Algebra

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Question
SSCCGLENQA12042498

A complete factorization of left parenthesis straight x squared plus 64 right parenthesis is

  • left parenthesis straight x squared plus 8 right parenthesis squared
  • left parenthesis straight x squared plus 8 right parenthesis thin space left parenthesis straight x squared minus 8 right parenthesis
  • left parenthesis straight x squared minus 4 straight x plus 8 right parenthesis thin space left parenthesis straight x squared minus 4 straight x minus 8 right parenthesis
  • left parenthesis straight x squared plus 4 straight x plus 8 right parenthesis thin space left parenthesis straight x squared minus 4 straight x plus 8 right parenthesis

Solution

D.

left parenthesis straight x squared plus 4 straight x plus 8 right parenthesis thin space left parenthesis straight x squared minus 4 straight x plus 8 right parenthesis straight x to the power of 4 plus 64 space equals space left parenthesis straight x squared right parenthesis squared space plus space left parenthesis 8 right parenthesis squared
or space
left parenthesis straight x squared space plus space 8 right parenthesis squared space minus space 2 space cross times space 8 straight x squared
              open square brackets because space straight a squared plus straight b squared space equals space left parenthesis straight a plus straight b right parenthesis squared minus 2 ab close square brackets
    equals space left parenthesis straight x squared plus 8 right parenthesis squared space minus space left parenthesis 4 straight x right parenthesis squared
space equals space left parenthesis straight x squared plus 4 straight x plus 8 right parenthesis space left parenthesis straight x squared minus 4 straight x plus 8 right parenthesis

Sponsor Area

Question
SSCCGLENQA12042286

A man loses 20 1 half percent sign of his money and after spending 80% of the remainder, he is left with ₹ 159. How much did he have at first?

  • ₹ 500

  • ₹ 800

  • ₹ 1000

  • ₹ 1200

Solution

C.

₹ 1000

Let the money be ₹ x.
According to the question,
               [(100 - 20.5)% of x] of (100 - 80)% = 159
rightwards double arrow space space space space fraction numerator 79.5 over denominator 100 end fraction cross times straight x cross times 20 over 100 space equals space 159
rightwards double arrow space space space space straight x space space equals space fraction numerator 159 space cross times space 100 space cross times space 100 over denominator 79.5 space cross times space 20 end fraction space equals space ₹ space 1000

Question
SSCCGLENQA12042357

Among below expressions which one can be expressed as the difference of two cubic expressions?

  • straight x cubed plus straight y cubed plus 3 straight x plus 3 straight y
  • straight x cubed plus 2 straight x squared plus 3 straight x plus straight x squared
  • straight x cubed plus 3 straight x squared plus 3 straight x minus 2
  • straight x cubed plus 3 straight x squared plus 3 straight x minus 7

Solution

D.

straight x cubed plus 3 straight x squared plus 3 straight x minus 7

Question
SSCCGLENQA12042835

Find the sum of:
open parentheses 1 minus fraction numerator 1 over denominator straight n plus 1 end fraction close parentheses space plus space open parentheses 1 minus fraction numerator 2 over denominator straight n plus 1 end fraction close parentheses space plus space open parentheses 1 minus fraction numerator 3 over denominator straight n plus 1 end fraction close parentheses plus...... open parentheses 1 minus fraction numerator straight n over denominator straight n plus 1 end fraction close parentheses

  • n

  • 1 half straight n
  • (n + 1)

  • 1 half left parenthesis straight n plus 1 right parenthesis

Solution

B.

1 half straight n open parentheses 1 minus fraction numerator 1 over denominator straight n plus 1 end fraction close parentheses plus space open parentheses 1 minus fraction numerator 2 over denominator straight n plus 1 end fraction close parentheses plus open parentheses 1 minus fraction numerator 3 over denominator straight n plus 1 end fraction close parentheses space plus...... open parentheses 1 minus fraction numerator straight n over denominator straight n plus 1 end fraction close parentheses
equals straight n minus open parentheses fraction numerator 1 over denominator straight n plus 1 end fraction plus fraction numerator 2 over denominator straight n plus 1 end fraction plus fraction numerator 3 over denominator straight n plus 1 end fraction plus.... fraction numerator straight n over denominator straight n plus 1 end fraction close parentheses
equals space straight n minus fraction numerator straight n left parenthesis straight n plus 1 right parenthesis over denominator 2 left parenthesis straight n plus 1 right parenthesis end fraction space equals space straight n minus straight n over 2 space equals space straight n over 2

Question
SSCCGLENQA12042080

For two positive numbers a and b, if a2 + b2 = 24 and ab = 6, then (a3 + b3) is equal to

  • 96

  • 10

  • 102

  • 108

Solution

D.

108

a2 + b2 = 24  and ab = 6

therefore space space left parenthesis straight a plus straight b right parenthesis squared space equals space straight a squared space plus space straight b squared space plus space 2 ab space equals space 24 space plus space 2 space cross times 6 space equals space 36
therefore space space straight a space plus space straight b space equals space square root of 36 space equals space 6
therefore space left parenthesis straight a cubed space plus space straight b cubed right parenthesis space equals space left parenthesis straight a space plus space straight b right parenthesis thin space left parenthesis straight a squared space minus space ab space plus space straight b squared right parenthesis
space equals space 6 space left parenthesis 24 space minus space 6 right parenthesis space equals space 6 space cross times space 18 space equals space 108

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