A cistern has 3 pipes A, B and C. A and B can fill it in 3 and 4 hours respectively, and C can empty it in 1 hour. If the pipes are opened at 3 p.m., 4 p.m. and 5 p.m. respectively on the same day, the cistern will be empty at
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7 : 12 p.m.
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7 : 15 p.m.
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7 : 10 p.m.
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7 : 18 p.m.
A.
7 : 12 p.m.
Part of the cistern filled by A in 2 hours i.e. till 5 p.m.
Part of the cistern filled by B in 1 hour i.e. till 5 p.m.
When all three pipes are opened, net part filled in one hour
i.e. part is emptied per hour.
∴ Time taken to empty
∴ Required time = 5 + 2 : 12 = 7 : 12 p.m.