A ball of lead 4 cm in diameter is covered with gold. If the volume of the gold and lead are equal, then the thickness of gold [given ] is approximately.
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5.038 m
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5.190 cm
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1.038 cm
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0.518 cm
D.
0.518 cm
Diameter of lead = 4 cm
Radius of lead = 2 cm
Volume of lead =
Let the thickness of gold be x cm, then
Volume of gold =