentrated NaOH solution, it disproportionates into Chloride (Cl-) and Chlorate (ClO3-) ions. 
3 Cl with 0 on top subscript 2 space plus space stack 6 NaOH space with Hot space and space concentrated below rightwards arrow space 5 Na Cl with negative 1 on top space plus Na Cl with plus 5 on top straight O subscript 3 space plus 3 straight H subscript 2 straight O

Question
CBSEENCH11008473

For the redox reaction

MnO4- + C2O4-2 + H+    Mn2+ + CO2 + H2O

The correct coefficients of the reactants for the balanced equation are

  • MnO4- C2O42- H+
    16 5 2
  • MnO4- C2O42- H+
    2 5 16
  • MnO4- C2O42- H+
    5 16 2
  • MnO4- C2O42- H+
    2 16 5

Solution

B.

MnO4- C2O42- H+
2 5 16

Mn+7O4-    M+2n2+ ; 5e- gain ... (i)C+32O42-    C+4O2 ;2e- loss ... (ii)Multiplying (i) and 2 and (ii)by 5 to balance e-2MnO4- + 5C2O42-  2Mn2+ + 10CO2On balancing charge;2MnO4- + 5C2O42-  + 16H+  2Mn2+ + 10 CO2 + 8 H2O

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