Problem On Trains
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A man travels 450 km to his home partly by train and partly by car. He takes 8 hours 40 minutes if he travels 240 km by train and rest by car. He takes 20 minutes more if he travels 180 km by train and the rest by car. The speed of the car in km/hr is
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45
-
50
-
60
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48
A.
45
Let the speed of train be x kmph.
Speed of car = y kmph.
Case I,
Case II,
Multiply equation (i) by 3 - Multiply equation (ii) by 4,
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A train 'B' speeding with 100 kmph crosses another train C, running in the same direction, in 2 minutes. If the length of the train B and C be 150 metre and 250 metre respectively, what is the speed of the train C (in kmph)?
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75
-
88
-
95
-
110
B.
88
Let the speed of train C be x kmph.
∴ Relative speed of B = (100 - x) kmph.
A train covers a distance between A and station B in 45 minutes, If the speed of the train is reduced by 5 km per hr, then the same distance is covered in 48 minutes. The distance between stations A and B is
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60 km
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64 km
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80 km
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55 km
A.
60 km
Let the distance between stations be x km.
∴ Speed of train = 
Now, speed is reduced by 5 km/hr, 
A train travelling with a speed of 60 km/hr catches another train travelling in the same direction and then leaves it 120 m behind in 18 seconds. The speed of the second train is
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26 km/hr
-
35 km/hr
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36 km/hr
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63 km/hr
C.
36 km/hr
Relative distance = 120 m
Relative Time (t) = 18 seconds
Relative speed = 
∴ Speed of second train = 60 - 24 = 36 km/hr
A train with a uniform speed crosses a pole in 2 seconds and a bridge of length 250m in 7 seconds. The length of the train is
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150 m
-
120 m
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100 m
-
80 m
C.
100 m
Let the length of the train be x metre, then
Speed of a train = 
...(i)
When it crosses a bridge, then
Speed of a train = 
...(ii)
According to the question,
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