Gravitation

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Question
CBSEENPH11020449

A particle of mass 10 g is kept on the surface of a uniform sphere of mass 100 kg and radius 10 cm. Find the work to be done against the gravitational force between
(you may take G = 6 . 67× 10-11 Nm2/ kg2)

  • 13.34 x 10-10 J

  • 3.33 x 10-10 J

  • 6.67 x10-9 J

  • 6.67 x10-10 J

Solution

D.

6.67 x10-10 J

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Question
CBSEENPH11020370

A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11 kms−1, the escape velocity from the

  • 1.1 kms−1

  • 11 kms−1

  • 110 kms−1

  • 0.11 kms−1

Solution

C.

110 kms−1

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Question
CBSEENPH11020254

A satellite is revolving in a circular orbit at a height ‘h’ from the earth’s surface (radius of earth R ; h<<R). The minimum increase in its orbital velocity required, so that the satellite could escape from the earth’s gravitational field, is close to: (Neglect the effect of atmosphere.)

  • square root of 2 gR end root
  • square root of gR
  • square root of gR divided by 2 end root
  • square root of gR space left parenthesis square root of 2 space minus 1 right parenthesis

Solution

D.

square root of gR space left parenthesis square root of 2 space minus 1 right parenthesis

Given, a satellite is revolving in a circular orbit at a height h from the Earth's surface having radius of earth R, i.e h <<R
Orbit velocity of a satellite
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therefore, the minimum increase in its orbital velocity required to escape from the Earth's Gravitational Field.
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Question
CBSEENPH11020477

A satellite of mass m revolves around the earth of radius R at a height x from its surface. If g is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite is

  • fraction numerator gR over denominator straight R minus straight x end fraction
  • gx

  • fraction numerator gR squared over denominator straight R space plus straight x end fraction
  • open parentheses fraction numerator gR squared over denominator straight R space plus straight x end fraction close parentheses to the power of 1 divided by 2 end exponent

Solution

D.

open parentheses fraction numerator gR squared over denominator straight R space plus straight x end fraction close parentheses to the power of 1 divided by 2 end exponent

The gravitational force exerted on satellite at a height x is
straight F subscript straight G space equals space fraction numerator GM subscript straight e straight m over denominator left parenthesis straight R plus straight x right parenthesis squared end fraction
where Me = mass of earth Since, gravitational force provides the necessary centripetal force, so,
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Question
CBSEENPH11020474

A solid sphere is rotating in free space. If the radius of the sphere is increased keeping mass same which one of the following will not be affected?

  • moment of inertia

  • angular momentum

  • angular velocity

  • rotational kinetic energy

Solution

B.

angular momentum

In free space, neither acceleration due to gravity for external torque act on the rotating solid sphere. Therefore, taking the same mass of sphere if the radius is increased then a moment of inertia, rotational kinetic energy and angular velocity will change but according to the law of conservation of momentum, angular momentum will not change.