Inverse Trigonometric Functions
Sponsor Area
is equal to
-
4
-
3
-
2
-
1/2
4
3
2
1/2
C.
2
We have,
Sponsor Area
A particle is projected from a point O with velocity u at an angle of 60o with the horizontal. When it is moving in a direction at right angles to its direction at O, its velocity then is given by
-
u/3
-
u/2
-
2u/3
-
D.

u cos 60o = v cos 30o
A value of θ for which
is purely imaginary is
-
π/3
-
π/6
-
-
D.
Let z =
is purely imaginary. Then, we have Re (z) = 0
We have Re (z) = 0
Now, consider z = 
Consider f(x) = tan-1
. A normal to y = f (x) at x = π/6 also passes through the point
-
(0,0)
-
(0, 2π/3)
-
(π/6 ,0)
-
(π/4, 0)
B.
(0, 2π/3)
If 0≤x<2π, then the number of real values of x, which satisfy the equation cosx+cos2x+cos3x+cos4x=0, is :
-
3
-
5
-
7
-
9
C.
7
Sponsor Area
Mock Test Series
Mock Test Series



