Question 1

# is equal to  4 3 2 1/2

Solution

C.

2

We have,

Question 2

## A particle is projected from a point O with velocity u at an angle of 60o with the horizontal. When it is moving in a direction at right angles to its direction at O, its velocity then is given by u/3 u/2 2u/3

Solution

D.

u cos 60o = v cos 30o
Question 3

## A value of θ for which  is purely imaginary is π/3 π/6

Solution

D.

Let z =  is purely imaginary. Then, we have Re (z) = 0
We have Re (z) = 0
Now, consider z =

Question 4

Solution

B.

(0, 2π/3)

Question 5

Solution

C.

7